I have a user table which contains among others money, level and ranking.
Id | money| ranking| level
---------------------------
1 |30000| 1 1
2 |20000| 2 3
3 |10000| 3 2
4 |50000| 4 2
I want to update the ranking field based on user level (first filter) and money.
That is a user in higher level will always be ranked higher.
That is i want the table after the update like this:
Id | money| ranking| level
---------------------------
1 |30000| 4 1
2 |20000| 1 3
3 |10000| 3 2
4 |50000| 2 2
Thanks!
As a side note, I would NOT store this field within the database - storing values that are dependent on other records in the table make maintenance much more difficult.
Here's a query that would work as a view or within a stored procedure:
SELECT
ID,
[money],
ROW_NUMBER() OVER (order by [level] desc, [money] desc) AS [ranking],
[level]
FROM myTable
If you REALLY wanted to update the table just make the query a subquery to an update:
UPDATE m1
SET ranking = m2.ranking
FROM myTable m1
INNER JOIN
(SELECT
ID,
ROW_NUMBER() OVER (order by [level] desc, [money] desc) ranking
FROM myTable) m2
ON m1.ID = m2.ID
If you simply want to select then here is the query :
select *, dense_rank() over (order by level desc, mony desc) as newranking from YourTable
and if you want to update then :
;with cte_toupdate (ranking, newranking)
as (
select ranking, dense_rank() over (order by level desc, mony desc) as newranking from YourTable
)
Update cte_toupdate set ranking = newranking
select * from YourTable
check here : http://sqlfiddle.com/#!3/8d6d3/10
Note : if you want unique ranks then use Row_Number() instead of dense_rank().
CREATE TABLE #tt
(
id INT,
mony INT,
ranking INT,
levell INT
)
INSERT INTO #tt
VALUES (1,30000,1,1),
(2,20000,2,3),
(3,10000,3,2),
(4,50000,4,2)
UPDATE a
SET ranking = rnk
FROM #tt a
JOIN (SELECT Row_number()
OVER (
ORDER BY levell DESC, mony DESC) AS rnk,
*
FROM #tt) b
ON a.levell = b.levell
AND a.mony = b.mony
Related
I'm trying to learn SQL commands and working currently with an query which will list all customers which has status active (ID = 1) and active-busy (ID = 2).
The problem is that some customers have the same ID but the different type. So I have an customer which has ID 1 and Type 3 but the same customer has also ID 1 but Type 1 so what I'm trying to do is select only this which has Type 1 but have also the same ID. So IF ID is the same and Type is 1 and 3, select only Type 3.
SELECT
CASE
WHEN corel.opts LIKE 3
THEN (SELECT corel.opts
WHERE corel.objid = rel.id
AND corel.type IN (1, 2)
AND corel.opts = 3
ELSE corel.opts 1
END)
It's not complete query because it has many other this which I can't post but if you guys would show me way how could I accomplish that, I would appreciate it. I just don't know how to tell IF the same ID in the table but different Type - select only Type 3. Each customer have different ID but it can have the same type.
USE Row_number() like this
DECLARE #T TABLE
(
Id INT,
TypeNo INT
)
INSERT INTO #T
VALUES(1,1),(1,3),(2,1),(2,3),(3,1),(4,3)
;WITH CTE
AS
(
SELECT
RN = ROW_NUMBER() OVER(PARTITION BY Id ORDER BY TypeNo DESC),
Id,
TypeNo
FROM #T
)
SELECT
Id,
TypeNo
FROM CTE
WHERE RN = 1
My Input
Output
Test scenario is borrowed form Jayasurya Satheesh, thx, voted your's up!
DECLARE #T TABLE
(
Id INT,
TypeNo INT
)
INSERT INTO #T
VALUES(1,1),(1,3),(2,1),(2,3),(3,1),(4,3)
--The query will use ROW_NUMBER with PARTITION BY to start a row count for each T.Id separately.
--SELECT TOP 1 WITH TIES will take all first place rows and not just the very first:
SELECT TOP 1 WITH TIES
Id,
TypeNo
FROM #T AS T
ORDER BY ROW_NUMBER() OVER(PARTITION BY T.Id ORDER BY T.TypeNo DESC)
If your Type=3 is not the highest type code the simple ORDER BY T.TypeNo DESC won't be enough, but you can easily use a CASE to solve this.
