Distinct by comparing multiple columns SQL - sql

Question

I have a select query
Select col1,col2,col3
from table;
The table contains following rows
col1 col2 col3
A | B | C
B | A | C
C | B | C
I need to get the distinct result which contains a single combination A,B,C by comparing multiple columns.
Result Should be some thing like
col1 col2 col3
A | B | C
the order can be changed of result rows.
How can I achieve this ?

Answer 1

Please try out this, I am not sure about you proper requirement. But on sample data given above. I have came across this solution,
With CTE as
(
Select MIN(col1) as col1 from MyTable
)
Select * from CTE
cross apply
(
Select MIN(col2) as col2 from MyTable
where col2 <> CTE.col1
)as a
cross apply
(
Select MIN(col3) as col3 from MyTable
where col3 not in (CTE.col1,a.col2)
)as b
DEMO HERE

Answer 2

SELECT *
FROM table
WHERE (col1 = 'A' AND col2 = 'B' AND col3 = 'C')

Answer 3

You can also go with this below query if the number of column and the values are known.
The CASE statement is the closest to IF in SQL
SELECT
CASE
WHEN (col1 = 'A' and col2 = 'B' and col3='C') or (col1 = 'C' and col2 = 'A' and col3='B') or (col1 = 'B' and col2 = 'C' and col3='A' )
THEN 1
ELSE 0
END as RESULT, *
FROM table
From the result you can take the required output by checking the value of RESULT==1(integer)
If you want the result as a boolean value then do the CAST like ,
SELECT
CAST(
CASE
WHEN (col1 = 'A' and col2 = 'B' and col3='C') or (col1 = 'C' and col2 = 'A' and col3='B') or (col1 = 'B' and col2 = 'C' and col3='A' )
THEN 1
ELSE 0
END as RESULT_INT)
as RESUTL, *
FROM table