I have a table with column uuid and type. I want all the uuid's 'xxxxx' such that no rows have uuid = 'xxxxx' AND type = 'buy'.
This ends up the same as if you took all uuid's in the table, and then removed all uuid's that match SELECT uuid FROM table WHERE type = 'buy'.
I approach these problems using aggregation and a having clause:
select a_uuid
from table t
group by a_uuid
having sum(case when type = 'Purchase' then 1 else 0 end) = 0;
EDIT:
If you have a table with one row per a_uuid, then the fastest is likely to be:
select a_uuid
from adtbs a
where not exists (select 1 from table t where t.a_uuid = a.a_uuid and t.type = 'Purchase');
For this query, you want an index on table(a_uuid, type).
select a_uuid
from t
group by a_uuid
having not bool_or(type = 'Purchase')
http://www.postgresql.org/docs/current/static/functions-aggregate.html#FUNCTIONS-AGGREGATE-TABLE
Related
Here is my query with the output below the syntax.
SELECT DISTINCT CASE WHEN id = 'RUS0261431' THEN value END AS sr_type,
COUNT(CASE WHEN id in ('RUS0290788') AND value in ('1','2','3','4') THEN respondentid END) AS sub_ces,
COUNT(CASE WHEN id IN ('RUS0290788') AND value in ('5','6','7') THEN respondentid END) AS pos_ces,
COUNT(*) as total_ces
FROM `some_table`
WHERE id in ( 'RUS0261431') AND id <> '' AND value IS NOT NULL
GROUP BY 1
As you can see with the attached table I'm unable to group the values based on Id RUS0290788 with the distinct values that map to RUS0261431. Is there anyway to pivot with altering my case when statements so I can group sub_ces and pos_ces by sr_type. Thanks in advanceenter image description here
You can simplify your WHERE condition to WHERE id = ('RUS0261431'). Only records with this value will be selected so you do not have to repeat this in the CASE statements.
I am having a table with below specified structure
From the table, I just want to retrieve the product id which is having Ram with value 12 and color with Blue. The expected result is 1.
I tried many queries and it's not sharing the expected result.
What will be the solution?
It's very difficult to manage the separate table for each feature as we have an undefined set of features.
You can use conditional aggregation:
select productid
from t
group by productid
having max(case when feature = 'Ram' then value end) = '12' and
max(case when feature = 'Color' then value end) = 'Blue';
use correlated subquery with not exists
select distinct product_id from tablename a
where not exists
(select 1 from tablename b where a.product_id=b.product_id and feature='Ram' and value<>12)
and not exists
(select 1 from tablename c where a.product_id=c.product_id and feature='Color' and value<>'blue')
What is better approach to check existence of an object in database?
select count(id) as count from my_table where name="searchedName";
OR
select id from my_table where name="searchedName";
And then check if count > 0 or the object is not null (ORM logic)
EDIT:
select id to be valid for Oracle.
The idea should be to that we only need to find one record in order to say that such record exists. This can be done with an EXISTS clause in standard SQL.
select exists (select * from mytable where name = 'searchedName');
returns true if the table contains a record with 'searchedName' and false otherwise.
If you want 0 for false and 1 for true instead (e.g. if the DBMS does not support booleans):
select case when exists (select * from mytable where name = 'searchedName')
then 1 else 0 end as does_exist;
You say you want this for Oracle. In Oracle you can use above query, but you'd have to select from the table dual:
select case when exists (select * from mytable where name = 'searchedName')
then 1 else 0 end as does_exist
from dual;
But for Oracle we'd usually use rownum instead:
select count(*) as does_exist
from mytable
where name = 'searchedName'
and rownum = 1; -- to find one record suffices and we'd stop then
This also returns 1 if the table contains a record with 'searchedName' and 0 otherwise. This is a very typical way in Oracle to limit lookups and the query is very readable (in my opinion).
I'd just call:
select id from my_table where name='searchedName';
Making sure there is an index for the name column.
And then check whether or not the result is empty.
Try with IF EXISTS (
if exists (select 1 from my_table where name = "searchedName")
begin
....
end
I have a basic SQL query where I am selecting data from a core records table. I want to add an AND clause to my statement to filter out the results based on a table variable, only if data actually exists in there.
SELECT
*
FROM
TABLE
WHERE
field = '123'
AND
(gender IN (SELECT gender FROM #genders))
In this case, I am looking for all records where field = 123. My goal here is to say that if #genders contains records, filter by that as well.
However, if #genders is empty and we don't have any data in it, it should include all records.
How can I go about doing this? The temp tables are created based on the user selecting one or more optional pieces of criteria from the UI. If they choose a gender for example, I put their selections into a temp table and then I need to search records that meet that criteria. However, if they don't select a gender, I want to include all records, regardless of what the main record has for the gender field.
