.Find Loop Word 2013 - vba

I have a document that has plain text and I want to do some preformatting before I move it to Access. Currently, I'm in Word trying to separate the formatting into titles and text. The document has hundreds of titles and after each title small explanation text (it's an error book with explanations for one machine).
I am trying to put a unique string at the end of a lane that starts with "start-of-title" unique string.
I want to make a macro that finds that string, then goes to the end of the lane and writes " end-of-title" and do that till there are results found.
What I've done so far, and works once, is the following:
Sub test3()
Selection.Find.ClearFormatting
With Selection.Find
.Text = "startoftitle "
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindAsk
.Format = False
.MatchCase = True
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute
Selection.EndKey Unit:=wdLine
Selection.TypeText Text:=" endoftitle"
End Sub
I've tried doing loops, but sadly I wasn't able to do the right syntax. The problem is that I can't make it loop till there are no results found...

This should do it
Sub test3()
Const STARTTOKEN = "startoftitle "
Const ENDTOKEN = " endoftitle"
For i = 1 To ThisDocument.Paragraphs.Count
If ThisDocument.Paragraphs(i).Range.Style = "Title" _
And Left(ThisDocument.Paragraphs(i).Range.Text, Len(STARTTOKEN)) <> STARTTOKEN Then
ThisDocument.Paragraphs(i).Range.Text = STARTTOKEN & ThisDocument.Paragraphs(i).Range.Text & ENDTOKEN
End If
Next i
End Sub

I managed to solve it before checking what you've written. Thank you for your help!
Here is the code for anyone with the same problem:
Sub test3()
'
' test3 Macro
'
'
Selection.Find.ClearFormatting
With Selection.Find
.Text = " startoftitle "
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = True
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Do While Selection.Find.Execute = True
Selection.EndKey Unit:=wdLine
Selection.TypeText Text:=" endoftitle"
Loop
End Sub

Related

Use VBA regular expression in Word Find/Replace macro?

