I have a table which has only 1 large column named Details; each record looks similar to this:
Record#1: ...ID: <klsdhf89435> Date: 1 Jun 2011 12:28:14 From: "Yahoo"...
Record#2: ...Subject: test Date: Fri, 24 May 2010 13:18:43 -0500 ID: <7532432423>...
Record#3: ...ID: <234321fd> Date: 14 Jun 2010 12:28:14 From: "Gmail"...
Record#4: ...ID: <12434> Date: 1 Jun 2011 12:28:14 From: "Yahoo"...
I would like the subtract the Date only. So, for those 4 records, I would like to extract:
1 Jun 2011 12:28:14
Fri, 24 May 2010 13:18:43 -0500
14 Jun 2010 12:28:14
1 Jun 2011 12:28:14
Please note that the double space from before "From" or before "ID" is a new line character which is Char(10) in SQL Server.
Thanks in advance
SELECT SUBSTR(Details, LOCATE('Date: ', Details), LOCATE(' From:', Details) - LOCATE('Date: ', Details))
FROM TABLENAME
Consider parsing the date into a new date column when the row is inserted.
http://dev.mysql.com/doc/refman/5.0/en/string-functions.html
Related
I have an issue as I am trying to select Date values stored in SQL server as String value with this format "Thu, 08 Jul 2021 06:08:20 -0700" and i need to select all table with newest date in first but I do not know how to convert this String into Date and sort it. Thanks in advance.
Table
|Thu, 08 Jul 2021 06:08:20 -0700|
|Fri, 09 Jul 2021 01:08:20 -0700|
|Sun, 11 Jul 2021 07:08:20 -0700|
output (Newest Date first)
|Sun, 11 Jul 2021 07:08:20 -0700|
|Fri, 09 Jul 2021 01:08:20 -0700|
|Thu, 08 Jul 2021 06:08:20 -0700|
Your date is just missing a valid timezone offset value so needs a ":" inserted so it's -07:00, you can do this with stuff and use substring to ignore the irrelevant day name. You don't state a specific database platform, for SQL Server you can then cast to a datetimeoffset, other databases have similar but slightly varied syntax. This assumes the strings are all formatted consistently of course.
declare #d varchar(30)='Thu, 08 Jul 2021 06:08:20 -0700'
select Cast(Stuff(Substring(#d,6,26),25,0,':') as datetimeoffset(0))
Result
2021-07-08 06:08:20 -07:00
I have field that contains strings and has dates within.
e.g
Rate (20 Jan 2020 - 19 Feb 2020)
or Rate (6 Dec 2019 - 5 Jan 2020)
I need a Start Date and End Date out of the above strings in SQL.
I can get Start Date but End Date (after the -) is a problem
Its quite crude but it will get you answers:
select left('20 Jan 2020 - 19 Feb 2020',CHARINDEX('-','20 Jan 2020 - 19 Feb 2020')-1)
,right('20 Jan 2020 - 19 Feb 2020',len('20 Jan 2020 - 19 Feb 2020') -CHARINDEX('-','20 Jan 2020 - 19 Feb 2020')-1)
CHARINDEX() will give you the position of the character you desire, in this case the dash. From there you can use LEFT(), RIGHT(), and LEN() to get the pieces out of the string that you need.
This works with SQLServer
sorry if I'm shooting newbie questions here.
I want to create a weekly report, but for this weekly report, I want full data from Monday to Sunday
Condition:
Last 4 weeks only
Showing full week (Monday - Sunday)
Hide the result if it's not full week
If i use getdate -14, if I access the data on Wednesday, they will start counting last week from Wednesday 2 weeks ago instead of last Monday. Meanwhile, I want the report to show full week only.
Can anyone share how to do that in SQL?