As far as I understand, you need something like:
SELECT c1.*
FROM corel c1
LEFT OUTER JOIN corel c2 ON c1.objid=c2.objid AND c1.type <> c2.type
WHERE (c1.type=1 AND c2.type IS NULL) OR (c1.type=3 AND c2.type=1)
I have table with some data, for example
ID Specified TIN Value
----------------------
1 0 tin1 45
2 1 tin1 34
3 0 tin2 23
4 3 tin2 47
5 3 tin2 12
I need to get rows with all fields by MAX(Specified) column. And if I have few row with MAX column (in example ID 4 and 5) i must take last one (with ID 5)
finally the result must be
ID Specified TIN Value
-----------------------
2 1 tin1 34
5 3 tin2 12
This will give the desired result with using window function:
;with cte as(select *, row_number(partition by tin order by specified desc, id desc) as rn
from tablename)
select * from cte where rn = 1
Edit: Updated query after question edit.
Here is the fiddle
http://sqlfiddle.com/#!9/20e1b/1/0
SELECT * FROM TBL WHERE ID IN (
SELECT max(id) FROM
TBL WHERE SPECIFIED IN
(SELECT MAX(SPECIFIED) FROM TBL
GROUP BY TIN)
group by specified)
I am sure we can simplify it further, but this will work.
select * from tbl where id =(
SELECT MAX(ID) FROM
tbl where specified =(SELECT MAX(SPECIFIED) FROM tbl))
One method is to use window functions, row_number():
select t.*
from (select t.*, row_number() over (partition by tim
order by specified desc, id desc
) as seqnum
from t
) t
where seqnum = 1;
However, if you have an index on tin, specified id and on id, the most efficient method is:
select t.*
from t
where t.id = (select top 1 t2.id
from t t2
where t2.tin = t.tin
order by t2.specified desc, id desc
);
The reason this is better is that the index will be used for the subquery. Then the index will be used for the outer query as well. This is highly efficient. Although the index will be used for the window functions; the resulting execution plan probably requires scanning the entire table.
Such SQL query:
SELECT ROW_NUMBER() OVER (PARTITION BY ID, YEAR order by ID ), ID, YEAR
from table t
give me following query set:
1 1000415591 2012
1 1000415591 2013
2 1000415591 2013
1 1000415591 2014
2 1000415591 2014
How could I update records with ROW_NUMBER() equals to 2? Other fields of this records is identically (select distinct from table where id = 1000415591 gives 3 records when there are 5 without distinct keyword), so I can depend only on ROW_NUMBER() value.
I need solution for Oracle, because I saw something similar for SQL-Server but it won't work with Oracle.
You could use a MERGE statement which is quite verbose and easy to understand.
For example,
MERGE INTO t s
USING
(SELECT ROW_NUMBER() OVER (PARTITION BY ID, YEAR order by ID ) RN,
ID,
YEAR
FROM TABLE t
) u ON (s.id = u.id)
WHEN MATCHED THEN
UPDATE SET YEAR = some_value WHERE u.RN = 2)
/
Note You cannot merge the same column which is used to join in the ON clause.
Try to use ROWID field:
UPDATE T
SET t.year = t.year*1000
WHERE (rowid,2) in (SELECT rowid,
ROW_NUMBER()
OVER (PARTITION BY ID, t.YEAR order by ID )
FROM T)
SQLFiddle demo
If you need to delete range of ROWNUMBERS then :
UPDATE T
SET t.year = t.year*1000
WHERE rowid in ( SELECT rowid FROM
(
SELECT rowid,
ROW_NUMBER()
OVER (PARTITION BY ID, t.YEAR order by ID ) as RN
FROM T
) T2 WHERE RN >=2 AND RN <=10
)
SQLFiddle demo
This is not the update statement but this is how to get the 2 rows you wanted to update:
SELECT *
FROM (
SELECT ROW_NUMBER() OVER (PARTITION BY ID, YEAR order by ID ) as rn, ID, YEAR
from t )
where rn = 2
SQLFIDDLE
When I've posted thq question, I've found that this could be wrong approach. I could modify table and add new fields. So better solution to create one more field IDENTITY and update it with numbers from the new sequence from 1 to total row numbers. Then I could update fields based on this IDENTIY field.
