Left Join Preserving NULL Records - sql

Question

Say I have these tables:
TableA TableB:
id name id name
-- ---- -- ----
1 Pirate 1 Rutabaga
2 Monkey 2 Pirate
3 Ninja 3 Darth Vader
4 Spaghetti 4 Ninja
When I Left Join I get the following:
SELECT * FROM TableA
LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
id name id name
-- ---- -- ----
1 Pirate 2 Pirate
2 Monkey null null
3 Ninja 4 Ninja
4 Spaghetti null null
But what I want is a different "Left Join" where I get the following:
id name id name
-- ---- -- ----
1 Pirate 2 Pirate
1 Pirate null null
2 Monkey null null
3 Ninja 4 Ninja
3 Ninja null null
4 Spaghetti null null
How would I get this augmented "Left Join" that returns null records for all left table entries along with the joined values?

Answer 1

It sounds to me like this is what you're looking for:
SELECT TableA.id, TableA.name, TableB.id, TableB.name
FROM TableA
INNER JOIN TableB
ON TableA.name = TableB.name
UNION
SELECT id, name, null, null
FROM TableA
Note that you don't need a LEFT JOIN in there because the second query obviates the need for doing that. You are asking for the INNER JOIN results plus records with TableA's data with just nulls for TableB's.

Answer 2

You would use union all. Of course, there is an issue with the ids. Something like this might work:
select row_number() over (order by (select NULL)) as id, name, bid, bname
from ((select a.id, a.name, b.id as bid, b.name as bname
from tableA a inner join
tableB b
on a.name = b.name
) union all
(select a.id, a.name, NULL, NULL
from tableA a
)
) ab;
This doesn't preserve the first id column. But then again, it is hard to say what that is for.
EDIT:
Actually, this might preserve it the way you want it:
select id, name, bid, bname
from ((select a.id, a.name, b.id as bid, b.name as bname
from tableA a inner join
tableB b
on a.name = b.name
) union all
(select a.id + (max(id) over ()), a.name, NULL, NULL
from tableA a
)
) ab;