I have three tables Attendance, Employee, Sector
Employee Table
EmiId -Name -SectorId
123 ABC 1
231 BCD 2
125 WER 1
Attendance
AttId -EmpId -Dt
1 123 12/12/2014 9:00
2 231 12/12/2014 10:00
Sector
SectorId -SectorName
1 North Sector
2 East Sector
my query is
SELECT COUNT(Attendance.Emp_Id) as AttCount,(select COUNT(*) from Employee) as EmpCount
FROM Employee INNER JOIN
Sector ON Employee.SectorId = Sector.SectorId INNER JOIN
Attendance ON Employee.EmpId = Attendance.EmpId
group by Sector.SectorId
and i keep getting same number of employees for both instead so the (select COUNT(*) from Employee)- EmpCount seems to be incorrect.I keep getting the same number for both the sectors. Although the Attcount seems to work fine.
Please help. Thanks in advance.
You just making select count from the same table - do not expect other results.
Perhaps someone could do it better
SELECT COUNT(Attendance.Emp_Id),COUNT(case when Employee.empid=attendance.attid then 1 else 0 end)
FROM Employee JOIN Sector ON Employee.SectorId = Sector.SectorId
LEFT JOIN Attendance ON Employee.EmpId = Attendance.Emp_Id
group by Sector.SectorId
Maybe you need LEFT JOIN with Attendance
SELECT COUNT(Attendance.Emp_Id),(select COUNT(*) from Employee)
FROM Employee JOIN Sector ON Employee.SectorId = Sector.SectorId
LEFT JOIN Attendance ON Employee.EmpId = Attendance.EmpId
group by Sector.SectorId
Related
The objective of the query is get a count of employees absent under each manager.
Attendance (Dates when employees are present)
id date
1 16/05/2020
2 16/05/2020
1 17/05/2020
2 18/05/2020
3 18/05/2020
Employee
id manager_id
1 2
2 3
3 NA
The desired output should be in this format:
Date manager_id Number_of_absent_employees
16/05/2020 NA 1
17/05/2020 3 1
17/05/2020 NA 1
18/05/2020 2 1
I have tried writing code but partially understood it, intuition being calculating total number of actual employees under each manager and subtracting it from number of employees present on given day. Please help me in completing this query, many thanks!
with t1 as /* for counting total employees under each manager */
(
select employee.manager_id,count(*) as totalc
from employee as e
inner join employee on e.employee_id=employee.employee_id
group by employee.manager_id
)
,t2 as /* for counting total employees present each day */
(
select Attendence.date, employee.manager_id,count(*) as present
from employee
Left join Attendence on employee.employee_id=Attendence.employee_id
group by Attendence.date, employee.manager_id
)
select * from t2
Left join t1 on t2.manager_id=t1.manager_id
order by date
Cross join the distinct dates from Attendance to Employee and left join Attendance to filter out the matching rows.
The remaining rows are the absences so then you need to aggregate:
select d.date, e.manager_id,
count(*) Number_of_absent_employees
from (select distinct date from Attendance) d
cross join Employee e
left join Attendance a on a.date = d.date and a.id = e.id
where a.id is null
group by d.date, e.manager_id
See the demo.
Results:
| date | manager_id | Number_of_absent_employees |
| ---------- | ---------- | -------------------------- |
| 16/05/2020 | NA | 1 |
| 17/05/2020 | 3 | 1 |
| 17/05/2020 | NA | 1 |
| 18/05/2020 | 2 | 1 |
Try this query. In first cte just simplify your code. And in the last query calculate absent employees.
--in this CTE just simplify counting
with t1 as /* for counting total employees under each manager */
(
select employee.manager_id,count(*) as totalc
from employee
group by manager_id
)
,t2 as
(
select Attendence.date, employee.manager_id,count(*) as present
from employee
Left join Attendence on employee.employee_id=Attendence.employee_id
group by Attendence.date, employee.manager_id
)
select t2.date,t2.manager_id, (t1.totalc-t2.present) as employees_absent from t2
Left join t1 on t2.manager_id=t1.manager_id
order by date
Select ec.manager_id, date, (total_employees - employee_attended) as employees_absent from
(Select manager_id, count(id) as total_employees
from employee
group by manager_id) ec,
(Select distinct e.manager_id, a.date, count(a.id) over (partition by e.manager_id, a.date) as employee_attended
from Employee e, attendence, a
where e.id = a.id(+)) ea
where ec.manager_id = ea.manager_id (+)
I guess this should work
I have three tables: Customers, Receipts, Salary
Customers
Id Name
1 john
Receipts
Id Amount
1 500
2 250
3 600
4 700
Salary
Id Amount
1 300
2 300
3 680
Id like to find sum of salary and receipts related to john.