I'll keep this question opened if someone come up with solution based on ROW_NUMBER() analytic function.
update TABLE set NEW_ID = TABLE_SEQ.nextval
where IDENTITY in (
select IDENTITY from (
select row_number() over(PARTITION BY ID, YEAR order by ID) as row_num, t.ID, t."YEAR", t.IDENTITY
from TABLE t
) where row_num > 1
)
I've this result set:
select a.id, a.categoria from Articolo a
where novita = 1
order by a.categoria, newid()
id categoria
----------- -----------
3 4
11 4
1 4
12 5
13 5
4 6
and i would to get the first product (in a random order) from each different category:
id categoria
----------- -----------
3 4
12 5
4 6
Ideally something like
select FIRST(a.id), a.categoria from Articolo a
where novita = 1
order by a.categoria, newid()
Any ideas?
Use MAX(a.id) with GROUP BY a.categoria
SELECT MAX(a.id), a.categoria
from Articolo a
where novita = 1
GROUP BY a.category
Update
To get random id for each categoria you can use the ranking function ROW_NUMBER() OVER(PARTITION BY categoria) with ORDER BY NEWID to get a random ordering, like this:
WITH CTE
AS
(
SELECT id, categoria, ROW_NUMBER() OVER(PARTITION BY categoria
ORDER BY NEwID()) AS rn
FROM Articolo
)
SELECT id, categoria
FROM CTE
WHERE rn = 1;
See it in action here:
SQL Fiddle Demo
This way, it will give you a random id for each categoria each time.
However, If you want the first, you can use the ORDER BY(SELECT 1) inside the ranking function ROW_NUMBER():
WITH CTE
AS
(
SELECT id, categoria, ROW_NUMBER() OVER(PARTITION BY categoria
ORDER BY (select 1)) AS rn
FROM Articolo
)
SELECT id, categoria
FROM CTE
WHERE rn = 1;
Updated SQL Fiddle Demo
This will give you the first id for each categoria.
Note that: There is no meaning of the first value in the database concepts, because in the relational model, the rows order is not significant. And it is not guaranteed to return the same order each time, you have to ORDER BY specific column to get consistent ordering.
I am trying to select two columns into a table (ID and state). The table should show the state with the maximum value for each ID. I've tried a few other examples but nothing seems to work.
Original data structure:
ID state value (FLOAT)
1 TX 921,294,481
1 SC 21,417,296
1 FL 1,378,132,290
1 AL 132,556,895
1 NC 288,176
1 GA 1,270,986,631
2 FL 551,374,452
2 LA 236,645,530
2 MS 2,524,536,050
2 AL 4,128,682,333
2 FL 1,503,991,028
The resulting data structure should therefore look like this:
ID STATE (Max Value)
1 FL
2 AL
Florida and Alabama having the largest values in their ID groups.
Any help would be greatly appreciated on this. I did find a SO answer here already, but could not make the answers work for me.
For SQL Server (and other products with windowed functions):
SELECT *
FROM
(
SELECT
*,
ROW_NUMBER() OVER (PARTITION BY ID ORDER BY value desc) as rn
FROM
UnnamedTable
) t
WHERE
t.rn = 1
You can use a subquery to get this result:
select t1.id, t1.[state] MaxValue
from yourtable t1
inner join
(
select id, max(value) MaxVal
from yourtable
group by id
) t2
on t1.id = t2.id
and t1.value = t2.maxval
order by t1.id
See SQL Fiddle with Demo
A solution, based on the assumption that value is numeric:
SELECT
[ID],
[State],
[Value]
FROM
(
SELECT
[ID],
[State],
[Value],
Rank() OVER (PARTITION BY [ID] ORDER BY [Value] DESC) AS [Rank]
FROM [t1]
) AS [sub]
WHERE [sub].[Rank] = 1
ORDER BY
[ID] ASC,
[State] ASC
If multiple States with the same ID have the same Value, they would all get the same Rank. This is different from using Row_Number, which return unique row numbers, but the order is chosen arbitrarily. (See also: SQL RANK() versus ROW_NUMBER())