I have the following SQL Code which is not giving me my desired results.
SELECT
POLICIES.CLIENTS_ID,
POLICIES.CLIENTCODE,
COUNT(POLICIES.POLICIES_ID) as [Total Policies],
(
SELECT
COUNT(POLICIES.POLICIES_ID)
FROM
POLICIES
WHERE
POLICIES.COVCODE = 'AUT'
) as [Auto Policies]
FROM
POLICIES
LEFT JOIN CLIENTS
ON CLIENTS.CLIENTS_ID = POLICIES.CLIENTS_ID
WHERE
POLICIES.CNR IS NULL
GROUP BY
POLICIES.CLIENTS_ID,
POLICIES.CLIENTCODE
ORDER BY
POLICIES.CLIENTS_ID
I get a result like this:
ID CODE Total Auto
3 ABCDE1 1 999999
4 ABCDE2 1 999999
5 ABCDE3 2 999999
6 ABCDE4 2 999999
I would like for the last column to COUNT the total auto policies that exists for that clientid rather than all of the auto policies that exist. I believe I need a nested select statement that somehow groups all like results on the clientid, but it ends up returning more than 1 row and throws the error.
If I add:
GROUP BY
POLICIES.CLIENTS_ID
I get:
Subquery returned more than 1 value. This is not permitted when the....
Any help would be appreciated greatly!
Thank you
You can use a CASE statement to do this. Instead of your subquery in the SELECT clause use:
SUM(CASE WHEN POLICIES.COVCODE = 'AUT' THEN 1 ELSE 0 END) as [AUTO POLICIES]
As Martin Smith pointed out. If client_id has multiple client_codes then this will give you the count of records for each combination of client_id/client_code. If client_id is 1:1 with client_code then this will give you a count of records for each distinct client_id, which I suspect is the case from your example and question.
Unrelated: You have a LEFT JOIN to your Clients table, but you don't use your Clients table anywhere int he query. Consider removing it if you don't need to select or filter by any its fields, since it's just unused overhead.
What if you modify the inner query for getting count to something like
SUM(CASE WHEN POLICIES.COVCODE = 'AUT' THEN 1 ELSE 0 END) as [Auto Policies]
Related
I should probably be able to figure this out from other questions/answers I've read here, but I just can't get anything to work today. Any help is really appreciated.
I have two queries, counting the instances of "GOOD" feedback, and "BAD" feedback from a single table. I just want to join them so that I can see something like below
ID | GOOD | BAD
121 | 0 | 7
123 | 5 | 0
287 | 32 | 8
I'm running numerous queries from VBA, if that matters, and the 0's can just be null. I can clean that stuff up in VBA.
Query 1:
select ID, count(*)
from HLFULL
where DEPT= 'HLAK'
and feedback = 'GOOD'
group by ID
Query 2:
select ID, count(*)
from HLFULL
where DEPT= 'HLAK'
and feedback = 'BAD'
group by ID
I've tried UNION, UNION ALL, JOIN, INNER JOIN, OUTER JOIN, aggregations, etc.
You can do conditional aggregation like this:
select ID,
count(case when feedback = 'GOOD' then 1 end) as Good,
count(case when feedback = 'BAD' then 1 end) as Bad
from HLFULL
where DEPT = 'HLAK'
and feedback in ('GOOD', 'BAD')
group by ID
You should be able to get the result using conditional aggregation. This type of query uses a CASE expression along with your aggregate function to get multiple columns:
select ID,
count(case when feedback = 'GOOD' then Id end) as Good,
count(case when feedback = 'BAD' then Id end) as Bad
from HLFULL
where DEPT= 'HLAK'
group by ID
I have a query that works great (listed below). The issue I am having is we have run into a patient that has had event on two different days and because I am grouping by the PATNUM, it is only showing it as one.
How can I get it to count 1 for each time if the PATNUM and SCHDT are different
Example:
PATNUM SCHDT
12345 30817
12345 30817
54321 30817
54321 30717
PATNUM 12345 should only count once while PATNUM 54321 should count twice.
My count statement is this:
SELECT ph.*, pi.*,
COUNT(DISTINCT CASE WHEN `SERVTYPE` IN ('INPT','INPFOP','INFOBS','IP') AND Complete ='7' THEN pi.PATNUM ELSE NULL END) AS count1,
COUNT(DISTINCT CASE WHEN `SERVTYPE` IN ('INPT','INPFOP','INFOBS','IP') AND Complete ='8' THEN pi.PATNUM ELSE NULL END) AS count2
FROM patientinfo as pi
INNER JOIN physicians as ph ON pi.SURGEON=ph.PName
WHERE PID NOT IN ('1355','988','767','1289','484','2784')
GROUP BY SURGEON
ORDER BY Dept,SURGEON ASC
Which columns do you want to see?
You can adjust your GROUP BY:
SELECT
ph.pname,
ph.specialty,
SUM(CASE WHEN complete = 7 THEN 1 ELSE 0 END) count1,
SUM(CASE WHEN complete = 8 THEN 1 ELSE 0 END) count2
FROM
(
SELECT
DISTINCT
surgeon,
patnum,
schdt,
complete,
servtype
FROM patientinfo
WHERE complete IN (7,8)
AND servtype IN ('INPT','INPFOP','INFOBS','IP')
AND pid NOT IN ('1355','988','767','1289','484','2784')
) pisub
INNER JOIN physicians ph ON pisub.surgeon = ph.pname
GROUP BY ph.pname, ph.specialty
ORDER BY ph.pname, ph.specialty;
Also, I would make a few suggestions:
If you're going to give your tables an alias, then use the alias when referring to any column in your query. I've made a guess here about some of your columns as to which table they come from (e.g. dept), so feel free to change it if it is not correct
You don't need to select all records from both tables if you don't need them
The query won't run if you don't GROUP BY all columns you're selecting. I've written about this for Oracle and SQL in general, but actually in MySQL I think it does run but show incorrect results.