I thought it's simple sql statement like:
select cus.Name, sum(sal.Amount) as Salary, sum(re.Amount) as Recieved
from Customers as cus inner join Salaries as sal on cus.Id = sal.Id
inner join Receipts as re on cus.Id = re.Id
where cus.Id= 1
Group by cus.Name
but I found the result so bigger
Name Salary Recieved
john 6150 4320
When I write the query without sum:
select cus.Name, sal.Amount as Salary, re.Amount as Recieved
from Customers as cus inner join Salaries as sal on cus.Id = sal.Id
inner join Receipts as re on cus.Id = re.Id
where cus.Id= 1
I get these duplicate records
john 500 100
john 500 300
john 500 680
john 250 100
john 250 300
john 250 680
john 600 100
john 600 300
john 600 680
john 700 100
john 700 300
john 700 680
why the inner join behavior like this? I expect to get the records one time but it repeated 4 times!
Did I have to try sub-select queries?
The query looks right.
http://www.sqlfiddle.com/#!9/1b5157/1
There's a fiddle with your approximate query and it works as expected. So as the person before said, since you have CustomerOrSupplier, you might be joining to the wrong table
select cus.Name,
sum(sal.Amount) as Salary,
sum(re.Amount) as Recieved
from Customers as cus
inner join Salary as sal
on cus.Id = sal.Id
inner join
Receipts as re
on cus.Id = re.Id
Group by cus.Name;
Demo
http://sqlfiddle.com/#!18/956fb/10
I see that the issue happens to be one of the tables names.
Change the following:
from Customers as cus inner
join Salaries as sal
on cus.Id = sal.Id
to:
from Customers as cus inner
join Salary as sal
on cus.Id = sal.Id
hi i have problem in sql query example
Employee
empid empname
1 gan
2 sam
Designation
id desig empid
1 sr officerr 1
2 jr officer 1
3 manager 2
i want join tables and want Employee Table repeated records Null
result like
empid name desig id
1 gan sr officerr 1
1 NULL jr officer 2
2 sam manager 3
i working on query but i not getting result
SELECT DISTINCT designatin.empid, employee.empname,designatin.desig
FROM designatin INNER JOIN employee e ON employee.empid = designatin.empid
GROUP BY employee.empid, employee.empname, designatin.desig
can anybody have solution?
Change the inner join to a left join:
SELECT DISTINCT designatin.empid, employee.empname,designatin.desig
FROM designatin LEFT JOIN employee e ON employee.empid = designatin.empid
GROUP BY employee.empid, employee.empname, designatin.desig
Let try this, it will help you
SELECT e.empid, e.empname,d.desig ,d.id
FROM employee e
INNER JOIN Designation d ON e.empid = d.empid
See DEMO
good day, i have these 3 tables...i.e.;
customer table
cust_id cust_name sales_employee
1 abc 1
2 cde 1
3 efg 2
transaction table
order_num cust_id sales_employee
1001 1 1
1002 2 2
sales_employee table
sales_employee employee name
1 john doe
2 jane doe
how can i show the employee name on both customer table and transaction table?
notice how the sales_employee can change per transaction, it does not necessarily have to be the same per customer.
please help.
To select customers with sales person name
select
C.*, E.employee_name
from
Customers as C
inner join Sales_Employees as E on E.sales_employee = C.sales_employee
To select transactions with customer name and salesperson name (at the point in time of the transaction)
select
T.*,
E.employee_name as Trans_employee,
C.cust_name,
EC.employee_name as Cust_employee
from
Transactions as T
inner join Sales_Employees as E on E.sales_employee = T.sales_employee
inner join Customers as C on C.cust_id= T.cust_id
inner join Sales_Employees as EC on EC.sales_employee = C.sales_employee
This code is meant to guide you, you will need to adjust it to match your table and field names.
I have two tables, employee and inventory. One employee can have zero or more inventories.
I would like to list employee information along with at most one inventory information
and count of inventories belongs to one employee.
employee table
emp_num last_name first_name
-----------------------------------
100 john smith
101 mike pet
102 jes lyoid
inventory table
inv_num emp_num
---------------------------
12 100
13 100
15 100
30 102
desired Output
emp_num last_name invnum count(inv_num)
--------------------------------------------------------------------------
100 john 12 3
101 mike - 0
102 jes 30 1
What sql query can I use in this case?
Try this:
SELECT emp_num, last_name, MAX(inv_num) AS invnum, COUNT(inv_num) AS inv_count
FROM employee e LEFT OUTER JOIN inventory i ON e.emp_num = i.emp_num
GROUP BY e.emp_num, e.last_name
You could do something like this
Select E.Emp_Num,
e.Last_name,
MIN(Inv_Num) AS OldestInv,
COUNT(Inv_Num) AS TotalInv
FROM Employee E
LEFT OUTER JOIN Inventory I
(E.Emp_Num = I.Emp_Num)
GROUP BY E.Emp_Num, E.Last_Name
This will give you the minimum invoice number and the total count. The left outer join is the key
SELECT
e.emp_num,
e.last_name,
IFNULL(MAX(i.inv_num),'-') AS 'invnum',
COUNT(i.inv_num) AS 'count(inv_num)'
FROM
employee e LEFT JOIN inventory i
ON e.emp_num = i.emp_num
GROUP BY
e.emp_num, e.last_name