I'm making like a "mini programming language" in visual basic.
Mostly just for practice and for fun.
I just have one problem. I want to make a commenting system.
I got an idea how it would work, but i don't know how to do it.
So this is what i want to do:
I want to start to select all text from //
So for example, if i write:
print = "Hello World!"; //This is a comment!
it will select everything from the // so it will select
//This is a comment!
Then i would just replace the selected text with nothing.
You can use String.IndexOf + Substring:
Dim code = "Dim print = ""Hello World!""; //This is a comment!"
Dim indexOfComment = code.IndexOf("//")
Dim comment As String = Nothing
If indexOfComment >= 0 Then comment = code.Substring(indexOfComment)
If you want the part before the comment dont use String.Replace but also Substring or Remove:
code.Substring(0, indexOfComment)
Related
I prepared this small example to show you my problem (vb.net and Newtonsoft)
I would prefer that the solution be done with Newtonsoft.
Public Class Message
Property Emoji As String
End Class
Public Sub GetJson()
Dim msgObject As New Message With {.Emoji = "\uD83D\uDE00"}
'Option 1
Dim JsonSerializerSettings As New JsonSerializerSettings
JsonSerializerSettings.StringEscapeHandling = StringEscapeHandling.EscapeNonAscii
Dim msgJson_1 As String = Newtonsoft.Json.JsonConvert.SerializeObject(msgObject, JsonSerializerSettings)
'Option 2
Dim msgJson_2 As String = Newtonsoft.Json.JsonConvert.SerializeObject(msgObject, Newtonsoft.Json.Formatting.None)
'Option 3
Dim stringWriter As New StringWriter()
Using writer As New JsonTextWriter(stringWriter)
writer.Formatting = Formatting.None
Dim serializer As New JsonSerializer()
serializer.Serialize(writer, msgObject)
End Using
Dim msgJson_3 As String = stringWriter.ToString()
End Sub
with none of the three options works, it always results in
{
"Emoji": "\\uD83D\\uDE00"
}
The result I need is
{
"Emoji": "\uD83D\uDE00"
}
How do I set Newtonsoft to not take into account the backslash character, as an escaped character?
Another unorthodox way could be:
jsonString = jsonString.replace("\\","\")
I do not really like
Thanks!!!!
\ is an escape char in JSON hence if you try and serialise a \ it gets escaped as \\ then when you deserialise \\ you get \
My guess is you have been given an example asking you to send "Emoji": "\uD83D\uDE00"
In json (and C#) \u#### specifies a unicode character (usually for something not found on a keyboard) as you are using VB.NET instead you should use $"{ChrW(&HD83D)}{ChrW(&HDE00)}"
"jsonString = jsonString.replace("//","/") " will never work, this is more safe way
json = json.Replace("\\\\u","\\u");
or since you don't like old, good classical solutions
json = Regex.Replace(json, #"\\u", #"u");
//or
json = json.Replace(#"\\u", #"\u");
even this will work in your case ( but I will not recommend for another cases since it is not safe)
json = Regex.Unescape(json);
I have been looking for a solution everywhere on the internet but nowhere I can see a single script which lets me read the name of a variable as a string in Godot 3.1
What I want to do:
Save path names as variables.
Compare the name of the path variable as a string to the value of another string and print the path value.
Eg -
var Apple = "mypath/folder/apple.png"
var myArray = ["Apple", "Pear"]
Function that compares the Variable name as String to the String -
if (myArray[myposition] == **the required function that outputs variable name as String**(Apple) :
print (Apple) #this prints out the path.
Thanks in advance!
I think your approach here might be a little oversimplified for what you're trying to accomplish. It basically seems to work out to if (array[apple]) == apple then apple, which doesn't really solve a programmatic problem. More complexity seems required.
