running a SQL query in access that is giving me matches where A = record 1, and B also = record 1 , C= record 2 and D E and F also = record 2.
I want my results to display (only max Value)
B =record 1
F= record 2. ( this is a matching query)
basically i want to eliminate duplicates and select "distinct" does not seem to be working for me.
SELECT
FEED_2.ID AS FEED_2_ID,
FEED_3.field_ID,
FEED_3.ID AS FEED_3_ID
FROM FEED_2 INNER JOIN FEED_3 ON FEED_2.[field_ID] = FEED_3.[field_ID]
order by FEED_3.ID
im getting results where feed 2 ID #1,3, and 5 all equal feed 3 - ID #1
i only want feed 2, #5 = feed 3 #1. no Dupes
sorry - hope that helps
It's a shot in the dark but, is something like this you are looking for?
SELECT max(Column_With_ABCDEF), Column_With_record from TABLE_NAME GROUP BY Column_With_record;
If this is not what you are asking for, please do edit your question with your table schema and/or the query you are using so we can help.
---------------- EDIT ----------------
Ok so you can try this:
Select max(FEED_2_ID), field_ID , FEED_3_ID
from (
SELECT FEED_2.ID AS FEED_2_ID, FEED_3.field_ID As field_ID, FEED_3.ID AS FEED_3_ID
FROM FEED_2 INNER JOIN FEED_3
ON FEED_2.[field_ID] = FEED_3.[field_ID]
)
GROUP BY FEED_3_ID, field_ID
ORDER BY FEED_3_ID
The main select is going to group the result from the subquery, that way you should not get duplicated values.
Hope this help
Related
I have a query I am using IN operator and I want all the rows from in given list as shown in the picture that I want 3 rows for id 1 and one for id 2, but I only get one row for Id = 1 is there any other solution for this.
IN can't do what you want. JOIN instead:
select * from logs
JOIN (values (1),(2),(1),(1)) x (id)
ON logs.id = x.id
I have a simple inline view that contains 2 columns.
-----------------
rn | val
-----------------
0 | A
... | ...
25 | Z
I am trying to select a val by matching the rn randomly by using the dbms_random.value() method as in
with d (rn, val) as
(
select level-1, chr(64+level) from dual connect by level <= 26
)
select * from d
where rn = floor(dbms_random.value()*25)
;
My expectation is it should return one row only without failing.
But now and then I get multiple rows returned or no rows at all.
on the other hand,
>>select floor(dbms_random.value()*25) from dual connect by level <1000
returns a whole number for each row and I failed to see any abnormality.
What am I missing here?
The problem is that the random value is recalculated for each row. So, you might get two random values that match the value -- or go through all the values and never get a hit.
One way to get around this is:
select d.*
from (select d.*
from d
order by dbms_random.value()
) d
where rownum = 1;
There are more efficient ways to calculate a random number, but this is intended to be a simple modification to your existing query.
You also might want to ask another question. This question starts with a description of a table that is not used, and then the question is about a query that doesn't use the table. Ask another question, describing the table and the real problem you are having -- along with sample data and desired results.
I just joined after having a problem writing a query in MS Access. I am trying to write a query that will pull out the first two valid samples in from a list of replicated sample results and then would like to average the sample values. I have written a query that does pull samples with only two valid samples and averages these values. However, my query doesn't pull samples where there are more than two valid sample results. Here's my query:
SELECT temp_platevalid_table.samp_name AS samp_name, avg (temp_platevalid_table.mean_conc) AS fin_avg, count(temp_platevalid_table.samp_valid) AS sample_count
FROM Temp_PlateValid_table
WHERE (Temp_PlateValid_table.id In (SELECT TOP 2 S.id
FROM Temp_PlateValid_table as S
WHERE S.samp_name = S.samp_name and s.samp_valid=1 and S.samp_valid=1
ORDER BY ID))
GROUP BY Temp_PlateValid_table.samp_name
HAVING ((Count(Temp_PlateValid_table.samp_valid))=2)
ORDER BY Temp_PlateValid_table.samp_name;
Here's an example of what I'm trying to do:
ID Samp_Name Samp_Valid Mean_Conc
1 54d2d2 1 15
2 54d2d2 1 20
3 54d2d2 1 25
The average mean_conc should be 17.5, however, with my current query, I wouldn't receive a value at all for 54d2d2. Is there a way to tweak my query so that I get a value for samples that have more than two valid values? Please note that I'm using MS Access, so I don't think I can use fancier SQL code (partition by, etc.).
Thanks in advance for your help!
Is this what you want?
select pv.samp_name, avg(pv.value_conc)
from Temp_PlateValid_table pv
where pv.samp_valid = 1 and
pv.id in (select top 2 id
from Temp_PlateValid_table as pv2
where pv2.samp_name = pv.samp_name and pv2.samp_valid = 1
)
group by pv.samp_name;
You might need avg(pv.value_conc * 1.0).
