Consider I have a table t1 with a single column a, and it has values, say
a
-
5
10
15
17
I want to write a single SQL query that does the following. Basically, I want to know the sum of all values up to the value in the table t1.
SELECT SUM(value) FROM t2 WHERE value<=5
UNION ALL
SELECT SUM(value) FROM t2 WHERE value<=10
UNION ALL
SELECT SUM(value) FROM t2 WHERE value<=15
UNION ALL
SELECT SUM(value) FROM t2 WHERE value<=17;
If someone changes the value in a, like delete or insert more elements, I have to rewrite the above query. Is there a query that always works automatically?
Here is the DB fiddle link.
I think you appears to want :
SELECT SUM(case when bound<=a[1] then value else 0 end),
. . .
FROM table t;
After edit with fiddle, you can use subquery instead of UNION :
select *, (select sum(t2.value) from t2 where t2.value <= t1.a)
from t1;
I think it's more clear with a join than a subquery, but just personal preference.
SELECT
t1.a,
SUM(COALESCE(t2.value, 0))
FROM
t1
LEFT JOIN
t2
ON
t2.value <= t1.a
GROUP BY
t1.a
how to get a sum of two sums from two tables?
SELECT (SELECT SUM(col) FROM table1) + SELECT (SUM(col) from table2)
doesn't work
You are very close. You just need parens around each subquery:
SELECT (SELECT SUM(col) FROM table1) + (SELECT SUM(col) from table2)
If either subquery could return NULL, you might prefer:
SELECT COALESCE(t1.s, 0) + COALESCE(t2.s)
FROM (SELECT SUM(col) as s FROM table1) t1 CROSS JOIN
(SELECT SUM(col) as s from table2) t2;
Due to this link, you can do that by :
SELECT T1C1 , T2C1
FROM
( select SUM(Col1) T1C1 FROM T1 ) A
CROSS JOIN
( select SUM(Col1) T2C1 FROM T2 ) B
also you can visit these links:
Query SUM for two fields in two different tables
Getting the sum of several columns from two tables
SQL: How to to SUM two values from different tables
select coalesce(sum(x),0) from
(
Select sum(a) x from tab1
Union all
Select sum(b) from tab2
) Ilv
I have to get table only with duplicate text values using SQL query. I have used Having count(columnname) > 1 but I'm not getting result, only with duplicate values instead getting all values.
Can anyone suggest whether I have to add anything to my query?
Thanks.
Use the below query. mention the column which is getting duplicated in the patition by clause..
with CTE_1
AS
(SELECT *,COUNT(1) OVER(PARTITION BY LTRIM(RTRIM(REPLACE(yourDuplicateColumn,' ',''))) Order by -anycolunm- ) cnt
FROM YourTable
)
SELECT *
FROM CTE_1
WHERE cnt>1
Assuming id is a primary key
select *
from myTable t1
where exists (select 1
from myTable t2
where t2.text = t1.text and t2.id != t1.id)
You can use similar to following query:
SELECT
column1, COUNT(*)
FROM table
GROUP BY column1
HAVING COUNT(*) > 1
I read some topics about this but I'm not very good with sql. I have 10 tables with these fields:
value
type
date
I want to sum all the value fileds together when they have a specific type. I was trying to do something like this, but it's not working.
select sum(tab1.value) + sum(tab2.value)
from tab1, tab2
where tab1.type = tab2.type = 'box'
I guess I could do many simple queries like these and then sum all the results
select sum(value) from tab1 where type='box'
select sum(value) from tab2 where type='box'
but I wonder if I can do one single query
thanks
Having multiple tables with the same structure is usually a sign of poor database design.
I would suggest that you use your last approach, but put the subqueries in the from clause and then add the results in the select:
select t1.value + t2.value + . .
from (select sum(value) as value from tab1 where type='box') t1 cross join
(select sum(value) as value from tab2 where type='box') t2 cross join
. . .
Alternatively, you could union all them together in the from clause and then take the sum:
select sum(value)
from ((select sum(value) as value from tab1 where type='box') union all
(select sum(value) as value from tab2 where type='box') union all
. . .
