Sql query for aggregation - sql

Question

Let consider the below table structure
Product Year Month Price
A 2011 01 23
A 2011 02 34
.......
.....
A 2011 12 54
B 2011 01 13
B 2011 02 12
.......
.....
B 2011 12 20
From this table i need to aggregate the value for every 3 months ie..,
Product Year Month Price
A 2011 1-3 45
A 2011 4-6 23
A 2011 7-9 45
A 2011 10-12 16
A 2012 1-3 12
.......
.......
Can anybody tell me how to do this calculation using sql query...
Thanks in Advance !!!

Answer 1

Try this. Use Case statement to group the month Quarter wise then find the sum of price
SELECT product,
[year],
CASE
WHEN ( [month] ) IN( '01', '02', '03' ) THEN '1-3'
WHEN ( [month] ) IN( '04', '05', '06' ) THEN '4-6'
WHEN ( [month] ) IN( '07', '08', '09' ) THEN '7-9'
WHEN ( [month] ) IN( '10', '11', '12' ) THEN '10-12'
END [Month],
Sum(Price)
FROM tablename
GROUP BY product,
[year],
CASE
WHEN ( [month] ) IN( '01', '02', '03' ) THEN '1-3'
WHEN ( [month] ) IN( '04', '05', '06' ) THEN '4-6'
WHEN ( [month] ) IN( '07', '08', '09' ) THEN '7-9'
WHEN ( [month] ) IN( '10', '11', '12' ) THEN '10-12'
END
Note : By looking at your month data it looks like its a varchar column but you can change it to TINYINT

Answer 2

Try using CASE in GROUP BY clause:
...
GROUR BY [Year], CASE WHEN Month in (1,2,3) THEN '1-3'
WHEN Month in (4,5,6) THEN '4-6'
...
END

Answer 3

Considering Month is stored as varchar(), you can write as:
Select Product,
Year,
[MonthRange] as [Month],
Sum(Price)
From (
select Product,
Year,
case when Month in ('01','02','03') then '[1-3]'
when Month in ('04','05','06') then '[4-6]'
when Month in ('07','08','09') then '[7-9]'
when Month in ('10','11','12') then '[10-12]'
end as [MonthRange],
Price
from #test) as T
Group by Product,Year,[MonthRange]
DEMO

Answer 4

select Product, [year], case when [month] between 1 and 3 then '01-03' else case when [month] between 4 and 6 then '04-06' else case when [month] between 7 and 9 then '07-09' else '10-12' end end end, sum([price])
from Table1
group by Product, [year], case when [month] between 1 and 3 then '01-03' else case when [month] between 4 and 6 then '04-06' else case when [month] between 7 and 9 then '07-09' else '10-12' end end end
Above sql query will give you the required results, if you don not use leading zeros which I used in month labels then you will not get result sorted by month.

Answer 5

Use this query.
CREATE table #test
(
product VARCHAR(10),
year int,
month int,
price int
)
INSERT INTO #test
SELECT 'A', 2011, 01, 23 UNION
SELECT 'A', 2011, 02, 65 UNION
SELECT 'A', 2011, 03, 45 UNION
SELECT 'B', 2011, 04, 34 UNION
SELECT 'B', 2011, 05, 67 UNION
SELECT 'B', 2011, 06, 34 UNION
SELECT 'B', 2011, 07, 87 UNION
SELECT 'B', 2011, 08, 2 UNION
SELECT 'B', 2011, 09, 345 UNION
SELECT 'B', 2011, 10, 9 UNION
SELECT 'B', 2011, 11, 293 UNION
SELECT 'B', 2011, 12, 23
SELECT product, [year], [MONTH], SUM(price)
FROM
(
SELECT product, [year], CASE WHEN [MONTH] IN (01,02,03) THEN '1-3'
WHEN [MONTH] IN (04,05,06) THEN '4-6'
WHEN [MONTH] IN (07,08,09) THEN '7-9'
WHEN [MONTH] IN (10, 11, 12) THEN '10-12'
END AS [Month],
price
FROm #Test
)AS A
group BY product, [year], [Month]