How can I retrieve values in a row as column values?
Example:
Consider the output of below query as INPUT :
Select 1,2,3,4,5,6,7,8,9,10
from dual;
I need a query that can give below output:
COL1
----
1
2
3
4
5
6
7
8
9
10
SELECT 1 AS "COL1" FROM dual
UNION
SELECT 2 FROM dual
UNION
SELECT 3 FROM dual
UNION
SELECT 4 FROM dual
UNION
SELECT 5 FROM dual
UNION
SELECT 6 FROM dual
UNION
SELECT 7 FROM dual
UNION
SELECT 8 FROM dual
UNION
SELECT 9 FROM dual
UNION
SELECT 10 FROM dual ;
If you want to generate a sequence of numbers in Oracle:
with n as (
select level as n
from dual
connect by level <= 10
)
select *
from n;
Or, if you have 10 columns, you can do an unpivot. An easy way is with union all:
select col1 from t union all
select col2 from t union al
. . .
select col10 from t;
Related
I have to find the name like : Robert#jr23 (There must be Alphabet,Any Special characters or Numbers except hyphen(-),apostrophe (') and Space).
I was doing as below:
select * from test where REGEXP_LIKE(trim(NAME_1), '[^- '']')
But I am not getting the right results with this.
Need to match:
Kevin#123
bob#jr
mike$dr
Needs to exclude:
Alex-jr
Robert'jr
Brian jr
You need to use not with a pattern matching the values you want to exclude. Otherwise you are matching strings that contain any character that is not in the exclusion list, which is all of them.
select column_value
from ora_mining_varchar2_nt
( 'Kevin#123'
, 'bob#jr'
, 'mike$dr'
, 'Alex-jr'
, 'Robert''jr'
, 'Brian jr'
, 'A!' )
where 1=1
and not regexp_like(column_value,'[- '']')
and regexp_like
(column_value, '([A-Z0-9]+[^A-Z0-9])|([^A-Z0-9]+[A-Z0-9])', 'i') ;
Edit: added a regex_like condition to ensure that values contain a letter or digit and a 'special character', meaning here a character that is neither a letter, digit or space, ' or -.
You can use following query to include all special characters except space, - and '
SQL> with tbl(name) as (
2 select 'Kevin#123' from dual union
3 select 'bob#jr' from dual union
4 select 'mike$dr' from dual union
5 select 'Alex-jr' from dual union
6 select 'Brian jr' from dual union
7 select 'Brian)jr' from dual union
8 select 'Robert''jr' from dual
9 )
10 select *
11 from tbl
12 where regexp_like(name, '[^[a-z]|[A-Z]|[:space:]|[:cntrl:]|/]')
13 and not regexp_like(name,'[- '']');
NAME
---------
Brian)jr -- see this is included
Kevin#123
bob#jr
mike$dr
SQL>
One option is to replace everything that's valid with NULL, and what remains is invalid:
SQL> with test (col) as
2 (select 'Robert#jr23' from dual union all
3 select 'Kevin#123' from dual union all
4 select 'bob#jr' from dual union all
5 select 'mike$dr' from dual union all
6 select 'Alex-jr' from dual union all
7 select 'Robert''jr' from dual union all
8 select 'Brian jr' from dual
9 )
10 select col
11 From test
12 where regexp_replace(col, '[[:alpha:]]|[[:digit:]]|-|''', null) is not null;
COL
-----------
Robert#jr23
Kevin#123
bob#jr
mike$dr
Brian jr
SQL>
I'm confused about what you, actually, want to get as a result. Here are some examples which show result of such a regular expression; which IDs do you want to get as a result?
SQL> with test (id, col) as
2 (select 1, 'Robert#jr23' from dual union all
3 select 2, 'Kevin#123' from dual union all
4 select 3, 'bob#jr' from dual union all
5 select 4, 'mike$dr' from dual union all
6 select 5, 'Alex-jr' from dual union all
7 select 6, 'Robert''jr' from dual union all
8 select 7, 'Brian jr' from dual union all
9 select 8, 'Brian10' from dual
10 )
11 select col,
12 regexp_replace(col,
13 '[[:alpha:]]|[[:digit:]]|[[:space:]]|-|''', null) result
14 from test;
COL RESULT
----------- ----------
Robert#jr23 #
Kevin#123 #
bob#jr #
mike$dr $
Alex-jr
Robert'jr
Brian jr
Brian10
8 rows selected.
SQL>
One of your comments says:
select a customer name where there must be a special character or numbers (except space, Hyphen and apostrophe)
which means that numbers and special characters should be treated as "equal". If that's so, does this help?
SQL> with test (id, col) as
2 (select 1, 'Robert#jr23' from dual union all
3 select 2, 'Kevin#123' from dual union all
4 select 3, 'bob#jr' from dual union all
5 select 4, 'mike$dr' from dual union all
6 select 5, 'Alex-jr' from dual union all
7 select 6, 'Robert''jr' from dual union all
8 select 7, 'Brian jr' from dual union all
9 select 8, 'Brian10' from dual
10 )
11 select id, col
12 from test
13 where regexp_replace(col, '[[:alpha:]]|[[:space:]]|-|''', '')
14 is not null;
ID COL
---------- -----------
1 Robert#jr23
2 Kevin#123
3 bob#jr
4 mike$dr
8 Brian10
SQL>
I want to fetch data from database using regular expression which should not include string '05613'.
