I am not able to click on 'Albums' in Facebook.
The HTML is Albums how to locate the element 'Albums' in selenium web driver.
I tried with using driver.findelement(By.xpath(span[#class="_3sz"]) showing error as element not found
And, the html looks the following:
<span class="_3sz">Albums</span>
If I am understanding your problem correctly then that xpath you mentioned returns more than one elements. Use a text based search which is more easier and specific.
driver.findelement(By.xpath("//*[.='Albums']").click();
And, here . is used to directly point to the parent element. Additional wait might be needed to wait for the element to interact. Also, I am assuming you are trying to click the element.
EDIT
Driver = new ChromeDriver();
WebDriverWait wait = new WebDriverWait(Driver, TimeSpan.FromSeconds(10));
Driver.Navigate().GoToUrl("http://www.facebook.com");
Driver.Manage().Window.Maximize();
Driver.FindElement(By.CssSelector("#email")).SendKeys("your email");
Driver.FindElement(By.CssSelector("#pass")).SendKeys("your pass");
Driver.FindElement(By.CssSelector("[type='submit'][value='Log In']")).Click();
Driver.FindElement(By.CssSelector(".fbxWelcomeBoxName")).Click();
Driver.FindElement(By.XPath("//*[.='Photos']")).Click();
wait.Until(ExpectedConditions.ElementIsVisible(By.XPath("//*[.='Albums']")));
Driver.FindElement(By.XPath("//*[.='Albums']")).Click();
By albumname = By.XPath("//strong[.='2014']"); //this should be your album name. In my case it's 2014
wait.Until(ExpectedConditions.ElementExists(albumname));
Driver.FindElement(albumname).Click();
wait.Until(ExpectedConditions.ElementExists(By.CssSelector(".fbPhotoAlbumHeader.fbPhotoAlbumOptionsPresent [type='file']")));
Driver.FindElement(By.CssSelector(".fbPhotoAlbumHeader.fbPhotoAlbumOptionsPresent [type='file']")).SendKeys(#"D:\Users\Saifur\Desktop\FacebookPicture\150232_585410621540701_1836495431_a.jpg");
wait.Until(ExpectedConditions.ElementExists(By.CssSelector(".pvm.phl.footerBox.uiBoxWhite")));
Driver.SwitchTo().ActiveElement();
wait.Until(ExpectedConditions.ElementExists(By.CssSelector("[name='postPhotosButton']")));
Driver.FindElement(By.CssSelector("[name='postPhotosButton']")).Click();
Notice mine is C#
It always best practice to follow this sequence while selecting elements.
1) ID
2) CSS
3) XPath (This will have some issues with different browsers specially IE)
In this case, considering this is no other span class with same name. It would have work like this "span._3sz". Simple and powerful.
Related
I am facing an issue where I am unable to locate Element on webpage with any type of locator expect Absolute xpath. Here are details:
URL : https://semantic-ui.com/modules/dropdown.html#selection
Required Element Screen shot:
Manually created Xpath Screen shot( Please note that I am able to recognize Element in web application with manually created xpath but Same xpath is not working in selenium code)
But Same xpath is not working in selenium script.
PLEASE NOTE THAT I AM ABLE TO IDENTIFY SAME OBJECT WITH Absolute xpath
Please help to me to understand reason for this.
Here is code:
public static WebDriver driver;
public static void main(String[] args) {
driver= new FirefoxDriver();
driver.manage().window().maximize();
driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
driver.get("https://semantic-ui.com/modules/dropdown.html");
//Selection
driver.findElement(By.xpath("//div[#class='ui selection dropdown upward']")).click();
driver.findElement(By.xpath("//div[#class='menu transition visible']/div[text()='Female']")).click();
System.out.println("Done");
This may be issue with your first x-path. You may try the following code. It may work.
driver.findElement(By.xpath("//div[#class='ui selection dropdown']").click();
driver.findElement(By.xpath("//div[#class='menu transition visible']/div[text()='Male']").click();
You are missing a preceding wildcard in you driver.FindElement XPath.
