I have datetime column value below
2015-01-04 20:37:00.000
I tried below
cast(cast(MyDateColumn as date) as datetime)+cast(datepart(hour,MyDateColumn ) as float)/24
as MyDateColumn
and
CAST(CONVERT(CHAR(16),MyDateColumn,113) AS datetime) as MyDateColumn
These are did not work for me
How can i get above datetime as 01-04.2015 20:37 ?
Since MS SQL 2012, you can use FORMAT,
SELECT FORMAT([MyDateColumn], 'dd-MM.yyyy HH:mm')
In MYSQL it will work
SELECT DATE_FORMAT(date, '%Y-%m-%d %H:%i') AS formated_date FROM table;
In MS SQL It will work
SELECT FORMAT(getdate(), 'dd-mm-yyyy HH:mm')
In SQL Server this will work:
DECLARE #now [datetime];
SET #now = GETDATE();
SELECT
CONVERT([varchar](10), #now, 105) + ' ' +
RIGHT('0' + CONVERT([varchar](2), DATEPART(HOUR, #now)), 2) + ':' +
RIGHT('0' + CONVERT([varchar](2), DATEPART(MINUTE, #now)), 2);
In SQL Server this should do the trick:
declare #dt datetime = '2015-01-04 20:37:00.000'
select right('0' + cast(DATEPART(MM, #dt) as varchar), 2) + '-'
+ right('0' +cast(DATEPART(DAY, #dt) as varchar), 2) + '.'
+ cast(DATEPART(YEAR, #dt) as varchar) + ' '
+ right('0' +cast(DATEPART(HOUR, #dt) as varchar), 2) + ':'
+ right('0' +cast(DATEPART(MINUTE, #dt) as varchar), 2)
Simply,
SELECT CAST(CONVERT(varchar, GETDATE(), 100) as datetime)
Here's another way and you get a datetime in return.
SELECT DATEADD(
MILLISECOND,
DATEPART(MILLISECOND, '2016-02-16 13:45:24.573') * -1,
DATEADD(SECOND, DATEPART(SECOND,'2016-02-16 13:45:24.573') * -1,
'2016-02-16 13:45:24.573')
)
this is the way i do it. I needed to get -2 minutes
select CONVERT(datetime, CONVERT(CHAR(18), DATEADD(minute, -2, getdate()) , 113) + '00')
Format(Cast(Convert(varchar(15),Cast(timeval as Time),100) as DateTime),'hh:mm tt') As newtime
This will remove seconds from time as well as add AM,PM with time.
Related
My start and finish columns are in the format Yyyy-mm-dd HH:mm:ss.ms I want the difference between the two in HH:mm:ss.ms format. How do I go about this?
My query looks like this:
select *, convert(time,
Dateadd(s,
Datediff(s, A.Finish, A.Start),
Cast('1900-01-01 00:00:00.000000' as datetime2)
)
) as dif
from (
select *,
dateadd(s,convert(int,left(start,10)),'1970-01-01') as Start,
dateadd(s,convert(int,left(finish,10)),'1970-01-01') as Finish,
from tableB
) A
order by dif asc
I've converted unix time stamps to standard format in inner query. When I run this the start date and start time appear as '2019-12-11 15:45:20.000' and '2019-12-12 15:45:17.000' but my dif appears as '00:00:03',which is wrong.
Any help would be appreciated
I have used two sources to try to help you:
https://www.rodolforodarte.com/2011/05/using-datediff-to-display-hhmmss/
AND
Show datediff as seconds, milliseconds
Here is my result code:
DECLARE #START_DATE DATETIME
DECLARE #END_DATE DATETIME
SET #START_DATE = '2011-01-01 16:00:22.000'
SET #END_DATE = '2011-01-01 22:47:21.022'
SELECT CONVERT(varchar(6), DATEDIFF(MILLISECOND, #START_DATE, #END_DATE)/3600000)
+ ':'
+ RIGHT('0' + CONVERT(varchar(2), (DATEDIFF(MILLISECOND, #START_DATE, #END_DATE) % 3600000) / 60000), 2)
+ ':'
+ RIGHT('0' + CONVERT(varchar(2), ((DATEDIFF(MILLISECOND, #START_DATE, #END_DATE) % 3600000) % 60000) / 1000), 2)
+ ':'
+ RIGHT('000' + CONVERT(varchar(2), (((DATEDIFF(MILLISECOND, #START_DATE, #END_DATE) % 3600000) % 60000) % 1000)), 3) AS 'HH:MM:SS:MS'
And here is a small demo
I am calculating the time difference between 2 times, I want to print the hour min and sec. Can anyone please tell me how to do it.
