How to change column value by CASE command depending on condition without giving adding a new column to table?
The only way I know is by adding new column:
SELECT
t1.*
,CASE
what='costs' THEN amount*(-1)
ELSE
sales
END AS NewAmount
FROM t1
Is there a way to get the results as on the picture below? Note that sometimes the condition is specified by values in more than one column (what=costs AND country=Atlantida)
Select just the columns that you want:
SELECT t1.what,
(CASE WHEN what = 'costs' THEN amount*(-1)
ELSE sales
END) AS Amount
FROM t1
Yes, there is way,
Instead of select *, use required column names only.
SELECT
t1.what
,CASE
WHEN what='costs' THEN amount*(-1)
ELSE
sales
END AS Amount
FROM t1
Don't you want amount when not cost?
SELECT
t1.*
,CASE when what='costs' THEN amount*(-1)
ELSE
amount
END AS NewAmount
FROM t1
Related
I have a table named Bank that contains a Bank_Values column. I need a calculated Bank_Value_Unique column to shows whether each Bank_Value exists somewhere else in the table (i.e. whether its count is greater than 1).
I prepared this query, but it does not work. Could anyone help me with this and/or modify this query?
SELECT
CASE
WHEN NULLIF(LTRIM(RTRIM(Bank_Value)), '') =
(SELECT Bank_Value
FROM [Bank]
GROUP BY Bank_Value
HAVING COUNT(*) = 1)
THEN '0' ELSE '1'
END AS Bank_Key_Unique
FROM [Bank]
A windowed count should work:
SELECT
*,
CASE
COUNT(*) OVER (PARTITION BY Bank_Value)
WHEN 1 THEN 1 ELSE 0
END AS Bank_Value_Unique
FROM
Bank
;
It works also, but I found solution also:
select CASE WHEN NULLIF(LTRIM(RTRIM(Bank_Value)),'') =
(select Bank_Value
from Bank
group by Bank_Value
having (count(distinct Bank_Value) > 2 )) THEN '1' ELSE '0' END AS
Bank_Value_Uniquness
from Bank
It was missing "distinct" in having part.
I have a query like:
select nvl(nvl(sum(a.quantity),0)-nvl(cc.quantityCor,0),0)
from RCV_TRANSACTIONS a
LEFT JOIN (select c.shipment_line_id,c.oe_order_line_id,nvl(sum(c.quantity),0) quantityCor
from RCV_TRANSACTIONS c
where c.TRANSACTION_TYPE='CORRECT'
group by c.shipment_line_id,c.oe_order_line_id) cc on (a.shipment_line_id=cc.shipment_line_id and a.shipment_line_id=7085740)
where a.transaction_type='DELIVER'
and a.shipment_line_id=7085740
group by nvl(cc.quantityCor,0);
The query runs OK, but returns no value. I want it to return 0 if there is no quantity found. Where have I gone wrong?
An aggregation query with a GROUP BY returns no rows if all rows are filtered out.
An aggregation query with no GROUP BY always returns one row, even if all rows are filtered out.
So, just remove the GROUP BY. And change the SELECT to:
select coalesce(sum(a.quantity), 0) - coalesce(max(cc.quantityCor), 0)
I may be wrong, but it seems you merely want to subtract CORRECT quantity from DELIVER quantity for shipment 7085740. You don't need a complicated query for that. Especially your GROUP BY clauses make no sense if that is what you are after.
One way to write this query would be:
select
sum(case when transaction_type = 'DELIVER' then quantity else 0 end) -
sum(case when transaction_type = 'CORRECT' then quantity else 0 end) as diff
from rcv_transactions
where shipment_line_id = 7085740;
I had a query like this and was trying to return 'X' when the item is not valid.
SELECT case when segment1 is not null then segment1 else 'X' end
--INTO v_orgValidItem
FROM mtl_system_items_b
WHERE segment1='1676001000'--'Jul-00'--l_item
and organization_id=168;
..but it was returning NULL.
Changed to use aggregation with no group by and now it returns 'X' when the item is not valid.
SELECT case when max(segment1) is not null then max(segment1) else 'X' end valid
--INTO v_orgValidItem
FROM mtl_system_items_b
WHERE segment1='1676001000'--'Jul-00'--l_item
and organization_id=168;--l_ship_to_organization_id_pb;
Here is another example, proving the order of operations really matters.
When there is no match for this quote number, this query returns NULL:
SELECT MAX(NVL(QUOTE_VENDOR_QUOTE_NUMBER,0))
FROM PO_HEADERS_ALL
WHERE QUOTE_VENDOR_QUOTE_NUMBER='foo.bar';
..reversing the order of MAX and NVL makes all the difference. This query returns the NULL value condition:
SELECT NVL(MAX(QUOTE_VENDOR_QUOTE_NUMBER),0)
FROM PO_HEADERS_ALL
WHERE QUOTE_VENDOR_QUOTE_NUMBER='foo.bar';
I have two tables, an Orders table which contains a list of a users orders and a OrderShippingCosts table which contains a price for shipping each item based on the OrderTypeID in the Orders table.
I am running a query like below to calculate the total shipping costs:
SELECT
SUM(CASE
WHEN OR.OrderTypeID = 1
THEN (SELECT CostOfShippingSmallParcel
FROM OrderShippingCosts)
ELSE (SELECT CostOfShippingBigParcel
FROM OrderShippingCosts)
END) AS TotalShippingCost
FROM
Orders AS OR
But I'm getting the following error:
Cannot perform an aggregate function on an expression containing an aggregate or a subquery
Does anyone know what is wrong with my query?
