how to change this sql query to hibernate query? - sql

Question

I want to change this sql query to hibernate query.
SQL query:
SELECT *
FROM User
WHERE (DATE_SUB(NOW(), INTERVAL 1 DAY) >= AccountStartDate)
AND PINStatus = 'N'
AND PetName IS NULL
AND SchoolName IS NULL
AND AccountType = 'Supervisor'
This is my User class
#Entity
#Table(name = "User")
public class User{
#Id
#GeneratedValue
#Column(name="UserID")
private long userID;
#Column(name="AccountStartDate")
private Date accountStartDate;
#Column(name="PINStatus")
private String pinStatus;
#Column(name="PetName")
private String petName;;
#Column(name="SchoolName")
private String schoolName;
#Column(name="AccountType")
private String accountType;
}

Answer 1

Here is part of the answer... Try this
User user = _session.CreateCriteria<User>()
.Add(Restrictions.Eq("PINStatus", "[VARIABLE PARAMETER]"))
.AddOrder(new Order("_id", false))
.List<User>()
.FirstOrDefault();
That will result in something like:
select * from User where PINStatus = ??? Order By Id desc

Answer 2

Query query=sessionFactory.getCurrentSession().createQuery("FROM User WHERE " +
"pinStatus=:pinStatus AND petName IS NULL AND schoolName IS NULL AND accountType=:accountType")
.setString("accountType", "User").setString("pinStatus", "N");
List<User> userList=query.list();
Iterator<User> itr = userList.iterator();
while(itr.hasNext()) {
User user = (User) itr.next();
long diff=currentDate.getTime() - user.getAccountStartDate().getTime();
long diffHours = diff / (60 * 60 * 1000);
if(diffHours>=24)
{
System.out.println("User added "+user.getFirstName());
userList1.add(user);
}
}