Union results from subselect - sql

Question

I have an SQL statement with following structure:
f(string parameter)=select * from table(parameter) ...
=> results in some table with rows.
f(string parameter) is used as shortcut for more complex sql subquery.
table parameters:
|---params----|
param1
param2
param3
....
how to combine f() with the table parameters where f() will be called for each param in this table. My question refers to SQL statement itself. As result I expect
f(param1)
union all
f(param2)
union all
f(param3)
...
If someone is interested what is staying in f() refer to my previous question answer
https://stackoverflow.com/a/27599637/2023524.

Answer 1

You can define f as a function like the below
create or replace function f(param IN VARCHAR2) return varchar2 is
Result varchar2(32767);
begin
with names as(
SELECT REGEXP_SUBSTR(regexp_replace(replace(param,
chr(13) || chr(10),
','),
'[[:space:]]*',
''),
'[^=]+',
1,
level) as name
FROM DUAL
CONNECT BY LEVEL <= (SELECT REGEXP_COUNT(param, '=') FROM DUAL)
)
select LISTAGG(nvl(regexp_substr(name, '[^,]+', 1, 2),
regexp_substr(name, '[^,]+', 1)),
',') WITHIN
GROUP(
ORDER BY name)
INTO Result
from names;
return(Result);
end f;
Then you can call your parameters like the below
with parameter(param) as (
select 'aa = black' ||chr(13)||chr(10)||'bb = change'||chr(13)||chr(10)||'mmmm=no'
from dual union all
select 'aa = black' ||chr(13)||chr(10)||'bb = change'||chr(13)||chr(10)||'kkk=no' from dual
)
select distinct regexp_substr(f(param),'[^,]+',1,level) from parameter
connect by level <=regexp_count(f(param),',')+1;
Update1:-Just for your information You can call a function within an Anonymous Block like the below
DECLARE
function f(param IN VARCHAR2) return varchar2 is
Result varchar2(32767);
begin
with names as(
SELECT REGEXP_SUBSTR(regexp_replace(replace(param,
chr(13) || chr(10),
','),
'[[:space:]]*',
''),
'[^=]+',
1,
level) as name
FROM DUAL
CONNECT BY LEVEL <= (SELECT REGEXP_COUNT(param, '=') FROM DUAL)
)
select LISTAGG(nvl(regexp_substr(name, '[^,]+', 1, 2),
regexp_substr(name, '[^,]+', 1)),
',') WITHIN
GROUP(
ORDER BY name)
INTO Result
from names;
return(Result);
end f;
begin
for i in 1 .. (regexp_count(f('aa = black' || chr(13) || chr(10) ||
'bb = change' || chr(13) || chr(10) ||
'kkk=no'),
',') + 1) loop
dbms_output.put_line(regexp_substr(f('aa = black' || chr(13) ||
chr(10) || 'bb = change' ||
chr(13) || chr(10) || 'kkk=no'),
'[^,]+',
1,
i));
end loop;
end;

Answer 2

In Oracle 11g, I think you can just do this in the from clause:
with params as (
select param1 as param from dual union all
select param2 union all
select param3
)
select *
from params p,
table(f(p.param)) f;