Split column value to match yes or no - sql

Question

I have two tables named Retail and Activity and the data is as shown below:
Retail Table
Activity Table
My main concern is about Ok and Fault column of the table Retail, as you can see it contains comma separated value of ActivityId.
What i want is, if the Ok column has ActivityId the corresponding column will have Yes, if the Fault column has ActivityId then it should be marked as No
Note I have only four columns that is fixed, it means i have to check that either four of the columns has its value in Ok or Fault, if yes then only i have to print yes or no, otherwise null.
Desired result should be like :
If the value is in Ok then yes other wise No.

Answer 1

I guessing you want to store 'yes' or 'No' in some column. Below is the query to update that column :
UPDATE RetailTable
SET <Result_Column>=
CASE
WHEN Ok IS NOT NULL THEN 'Yes'
WHEN Fault IS NOT NULL THEN 'No'
END

Answer 2

You can use below code as staring point:
DECLARE #Retail TABLE
(
PhoneAuditID INT,
HandsetQuoteID INT,
Ok VARCHAR(50)
)
INSERT INTO #Retail VALUES (1, 1009228, '4,22,5')
INSERT INTO #Retail VALUES (2, 1009229, '1')
DECLARE #Activity TABLE
(
ID INT,
Activity VARCHAR(50)
)
INSERT INTO #Activity VALUES (1, 'BatteryOK?'), (4, 'PhonePowersUp?'), (22,'SomeOtherQuestion?'), (5,'LCD works OK?')
SELECT R.[PhoneAuditID], R.[HandsetQuoteID], A.[Activity], [Ok] = CASE WHEN A.[ID] IS NOT NULL THEN 'Yes' END
FROM #Retail R
CROSS APPLY dbo.Split(R.Ok, ',') S
LEFT JOIN #Activity A ON S.[items] = A.[ID]
I have used Split function provided here:
separate comma separated values and store in table in sql server

Answer 3

Try following query. i have used pivot to show row as columns. I have also used split function to split id values which you can find easily on net:
CREATE TABLE PhoneAudit
(
PhoneAuditRetailID INT,
HandsetQuoteID INT,
Ok VARCHAR(50),
Fault VARCHAR(50)
)
INSERT INTO PhoneAudit VALUES (1,10090,'1,2','3')
CREATE TABLE ActivityT
(
ID INT,
Activity VARCHAR(100)
)
INSERT INTO ActivityT VALUES (1,'Battery')
INSERT INTO ActivityT VALUES (2,'HasCharger')
INSERT INTO ActivityT VALUES (3,'HasMemoryCard')
INSERT INTO ActivityT VALUES (4,'Test')
DECLARE #SQL AS NVARCHAR(MAX)
DECLARE #ColumnName AS NVARCHAR(MAX)
SELECT #ColumnName= ISNULL(#ColumnName + ',','') + QUOTENAME(Activity) FROM (SELECT DISTINCT Activity FROM ActivityT) AS Activities
SET #SQL = 'SELECT PhoneAuditRetailID, HandsetQuoteID,
' + #ColumnName + '
FROM
(SELECT
t1.PhoneAuditRetailID,
t1.HandsetQuoteID,
TEMPOK.*
FROM
PhoneAudit t1
CROSS APPLY
(
SELECT
Activity,
(CASE WHEN ID IN (SELECT * FROM dbo.SplitIDs(t1.Ok,'',''))
THEN ''YES''
ELSE ''NO''
END) AS VALUE
FROM
ActivityT t2
) AS TEMPOK) AS t3
PIVOT
(
MIN(VALUE)
FOR Activity IN ('+ #ColumnName + ')
) AS PivotTable;'
EXEC sp_executesql #SQL
DROP TABLE PhoneAudit
DROP TABLE ActivityT

Answer 4

There are several ways to do this. If you are looking for a purely declarative approach, you could use a recursive CTE. The following example of this is presented as a generic solution with test data which should be adaptable to your needs:
Declare #Delimiter As Varchar(2)
Set #Delimiter = ','
Declare #Strings As Table
(
String Varchar(50)
)
Insert Into #Strings
Values
('12,345,6,78,9'),
(Null),
(''),
('123')
;With String_Columns As
(
Select
String,
Case
When String Is Null Then ''
When CharIndex(#Delimiter,String,0) = 0 Then ''
When Len(String) = 0 Then ''
Else Left(String,CharIndex(#Delimiter,String,0)-1)
End As String_Column,
Case
When String Is Null Then ''
When CharIndex(#Delimiter,String,0) = 0 Then ''
When Len(String) = 0 Then ''
When Len(Left(String,CharIndex(#Delimiter,String,0)-1)) = 0 Then ''
Else Right(String,Len(String)-Len(Left(String,CharIndex(#Delimiter,String,0)-1))-1)
End As Remainder,
1 As String_Column_Number
From
#Strings
Union All
Select
String,
Case
When CharIndex(#Delimiter,Remainder,0) = 0 Then Remainder
Else Left(Remainder,CharIndex(#Delimiter,Remainder,0)-1)
End As Remainder,
Case
When CharIndex(#Delimiter,Remainder,0) = 0 Then ''
When Len(Left(Remainder,CharIndex(#Delimiter,Remainder,0)-1)) = 0 Then ''
Else Right(Remainder,Len(Remainder)-Len(Left(Remainder,CharIndex(#Delimiter,Remainder,0)-1))-1)
End As Remainder,
String_Column_Number + 1
From
String_Columns
Where
(Remainder Is Not Null And Len(Remainder) > 1)
)
Select
String,
String_Column,
String_Column_Number
From
String_Columns