I often use a legacy text editor (Vim) to take meeting notes because I can keep up with the talking. However, most people (including myself) prefer the final notes to be in Word, with bullets and sub-bullets. Here is an example of a text file that I wanted to convert to Word bullets:
Meeting notes
-------------
* The quick brown fox
* The quick brown fox
- Jumped over the lazy dogs
- Jumped over the lazy dogs
* The quick brown fox
I recorded a macro to convert text bullets to Word bullets. Any paragraph starting with text bullet "*" gets converted to "List Bullet 2", then I globally replace "*" with "" (i.e., deleted). Any paragraph starting with the more indented text bullet " -" gets converted to "List Bullet 4", then I globally delete " -". The "BulletsTxt2wrd" macro is shown below.
The problem is, I use Word's Find/Replace function, which can't really restrict the search of the above strings to the beginning of a paragraph. If there is a "*" in the middle of the paragraph (perhaps "25 * 3.1415"), the same paragraph formatting and deletion occurs.
Regular expressions can confine searches to the start of a paragraph. I used regular expressions in a unix environment, and after years of reading that it can be done in VBA, I used it in simple Excel function to convert time durations specified in days/minutes to hours. For example (see "DurtnStr2hrs" function below:
"20 hours" becomes 20
"1 hour" becomes 1
"1 day" becomes 24
"3 days" becomes 3*24
"1 minute" becomes 1/60
"70 minutes" becomes 70/60
I use this function within a spreadsheet cell, with the argument being another cell containing the string to be converted.
Is there a way to use the regular expression package and objects in the "BulletsTxt2wrd" Word macro? It seems to function like a black box, and the VBA code doesn't really expose the object property containing the string that I want to operate on.
P.S. This post doesn't deal with the Find/Replace method that I recorded, which goes through the entire document to locate matches.
This post refers to VBScript, but I really would like to avoid having to figure out another language to accomplish my simple task.
This post also doesn't use the Find/Replace recorded in my macro.
Sub BulletsTxt2wrd()
'
' BulletsTxt2wrd Macro
'
'
Selection.HomeKey Unit:=wdStory
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Style = ActiveDocument.Styles("List Bullet 2")
With Selection.Find
.Text = " * "
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = " * "
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Style = ActiveDocument.Styles("List Bullet 4")
With Selection.Find
.Text = " - "
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = " - "
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
Function DurtnStr2hrs(str) As Double
' Use for DurtnHrs column
Dim NewStr As String
Dim regex1 As Object
Set regex1 = New RegExp
NewStr = str
regex1.Pattern = " hours?"
NewStr = regex1.Replace(NewStr, "")
regex1.Pattern = " minutes?"
NewStr = regex1.Replace(NewStr, "/60")
regex1.Pattern = " days?"
NewStr = regex1.Replace(NewStr, "*24")
DurtnStr2hrs = Evaluate(NewStr)
End Function
«The problem is, I use Word's Find/Replace function, which can't really restrict the search of the above strings to the beginning of a paragraph» Au contraire, you could use:
Sub Demo1()
Application.ScreenUpdating = False
With ActiveDocument.Range
With .Find
.ClearFormatting
.Replacement.ClearFormatting
.Text = "^13[ *-]{1,}"
.Replacement.Text = ""
.Format = False
.Forward = True
.Wrap = wdFindStop
.MatchWildcards = True
End With
Do While .Find.Execute
.Start = .Start + 1
Select Case Trim(.Text)
Case "*": .Paragraphs.Last.Style = wdStyleListBullet2
Case "-": .Paragraphs.Last.Style = wdStyleListBullet4
End Select
.Text = vbNullString
.Collapse wdCollapseEnd
Loop
End With
Application.ScreenUpdating = True
End Sub
As for the DurtnStr2hrs conversion, I note there remains a disconnect between your text description of ""20 hours" becomes 20*60" and your Regex of "NewStr = regex1.Replace(NewStr, "/60")". That said, try:
Sub Demo2()
Application.ScreenUpdating = False
With ActiveDocument.Range
With .Find
.ClearFormatting
.Replacement.ClearFormatting
.Text = "<[0-9]# [dh][ao][yu]*>"
.Replacement.Text = ""
.Format = False
.Forward = True
.Wrap = wdFindStop
.MatchWildcards = True
End With
Do While .Find.Execute
.Start = .Start + 1
Select Case Split(.Text, " ")(1)
Case "hour": .Text = Split(.Text, " ")(0)
Case "hours": .Text = Split(.Text, " ")(0) & "/60"
Case "day": .Text = "24"
Case "days": .Text = Split(.Text, " ")(0) & "*24"
End Select
.Collapse wdCollapseEnd
Loop
End With
Application.ScreenUpdating = True
End Sub
The following seems to do the job:
Sub BulletTxt2doc()
doL1bullet:
Selection.HomeKey Unit:=wdStory
Selection.Find.ClearFormatting
With Selection.Find
.Text = "^p * "
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
Selection.Find.Execute
If .Found = True Then
Selection.EndKey Unit:=wdLine
Selection.Style = ActiveDocument.Styles("List Bullet 2")
Selection.MoveUp Unit:=wdParagraph, Count:=1
Selection.MoveRight Unit:=wdWord, Count:=2, Extend:=wdExtend
Selection.Delete Unit:=wdCharacter, Count:=1
GoTo doL1bullet
End If
End With
doL2bullet:
Selection.HomeKey Unit:=wdStory
Selection.Find.ClearFormatting
With Selection.Find
.Text = "^p - "
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
Selection.Find.Execute
If .Found = True Then
Selection.EndKey Unit:=wdLine
Selection.Style = ActiveDocument.Styles("List Bullet 4")
Selection.MoveUp Unit:=wdParagraph, Count:=1
Selection.MoveRight Unit:=wdWord, Count:=2, Extend:=wdExtend
Selection.Delete Unit:=wdCharacter, Count:=1
GoTo doL2bullet
End If
End With
End Sub