I have this
RECORD ITEMS ITEMSTOTAL
------------------------------------ ---------- ----------
ababababaa 0 1
ababababab 0 0
ababababac 0 1
ababababad 1 1
ababababae 0 2
but I need this output when ITEMS=ITEMSTOTAL
RECORD
------------------------------------
ababababab
ababababad
Currently I'm using this query for the first result, but I don't know how to get the second output, Maybe this sounds obvious but I can't find the answer :(
SELECT RECORD,
(SELECT COUNT(*) FROM TABLE1 WHERE SOMETHING=X) AS ITEMS,
(SELECT COUNT(*) FROM TABLE2 WHERE SOMETHING2=Y) AS ITEMSTOTAL
FROM RECORDS_TABLE
WHERE DELETED=0
--and ITEMS.count = ITEMSTOTAL.count <-- tried something like this but it doesn't work.
One option would be to use a subquery and apply the where criteria to the outer query.
select *
from (
your query here
) t
where items = itemstotal
I assume that isn't your actual query btw. where comes after from. Also, those count statements would return the same values.
After many attempts I have failed at this and hoping someone can help. The query returns every entry a user makes when items are made in the factory against and order number. For example
Order Number Entry type Quantity
3000 1 1000
3000 1 500
3000 2 300
3000 2 100
4000 2 1000
5000 1 1000
What I want to the query do is to return filter the results like this
If the order number has an entry type 1 and 2 return the row which is type 1 only
otherwise just return row whatever the type is for that order number.
So the above would end up:
Order Number Entry type Quantity
3000 1 1000
3000 1 500
4000 2 1000
5000 1 1000
Currently my query (DB2, in very basic terms looks like this ) and was correct until a change request came through!
Select * from bookings where type=1 or type=2
thanks!
select * from bookings
left outer join (
select order_number,
max(case when type=1 then 1 else 0 end) +
max(case when type=2 then 1 else 0 end) as type_1_and_2
from bookings
group by order_number
) has_1_and_2 on
type_1_and_2 = 2
has_1_and_2.order_number = bookings.order_number
where
bookings.type = 1 or
has_1_and_2.order_number is null
Find all the orders that have both type 1 and type 2, and then join it.
If the row matched the join, only return it if it is type 1
If the row did not match the join (has_type_2.order_number is null) return it no matter what the type is.
A "common table expression" [CTE] can often simplify your logic. You can think of it as a way to break a complex problem into conceptual steps. In the example below, you can think of g as the name of the result set of the CTE, which will then be joined to
WITH g as
( SELECT order_number, min(type) as low_type
FROM bookings
GROUP BY order_number
)
SELECT b.*
FROM g
JOIN bookings b ON g.order_number = b.order_number
AND g.low_type = b.type
The JOIN ON conditions will work so that if both types are present then low_type will be 1, and only that type of record will be chosen. If there is only one type it will be identical to low_type.
This should work fine as long as 1 and 2 are the only types allowed in the bookings table. If not then you can simply add a WHERE clause in the CTE and in the outer SELECT.
I am not able to understand the SQL query output :
SQL> select distinct(STATUS) from TMP_ORDER_ACTION_PSTN_CP_11035;
InDelivery_SOMBe
In Delivery
Complete
Amended
Cancelled
Failed InComplete
1 SQL> select count(*) from TMP_ORDER_ACTION_PSTN_CP_11035 where
STATUS='Complete';
1484
2 SQL> select count(*) from TMP_ORDER_ACTION_PSTN_CP_11035 where STATUS
!= 'Complete';
3167
3 SQL> select count(*) from TMP_ORDER_ACTION_PSTN_CP_11035;
5091
The sum of count for the 1 and 2 queries should be same as the total count(3 query).Why is the sum differing from the whole count?
It seems like a dump question but i dont know why is this happening.
Please note that My question is not related to null check at all.It is the that
sum(1+2)=3.1484+3167 !=5091.Why is the result different?
My guess is NULL values, which match none of your WHERE clauses, including the last one. Try
select count(*) from TMP_ORDER_ACTION_PSTN_CP_11035 where STATUS is null;
where status = null is never true, nor is where null = null. You have to use is null.
The sum of count for the 1 and 2 queries should be same as the total count(3 query).Why is the sum differing from the whole count?
No, because the records with NULL are not matching query 1 or query 2, but they are counted in query 3.
1 + 2 + IS NULL should equal 3.
WHERE STATUS = NULL won't work. Nothing equals NULL.
Try IS instead of =...
select count(*) from TMP_ORDER_ACTION_PSTN_CP_11035 where STATUS IS null
Try this:
Assuming p_key is a primary key for the table,
select count(p_key) from TMP_ORDER_ACTION_PSTN_CP_11035 where STATUS='Complete';
select count(p_key) from TMP_ORDER_ACTION_PSTN_CP_11035 where STATUS <> 'Complete';
select count(p_key) from TMP_ORDER_ACTION_PSTN_CP_11035 ;