First, you might have a function to return all of your icon names, something like this.
func get_avatar_names():
var avatar_names = []
var folder_path = "res://my/path"
var avatar_dir = Directory.new()
avatar_dir.open(folder_path)
avatar_dir.list_dir_begin(true, true)
while true:
var avatar_file = avatar_dir.get_next()
if avatar_file == "":
break
else:
var avatar_name = avatar_file.trim_suffix(".png")
avatar_names.append(avatar_name)
return avatar_names
Then something like this back in the main function, where you have your list of names you care about at the moment, and for each name, check the list of avatar names, and if you have a match, reconstruct the path and do other work:
var some_names = ["Jim","Apple","Sally"]
var avatar_names = get_avatar_names()
for name in some_names:
if avatar_names.has(name):
var img_path = "res://my/path/" + name + ".png"
# load images, additional work, etc...
That's the approach I would take here, hope this makes sense and helps.
I think the current answer is best for the approach you desire, but the performance is pretty bad with string comparisons.
I would suggest adding an enumeration for efficient comparisons. unfortunately Godot does enums differently then this, it seems like your position is an int so we can define a dictionary like this to search for the index and print it out with the int value.
var fruits = {0:"Apple",1:"Pear"}
func myfunc():
var myposition = 0
if fruits.has(myposition):
print(fruits[myposition])
output: Apple
If your position was string based then an enum could be used with slightly less typing and different considerations.
reference: https://docs.godotengine.org/en/latest/tutorials/scripting/gdscript/gdscript_basics.html#enums
Can't you just use the str() function to convert any data type to stirng?
var = str(var)
I want to let the user give me a variable number of strings (as virables).
example :
begin
cout('Hello').(' ').('world')
end.
this will print: "Hello world"
I know I just can let him input a string but I want to this code to work...
I think a record will help nut I dont know how
thank you
Im not sure what is that code example you have written ... but i try to help you.
Program test;
uses crt;
var string1,string2,string3:string;
begin
write("Write to first string : "); readln(string1);
write("Write to second string: "); readln(string2);
write("Write to third string : "); readln(string3);
String2:= string1 +" "+ string3; // it will add first with third string to one with one space
String3:= string2 +" "+ string1;// also 2.+ 1.
clrscr; //clearscreen (in CRT)
writeln("1. = 1.");
writeln("2. = 1. + 3.");
writeln("3. = 2. + 1.");
writeln;
writeln(string1);
writelm(string2);
writeln(string3);
I havent tested this (i have written it now for you) i think you will read it and learn how to addict or how to do simple with strings.
Normally I use "\n" to add extra information in an inputdialog window.
p.e.
let myvar = "How many characters do you want to add? \n (max. 10)"
let f = inputdialog(myvar)
The break works fine.
but when I add a variable in the text, the break doesn't work anymore:
let myvar = 'How many ' .a:type. ' do you want to add? \n (max. 10)'
let f = inputdialog(myvar)
The variable is a:type is inserted well but the break doesn't work. Why?
Neither of you examples work: you should have been using double strokes instead of single.
In perl you can write
$string =~ tr/[a,e,i,o,u,y]/[A,E,I,O,U,Y]/;
for example.
Is it possible to achieve the same "translation" effects with VB.Net regexes?
Thanks you!
PS: I'm not searching for a way to port this very example, it's more of a curiosity question :)
There is no standard method for this. You can do it by iterating over each character in your input string and using a dictionary to map it to another character (or leave it unchanged if the character is not found in the dictionary). The result can be built using a StringBuilder for performance reasons.
If performance is not an issue then you might be able to use a few replace operations instead:
s = s.Replace("a", "A")
.Replace("e", "E")
...
.Replace("y", "Y");
Here's one way to do this:
public string fakeTR(string theString, char[] org, char[] rep)
{
for(int i=0;i<org.lenght;i++)
{
theString = theString.Replace(org[i], rep[i]);
}
return theString;
}
You would be able to call it with somewhat clunky but shorter:
string v = "Black in South Dakota";
v = fakeTR(v, new char[]{'B','l','a','c','k'}, new char[]{'W','h','i','t','e'});
H/T http://discuss.joelonsoftware.com/default.asp?dotnet.12.306220.6