) t;
If the tables are not linked via FK/PK you can use multiple sub-queries:
SELECT (SELECT SUM(tab1.value) FROM tab1 WHERE type='box') as Tab1Sum,
(SELECT SUM(tab2.value) FROM tab2 WHERE type='box') as Tab2Sum -- and so on...
This yields a single record where each column is the sum of each table.
1.Use single select;
DECLARE #type NVARCHAR(255) = N'Box';
SELECT (SELECT SUM(value) FROM tab1 WHERE type=#Box)
+ (SELECT SUM(value) FROM tab2 WHERE type=#Box)
+ (SELECT SUM(value) FROM tab3 WHERE type=#Box)
+ (...)
I think it's simplest one.
2.you create a view as
CREATE VIEW tabs
AS
SELECT value, type FROM tab1
UNION
SELECT value, type FROM tab2
UNION
SELECT value, type FROM tab3
UNION
...
Then
SELECT SUM(value) FROM tabs WHERE type = 'BOX'
3.Think why similar column are different tables. Can they be merged into single table?
If answer is No, and you have too many tables, consider concatenate SQL strings and use sp_executesql to execute it.
How can one programmatically sort a union query when pulling data from two tables? For example,
SELECT table1.field1 FROM table1 ORDER BY table1.field1
UNION
SELECT table2.field1 FROM table2 ORDER BY table2.field1
Throws an exception
Note: this is being attempted on MS Access Jet database engine
Sometimes you need to have the ORDER BY in each of the sections that need to be combined with UNION.
In this case
SELECT * FROM
(
SELECT table1.field1 FROM table1 ORDER BY table1.field1
) DUMMY_ALIAS1
UNION ALL
SELECT * FROM
(
SELECT table2.field1 FROM table2 ORDER BY table2.field1
) DUMMY_ALIAS2
SELECT field1 FROM table1
UNION
SELECT field1 FROM table2
ORDER BY field1
I think this does a good job of explaining.
The following is a UNION query that uses an ORDER BY clause:
select supplier_id, supplier_name
from suppliers
where supplier_id > 2000
UNION
select company_id, company_name
from companies
where company_id > 1000
ORDER BY 2;
Since the column names are different between the two "select" statements, it is more advantageous to reference the columns in the ORDER BY clause by their position in the result set.
In this example, we've sorted the results by supplier_name / company_name in ascending order, as denoted by the "ORDER BY 2".
The supplier_name / company_name fields are in position #2 in the
result set.
Taken from here: http://www.techonthenet.com/sql/union.php
Using a concrete example:
SELECT name FROM Folders ORDER BY name
UNION
SELECT name FROM Files ORDER BY name
Files:
name
=============================
RTS.exe
thiny1.etl
thing2.elt
f.txt
tcpdump_trial_license (1).zip
Folders:
name
============================
Contacts
Desktop
Downloads
Links
Favorites
My Documents
Desired Output: (results of first select first, i.e. folders first)
Contacts
Desktop
Downloads
Favorites
Links
My Documents
f.txt
RTMS.exe
tcpdump_trial_license (1).zip
thiny1.etl
thing2.elt
SQL to achieve the desired results:
SELECT name
FROM (
SELECT 1 AS rank, name FROM Folders
UNION
SELECT 2 AS rank, name FROM Files) dt
ORDER BY rank, name
Here's an example from Northwind 2007:
SELECT [Product ID], [Order Date], [Company Name], [Transaction], [Quantity]
FROM [Product Orders]
UNION SELECT [Product ID], [Creation Date], [Company Name], [Transaction], [Quantity]
FROM [Product Purchases]
ORDER BY [Order Date] DESC;
The ORDER BY clause just needs to be the last statement, after you've done all your unioning. You can union several sets together, then put an ORDER BY clause after the last set.
(SELECT table1.field1 FROM table1
UNION
SELECT table2.field1 FROM table2) ORDER BY field1
Work? Remember think sets. Get the set you want using a union and then perform your operations on it.
