Overriding mixins in LESS - less

Question

when defining a mixin multiple times in LESS, and later calling that mixin as follows
.background-color() {
background: red;
}
.background-color() {
background: yellow;
}
body {
.background-color;
}
the result will be a combined output from all the defined mixins
body {
background: red; // << output from mixin #1
background: yellow; // << output from mixin #2
}
while when you apply the same scenario in both Sass & Stylus ( using their own syntax of course ), when you call a mixin that is defined multiple times across your stylesheets, Only the last defined one will be executed ( it will override all previously defined mixins ) as follows.
result Sass and Stylus
body {
background: yellow; // << output from mixin #2
}
how can I override a mixin in LESS so that the output will be from the last defined mixin ?

Answer 1

You can not override them, alternatively use a variable to define the 'background-color'. For Less variables the last declared win.
Also read Pattern-matching
In Less all matching mixins are compiled in the source. You can use namespace to prevent name collisions, for instance:
#ns1 {
.background-color() {
background: red;
}
}
#ns2 {
.background-color() {
background: yellow;
}
}
than you can use:
body {
#ns2 > .background-color;
}
Double properties are also not removed to make some browser hacks possible, example:
#myElement {
width: 300px;
width: 500px\9;
}
To find a solution for your use case you should reformulate your question and explain why you have these same named mixins in the first place.