Here in one column dates are in random order. I want to build query where it will count all the months how many times it appears.
SQL Table :-
EMP_table_date
10/26/2014
10/26/2014
10/24/2014
11/26/2014
11/26/2014
11/23/2014
12/26/2014
12/26/2014
Expected Output : -
Oct | Nov | Dec
3 | 3 | 2
Note:
Only single column mentioned above
Using Oracle 11G Database
select count(case when extract(month from emp_table_date) = 1 then 1 end) as jan,
count(case when extract(month from emp_table_date) = 2 then 1 end) as feb,
count(case when extract(month from emp_table_date) = 3 then 1 end) as mar,
count(case when extract(month from emp_table_date) = 4 then 1 end) as april,
count(case when extract(month from emp_table_date) = 5 then 1 end) as may,
count(case when extract(month from emp_table_date) = 6 then 1 end) as jun,
count(case when extract(month from emp_table_date) = 7 then 1 end) as jul,
count(case when extract(month from emp_table_date) = 8 then 1 end) as aug,
count(case when extract(month from emp_table_date) = 9 then 1 end) as sep,
count(case when extract(month from emp_table_date) = 10 then 1 end) as oct,
count(case when extract(month from emp_table_date) = 11 then 1 end) as nov,
count(case when extract(month from emp_table_date) = 12 then 1 end) as december
from emp_table;
SELECT TRUNC(emp_table_date,'MON') as "MON",
COUNT(emp_table_date) as "CNT"
FROM emp_table
GROUP BY TRUNC(emp_table_date,'MON');
This will return the count of each month in rows. Use standard PIVOT to convert it into columns.
Related
I got two tables with the relationship like this
I have a data set like this
and want to get ALL the demerits, the code, description, total number of offences committed for the demerit code so far in any month (of any year) and then the total of offences committed for the demerit
code in each month (of any year) which is basically a result like this
I can get the total number(by using group by) and monthly data(by using pivot rows as columns) separately, but don't know how to get them in one query. Any help would be appreciated.
select * from (
select
d.dem_code,
d.dem_code as dem_code_copy,
d.dem_description,
case
when EXTRACT(month FROM off_datetime) = 1 then 'Jan'
when EXTRACT(month FROM off_datetime) = 2 then 'Feb'
when EXTRACT(month FROM off_datetime) = 3 then 'Mar'
when EXTRACT(month FROM off_datetime) = 4 then 'Apr'
when EXTRACT(month FROM off_datetime) = 5 then 'May'
when EXTRACT(month FROM off_datetime) = 6 then 'Jun'
when EXTRACT(month FROM off_datetime) = 7 then 'Jul'
when EXTRACT(month FROM off_datetime) = 8 then 'Aug'
when EXTRACT(month FROM off_datetime) = 9 then 'Sep'
when EXTRACT(month FROM off_datetime) = 10 then 'Oct'
when EXTRACT(month FROM off_datetime) = 11 then 'Nov'
when EXTRACT(month FROM off_datetime) = 12 then 'Dec'
end
as "Month"
from demerit d
left join offence o on d.dem_code = o.dem_code
order by d.dem_code
)
pivot(
count(dem_code_copy)
for "Month"
in (
'Jan','Feb','Mar','Apr','May','Jun','Jul','Aug','Sep','Oct','Nov','Dec'
)
)
This query gives me the monthly result
select
d.dem_code,
d.dem_description,
count(o.off_no) as total
from demerit d
left join offence o on d.dem_code = o.dem_code
group by d.dem_code, d.dem_description
order by d.dem_code
This query gives the total number
I would just use conditional aggregation:
select d.dem_code, d.dem_description,
sum(case when EXTRACT(month FROM off_datetime) = 1 then 1 else 0 end) as Jan,
sum(case when EXTRACT(month FROM off_datetime) = 2 then 1 else 0 end) as Feb
sum(case when EXTRACT(month FROM off_datetime) = 3 then 1 else 0 end) as Mar,
sum(case when EXTRACT(month FROM off_datetime) = 4 then 1 else 0 end) as Apr,
sum(case when EXTRACT(month FROM off_datetime) = 5 then 1 else 0 end) as May,
sum(case when EXTRACT(month FROM off_datetime) = 6 then 1 else 0 end) as Jun,
sum(case when EXTRACT(month FROM off_datetime) = 7 then 1 else 0 end) as Jul,
sum(case when EXTRACT(month FROM off_datetime) = 8 then 1 else 0 end) as Aug,
sum(case when EXTRACT(month FROM off_datetime) = 9 then 1 else 0 end) as Sep,
sum(case when EXTRACT(month FROM off_datetime) = 10 then 1 else 0 end) as Oct,
sum(case when EXTRACT(month FROM off_datetime) = 11 then 1 else 0 end) as Nov,
sum(case when EXTRACT(month FROM off_datetime) = 12 then 1 else 0 end) as Dec
from demerit d left join
offence o
on d.dem_code = o.dem_code
group by d.dem_code, d.dem_description;
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I am creating a feature for my application where I need to generate a report for the whole 2018.
