I have this ms access query:
SELECT weber, t1.artnr, t1.varnr, t1.lfdnr_kal, fert.invnr, fert.min, fert.[lst/h] FROM (
SELECT stammdat.weber, lackzahlen.artnr, lackzahlen.varnr, first(stammdat.[lfdnr-kal]) AS lfdnr_kal
FROM lackzahlen LEFT JOIN stammdat ON (lackzahlen.artnr=cstr(IIf(stammdat.artnr Is Null,'',cstr(stammdat.artnr)))) AND (lackzahlen.varnr=cstr(IIf(stammdat.varnr Is Null,'',cstr(stammdat.varnr))))
GROUP BY lackzahlen.artnr, lackzahlen.varnr, io_stkzahl, weber) AS t1
LEFT JOIN fert ON (t1.lfdnr_kal=fert.[lfdnr-kal]) AND (t1.artnr=cstr(iif(fert.artnr Is Null,'',cstr(fert.artnr)))) WHERE fert.invnr IN ('338902', 'R20000')
Now, I would like to filter the records on the image:
As you see, I would like to have the records, where there is pro weber, artnr, varnr, lfdnr_kal and invnr more than one row with the same min and lst/h value.
I guess, I should use cound (maybe having count) and group by. But how?
In the example, I haven't marked all the rows.
Add group by and having to get the duplicate rows
GROUP BY weber, t1.artnr, t1.varnr, t1.lfdnr_kal, fert.invnr, fert.min, fert.[lst/h]
having count(*) >1
Try below SQL : As you didnt mention sum or AVG values i guess distinct records will solve your problem.
select weber, a.artnr,a.varnr, a.lfdnr_kal, a.invnr, a.min, a.lst_h
(
SELECT weber, t1.artnr, t1.varnr, t1.lfdnr_kal, fert.invnr, fert.min, fert.[lst/h] as lst_h FROM (
SELECT stammdat.weber, lackzahlen.artnr, lackzahlen.varnr, first(stammdat.[lfdnr-kal]) AS lfdnr_kal
FROM lackzahlen LEFT JOIN stammdat ON (lackzahlen.artnr=cstr(IIf(stammdat.artnr Is Null,'',cstr(stammdat.artnr)))) AND (lackzahlen.varnr=cstr(IIf(stammdat.varnr Is Null,'',cstr(stammdat.varnr))))
GROUP BY lackzahlen.artnr, lackzahlen.varnr, io_stkzahl, weber) AS t1
LEFT JOIN fert ON (t1.lfdnr_kal=fert.[lfdnr-kal]) AND (t1.artnr=cstr(iif(fert.artnr Is Null,'',cstr(fert.artnr)))) WHERE fert.invnr IN ('338902', 'R20000')
) a group by weber, a.artnr,a.varnr, a.lfdnr_kal, a.invnr, a.min, a.lst_h
Having count(*) > 1
Hope this helps :)
Related
I need to add a column with the content of this query :
SELECT COUNT(*) FROM account_subscriptiongroups WHERE account_subscriptiongroups.active = true AND account_subscriptiongroups.user_id = account_user.id
to this query :
SELECT
account_user.id as user_id, account_user.email, account_user.first_name, account_user.last_name, account_user.phone,
account_subscriptiongroup.id as sub_group_id,
account_adminaction.description,
account_adminaction.id as admin_action_id,
account_adminaction.created_on as subscription_ended_on
FROM
account_adminaction
LEFT JOIN
account_user ON account_user.id = account_adminaction.user_id
LEFT JOIN
account_subscriptiongroup ON account_adminaction.sub_group_id = account_subscriptiongroup.id
WHERE
account_adminaction.created_on >= '2021-04-07' AND account_adminaction.created_on <= '2021-04-13' AND
((account_adminaction.description LIKE 'Arrêt de l''abonnement%') OR (account_adminaction.description LIKE 'L''utilisateur a arrêté%'))
ORDER BY
subscription_ended_on
I tried adding a LEFT JOIN like that:
LEFT JOIN
account_subscriptiongroup all_sg ON account_user.id = account_subscriptiongroup.user_id
with this line in my WHERE statement :
AND all_sg.active = true
and this line in my SELECT :
COUNT(all_sg.id)
but I get an error :
ERROR: column "account_user.id" must appear in the GROUP BY clause or be used in an aggregate function
LINE 2: account_user.id as user_id, account_user.email, account_us...