SELECT
*
FROM
TABLE
WHERE
field = '123'
AND ((SELECT count(1) FROM #genders) = 0 OR
(gender IN (SELECT gender FROM #genders)))
You can use IF condition:
IF EXISTS(SELECT gender FROM #genders)
BEGIN
SELECT * FROM TABLE
WHERE field = '123'
AND
(gender IN (SELECT gender FROM #genders))
END
ELSE
BEGIN
SELECT * FROM TABLE
END
You are going to think this is odd but it is efficient
SELECT t.*
FROM TABLE t
JOIN GENDERS g
on g.gender = t.gender
and t.field = '123'
union all
SELECT t.*
FROM TABLE t
where not exists (select 1 from genders)
Maybe I'm under-thinking it, but isn't it just this?
SELECT
*
FROM
TABLE AS t
LEFT JOIN
#genders AS g
ON
g.gender = t.gender
WHERE
field = '123'
AND
(g.gender = t.gender OR g.gender IS NULL);
If your query doesn't get too complicated, I'd recommend an if statement. Once you find yourself continually adding if else statement in there, I'd recommend looking into dynamic SQL.
IF EXISTS(SELECT gender FROM #genders)
BEGIN
SELECT * FROM TABLE
WHERE field = '123'
and gender IN (SELECT distinct gender FROM #genders)
END
ELSE
BEGIN
SELECT * FROM TABLE WHERE field = '123'
END
I am writing data to a table and allocating a "group-id" for each batch of data that is written. To illustrate, consider the following table.
GroupId Value
------- -----
1 a
1 b
1 c
2 a
2 b
3 a
3 b
3 c
3 d
In this example, there are three groups of data, each with similar but varying values.
How do I query this table to find a group that contains a given set of values? For instance, if I query for (a,b,c) the result should be group 1. Similarly, a query for (b,a) should result in group 2, and a query for (a, b, c, e) should result in the empty set.
I can write a stored procedure that performs the following steps:
select distinct GroupId from Groups -- and store locally
for each distinct GroupId: perform a set-difference (except) between the input and table values (for the group), and vice versa
return the GroupId if both set-difference operations produced empty sets
This seems a bit excessive, and I hoping to leverage some other commands in SQL to simplify. Is there a simpler way to perform a set-comparison in this context, or to select the group ID that contains the exact input values for the query?
This is a set-within-sets query. I like to solve it using group by and having:
select groupid
from GroupValues gv
group by groupid
having sum(case when value = 'a' then 1 else 0 end) > 0 and
sum(case when value = 'b' then 1 else 0 end) > 0 and
sum(case when value = 'c' then 1 else 0 end) > 0 and
sum(case when value not in ('a', 'b', 'c') then 1 else - end) = 0;
The first three conditions in the having clause check that each elements exists. The last condition checks that there are no other values. This method is quite flexible, for various exclusions and inclusion conditions on the values you are looking for.
EDIT:
If you want to pass in a list, you can use:
with thelist as (
select 'a' as value union all
select 'b' union all
select 'c'
)
select groupid
from GroupValues gv left outer join
thelist
on gv.value = thelist.value
group by groupid
having count(distinct gv.value) = (select count(*) from thelist) and
count(distinct (case when gv.value = thelist.value then gv.value end)) = count(distinct gv.value);
Here the having clause counts the number of matching values and makes sure that this is the same size as the list.
EDIT:
query compile failed because missing the table alias. updated with right table alias.
This is kind of ugly, but it works. On larger datasets I'm not sure what performance would look like, but the nested instances of #GroupValues key off GroupID in the main table so I think as long as you have a good index on GroupID it probably wouldn't be too horrible.
If Object_ID('tempdb..#GroupValues') Is Not Null Drop Table #GroupValues
Create Table #GroupValues (GroupID Int, Val Varchar(10));
Insert #GroupValues (GroupID, Val)
Values (1,'a'),(1,'b'),(1,'c'),(2,'a'),(2,'b'),(3,'a'),(3,'b'),(3,'c'),(3,'d');
If Object_ID('tempdb..#FindValues') Is Not Null Drop Table #FindValues
Create Table #FindValues (Val Varchar(10));
Insert #FindValues (Val)
Values ('a'),('b'),('c');
Select Distinct gv.GroupID
From (Select Distinct GroupID
From #GroupValues) gv
Where Not Exists (Select 1
From #FindValues fv2
Where Not Exists (Select 1
From #GroupValues gv2
Where gv.GroupID = gv2.GroupID
And fv2.Val = gv2.Val))
And Not Exists (Select 1
From #GroupValues gv3
Where gv3.GroupID = gv.GroupID
And Not Exists (Select 1
From #FindValues fv3
Where gv3.Val = fv3.Val))