Word VBA macro to bold part of all instances of a specific text string

I am using the following code to bold parts of a text string, in this case where the word 'Fish' is in brackets after the word 'Oil':
Sub ReplaceAndFormat16()
Dim sConst1 As String, sReplaceMent As String
Dim rRange As Range, rFormat As Range
sConst1 = "Fish"
sReplaceMent = "Oil (" & sConst1 & ")"
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "Oil (Fish)"
.Replacement.Text = sReplaceMent
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = True
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
.Execute Replace:=wdReplaceOne
If .Found Then
Set rRange = Selection.Range
Set rFormat = ActiveDocument.Range(rRange.Start + 5, rRange.Start + 5 + VBA.Len(sConst1))
rFormat.Font.Bold = True
End If
End With
End Sub
This code works perfectly, but only bolds the first instance, and my documents may have up to four instances of this phrase that need to be formatted bold.
How do I amend the code so it carries on and bolds all instances in the document? I am very new to VBA, so apologies if this seems like a stupid question.
Change the line
.Execute Replace:=wdReplaceOne
to
.execute Replace:=wdReplaceAll
Edit
OK the above was a stupid response. The code below does the right thing
Sub ReplaceAndFormat16()
Const myFindStr As String = "Oil (Fish)"
Dim myFindRange As Word.Range
Set myFindRange = ActiveDocument.StoryRanges(wdMainTextStory)
Do
With myFindRange.Find
.ClearFormatting
.Text = myFindStr
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
.Execute
If .Found Then
With myFindRange
.MoveStartUntil cset:="fF"
.MoveEndUntil cset:="hH", Count:=wdBackward
.Font.Bold = True
.Collapse Direction:=wdCollapseEnd
End With
Else
Exit Sub
End If
End With
Loop
End Sub

vba word: If Then find and replace

in this code, I want to do the following:
If the word is finished with a letter M Replace with letter N.
If the word ends with a letter N, Replace with letter M.
I do not know well using the IF - Then statement.
Any help would be greatly appreciated.
Sub find_end()
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "[nm]>"
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.MatchWildcards = True
Selection.Find.Execute
With Selection
If Selection.Find.Found = n Then
Selection.TypeText Text:=m
ElseIf Selection.Find.Found = m Then
Selection.TypeText Text:=n
End If
End Sub
I modified the code found at: Repeating Microsoft Word VBA until no search results found
and it will spin thru a document and replace the last letter (if it's an 'm' or 'n') of each word. NOTE there is a 'loop check in that code that you may want to remove if it's possible you may find over 2000 m or n's.
Option Explicit
' The following code adapted from: https://stackoverflow.com/questions/13465709/repeating-microsoft-word-vba-until-no-search-results-found
Sub SearchFN()
Dim iCount As Integer
Dim lStart As Long
'Always start at the top of the document
Selection.HomeKey Unit:=wdStory
'find a footnote to kick it off
With Selection.Find
.ClearFormatting
.Text = "[nm]>"
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchKashida = False
.MatchDiacritics = False
.MatchAlefHamza = False
.MatchControl = False
.MatchByte = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchFuzzy = False
.MatchWildcards = True
.Execute
End With
'Jump back to the start of the document.
Selection.HomeKey Unit:=wdStory
'If we find one then we can set off a loop to keep checking
'I always put a counter in to avoid endless loops for one reason or another
Do While Selection.Find.Found = True And iCount < 2000
iCount = iCount + 1
Selection.Find.Execute
'On the last loop you'll not find a result so check here
If Selection.Find.Found Then
' Exit if we start back at the beginning
If Selection.Start < lStart Then
Exit Do
End If
'Reset the find parameters
With Selection.Find
.ClearFormatting
.Text = "[nm]>"
If Selection.Text = "m" Then
Debug.Print "found 'm' at position: " & Selection.Start
Selection.Text = "n"
ElseIf Selection.Text = "n" Then
Debug.Print "found 'n' at position: " & Selection.Start
Selection.Text = "m"
End If
lStart = Selection.Start
' .Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchKashida = False
.MatchDiacritics = False
.MatchAlefHamza = False
.MatchControl = False
.MatchByte = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchFuzzy = False
.MatchWildcards = True
End With
End If
Loop
End Sub