Function SUM takes an expression on input, which evaluates into single data value, not a dataset. Expression definition from MSDN:
Is a combination of symbols and operators that the SQL Server Database Engine evaluates to obtain a single data value.
You trying to pass to SUM function a dataset (which is result of subquery), not a single data value. This is simplification of what you trying to query:
SELECT SUM(SELECT Number FROM SomeTable)
It is not valid. The valid query would be:
SELECT SUM(Value) FROM SomeTable
In your particular case looks like you missing JOIN. Your original logic will result in summary of entire OrderShippingCosts table for each row of Orders table. I think, it should be something like this:
SELECT
SUM
(
CASE
WHEN ord.OrderTypeID = 1 THEN ship.CostOfShippingSmallParcel
ELSE ship.CostOfShippingBigParcel
END
) TotalShippingCost
FROM Orders AS ord
JOIN OrderShippingCosts ship ON /* your search condition, e.g.: ord.OrderID = ship.OrderID */
By the way, it is not a good idea to use reserved symbols as aliases, names and so on. In your query you use OR as alias for Orders table. Symbol OR is reserved for logical or operation. If you really need to use reserved symbol, wrap it into [ and ] square braces. Look here and here for more details.
The error message is clear, you can avoid it with a join:
SELECT
SUM(CASE WHEN [OR].OrderTypeID = 1
THEN CostOfShippingSmallParcel
ELSE CostOfShippingBigParcel END) AS TotalShippingCost
FROM Orders [OR]
CROSS JOIN OrderShippingCosts
You can try like this...
SELECT
CASE WHEN OR.OrderTypeID = 1
THEN (SELECT SUM(CostOfShippingSmallParcel) FROM OrderShippingCosts)
ELSE (SELECT SUM(CostOfShippingBigParcel) FROM OrderShippingCosts) END AS TotalShippingCost
FROM Orders AS OR
Let me know
select sum (or.TotalShippingCost)
FROM
SELECT
(CASE WHEN OR.OrderTypeID = 1
THEN (SELECT CostOfShippingSmallParcel FROM OrderShippingCosts)
ELSE (SELECT CostOfShippingBigParcel FROM OrderShippingCosts) END) AS TotalShippingCost
FROM Orders AS OR
Try this
SELECT
ISNULL
(
SUM
(
CASE
WHEN O.OrderTypeID = 1 THEN C.CostOfShippingSmallParcel
ELSE C.CostOfShippingBigParcel END
), 0
) AS TotalShippingCost
FROM
Orders AS O LEFT JOIN
OrderShippingCosts C ON O.Id = C.OrderId -- Your releation id
I have to do a lot of queries with this kind of logic:
Check if a table contains a record for a patient
If it does return then 'Yes'
Else return 'No'
Now, I want to create a procedure that will do this, so I tried to create a function that will do the above, but ended up in dynamic queries which is not possible in functions.
Is it possible to achieve this? How can I go about this?
PS:
Maybe something like:
select
(IF EXISTS(SELECT * FROM Dtl_Patient WHERE Pk = 3990 select 'Yes' else select 'No')) as output from dtl_AllPatient;
Try CASE
SELECT
CASE WHEN EXISTS (SELECT PatientID FROM Table2 T2 WHERE T2.PatientID =T1.PatientID)
THEN 'YES' ELSE 'NO' END AS PatientExists
FROM
Table1 T1
EDIT
SELECT
CASE WHEN EXISTS (SELECT Pk FROM Dtl_Patient WHERE Pk = 3990) THEN 'YES' ELSE 'NO' END AS PatientExists
FROM dtl_AllPatient
check this EXISTS Condition
The SQL EXISTS condition is considered "to be met" if the subquery returns at least one row.
I have a table with several rows, and several columns. It looks like this:
Name Description
X PASS
X PASS
X FAIL
I want it to return only one row. If all of them are PASS, return PASS.
If one or more of them are FAIL, then return FAIL.
What's the best way to go about achieving this in SQL Server 2008?
EDIT: The values in the name column will always be the same.
Depending on the database indexes, and assuming you want one row returned per unique name, I would look at the performance of
select
name,
min([description]) as description
from
tableA
group by
name
compared to the other solutions
SELECT TOP 1 CASE Description WHEN 'FAIL' THEN 'FAIL' ELSE 'PASS' END
FROM DaTable
ORDER BY Description
OP: Is it possible that the table is empty? In that case this query won't return any rows, obviously.
EDIT
According to aquinas's comment I created a modified query without ordering:
SELECT CASE COUNT(Description) WHEN 0 THEN 'FAIL' ELSE 'PASS' END
FROM DaTable
WHERE Description = 'FAIL'
This query will return PASS if DaTable is empty.
This is the simplest solution you will find:
SELECT MIN(Description) FROM tbl
If there's at least one FAIL, then our result column will contain FAIL, otherwise, it will contain PASS.
You can use EXISTS to get the existance of a row containing "FAIL".
You could also try something like:
SELECT TOP 1 COALESCE(tFail.Description,t.Description)
FROM myTable AS t
LEFT JOIN myTable AS tFail ON tFail.Name = t.Name AND tFail.Description = 'FAIL'
WHERE t.Name = 'x'
Here is the query:
--DROP TABLE result
CREATE TABLE result(Name varchar(10),Description varchar(20))
--select * from result
INSERT INTO result
VALUES('X','PASS'),('X','PASS'),('X','FAIL')
;WITH CTE(descp,cnt) as (SELECT [description],COUNT(*) as cnt FROM result group by [description])
SELECT CASE WHEN COUNT(*) > 1 then 'FAIL' when COUNT(*)=1 then MAX(descp) else 'PASS' END FROM CTE