My query
SELECT
CONVERT(VARCHAR(8), DATEADD(ms, DATEDIFF(ms, CONVERT(VARCHAR(8), GETDATE(), 114), CONVERT(VARCHAR(8), VCTime, 114)), 0), 114) AS TImeDifference
FROM
Test
Output:
TimeDifference
---------------
10:51:37
20:51:37
21:51:37
22:21:37
08:51:37
00:51:37
Expected Output
TimeDifference
---------------
10h:51m:37s
20h:51m:37s
21h:51m:37s
22h:21m:37s
08h:51m:37s
00h:51m:37s
One way is to use sub query and concatenation operator + for 2008 with DATEPART function as below:
SELECT (
CAST(DATEPART(HOUR,(TImeDifference)) AS VARCHAR) + 'h:' +
CAST(DATEPART(MINUTE,(TImeDifference)) AS VARCHAR) + 'm:' +
CAST(DATEPART(SECOND,(TImeDifference)) AS VARCHAR) + 's')
FROM(
SELECT
CONVERT(varchar(8), DATEADD(ms, DATEDIFF(ms, convert(varchar(8),getdate(),114),
convert(varchar(8),VCTime,114)), 0), 114) as TImeDifference
FROM test
) t
Yes I realized concat is introduced in 2012 so we can use + instead
you can follow below way
DECLARE #x int,
#dt1 smalldatetime = '2018-08-17 03:24:16',
#dt2 smalldatetime = getdate()
SET #x = datediff (s, #dt1, #dt2)
SELECT convert(varchar, #x / (60 * 60 * 24)) + ':'
+ convert(varchar, dateadd(s, #x, convert(datetime2, '0001-01-01')), 108)
this will return 1:05:57:00
Try this:
select cast(date_diff / 3600 as varchar(4)) + 'h:' +
cast((date_diff % 3600) / 60 as varchar(4)) + 'm:' +
cast(date_diff % 60 as varchar(4)) + 's'
from (
select datediff(second, getdate(), VCTime) date_diff from my_table
) a
First, you should not be converting to strings to get the difference. I think this should be fine:
SELECT CONVERT(VARCHAR(8),
DATEDIFF(ms, CAST(GETDATE() as TIME), CAST(VCTime as TIME)),
114
) as TImeDifference
FROM Test;
Then you want to add "h", "m", and "s". You can use the STUFF() function. But let me do this using APPLY so the code doesn't look quite so messy:
SELECT ( STUFF(STUFF(TimeDifference_str, 6, 0, 'm'), 3, 0, 'h') + 's' ) as TimeDifference_hms
FROM test t CROSS APPLY
(VALUES (CONVERT(VARCHAR(8),
DATEDIFF(ms, CAST(GETDATE() as TIME), CAST(VCTime as TIME)),
114
)
)
) v(TimeDifference_str)
I have big-int data, and I want to convert it from Big-int to just time, for example I have this value 53006745 for ' 14hrs 43min '
Please help me to write the query in SQL Server, so that will convert big-int into minutes.
If You're looking Pure Time you could try below SQL Query which will give Minutes from Your Integer Value:
DECLARE #value INT = 53006745
SELECT DATEPART(MINUTE, DATEADD(s, CONVERT(BIGINT, #value) / 1000, CONVERT(DATETIME, '1-1-2017 00:00:00'))) [Minutes];
Result :
Minutes
43
You can use this code for yourself in SQL :
SELECT DATEADD(s, CONVERT(BIGINT, 53006745 ) / 1000,
CONVERT(DATETIME,
'1-1-1970 00:00:00'))
This code return 1970-01-01 14:43:26.000 as you like
DECLARE #Value INT = 53006745
SELECT
CONVERT(VARCHAR, #Value/3600000) + ':' -- Hours
+ RIGHT('0' + CONVERT(VARCHAR, #Value%3600000/60000), 2) + ':' -- Minutes
+ RIGHT('0' + CONVERT(VARCHAR, #Value%3600000%60000/1000), 2) + '.' -- Seconds
+ RIGHT('00' + CONVERT(VARCHAR, #Value%1000), 3) -- Milliseconds
I produce a CSV file but cannot figure out the proper date format.
I am aware of the MSDN site codes for datetime conversions:
http://msdn.microsoft.com/en-us/library/ms187928.aspx
It seems there is no code to convert my datetime into this format:
MM/DD/YYYY HH:MMAM
e.g.:
12/28/2014 4:33AM
How do you achieve such format?
