im looking for a query to fill this condition:
That currently gives us the number of BACs at the entity (which is something we need). The database assigns the BAC IDs consecutively within each accounting entity. So we need to add one more field to the query showing the current highest BAC ID at the entity. And once we have that, just filter the results down to anyplace the number of records doesn't equal the highest ID.
My current query:
select accounting_entity_id, count(bac_id)
from dc.pl_bac_information
group by accounting_entity_id
having count(bac_id) > 1;
Use analytic functions for this:
select bi.*
from (select bi.*, max(bac_id) over (partition by accounting_entity_id) as max_bac_id
from dc.pl_bac_information bi
) bi
where bac_id = max_bac_id;
This assumes you are using Oracle.
SELECT ACCOUNTING_ENTITY_ID
FROM DC.PL_BAC_INFORMATION
HAVING COUNT(BAC_ID) > 1 AND COUNT(BAC_ID) != MAX(BAC_ID)
GROUP BY ACCOUNTING_ENTITY_ID;
Related
I am attempting to filter my table and get the item that sold for the most amount of money. In order to do this I am using "AuctionOpen" to determine whether or not the auction is still open. The auction cannot be open and have the item been sold (later I will use this for the most expensive item available).
I am able to use the AND operator to compare AuctionOpen by using the following:
select s.*
from auctionsite.dbo.Auction s
where s.HighestBid = (select max(s2.HighestBid) from auctionsite.dbo.Auction
s2) and s.AuctionOpen = 0;
When I set this equal to zero I get results, but when I set it equal to 1, it only returns the column titles even though there are values set to 1 in the table.
Results when compared to 0:
Results when compared to 1:
Clearly, the highest bid is on a record where AuctionOpen <> 1.
I recommend using order by and fetch (or the equivalent in your database):
select s.*
from auctionsite.dbo.Auction s
where s.AuctionOpen = 0
order by s.HIghestBid desc
fetch first 1 row only
In SQL Server, use either select top (1) or offset 0 rows fetch first 1 row only.
I think you should try the Count aggregate function
here, try this:
**Select count(Item_name) As
[Item with the highest money]
from table_name
Group by Item_name DSEC;**
You can check my page hereSQL/MySQL tips for some SQL/MySQL lessons
This has been driving me crazy all day, and I've gone through every solution I can find on here. This should be a very simple thing.
I have a table in Access that contains a list of applications:
ApplicantNumber | Region
There are many more columns, but those are the two I care about at the moment. Each row is a separate application, and each applicant can submit multiple applications.
I have a query in Access that finds the count per applicant of applications in each region:
ApplicantNumber | Region | CountOfAPplications
How the ##&*!!! do I pull out of that the region with the most applications for each ApplicantNumber?
As far as I can tell, the following should work fine but it just provides the same output as the initial query with the full count per applicant:
SELECT myQry.ApplicantNumber, myQRY.Region, Max(myQRY.CountOfRegion)
FROM (SELECT AppliedCensusBlocks.ApplicantNumber, AppliedCensusBlocks.Region, Count(AppliedCensusBlocks.Region) AS CountOfRegion
FROM AppliedCensusBlocks
GROUP BY AppliedCensusBlocks.ApplicantNumber, AppliedCensusBlocks.Region) AS myQRY
GROUP BY myQry.ApplicantNumber, myQry.Region
What am I doing wrong? If I remove the Region field, Access will work as I'd expect and just show the ApplicantNumber and maximum count. BUt I'm really trying to get at the region name associated with the maximum count.
This is a bit tricky. MS Access is not the best suited for this sort of query. But here is one way
SELECT acb.ApplicantNumber, acb.Region, Count(*) AS CountOfRegion
FROM AppliedCensusBlocks as acb
GROUP BY acb.ApplicantNumber, acb.Region
HAVING COUNT(*) = (SELECT TOP 1 COUNT(*)
FROM AppliedCensusBlocks as acb2
WHERE acb2.ApplicantNumber = acb.ApplicantNumber
GROUP BY acb2.Region
ORDER BY COUNT(*) DESC, acb2.Region
);
SELECT TOP 1 ApplicantNumber, Region, COUNT(*) AS Applications
FROM AppliedCensusBlocks
GROUP BY ApplicantNumber, Region
ORDER BY COUNT(*) DESC
fellow SQLers.
I have a simple yet complex problem that I need to solve with SQL (SQLite) for my FME-script to run efficiantly. I have data I want to aggregate but in subgroups - taking z-level into account. It's a geological profile where I want to simplify the incoming data before I create my profile.
Example data
x,y,z_from,z_to,value
1,2,1,2,A
1,2,2,3,A
1,2,3,4,B
1,2,4,5,A
1,2,5,6,A
1,2,6,7,A
1,2,7,8,C
With SQL I want to aggregate on value but only rows that are adjacent (sort of a dissolve but on non-spatial data). And I want to calculate (also in sql) the correct z_from- and z_to-values. So the result from the example data above should be:
x,y,z_from,z_to,value
1,2,1,3,A
1,2,3,4,B
1,2,4,7,A
1,2,7,8,C
Any help on this will be remembered for all eternity.
