Awk input variable as a rule - awk

Question

Good day!
I have the next code:
BLOCK=`awk '
/\/\* R \*\// {
level=1
count=0
}
level {
n = split($0, c, "");
for (i = 1; i <= n; i++)
{
printf(c[i]);
if (c[i] == ";")
{
if(level==1)
{
level = 0;
if (count != 0)
printf("\n");
};
}
else if (c[i] == "{")
{
level++;
count++;
}
else if (c[i] == "}")
{
level--;
count++;
}
}
printf("\n")
}' $i`
That code cuts the piece of the file from /* R */ mark to the ';' symbol with taking into account the details like braces etc. But that isn't important. I want to replace the hard-coded /* R */ by the variable:
RECORDSEQ="/* R */"
...
BLOCK=`awk -v rec="$RECORDSEQ" '
rec {
level=1
count=0
}
But that doesn't work.
How can I fix it?
Thank you in advance.

Answer 1

Found the solution:
RECORDSEQ="/* R */"
# Construct regexp for awk
RECORDSEQREG=`echo "$RECORDSEQ" | sed 's:\/:\\\/:g;s:\*:\\\*:g'`
# Cycle for files
for i in $SOURCE;
do
# Find RECORDSEQ and cut out the block
BLOCK=`awk -v rec="$RECORDSEQREG" '
$0 ~ rec {
level=1
count=0
}
...
Many thanks to people who helped.