I need to count all the tickets for 2018. Each ticket has a category.
For example:
Change of name.
Senior Citizen etc.
I need to count the number of change name tickets, senior citizen tickets for 2018 per month
I tried to to this but I can't seem to get the result that I want.
I can't seem to break down the count per month.
This is the query that I have so far:
SELECT SUBCATEGORY,COUNT(ticket_no)
FROM CNR_TICKET
WHERE date_created >= TO_DATE('1/01/2018','MM/DD/YYYY')
AND date_created <= TO_DATE('12/31/2018','MM/DD/YYYY')
GROUP BY SUBCATEGORY;
This is the columns I want to see:
CATEGORY | JAN | FEB | MARCH | APRIL | MAY | JNE | JUL | AUG | SEPT | OCT| NOV| DEC
SENIOR 2 5 20 50 1 11 23 4 1 2 4 6
COAN 23 55 22 55 6 2 12 23 12 12 5 89
Something like this :
SELECT
SUBCATEGORY,
count( distinct case when EXTRACT(month FROM date_created) = 1 then ticket_no else null end) as JAN,
count( distinct case when EXTRACT(month FROM date_created) = 2 then ticket_no else null end) as FEB,
count( distinct case when EXTRACT(month FROM date_created) = 3 then ticket_no else null end) as MARCH,
count( distinct case when EXTRACT(month FROM date_created) = 4 then ticket_no else null end) as APRIL,
count( distinct case when EXTRACT(month FROM date_created) = 5 then ticket_no else null end) as MAY,
count( distinct case when EXTRACT(month FROM date_created) = 6 then ticket_no else null end) as JNE,
count( distinct case when EXTRACT(month FROM date_created) = 7 then ticket_no else null end) as JUL,
count( distinct case when EXTRACT(month FROM date_created) = 8 then ticket_no else null end) as AUG,
count( distinct case when EXTRACT(month FROM date_created) = 9 then ticket_no else null end) as SEPT,
count( distinct case when EXTRACT(month FROM date_created) = 10 then ticket_no else null end) as OCT,
count( distinct case when EXTRACT(month FROM date_created) = 11 then ticket_no else null end) as NOV,
count( distinct case when EXTRACT(month FROM date_created) = 12 then ticket_no else null end) as DEC
FROM
CNR_TICKET
WHERE
date_created >= to_date('1/01/2018','MM/DD/YYYY') and
date_created <= to_date('12/31/2018','MM/DD/YYYY')
GROUP BY
SUBCATEGORY
you can change your WHERE clause using :
EXTRACT(year FROM date_created ) = 2018
You may try PIVOT statement
select * from (
select SUBCATEGORY, month(date_created) mon
from CNR_TICKET
where date_created >= to_date('1/01/2018','MM/DD/YYYY') and date_created <= to_date('12/31/2018','MM/DD/YYYY')
)
pivot (
count(*)
for mon
in ( 1 Jan, 2 Feb, 3 MARCH, 4 APRIL, 5 MAY, 6 JNE, 7 JUL, 8 AUG, 9 SEPT, 10 OCT, 11 NOV, 12 DEC )
)
you can use Pivot keyword by using for month for the pivoting query as
select *
from
(
select subcategory, to_char(date_created,'mm') as month
from cnr_ticket
where to_char(date_created,'yyyy')='2018'
)
pivot(
count(*)
for (month)
in ('01' as jan ,'02' as feb, '03' as mar,
'04' as apr ,'05' as may, '06' as jun,
'07' as jul ,'08' as aug, '09' as sep,
'10' as oct ,'11' as nov, '12' as dec
)
)
or using conditional aggregation
select subcategory,
sum(case when to_char(date_created,'mm') = '01' then 1 else 0 end) as jan,
sum(case when to_char(date_created,'mm') = '02' then 1 else 0 end) as feb,
sum(case when to_char(date_created,'mm') = '03' then 1 else 0 end) as mar,
sum(case when to_char(date_created,'mm') = '04' then 1 else 0 end) as apr,
sum(case when to_char(date_created,'mm') = '05' then 1 else 0 end) as may,
sum(case when to_char(date_created,'mm') = '06' then 1 else 0 end) as jun,
sum(case when to_char(date_created,'mm') = '07' then 1 else 0 end) as jul,
sum(case when to_char(date_created,'mm') = '08' then 1 else 0 end) as aug,
sum(case when to_char(date_created,'mm') = '09' then 1 else 0 end) as sep,
sum(case when to_char(date_created,'mm') = '10' then 1 else 0 end) as oct,
sum(case when to_char(date_created,'mm') = '11' then 1 else 0 end) as nov,
sum(case when to_char(date_created,'mm') = '12' then 1 else 0 end) as dec
from cnr_ticket
where to_char(date_created,'yyyy')='2018'
group by subcategory
Rextester Demo
I have a Shipments table which basicly contains Shipments data with dates
id is integer
dateshipped is date
id dateshipped
1 1-JAN-16
2 1-JAN-16
3 3-FEB-16
4 9-FEB-16
I want to write a query which count all shipments based on Months.