I have values like NAW_05613_11_PL04_02 in my table. I want to give condition that all rows which have 05613 in it should not be displayed.
I have tried using REGEXP_LIKE(d.variable_value_string, '^N(*)[^{05613}](*)')
SELECT * from tablename where REGEXP_LIKE(columnname, '^N(*)[^{05613}](*)')
Expected result should be- row with value having 05613 should not be retrieved.
A simple LIKE could be enough:
... columnName not like '%05613%'
For example:
SQL> with test(c) as (
2 select '05613XX' from dual union all
3 select 'XX05613' from dual union all
4 select 'X05613X' from dual union all
5 select 'XXX' from dual
6 )
7 select *
8 from test
9 where c not like '%05613%';
C
-------
XXX
SQL>
If you need, for some reason, regexp_like, this is a way:
SQL> with test(c) as (
2 select '05613XX' from dual union all
3 select 'XX05613' from dual union all
4 select 'XX05613' from dual union all
5 select 'X05613X' from dual union all
6 select 'XXX' from dual
7 )
8 select *
9 from test
10 where not regexp_like(c, '05613');
C
-------
XXX
If this is your assignment and usage of regexp_like is mandated then use following regexp_like:
SELECT * from tablename D
where Not REGEXP_LIKE(d.variable_value_string, '05613')
Cheers!!
I am working on SQL Developer. I want only those records which have non-numeric data. The query I used is:
select * from TBL_NAME where regexp_like (mapping_name,'%[!0-9]%');
Strangely this is not working.
How about this? As you said, return values that are NOT numbers.
SQL> with test (col) as
2 (select 'abc123' from dual union
3 select '12345' from dual union
4 select 'abc' from dual union
5 select '($ff3' from dual union
6 select '12.345' from dual
7 )
8 select col
9 from test
10 where not regexp_like (col, '^\d+|(\.\d+)$');
COL
------
($ff3
abc
abc123
SQL>
If there are no decimal values, regular expression is even simpler: '^\d+$'
[EDIT, after sample data have been provided]
Piece of cake:
SQL> with test (col) as
2 (select 'ABC' from dual union
3 select 'BCE1' from dual union
4 select '2GHY' from dual union
5 select 'WE56S' from dual union
6 select 'TUY' from dual
7 )
8 select col
9 from test
10 where not regexp_like (col, '\d');
COL
-----
ABC
TUY
SQL>
Input is:
Section1
Section2
Section3
Section10
Section11
Section1A
Section1B
Section12
Section11A
Section11B
And I want output like:
Section1
Section1A
Section1B
Section2
Section3
Section10
Section11
Section11A
Section11B
Section12
I tried query :
select section_name
from sections
order by length(section_name),section_name
Assuming that the structure of your strings is fixed, as in your example, this could be a way:
SQL> select x,
2 to_number(regexp_substr(x, '[0-9]+')) numericPart,
3 regexp_substr(x, '([0-9]+)([A-Z])', 1, 1, '', 2) optionalChar
4 from (
5 select 'Section1' x from dual union all
6 select 'Section2' from dual union all
7 select 'Section3' from dual union all
8 select 'Section10' from dual union all
9 select 'Section11' from dual union all
10 select 'Section1A' from dual union all
11 select 'Section1B' from dual union all
12 select 'Section12' from dual union all
13 select 'Section11A' from dual union all
14 select 'Section11B' from dual
15 )
16 order by numericPart,
17 optionalChar nulls first
18 ;
X NUMERICPART OPTIONALCHAR
---------- ----------- ----------------------------------------
Section1 1
Section1A 1 A
Section1B 1 B
Section2 2
Section3 3
Section10 10
Section11 11
Section11A 11 A
Section11B 11 B
Section12 12
Here you first order by the numeric part, treating it as number, and then consider the (optional) character after the number.
I have a column in the database in the following format: yymmddhh24miss
Sample Data:
140203101241
140202101141
140102101240
143001101244
142801101245
142701131347
142601121542
142101131744
...
I need to get the nearest high value from the list. Ex: If I pass 142701131333, then it should return 142701131347 from the above list.
Any help appreciated!
SELECT data
FROM
(
SELECT data
FROM tbl
WHERE data > '142701131333'
ORDER BY data
) a
WHERE rownum = 1
SQL> with t (x) as (
2 select 140203101241 from dual union all
3 select 140202101141 from dual union all
4 select 140102101240 from dual union all
5 select 143001101244 from dual union all
6 select 142801101245 from dual union all
7 select 142701131347 from dual union all
8 select 142601121542 from dual union all
9 select 142101131744 from dual
10 )
11 select min(x) minx from t where x > 142701131333
12 /
MINX
-----------------
142701131347
SELECT MIN(sample_data)
FROM tableName
WHERE sample_data > 142701131333