^
I don't understand how I could perform this action properly
To count something, you need to specify a group where that count applies.
So every column that you select (and is not used in an aggregate function, like COUNT or SUM), you need to mention in the GROUP BY clause.
Or to put it the other way around: the non-aggregate columns must apply to all rows that are contained in that particular COUNT.
So between the WHERE and ORDER BY clauses, add a GROUP BY clause:
GROUP BY account_user.id, account_user.email, account_user.first_name, account_user.last_name, account_user.phone,
account_subscriptiongroup.id,
account_adminaction.description,
account_adminaction.id,
account_adminaction.created_on
If, on the other hand, you want a count from a different table, you can add a sub-select:
SELECT
account_user.id as user_id, account_user.email, account_user.first_name, account_user.last_name, account_user.phone,
account_subscriptiongroup.id as sub_group_id,
account_adminaction.description,
account_adminaction.id as admin_action_id,
account_adminaction.created_on as subscription_ended_on,
(SELECT COUNT(*)
FROM account_subscriptiongroups
WHERE account_subscriptiongroups.active = true
AND account_subscriptiongroups.user_id = account_user.id) AS groupcount
FROM
account_adminaction
LEFT JOIN
account_user ON account_user.id = account_adminaction.user_id
You can left join to to a derived table that does the grouping and counting:
SELECT au.id as user_id, au.email, au.first_name, au.last_name, au.phone,
asg.id as sub_group_id,
ad.description,
ad.id as admin_action_id,
ad.created_on as subscription_ended_on,
asgc.num_groups
FROM account_adminaction ad
LEFT JOIN account_user au ON au.id = ad.user_id
LEFT JOIN account_subscriptiongroups asg on ON ad.sub_group_id = asg.id
LEFT JOIN (
SELECT user_id, count(*) as num_groups
FROM account_subscriptiongroups ag
WHERE ag.active
GROUP by user_id
) asgc on asgc.user_id = au.id
WHERE ad.created_on >= '2021-04-07'
AND ad.created_on <= '2021-04-13'
AND ((ad.description LIKE 'Arrêt de l''abonnement%') OR (ad.description LIKE 'L''utilisateur a arrêté%'))
ORDER BY subscription_ended_on
It's not entirely clear to me, what you are trying to count, but another option (most probably slower) could be to use a window function combined with a filter clause:
count(*) filter (where asg.active) over (partition by asg.user_id) as num_groups
EDIT: my answer is the same as submitted by a_horse_with_no_name
Two answers, a literal one just solving the problem you posed, and then another one questioning whether what you asked for is really what you want.
Simple answer: modify your desired query to add user_id to the Select and remove user_id from the Where clause. Now you have a table that can be left-joined to the rest of your larger query.
...
Left Join (Select user_id, count(*) as total_count
From account_subscriptiongroup
Where account_subscriptiongroups.active = true
Group By user_id) Z
On Z.user_id=account_user.id
I question whether this count is what you really want here. This counts every account_subscriptiongroup entry for all time but only the active ones. Your larger query brings back inactive as well as active records, so if your goal is to create a denominator for a percentage, you are mixing 'apples and oranges' here.
If you decide you want a total by user of the records in your query instead, then you can add one more element to your larger query without adding any more tables. Use a windowing function like this:
Select ..., Sum(Case When account_subscriptiongroup.active Then 1 else 0 End) Over (Group By account_user.id) as total count
This just counts the records within the date range and having the desired actions.
Here is my query and I want to add the "count of SalID group by OFID" and store the result in the same table.