Instead of driver.findElement(By.xpath("//div..."));, do driver.findElement(By.xpath("//*div..."));.
Currently, what your code is doing is telling the XPath locator to find a first level div (not easily possible, as the first item is almost always the document body), but the wildcard of "*" tells it that it can look for the div at any level.
As an aside, please edit your answer up top with actual code instead of pictures so others with the same problem can find their solution easier.
Longshot:
You are using Chrome to look at the source, but Selenium is using Firefox.
There is a chance that the source is rendered differently between the two browsers. Specifically, your xpath is relying on an exact match of class. I do know that FireFox is notorious for modifying source output.
I haven't done any testing but I would not be surprised if the class is in a different order and it's failing on an exact match.
There are two solutions if that is the case:
Don't do a single exact match (xpath = "") but instead do a mix of contains joined with && (contains ui && contains selection && dropdown)
Don't rely on the output from the console tab. Instead "View Page Source" and view what is actually being sent instead of what is being interpreted by the browser
Find the dropdown container element firstly, then use it to find self descendant, like option etc.
driver.get("https://semantic-ui.com/modules/dropdown.html");
// find dropdown container element
WebElement dropdownWrapper = driver.findElement(
By.xpath("//div[#class='html']/div[input[#name='gender']]"));
// expand drop down options by click on the container element
dropdownWrapper.click();
// or click the down arrow
dropdownWrapper.findElement(By.css('i')).click();
// select option
dropdownWrapper.findElement(By.xpath(".//div[text()='Female']")).click();
To locate the element with text as Gender and select the option Female you can use the following Locator Strategy :
Code Block :
System.setProperty("webdriver.chrome.driver", "C:\\path\\to\\geckodriver.exe");
WebDriver driver = new FirefoxDriver();
driver.get("https://semantic-ui.com/modules/dropdown.html#selection");
driver.findElement(By.xpath("//div[#class='another dropdown example']//div[#class='ui dropdown selection']")).click();
driver.findElement(By.xpath("//div[#class='another dropdown example']//div[#class='ui dropdown selection active visible']//div[#class='menu transition visible']//div[#class='item' and contains(.,'Female')]")).click();
System.out.println("Gender Female selected.");
Console Output :
Gender Female selected.
This might be helpful to clearify how selectors are working in general:
.(dot): Dot at starting represents the current node. It tells us that the processing will start from the current node.
. .(double dot): It will select parent of current node. For example, //table/. . will return div element because div is the parent of table element.
‘*’: is used to select all the element nodes descending from the current node. For example:
/table/*: It will select all child elements of a table element.
//*: It will select all elements in the document.
//*[#id = ‘username’]: It will select any element in document which has an attribute named “id” with the specified value “username”.
#: It represents an attribute which selects id, name, className, etc. For example:
#id: It will select all elements that are defined with the id attribute in the document. No matter where it is defined in the document.
//img/#alt: It will select all the img elements that are defined with the #alt attribute.
//td[#*]: It will select all td elements with any attribute.