SELECT table1Column1 as col1,table1Column2 as col2
FROM table1
UNION
( SELECT table2Column1 as col1, table1Column2 as col2
FROM table2
)
ORDER BY col1 ASC
SELECT field1
FROM ( SELECT field1 FROM table1
UNION
SELECT field1 FROM table2
) AS TBL
ORDER BY TBL.field1
(use ALIAS)
This is the stupidest thing I've ever seen, but it works, and you can't argue with results.
SELECT *
FROM (
SELECT table1.field1 FROM table1 ORDER BY table1.field1
UNION
SELECT table2.field1 FROM table2 ORDER BY table2.field1
) derivedTable
The interior of the derived table will not execute on its own, but as a derived table works perfectly fine. I've tried this on SS 2000, SS 2005, SS 2008 R2, and all three work.
This is how it is done
select * from
(select top 100 percent pointx, pointy from point
where pointtype = 1
order by pointy) A
union all
select * from
(select top 100 percent pointx, pointy from point
where pointtype = 2
order by pointy desc) B
Browsing this comment section I came accross two different patterns answering the question. Sadly for SQL 2012, the second pattern doesn't work, so here's my "work around"
Order By on a Common Column
This is the easiest case you can encounter. Like many user pointed out, all you really need to do is add an Order By at the end of the query
SELECT a FROM table1
UNION
SELECT a FROM table2
ORDER BY field1
or
SELECT a FROM table1 ORDER BY field1
UNION
SELECT a FROM table2 ORDER BY field1
Order By on Different Columns
Here's where it actually gets tricky. Using SQL 2012, I tried the top post and it doesn't work.
SELECT * FROM
(
SELECT table1.field1 FROM table1 ORDER BY table1.field1
) DUMMY_ALIAS1
UNION ALL
SELECT * FROM
(
SELECT table2.field1 FROM table2 ORDER BY table2.field1
) DUMMY_ALIAS2
Following the recommandation in the comment I tried this
SELECT * FROM
(
SELECT TOP 100 PERCENT table1.field1 FROM table1 ORDER BY table1.field1
) DUMMY_ALIAS1
UNION ALL
SELECT * FROM
(
SELECT TOP 100 PERCENT table2.field1 FROM table2 ORDER BY table2.field1
) DUMMY_ALIAS2
This code did compile but the DUMMY_ALIAS1 and DUMMY_ALIAS2 override the Order By established in the Select statement which makes this unusable.
The only solution that I could think of, that worked for me was not using a union and instead making the queries run individually and then dealing with them. So basically, not using a Union when you want to Order By
By using order separately each subset gets order, but not the whole set, which is what you would want uniting two tables.
You should use something like this to have one ordered set:
SELECT TOP (100) PERCENT field1, field2, field3, field4, field5 FROM
(SELECT table1.field1, table1.field2, table1.field3, table1.field4, table1.field5 FROM table1
UNION ALL
SELECT table2.field1, table2.field2, table2.field3, table2.field4, table2.field5 FROM table2)
AS unitedTables ORDER BY field5 DESC
The second table cannot include the table name in the ORDER BY clause.
So...
SELECT table1.field1 FROM table1 ORDER BY table1.field1
UNION
SELECT table2.field1 FROM table2 ORDER BY field1
Does not throw an exception
If necessary to keep the inner sorting:
SELECT 1 as type, field1 FROM table1
UNION
SELECT 2 as type, field1 FROM table2
ORDER BY type, field1
(SELECT FIELD1 AS NEWFIELD FROM TABLE1 ORDER BY FIELD1)
UNION
(SELECT FIELD2 FROM TABLE2 ORDER BY FIELD2)
UNION
(SELECT FIELD3 FROM TABLE3 ORDER BY FIELD3) ORDER BY NEWFIELD
Try this. It worked for me.
For Sql Server 2014/2012/Others(Not Checked) :
SELECT * FROM
(
SELECT table1.field1 FROM table1 ORDER BY table1.field1
)
as DUMMY_ALIAS1
UNION ALL
SELECT * FROM
(
SELECT table2.field1 FROM table2 ORDER BY table2.field1
)
as DUMMY_ALIAS2