SELECT
T_OF.OFID,
T_OF.OFDateDPrev, T_OF.OFDateFPrev,
T_OF_User.OFUserID,
T_OF_User.SalID
INTO T_tracing
FROM T_OF
INNER JOIN T_OF_User
ON T_OF_User.OFID = T_OF.OFID
I tried this:
SELECT
T_OF.OFID,
T_OF.OFDateDPrev, T_OF.OFDateFPrev,
T_OF_User.OFUserID,
Count (SalID) FROM T_OF_User GROUP BY OFID
INTO T_tracing
FROM T_OF
INNER JOIN T_OF_User
ON T_OF_User.OFID = T_OF.OFID
But I have an error message. Any help please?
I think you want a window function:
SELECT T_OF.OFID, T_OF.OFDateDPrev, T_OF.OFDateFPrev, T_OF_User.OFUserID,
Count(SalID) OVER (PARTITION BY T_OF.OFID) as cnt
INTO T_tracing
FROM T_OF JOIN
T_OF_User
ON T_OF_User.OFID = T_OF.OFID;
You also need to give the result of the expression a name for T_Tracing.
I am getting an error saying that I cannot use Top 10 with distinct I am wondering if there is any way I can get my query to work on that fashion. this is what the error is saying .
[Teradata Database] [6916] TOP N Syntax error: Top N option is not supported with DISTINCT option.
Query Below:
Thank you.
Select Distinct TOP 10 t1.Adjustment_ID, t1.OfficeNum, t1.InvoiceNum, t1.PatientNum,
t1.CurrentStatus, t1.AdjustmentTotal, t1.SubmittedOn, t1.UserSubmitted,
t1.Invoice_Type, t1.Pat_First_Name, t1.Pat_Last_Name,t2.Reason_Code FROM App_UnityAdj_AdjInfo_Tbl t1
Left Join RCM_WORK_PRD.App_UnityAdj_AdjRecord_Tbl t2
On t1.Adjustment_ID = t2.Adjustment_ID
Where t1.UserSubmitted = 'Name' AND (t1.CurrentStatus = 'Pending' OR t1.CurrentStatus = 'Deny')
What are you trying to do? You have columns in the SELECT that are not in the GROUP BY. You also have TOP without ORDER BY, which is suspicious.
One simple method is to move all the SELECT columns to the GROUP BY:
select TOP 10 t1.Adjustment_ID, t1.OfficeNum, t1.InvoiceNum, t1.PatientNum,
t1.CurrentStatus, t1.AdjustmentTotal, t1.SubmittedOn, t1.UserSubmitted,
t1.Invoice_Type, t1.Pat_First_Name, t1.Pat_Last_Name, t2.Reason_Code
from App_UnityAdj_AdjInfo_Tbl t1 Left Join
RCM_WORK_PRD.App_UnityAdj_AdjRecord_Tbl t2
On t1.Adjustment_ID = t2.Adjustment_ID
where t1.UserSubmitted = 'Name' AND
t1.CurrentStatus in ('Pending', 'Deny')
group by t1.Adjustment_ID, t1.OfficeNum, t1.InvoiceNum, t1.PatientNum,
t1.CurrentStatus, t1.AdjustmentTotal, t1.SubmittedOn, t1.UserSubmitted,
t1.Invoice_Type, t1.Pat_First_Name, t1.Pat_Last_Name,t2.Reason_Code;
I think I figured it out, in case anyone wants to know it is sample 10
Select Distinct t1.Adjustment_ID, t1.OfficeNum, t1.InvoiceNum, t1.PatientNum,
t1.CurrentStatus, t1.AdjustmentTotal, t1.SubmittedOn, t1.UserSubmitted,
t1.Invoice_Type, t1.Pat_First_Name, t1.Pat_Last_Name,t2.Reason_Code FROM App_UnityAdj_AdjInfo_Tbl t1
Left Join RCM_WORK_PRD.App_UnityAdj_AdjRecord_Tbl t2
On t1.Adjustment_ID = t2.Adjustment_ID
Where t1.AssignedTo IS null AND (t1.CurrentStatus = 'Pending')
sample 10
I have the following SQL query:
SELECT VehicleRegistrations.ID, VehicleRegistrations.VehicleReg,
VehicleRegistrations.Phone, VehicleType.VehicleTypeDescription,