Peter
It looks like you want all rows where the the "next" value is different, as defined by z_to. Unfortunately, SQLite doesn't support lead(), but you can do:
select e.*
from (select e.*,
(select e2.value
from example e2
where e2.z_to > e.z_to
order by e2.z_to
limit 1
) as next_value
from example e
) e
where next_value is null or next_value <> value;
There may be a very simple way to do this, but I can't quite think of it -- I have a dataset that returns a minimum job title and minimum effective date, then all effdts > than the min_effdt. In order to use this data in a charting program, I would like to rank each successive effdt if it exists, as in Min Role Effdt, then 2nd, 3rd, Max. Of course there could be anywhere from 2 to 20 jobs per person.
At first I considered trying a case statement, but I don't think that works when analyzing two columns at once. Is there a SQL statement that will allow ranking? Right now my data looks like
Employee Number | Min Base Role | Min Role Effdt | Base Role | Role Effdt
and comes from two tables, with the 2nd table brought in twice to get the Role / Effdt as Min, then All greater than Min.
I am using ORACLE. Code is below:
SELECT DISTINCT AL4.FULL_NAME,
AL4.EMPLOYEE_NUMBER,
AL4.HIRE_DATE,
AL4.DATE_OF_BIRTH,
AL4.AGE,
AL4.TERM_DATE,
AL4.ETHNIC_ORIGIN,
AL2.RECORDVALUE AS MIN_BASE_ROLE,
AL3.RECORDVALUE AS BASE_ROLE,
AL3.EFFECTIVE_START_DATE AS "ROLE EFFECTIVE DATE",
AL2.EFFECTIVE_START_DATE AS "MIN ROLE EFFDT"
FROM T1 AL2,
T2 AL3,
T3 AL4
WHERE AL4.PERSON_ID = AL2.PERSON_ID
AND AL4.PERSON_ID = AL3.PERSON_ID
AND AL4.EMPLOYEE_NUMBER = AL2.HISL_ID
AND AL4.EMPLOYEE_NUMBER = AL3.HISL_ID
AND AL2.RECORDTYPE = 'BASE_ROLE'
AND AL3.RECORDTYPE = 'BASE_ROLE'
AND AL2.EFFECTIVE_START_DATE = (SELECT MIN(A.EFFECTIVE_START_DATE) from T1 A where A.person_id = al2.person_id and a.recordtype = al2.recordtype)
AND AL3.EFFECTIVE_START_DATE > AL2.EFFECTIVE_START_DATE
AND (AL4.TERM_DATE >= '01-JAN-2012' or AL4.TERM_DATE is NULL)
order by AL4.EMPLOYEE_NUMBER
The function that you are looking for is row_number(). I think the expression you want is:
row_number() over (partition by AL4.EMPLOYEE_NUMBER
order by AL2.EFFECTIVE_START_DATE
) as ranking
The function row_number() says "assign a sequential number to a group of rows". The partition by clause defines the group, where the numbering starts over again at 1. The order by clause specifies the ordering within the group.
Similar functions rank() and dense_rank() might also be useful. They differ in how they handle duplicate values.
I have the below query. The problem is the last column productdesc is returning two records and the query fails because of distinct. Now i need to add one more column in where clause of the select query so that it returns one record. The issue is that the column i need
to add should not be a part of group by clause.
SELECT product_billing_id,
billing_ele,
SUM(round(summary_net_amt_excl_gst/100)) gross,
(SELECT DISTINCT description
FROM RES.tariff_nt
WHERE product_billing_id = aa.product_billing_id
AND billing_ele = aa.billing_ele) productdescr
FROM bil.bill_sum aa
WHERE file_id = 38613 --1=1
AND line_type = 'D'
AND (product_billing_id, billing_ele) IN (SELECT DISTINCT
product_billing_id,
billing_ele
FROM bil.bill_l2 )
AND trans_type_desc <> 'Change'
GROUP BY product_billing_id, billing_ele
I want to modify the select statement to the below way by adding a new filter to the where clause so that it returns one record .
(SELECT DISTINCT description
FROM RRES.tariff_nt
WHERE product_billing_id = aa.product_billing_id
AND billing_ele = aa.billing_ele
AND (rate_structure_start_date <= TO_DATE(aa.p_effective_date,'yyyymmdd')
AND rate_structure_end_date > TO_DATE(aa.p_effective_date,'yyyymmdd'))
) productdescr
The aa.p_effective_date should not be a part of GROUP BY clause. How can I do it? Oracle is the Database.
So there are multiple RES.tariff records for a given product_billing_id/billing_ele, differentiated by the start/end dates
You want the description for the record that encompasses the 'p_effective_date' from bil.bill_sum. The kicker is that you can't (or don't want to) include that in the group by. That suggests you've got multiple rows in bil.bill_sum with different effective dates.
The issue is what do you want to happen if you are summarising up those multiple rows with different dates. Which of those dates do you want to use as the one to get the description.
If it doesn't matter, simply use MIN(aa.p_effective_date), or MAX.
Have you looked into the Oracle analytical functions. This is good link Analytical Functions by Example