Word Macro that would find and create hyperlink of similar words

This is the code of my macro (Macro1):
Sub Macro1()
'
' Macro1 Macro
'
Selection.Find.ClearFormatting
With Selection.Find
.Text = "REQ"
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = True
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute
Selection.MoveRight Unit:=wdCharacter, Count:=8, Extend:=wdExtend
Selection.Copy
ActiveDocument.Hyperlinks.Add Anchor:=Selection.Range, Address:= _
"http://www.neki.com/REQ12345678", SubAddress:="", ScreenTip:="", _
TextToDisplay:="REQ12345678"
End Sub
The code works fine finding the REQxxxxxxxx texts, but then pastes wrong TextToDisplay and wrong ending of an address. Instead of REQ12345678 in both places should be pastet the same text I copied before at: Selection.Copy.
I also have no idea, how to create a loop or something like that, so that Macro1 would be running until it reaches the end of a document.
Help me, please!
Hey, I solved the 1st problem with creating hyperlinks. Now I have to loop that "hyperlink" macro. I decided to create another macro, that would loop the first one. Here is my code:
Sub Macro2()
'
' Macro2 Macro
'
Do Until ActiveDocument.Bookmarks.Exists("Konec")
Application.Run MacroName:="Macro1"
Loop
End Sub
Macro1 works perfectly fine, but I can't figure it out how to loop it until the end of document - Until the ending bookmark...
I used the following code to link selected text to similar text that appears later in the document.
Sub Macro1()
'
' Macro1 Macro
'
'
With Selection.Find
.Text = Selection
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = True
.MatchWholeWord = True
.MatchWildcards = True
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute
With ActiveDocument.Bookmarks
.Add Range:=Selection.Range, Name:=Selection
.DefaultSorting = wdSortByName
.ShowHidden = False
End With
With Selection.Find
.Text = Selection
.Replacement.Text = ""
.Forward = False
.Wrap = wdFindContinue
.Format = False
.MatchCase = True
.MatchWholeWord = True
.MatchWildcards = True
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute
ActiveDocument.Hyperlinks.Add Anchor:=Selection.Range, Address:="", _
SubAddress:=Selection, ScreenTip:="", TextToDisplay:=Selection
End Sub

Word-macro to replace all instances of a particular string in current line

I'm trying to create a macro in word to find particular cells in a table and replace certain strings there. For example:
(word1 or word2 or word3).ab,ti.
Should be replaced by
word1[TIAB] or word2[TIAB] or word3[TIAB]
So, what I've done so far is a simple replaceAll to delete the initial brackets and replace the suffix ").ab,ti." by "[TIAB]. But that doesn't append the endings to word1 and word2, of course.
Sub Makro6()
'
' Makro6 Makro
'
'
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = ".ab,ti."
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
I guess what I need is to embed a loop in the replaceAll sub, which runs from the first position to the end of the current row and replaces the string " or " by "[TIAB] or ". However, I'm completely new to VBA so I somehow can't figure out how to do this. Any suggestions?
Thanks for your help!
Leni
This code performs the actions you want:
Sub Makro6()
Dim maxCount, curCount As Integer
maxCount = 3
curCount = 0
Do
curCount = curCount + 1
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = Chr(40) & "word" & curCount & Chr(41) & ".ab,ti."
.Replacement.Text = "word" & curCount & "[TIAB]"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = False
.Execute Replace:=wdReplaceAll
End With
Loop While (curCount < maxCount)
End Sub
Note that I had to rely on ASCII codes (Chr(40) & Chr(41)) to account for the parenthesis because surprisingly (at least, for me), the macro wasn't able to find the target string. I did some tests and the problem only happens with parenthesis followed by another character (?!).