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Is it possible to create a totalprice column in a table which gets its answer from multiplying 2 values from 2 different tables?
e.g
orderquantity
order_id | product_code | quantity
ordertotalprice
order_id | customer_id | totalprice
products
product_Code | product_name | product_desc | productcost
I want the totalprice column to be = productcost*quantity
To query the totals per order:
SELECT orderquantity.order_id,
SUM(products.productcost * orderquantity.quantity) AS total
FROM orderquantity
INNER JOIN products ON products.product_code = orderquantity.product_code
GROUP BY orderquantity.order_id
Wrap this query in an UPDATE statement to update column totalprice in table ordertotalprice:
UPDATE ordertotalprice
SET totalprice = grouped.total
FROM (
SELECT orderquantity.order_id,
SUM(products.productcost * orderquantity.quantity) AS total
FROM orderquantity
INNER JOIN products ON products.product_code = orderquantity.product_code
GROUP BY orderquantity.order_id
) AS grouped
WHERE ordertotalprice.order_id = grouped.order_id
I am assuming here table ordertotalprice already contains the necessary records. If that is not the case, then you will need an INSERT statement instead of an UPDATE. But then I wonder where to get the customer_id from.
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I'm trying to write a SQL query to take the below data and transform it into the expected result table.
INV
ITEM
Amount
INV123
null
12.00
INV123
null
96.00
INV123
abc
null
INV123
xyz
null
Expected result:
INV
ITEM
Amount
INV123
abc
12.00
INV123
xyz
96.00
Assuming mapping the "first" non-null item to the "first" non-null amount is actually arbitrary, here's one way:
WITH items AS
(
SELECT inv, item, r = ROW_NUMBER() OVER (PARTITION BY inv ORDER BY ##SPID)
FROM dbo.MyTable WHERE item IS NOT NULL
), amounts AS
(
SELECT inv, amount, r = ROW_NUMBER() OVER (PARTITION BY inv ORDER BY ##SPID)
FROM dbo.MyTable WHERE amount IS NOT NULL
)
SELECT inv = COALESCE(items.inv, amounts.inv),
items.item, amounts.amount
FROM items FULL OUTER JOIN amounts
ON items.inv = amounts.inv
AND items.r = amounts.r
ORDER BY COALESCE(items.r, amounts.r);
Working example in this fiddle.
The FULL OUTER JOIN is used because you probably won't always have the same number of non-null items and non-null amounts for a given inv. However you might also want to handle the case where both columns have a non-null value - do those columns stick together on the same output row, or no?
If the ordering needs to be more deterministic, you need to explain what other data exists in the table to allow you to rank those columns. Or if you want alphabetical for item and numerical for amount, just change ORDER BY ##SPID to ORDER BY item/ORDER BY amount respectively.
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I have data of the following form:
ID
Category
Amount
1
A
100
1
B
200
1
B
150
1
C
500
2
B
20
3
A
100
1
B
100
I wish to GROUP BY the column ID, find out the DISTINCT types of Category present for each ID group and create a new column where I can create the following classification labels for each grouped ID based on the unique or distinct categories present and also calculate the corresponding sum of amount for each grouped ID. So the output should be the follows:
ID
Classification
Sum of Amount
1
ALL
950
1
B only
20
1
A and B only
200
I tried the following SQL code but it doesn't work, most likely because DISTINCT() command within a CASE WHEN statement cannot consider multiple values.
My query:
SELECT
ID,
(CASE WHEN DISTINCT(CATEGORY) IN ("A") then "A Only" WHEN WHEN DISTINCT(CATEGORY) IN ("B") THEN "B only"..........)
SUM(AMOUNT)
FROM Table
GROUP BY 1,2
I have tried multiple ways of using the DISTINCT statement with CASE WHEN but none of them works.
Hmmm . . . How about this?
select id,
(case when min(category) = max(category)
then min(category) || ' only'
when count(distinct category) = 3
then 'All'
when min(category) is NULL
then 'None'
else min(category) || ' and ' || max(category)
end)
from t
group by id;
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Please find below Tables.
How to show all departments where in March 2014 there were sales of goods with a price of less than 400?
CREATE TABLE dep
(
id NUMBER (10) NOT NULL,
city VARCHAR2 (100) NOT NULL,
name VARCHAR2 (100) NOT NULL,
CONSTRAINT dep_pk PRIMARY KEY (id)
);
I guess you need below query -
SELECT D.name, SUM(cost)
FROM sales S
JOIN dep D ON S.dep_id = D.id
WHERE EXTRACT(YEAR FROM time) = 2014
AND EXTRACT(MONTH FROM time) = 3
GROUP BY D.name
HAVING SUM(cost) < 400
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Let's say I have a table like this:
ID. Location. Value.
1. AGF. 10.00
2. VHJ. -20.00
3. AGF. -20.00
4. AGF. 5.00
5. KLZ. 50.00
6. AGF. 10.00
I want to select the rows that have same Location AND whose Values sum to zero.
In this case the result should be:
1
3
6
because those rows are all in Location AGF and they sum to 0 (10 + -20 + 10).
Try:
Select ID from YourTable where Location IN(
Select location from YouTable
Group By Location
Having sum(Value) = 0
)
You need to find all locations with zero sum using grouping and group filters (group by and having clauses respectively). This can be done in a subquery. Then select all IDs with the just selected locations.
select ID
from YOUR_TABLE
where Location in (
select Location
from YOUR_TABLE
group by Location
having sum(Value) = 0
)
You could use GROUP BY and HAVING, like this:
Select ID from tablelocation where Location IN(
Select location from tablelocation
Group By Location
Having sum(Value) = 0
)
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This is my tables description :
Ticket
Id int pk
ShowTicketStateID_FK int
TicketStateID_FK int
TicketState
Id int
Name int
Actually, the TicketState has two foreign keys to Tickettable.
Here is some rows from Ticket table :
1 1 1
2 2 1
3 1 2
...
And here is rows for TicketState
1 'sold'
2 'reserved'
Now i want this Result set :
1 sold sold
2 reserved sold
3 sold reserved
How should I select rows from ticket table with both states name?
SELECT T.ID, S1.Name AS ShowState, S2.Name AS TicketState
FROM Ticket AS T
JOIN TicketState AS S1 ON T1.ShowTicketStateID = S1.ID
JOIN TicketState AS S2 ON T1.TicketStateID = S2.ID
The key concept is using the two different table aliases for the TicketState table in a single query. The table has to be scanned twice (speaking loosely), once for the ShowTicketStateID lookup and once for the TicketStateID lookup.