Here is a link to the article:
https://www.scientecheasy.com/2020/07/selenium-xpath-example.html/
I trying to locate a link "Taschen" in the below code(<a data-flyout-target="handbags" title="Taschen" href="#">Taschen</a>) using selinium webdriver. Could anyone please guide me
<a data-flyout-target="handbags" title="Taschen" href="#">Taschen</a>
Here are your choices:
By.className
By.cssSelector
By.id
By.linkText
By.name
By.partialLinkText
By.tagName
By.xpath
So assuming that "Taschen" is partial link text
WebElement aLink = driver.findElement(By.partialLinkText("Taschen"));
If you haven't bothered with page loads and proper implicit waits then this might work better
WebDriverWait wait = new WebDriverWait(driver, 30);
WebElement aLink = wait.until(
ExpectedConditions.elementToBeClickable(By.partialLinkText("Taschen"))
);
aLink.click();
You are not using java? Update your question to show your code and add a language tag to your question. Your brain isn't a network connected device and we only know what you tell us. :-)
You can also use the XPath as below:-
//a[#title='Taschen']/text()
Code will be as below:-
WebElement tash = driver.findElement(By.xpath("Taschen"));
If you need to get the text then you can use :-
String tash = driver.findElement(By.xpath("Taschen")).getText();
You can also use the contains function in XPath
//a[contains(.,'Taschen')]
Hope it will help you :)
I am new to Selenium. Not sure how to handle this scenario. I am working on a website which has several buttons with following code,
<a class="Some big class name" datacommunication="SelectItem" token="some token number" model-id="Id1" element="button">
<i class="classname">Book Ticket</i>
</a>
<a class="Some big class name" datacommunication="SelectItem" token="some token number" model-id="Id2" element="button">
<i class="classname">Book Ticket</i>
</a>
I tried to click on it using following commands,
ele = driver.FindElement(By.ClassName("Some big class name")); but it fails with following message, Compound class names are not supported. Consider searching for one class name and filtering the results.
ele = driver.FindElement(By.CssSelector("a[model-id='Id1']")); fails with 'Test method TestBot.HomeTest.bookTicket threw exception:
OpenQA.Selenium.WebDriverTimeoutException: Timed out after 10 seconds'
Tried using XPATH,
ele = driver.FindElement(By.XPath("\\\a[#model-id='Id1']")); doesn't work either.
I have no control on html. Can't change it.
Please let me know how to identify elements in such scenarios.
You can't have spaces in class names. Those are actually multiple classes separated by a space. You can find the above elements using a css selector
var ele = driver.FindElements(By.CssSelector(".Some.big.class.name"))
Of course, this will find both elements. To find just the first, you could use
var ele = driver.FindElement(By.CssSelector("a[model-id='Id1']"))
You can find help on css selectors here: http://www.w3schools.com/cssref/css_selectors.asp
Update:
I just noticed your XPath appears to have the slashes the wrong way around. If you wish to use XPath, try
//a[#model-id='Id1']
Note, however, that css selectors perform better than XPath.
There are multiple number of ways to locate your WebElement in Selenium WebDriver.
But always remember all are based on you attribute or combination of HTML tags so case could be any of them
1- First way is using id
2- 2nd one is Name
3- Class Name
4- Some time you can used Tagname
5- Some time linkText
6- Some time partial link text
7- Using xpath
8- Using css selector
So in you case we need to take help of Xpath and Css Selector
So xpath of you elements
Syntax : //[#attribute ='value of selected tag']
Example
id1: //a[#model-id='Id1']
id2: //a[#model-id='Id2']
For both element following are the css Selector
Syntax [attribute ='value']
id1:
a[model-id='Id1']
id2:
a[model-id='Id2']
http://www.slideshare.net/weekendtesting/css-selector-29312437
http://www.slideshare.net/weekendtesting/locators-in-selenium-bnt-09
Thanks a lot for help. I have used following code to overcome above mentioned issue,
WebDriverWait wait = new WebDriverWait(driver, TimeSpan.FromSeconds(10));
wait.Until(ExpectedConditions.ElementIsVisible(By.CssSelector("a[data-model-id='c5']"))).Click();
With above code, I am able to click on the button.
Thanks again for your help and knowledge sharing.
Amit
You can locate by using xpath.
WebElement ele = driver.findElement(By.xpath("//*[#class='Some big class name']"));
there is difference between findElements and findElement.
FindElement: findElement returns a single element.
FindElements : returns a list of same element.As in this example there are multiple classes with same class name , so use driver.findElements method .
driver.findElements will return a list of all elements with that class name .
Now , you have list of all elements but you want only one of the element.
So iterate over list to get a single element out of a list.