Platform:
Microsoft SQL server 2008
SELECT CONVERT(VARCHAR(10), GETDATE(), 101) +
RIGHT(CONVERT(VARCHAR, GETDATE(), 100), 7)
This is what you can use and is probably the most straightforward:
SELECT
RIGHT('0' + cast(month(dateColumn) AS NVARCHAR(2)), 2) + '/' -- generate the day
+ RIGHT('0' + cast(day(dateColumn) AS NVARCHAR(2)), 2) + '/' -- generate the month
+ cast(year(dateColumn) AS NVARCHAR(4)) + ' ' -- generate the year
+ convert(VARCHAR, cast(dateColumn AS TIME)), 100) -- generate the time
FROM TABLE
SELECT CONVERT(VARCHAR, GetDate(), 101) + ' ' +
CONVERT(VARCHAR, DATEPART(hh, GetDate())) + ':' +
RIGHT('0' + CONVERT(VARCHAR, DATEPART(mi, GetDate())), 2) AS TIME
EDIT: This gets the AM/PM also
SELECT CONVERT(CHAR(11),GETDATE(),101)
+ CONVERT(CHAR( 5),GETDATE(),114)
+ RIGHT(CONVERT(CHAR( 5),GETDATE(),109), 2)
SELECT CONVERT(VARCHAR(10),GETDATE(),3) as 'dd/MM/yy'
SELECT CONVERT(VARCHAR(10),GETDATE(),103) as 'dd/MM/yyyy'
SELECT CONVERT(VARCHAR(10),GETDATE(),4) as 'dd.MM.yy'
SELECT CONVERT(VARCHAR(10),GETDATE(),104) as 'dd.MM.yyyy'
SELECT CONVERT(VARCHAR(10),GETDATE(),5) as 'dd-MM-yy'
SELECT CONVERT(VARCHAR(10),GETDATE(),105) as 'dd-MM-yyyy'
SELECT CONVERT(VARCHAR(10),GETDATE(),6) as 'ddMonthyy'
SELECT CONVERT(VARCHAR(10),GETDATE(),106) as 'ddMonthyyyy'
SELECT CONVERT(VARCHAR(10),GETDATE(),7) as 'Monthdd.yy'
SELECT CONVERT(VARCHAR(10),GETDATE(),107) as 'Monthdd.yyyy'
SELECT CONVERT(VARCHAR(10),GETDATE(),8) as 'hh.mm.ss'
SELECT CONVERT(VARCHAR(10),GETDATE(),108) as 'hh.mm.ss'
SELECT CONVERT(VARCHAR(100),GETDATE(),9) as 'Monthddyy hh.mm.ss.mss'
SELECT CONVERT(VARCHAR(100),GETDATE(),109) as 'Monthddyyyy hh.mm.ss.mss'
SELECT CONVERT(VARCHAR(100),GETDATE(),10) as 'mm-dd-yy'
SELECT CONVERT(VARCHAR(100),GETDATE(),110) as 'mm-dd-yyyy'
SELECT CONVERT(VARCHAR(100),GETDATE(),11) as 'yy/MM/dd'
SELECT CONVERT(VARCHAR(100),GETDATE(),111) as 'yyyy/MM/dd'
SELECT CONVERT(VARCHAR(100),GETDATE(),12) as 'yyMMdd'
SELECT CONVERT(VARCHAR(100),GETDATE(),112) as 'yyyyMMdd'
SELECT CONVERT(VARCHAR(100),GETDATE(),13) as 'ddMonthyy hh.mm.ss.mss'
SELECT CONVERT(VARCHAR(100),GETDATE(),113) as 'ddMonthyyyy hh.mm.ss.mss'
I want to concatenate two TIME columns and show as one column.
Example:
FromTime: 9:00
ToTime: 12:00
Result should be:
9:00-12:00
Generic SQL:
-- hh:mm:ss
SELECT 'result:' + CONVERT(CHAR(6), FromTime, 8) + '-' + CONVERT(CHAR(6), ToTime)
FROM yourTable
MySQL:
-- hh:mm
SELECT 'result:' + DATE_FORMAT(FromTime, '%H:%i') + '-' + DATE_FORMAT(ToTime, '%H:%i')
FROM yourTable
SQL Server:
-- hh:mm
SELECT 'result:' + convert(char(2), DATEPART(hh, FromTime)) + ':' +
CONVERT(CHAR(2), DATEPART(mm, FromTime)) + '-' +
CONVERT(CHAR(2), DATEPART(hh, ToTime)) + ':' +
CONVERT(CHAR(2), DATEPART(mm, ToTime))
FROM yourTable
declare #FromTime time
declare #ToTime time
set #FromTime='9:00'
set #ToTime='12:00'
select cast(#FromTime as varchar(10))+ '-' + cast(#ToTime as varchar(10)) as result
sql demo
You can use convert
select convert(VARCHAR(5),getdate(),108) + ' - ' + convert(VARCHAR(5),getdate()-1,108)