According this answer
https://stackoverflow.com/a/18726682/2674303
I see that I can add property to node in crxde. But I don't understand how can I add multivalue property(array) to node.
Please, help.
You have to create an array of values:
ValueFactory valueFactory = session.getValueFactory();
Node node = session.getNode("/content/path/to/my/node");
Value[] values = new Value[3];
values[0] = valueFactory.createValue("First value");
values[1] = valueFactory.createValue("Second value");
values[2] = valueFactory.createValue("Third value");
node.setProperty("propertyName", values);
alternatively, you may use a String array:
node.setProperty("propertyName", new String[] {"First value", "Second value", "Third value"});
Related
I have following Code where i will receive list of names as parameter.In the loop, first i'm assigning index 0 value from list to local variable name. There after comparing next values from list with name. If we receive any non-equal value from list, i'm assigning value of result as 1 and failing the test case.
Below is the Array list
List<String> names= new ArrayList<String>();
names.add("John");
names.add("Mark");
Below is my selenium test method
public void test(List<String> names)
String name=null;
int a=0;
for(String value:names){
if(name==null){
System.out.println("Value is null");
name=value;
}
else if(name.equals(value)){
System.out.println("Received Same name");
name=value;
}
else{
a=1;
Assert.fail("Received different name in between");
}
}
How can i convert above code into lambda expressions?. I'm using cucumber data model, hence i receive data as list from feature file. Since i can't give clear explanation, just posted the example logic i need to convert to lambda expression.
Here's the solution: it cycles all element in your list checking if are all the same.
You can try adding or editing the list so you can have different outputs. I've written the logic, you can easly put it into a JUnit test
List<String> names= new ArrayList<>();
names.add("John");
names.add("Mark");
String firstEntry = names.get(0);
boolean allMatch = names.stream().allMatch(name -> firstEntry.equals(name));
System.out.println("All names are the same: "+allMatch);
Are you looking for duplicates, whenever you have distinct value , set a=1 and say assert to fail. You can achieve this by :
List<String> names= new ArrayList<String>();
names.add("John");
names.add("Mark");
if (names.stream().distinct().limit(2).count() > 1) {
a= 1,
Assert.fail("Received different name in between");
} else {
System.out.println("Received Same name");
}
How do I write a filter which will compare Mylist-values to MyKeyTable-values?
I tried something like the following:
List<string> Mylist = new List<string>();
Mylist.Add("Welcome");
Mylist.Add("Hello");
var output = await client.For<MyKeyTable>()
//this is wrong I knew I need to correct this
.Filter(Mylist.Contains(x=>x.Key))
.FindEntriesAsync();
So output will come with all the values whoes Key-value matches as welcome and hello
Thanks in advance.
Done I tried it using custom expression
ParameterExpression pe = Expression.Parameter(typeof(MyTableClass), "entity");
Expression expression = null;
Expression predicateBody = null;
Expression leftExpression = Expression.Property(pe, "Key");
Expression rightExpression = Expression.Constant("Welcome");
expression = Expression.Equal(leftExpression, rightExpression);
predicateBody = predicateBody == null
? expression
: Expression.OrElse(predicateBody, expression);
I have a doc like the following:
as you can see I have an array entity: {1,3,4}
Now I want to just change 4 to 10 in that array and update it for that I have the following code:
DBCollection coll = db.getCollection("test");
BasicDBObject newDocument = new BasicDBObject();
BasicDBObject searchQuery = new BasicDBObject().append("time", "20141105230000");
coll.update(searchQuery, newDocument);
String[] str = { "1", "3", "10" };
DBObject updateMatchingElem = new BasicDBObject("$set",
new BasicDBObject().append("entity", str));
coll.update(searchQuery, updateMatchingElem);
But this way is not a good way because I kind of remove entity and then insert the whole array again. Is there anyway that I can just change the one element like 4 to 10?
Now I want to just change 4 to 10 in that array and update it
You can do it in the following way, using the $ positional operator.
//db.collection.update({"entity":4},{$set:{"entity.$":10}})
DBObject find = new BasicDBObject( "entity", 4);
DBObject set = new BasicDBObject( "entity.$", 10);
DBObject update = new BasicDBObject().append("$set", set);
coll.update(find, update);
Note that you can at most update only one single matching array element, even if there are other matching elements in the array. For instance, if there are two 4s in the array, only the first occurrence of 4 will get updated. This is how the positional operator works.
Whenever you use the positional operator in the update query, the find query must contain the field in the find part of the query.
In Java, and many other languages, one can grab a subsection of a string by saying something like String.substring(begin, end). My question is, Does there exist a built-in capability to do the same with Lists in Java that returns a sublist from the original?
This method is called subList and exists for both array and linked lists. Beware that the list it returns is backed by the existing list so updating the original one will update the slice.
The answer can be found in the List API: List#subList(int, int) (can't figure out how to get the link working....)
Be warned, though, that this is a view of the underlying list, so if you change the original list, you'll change the sublist, and the semantics of the sublist is undefined if you structurally modify the original list. So I suppose it isn't strictly what you're looking for...
If you want a structurally independent subsection of the list, I believe you'll have to do something like:
ArrayList<something> copy = new ArrayList<>(oldList.subsection(begin, end));
However, this will retain references to the original objects in the sublist. You'll probably have to manually clone everything if you want a completely new list.
The method is called sublist and can be found here in the javadocs
http://docs.oracle.com/javase/7/docs/api/java/util/ArrayList.html#subList(int, int)
You can use subList(start, end)
ArrayList<String> arrl = new ArrayList<String>();
//adding elements to the end
arrl.add("First");
arrl.add("Second");
arrl.add("Third");
arrl.add("Random");
arrl.add("Click");
System.out.println("Actual ArrayList:"+arrl);
List<String> list = arrl.subList(2, 4);
System.out.println("Sub List: "+list);
Ouput :
Actual ArrayList:[First, Second, Third, Random, Click]
Sub List: [Third, Random]
You might just want to make a new method if you want it to be exactly like substring is to String.
public static List<String> sub(List<String> strs, int start, int end) {
List<String> ret = new ArrayList<>(); //Make a new empty ArrayList with String values
for (int i = start; i < end; i++) { //From start inclusive to end exclusive
ret.add(strs.get(i)); //Append the value of strs at the current index to the end of ret
}
return ret;
}
public static List<String> sub(List<String> strs, int start) {
List<String> ret = new ArrayList<>(); //Make a new empty ArrayList with String values
for (int i = start; i < strs.size(); i++) { //From start inclusive to the end of strs
ret.add(strs.get(i)); //Append the value of strs at the current index to the end of ret
}
return ret;
}
If myStrings is an ArrayList of the following Strings: {"do","you","really","think","I","am","addicted","to","coding"}, then sub(myStrings,1,6) would return {"you", "really", "think", "I", "am"} and sub(myStrings,4) would return {"I", "am", "addicted", "to", "coding"}. Also by doing sub(myStrings, 0) it would rewrite myStrings as a new ArrayList which could help with referencing problems.
Need help in getting the string[] values of node property??
for example I have a node image which has property "references" of type String[] . I need to get the first value of array.
Thanks
From the Node, you can get the references property. And then call getValues to the reference values. From there, just take the first. Something like
public String getFirstReference(Node node) throws RepositoryException {
Property references = node.getProperty("references");
Value[] values = references.getValues();
return values[0].getString();
}
Property nProp = node.getProperty("references");
Value[] values = propertyNode.getValues();
for (Value v : values) {
System.out.println("Property Name = "+nProp.getName()+" ; Property Value= "+v.getString());
}