Here I provide sample data:
Column name = DATE -- Column name: TOTAL_PERSON
- Fri, 1 Jun 2018 -- 10
- Sat, 2 Jun 2018 -- 4
- Sun, 3 Jun 2018 -- 12
- Mon, 4 Jun 2018 -- 15
- Tue, 5 Jun 2018 -- 10
- Wed, 6 Jun 2018 -- 3
- Thu, 7 Jun 2018 -- 1
- Fri, 8 Jun 2018 -- 13
- Sat, 9 Jun 2018 -- 9
- Sun, 10 Jun 2018 -- 23
- Mon, 11 Jun 2018 -- 5
- Tue, 12 Jun 2018 -- 3
- Wed, 13 Jun 2018 -- 1
- Thu, 14 Jun 2018 -- (TODAY)
In this case, if I am accessing on Thu 6 Jun 2018 I want to get TOTAL PERSON data from Mon, 4 Jun 2018 to Sun, 10 Jun 2018 only and not showing data from the rest since the week is not full.
Can anyone help me how to do that?
Thanks a lot!
I think you want:
where datediff(week, date, getdate()) <= 2
This counts the number of week boundaries between two dates, so it returns an entire week.
For MySQL, you can use such a select:
SELECT * FROM `myDB` WHERE `Date`
BETWEEN DATE_SUB(NOW()-INTERVAL DATE_FORMAT(CURRENT_DATE, '%w') DAY, INTERVAL 28 DAY)
AND NOW()- INTERVAL DATE_FORMAT(CURRENT_DATE, '%w') DAY
This uses the capability to transform the current day of this week into a number and substract this to get the last Sunday. from there, we select an intervall of 28 days.
(Only testet with 14 days and a very limited test-dataset, but should work)
i have a table which looks like this :
coumn 1 = timestamp : string , column 2 = numOfentites : int
please note i am using hiveql
Fri, 10 Aug 2001 274
Fri, 10 Dec 1999 39
Fri, 10 Mar 2000 107
Fri, 10 May 2002 26
Fri, 10 Nov 2000 351
Fri, 10 Sep 1999 22
Fri, 11 Aug 2000 189
Fri, 11 Dec 1998 1
Fri, 11 Feb 2000 84
Fri, 11 Jan 2002 580
Fri, 11 Jun 1999 12
Fri, 11 May 2001 571
Fri, 12 Apr 2002 41
Now, I retrieved the frequency per year from this table and found out some year XXXX had the most number of entities.
My aim now is to go one level deep and extract the frequency per month for the year XXXX.
I tired using the group by clause on the substring indicating month but it doesn’t work.
can you guys please give me a direction on how to proceed..
Just need a hint not the answer :P trying to learn hiveql here
EDIT
here is the query that i used to extract the frequency of entities on yearly basis.
note that timestamp is the first column of the input.
select dates , count(dates) as numEmails
from (select split(timestamp," ")[3] as dates , count(timestamp)
from dataset
group by timestamp
) mailfreq
group by dates
order by numEmails desc;
I know that hivesql has strange limitations, but won't this work?
select split(timestamp," ")[3] as yr, split(timestamp," ")[2] as mon, count(timestamp)
from dataset
group by split(timestamp," ")[3], split(timestamp," ")[2];
I have tried in n-number ways to solve this solution but unfortunately I got stuck in all the ways..
source table
id year jan feb mar apr may jun jul aug sep oct nov dec
1234 2014 05 06 12 15 16 17 18 19 20 21 22 23
1234 2013 05 06 12 15 16 17 18 19 20 21 22 23
Task: Assume that we are currently at March 2014, and we need 12 months back date ...(i.e., from Mar 2013 to Feb 2014, and the remaining values needs to be zero except year and id.)
Solution:
id year jan feb mar apr may jun jul aug sep oct nov dec
1234 2014 05 06 0 0 0 0 0 0 0 0 0 0
1234 2013 0 0 12 15 16 17 18 19 20 21 22 23
This needs a code solution for SQL Server 2008. I would be very happy if any body can solve this.
Note:
I got stuck to pull the column names dynamically.
You can try this:
select id, year, case when DATEDiff(month, getdate(), convert(datetime, year + '-01-01'))) < 12 then jan else 0,
DATEDiff(month, getdate(), convert(datetime, year + '-02-01'))) < 12 then fab else 0 ....