dt.ID AS 'CostID', dt.IVehHire, dt.FixedCostPerYear, dt.VehicleParts,
dt.MaintenancePerMile, dt.DateEffective
FROM VehicleRegistrations
INNER JOIN VehicleType ON VehicleRegistrations.VehicleType = VehicleType.ID
LEFT OUTER JOIN (SELECT TOP (1) ID, VehicleRegID, DateEffective, IVehHire,
FixedCostPerYear, VehicleParts, MaintenancePerMile
FROM VehicleFixedCosts
WHERE (DateEffective <= GETDATE())
ORDER BY DateEffective DESC) AS dt
ON dt.VehicleRegID = VehicleRegistrations.ID
What I basically want to do is always select the top 1 record from the 'VehicleFixedCosts' table, where the VehicleRegID matches the one in the main query. What is happening here is that it's selecting the top row before the join, so if the vehicle registration of the top row doesn't match the one we're joining to it returns nothing.
Any ideas? I really don't want to have use subselects for each of the columns I need to return
Try this:
SELECT vr.ID, vr.VehicleReg,
vr.Phone, VehicleType.VehicleTypeDescription,
dt.ID AS 'CostID', dt.IVehHire, dt.FixedCostPerYear, dt.VehicleParts,
dt.MaintenancePerMile, dt.DateEffective
FROM VehicleRegistrations vr
INNER JOIN VehicleType ON vr.VehicleType = VehicleType.ID
LEFT OUTER JOIN (
SELECT ID, VehicleRegID, DateEffective, IVehHire, FixedCostPerYear, VehicleParts, MaintenancePerMile
FROM VehicleFixedCosts vfc
JOIN (
select VehicleRegID, max(DateEffective) as DateEffective
from VehicleFixedCosts
where DateEffective <= getdate()
group by VehicleRegID
) t ON vfc.VehicleRegID = t.VehicleRegID and vfc.DateEffective = t.DateEffective
) AS dt
ON dt.VehicleRegID = vr.ID
Subquery underneath dt might need some grouping but without schema (and maybe sample data) it's hard to say which column should be involved in that.
My problem is I want to apply distinct key word on just one column in select statement.
Here is my sql query.
SELECT ARM.AppId,
ARM.AppFirstName,
ARM.AppLastName,
AQD.QualiId,
VacQualiDetail.QualiName,
VacQualiDetail.VacID,
ARM.TotalExpYear,
ARM.TotalExpMonth,
VacQualiDetail.VacTitle,
VacQualiDetail.DeptId,
VacQualiDetail.CompId
FROM tblAppResumeMaster ARM,
tblAppQualificationDetail AQD,
(SELECT VM.VacID,
VM.VacTitle,
VM.CompId,
VM.DeptId,
vcd.QualificationID,
QM.QualiName,
VM.RequiredExperience as Expe
FROM tblVacancyCriteriaDetail VCD,
tblVacancyMaster VM,
tblQualificationMaster QM
WHERE VCD.VacID = VM.VacID
AND VCD.QualificationID = QM.QualificationId) as VacQualiDetail
WHERE AQD.AppId = arm.AppId
AND aqd.QualiId = VacQualiDetail.QualificationID
AND ARM.TotalExpYear >= Expe
In this query, ARM.AppId is repeated and I want to apply distinct keyworld on ARM.AppId
How can I achieve my goal?
example use 2 or more SELECT DISTICT:
SELECT DISTINCT ARM.AppId,
(SELECT DISTINCT ARM.AppFirstName) AS name
FROM ..............
if data database repeated,
according me the relation of each table is wrong.
please show the structure of the table
select distinct ARM.AppId, ARM.AppFirstName .....