I had a built a query previously that returned zero duplicates until I decided to join in a couple more tables. Now that I've joined them in, I'm unable to create the desired flag due to duplicates being returned. I've attached the scenario below as an example.
I only want one occurrence of each reference number (123456789). I want to create a flag when certain criteria are met. For example, I want to see when reference numbers for a certain account meet "X", but when I join the table I get every instance of that reference number in the joined table.
REFNO BEG END STATUS
123456789 123 456 E
123456789 456 789 E
123456789 789 012 A
I want to see all of the REFNO's based on other parameters set in the query, but I want a flag for anything where END = '012'. I can't left join to the table because I will get all three lines. If I do an inner join then I just get the 012 lines. I Tried the code below in my select statement to only pull when that scenario exists, but I'm getting wacky returns and don't know why. I feel like this should be fairly easy to accomplish, but I can't wrap my head around how to create a flag for just that scenario without getting duplicates or removing results with an inner join.
,(CASE WHEN EXISTS(SELECT 1
FROM QW.ABCD Z
WHERE Z.ABCD = P.ABCD
AND Z.END = '012'
AND Z.TIMESTAMP IS NULL
AND Z.STATUS IN ('A','E'))
THEN 'Y' ELSE 'N'
END)
AS "FLAG"
Please help as I'm not sure what I'm doing wrong to get the flag I want to see.
I am not sure id DB2 allows this combination of UNION and GROUP BY, but what you want is probably something like this:
SELECT 'N' AS FLAG, REF_NO,MIN(BEG),MAX(THEEND) FROM TAB_QW A
WHERE NOT EXIST (SELECT * FROM TAB_QW B WHERE B.REF_NO = A.REF_NO AND B.THEEND = '012')
GROUP BY REF_NO
UNION
SELECT 'Y' AS FLAG, REF_NO,MIN(BEG),MAX(THEEND) FROM TAB_QW C
WHERE EXISTS (SELECT * FROM TAB_QW D WHERE D.REF_NO = C.REF_NO AND D.THEEND = '012')
GROUP BY REF_NO
I have a table that looks like this:
Column A | Column B | Counter
---------------------------------------------
A | B | 53
B | C | 23
A | D | 11
C | B | 22
I need to remove the last row because it's cyclic to the second row. Can't seem to figure out how to do it.
EDIT
There is an indexed date field. This is for Sankey diagram. The data in the sample table is actually the result of a query. The underlying table has:
date | source node | target node | path count
The query to build the table is:
SELECT source_node, target_node, COUNT(1)
FROM sankey_table
WHERE TO_CHAR(data_date, 'yyyy-mm-dd')='2013-08-19'
GROUP BY source_node, target_node
In the sample, the last row C to B is going backwards and I need to ignore it or the Sankey won't display. I need to only show forward path.
Removing all edges from your graph where the tuple (source_node, target_node) is not ordered alphabetically and the symmetric row exists should give you what you want:
DELETE
FROM sankey_table t1
WHERE source_node > target_node
AND EXISTS (
SELECT NULL from sankey_table t2
WHERE t2.source_node = t1.target_node
AND t2.target_node = t1.source_node)
If you don't want to DELETE them, just use this WHERE clause in your query for generating the input for the diagram.
If you can adjust how your table is populated, you can change the query you're using to only retrieve the values for the first direction (for that date) in the first place, with a little bit an analytic manipulation:
SELECT source_node, target_node, counter FROM (
SELECT source_node,
target_node,
COUNT(*) OVER (PARTITION BY source_node, target_node) AS counter,
RANK () OVER (PARTITION BY GREATEST(source_node, target_node),
LEAST(source_node, target_node), TRUNC(data_date)
ORDER BY data_date) AS rnk
FROM sankey_table
WHERE TO_CHAR(data_date, 'yyyy-mm-dd')='2013-08-19'
)
WHERE rnk = 1;
The inner query gets the same data you collect now but adds a ranking column, which will be 1 for the first row for any source/target pair in any order for a given day. The outer query then just ignores everything else.
This might be a candidate for a materialised view if you're truncating and repopulating it daily.
If you can't change your intermediate table but can still see the underlying table you could join back to it using the same kind of idea; assuming the table you're querying from is called sankey_agg_table:
SELECT sat.source_node, sat.target_node, sat.counter
FROM sankey_agg_table sat
JOIN (SELECT source_node, target_node,
RANK () OVER (PARTITION BY GREATEST(source_node, target_node),
LEAST(source_node, target_node), TRUNC(data_date)
ORDER BY data_date) AS rnk
FROM sankey_table) st
ON st.source_node = sat.source_node
AND st.target_node = sat.target_node
AND st.rnk = 1;
SQL Fiddle demos.
DELETE FROM yourTable
where [Column A]='C'
given that these are all your rows
EDIT
I would recommend that you clean up your source data if you can, i.e. delete the rows that you call backwards, if those rows are incorrect as you state in your comments.