List<WebElement> elementList= driver.FindElement(By.ClassName("Some.big.class.name"));
Iterator itr = elementList.iterator();
while(itr.hasNext())
{
WebElement element = itr.next();
if(element.getAttribute("model-id").equals("Id1")){
element.click();
break;
}//if block ends here
}//while loop ends here
You can also use XPATH , if nothing works
To identify the elements in selenium there are multiple ways.
To see the details please refer BY Class.
Try to find the way which can identify the element uniquely. Start with id if available and if nothing works go for XPATH. XPATH is slower than id and CSS selector.
I'm trying to navigate in site: http://startupnationbook.com/startup-map
I want to click on link of Startups, however I'm not able to locate the element.
I tried:
elem = driver.findElement(By.xpath("//a[contains(text(),'Startups')]"));
and
elem = driver.findElement(By.xpath("//*[#id='listtoggle' and contains(text(),'Startups')]"));
In both cases I get: "Unable to locate element" error
What is wrong in my expressions and how can I locate the element to perform a click.
The map is in an iframe, you're probably not telling Selenium to look in there. I would also look for the span tag, and since the id listtoggle is used many times (poor design, making it worthless), just look for contains Startups.
// Also should probably use a wait here, in case the page takes too long to load
chromeDriver.switchTo().frame(chromeDriver.findElement(By.tagName("iframe")));
WebElement elem = chromeDriver.findElement(By.xpath("//span[contains(text(),'Startups')]"));
You can do like below :
WebDriver driver = new FirefoxDriver();
driver.get("http://startupnationbook.com/");
driver.findElement(By.xpath(".//*[#id='main-nav']/li[5]/a")).click();
Hope this will work. I have tested.
I was working on reading mails from gmail using webdriver and in between I hit upon this difference between By.id and By.tagname.
I am trying to get access to a "table" whose id is ":pg". So I could
Either use By.id(":pg")
OR use By.tagname("table") and search for an element with id :pg
Here is the code for both cases.
By.id:
WebDriver webDriver = new FirefoxDriver();
webDriver.manage().timeouts().implicitlyWait(5, TimeUnit.SECONDS);
webDriver = webDriver.switchTo().frame("canvas_frame");
WebElement table1 = webDriver.findElement(By.id(":pg"));`
Above code, I directly get the element which has id ":pg"
By.tagname:
WebDriver webDriver = new FirefoxDriver();
webDriver.manage().timeouts().implicitlyWait(5, TimeUnit.SECONDS);
List<WebElement> tables = webDriver.findElements(By.tagName("table"));
for(WebElement table2: tables){
String id = table2.getAttribute("id");
System.out.println("id: "+ id);
if(id != null && id.equals(":pg")){
System.out.println("FOUND IT!!!");
}
}
Above code, I find all elements with the tagname of table and then see which one has the id ":pg".
Both these code snippets are essentially doing the same but using different ways(By.id or By.tagname). However, the first snippet of code which uses By.id always succeeds while the second snippet of code which uses By.tagname fails almost always. (It will work with additional waiting however)
Why is this difference between By.id and By.tagname?
Thanks,
Chris.
The :pg element is not present on the page initially.
Using By.Tag, selenium will not wait for the :pg element.
Because By.Id example is more specific, selenium will continue checking if the :pg element exists until the implicit wait (5 seconds) times out.
By.Tag is not specific at all. On findElements(By.tagName("table"), Selenium will return an array of all the tables that are present immediately after the page loads. As the :pg element is not present yet, it will not be in the array.
To answer your question, yes it is better to use By.Id because:
1. It is more specific.
2. Saves lines of code
3. Forces selenium to wait for the element to exist.
It is better to use By.Id according to your question.
By.tag is not used for specific data, it actually will search and return an array of all the tables with the specified tag name. On the other hand using id you can get the appropriate output for identifying/locating element.
Go for tag only if id, name or class is not specified and the best way can be By.cssSelector if no element is found.
Thanks