What I should get is:
Jan Feb March....
2 2 0
I know I can do it by having query for each column, get only relevent rows for this specific month and just count them.
As follows:
Select (Select count(*)
from Shipments
Where EXTRACT(YEAR FROM dateshipped)::int=2016 and EXTRACT(MONTH FROM dateshipped)::int=1 )as JAN,
(Select count(*)
from Shipments
Where EXTRACT(YEAR FROM dateshipped)::int=2016 and EXTRACT(MONTH FROM dateshipped)::int=2 )as FEB
This works however its too much of the same code...
I am wondring if it is possible to do it with a single FROM statment and each column get it's own relevent rows for count.
Something like:
Select COL1,COL2,COL3...
from Shipments
Where EXTRACT(YEAR FROM dateshipped)::int=2016;
and have something like:
COL1 = count only JAN records
COL2 = count only FEB records
....
maybe there is something with Parations on months or any other solution?
You need a pivot query to accomplish this:
SELECT SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 1 THEN 1 ELSE 0 END) AS Jan,
SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 2 THEN 1 ELSE 0 END) AS Feb,
SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 3 THEN 1 ELSE 0 END) AS Mar,
SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 4 THEN 1 ELSE 0 END) AS Apr,
SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 5 THEN 1 ELSE 0 END) AS May,
SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 6 THEN 1 ELSE 0 END) AS Jun,
SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 7 THEN 1 ELSE 0 END) AS Jul,
SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 8 THEN 1 ELSE 0 END) AS Aug,
SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 9 THEN 1 ELSE 0 END) AS Sep,
SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 10 THEN 1 ELSE 0 END) AS Oct,
SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 11 THEN 1 ELSE 0 END) AS Nov,
SUM(CASE WHEN EXTRACT(MONTH FROM dateshipped)::int = 12 THEN 1 ELSE 0 END) AS Dec
FROM Shipments
WHERE EXTRACT(YEAR FROM dateshipped)::int=2016
Since 9.4 you can use FILTER
SELECT
count(*) AS total,
count(*) FILTER (WHERE Extract(MONTH FROM dateshipped)::int=1) AS JAN,
count(*) FILTER (WHERE Extract(MONTH FROM dateshipped)::int=2) AS FEB,
...
FROM Shipments
WHERE Extract(YEAR FROM dateshipped)::int=2016;
Try case with sum function:
Select
sum(case when extract(MONTH from dateshipped)=1 then 1 else 0 end) as jan,
sum(case when extract(MONTH from dateshipped)=2 then 1 else 0 end) as feb,
sum(case when extract(MONTH from dateshipped)=3 then 1 else 0 end) as march
.....
.....
from Shipments
Where EXTRACT(YEAR FROM dateshipped)::int=2016;
I do have a table license_Usage which works like a log of the usage of licenses in a day
ID User license date
1 1 A 22/1/2015
2 1 A 23/1/2015
3 1 B 23/1/2015
4 1 A 24/1/2015
5 2 A 22/2/2015
6 2 A 23/2/2015
7 1 B 23/2/2015
Where I want it to return the count of licenses of the day of the month with most usage of licenses the result should look like:
User Jan Feb
1 2 1 ...
2 0 2
I know I can get the total of licenses in a month using this query:
SELECT vlu.[Userkey],
COUNT(CASE WHEN MONTH = 1 THEN 1 END) as JAN,
COUNT(CASE WHEN MONTH = 2 THEN 1 END) as FEB,
COUNT(CASE WHEN MONTH = 3 THEN 1 END) as MAR,
COUNT(CASE WHEN MONTH = 4 THEN 1 END) as APR,
COUNT(CASE WHEN MONTH = 5 THEN 1 END) as MAY,
COUNT(CASE WHEN MONTH = 6 THEN 1 END) as JUN,
COUNT(CASE WHEN MONTH = 7 THEN 1 END) as JUL,
COUNT(CASE WHEN MONTH = 8 THEN 1 END) as AUG,
COUNT(CASE WHEN MONTH = 9 THEN 1 END) as SEP,
COUNT(CASE WHEN MONTH = 10 THEN 1 END) as OCT,
COUNT(CASE WHEN MONTH = 11 THEN 1 END) as NOV,
COUNT(CASE WHEN MONTH = 12 THEN 1 END) as DEC
FROM license_usage vlu
CROSS APPLY (SELECT MONTH(vlu.EndDate)) AS CA(Month)
WHERE vlu.[EndDate] >='2015-01-01'
AND vlu.[EndDate] < '2016-01-01'
GROUP BY vlu.[Userkey]
How can I get it to return my results?
Example:
http://sqlfiddle.com/#!3/be0b4/1
Got it by using distinct on the Count (*)
select umd.pbrUserkey,
max(case when mm = 1 then cnt else 0 end) as Jan,
max(case when mm = 2 then cnt else 0 end) as Feb,
max(case when mm = 3 then cnt else 0 end) as Mar,
max(case when mm = 4 then cnt else 0 end) as Apr,
max(case when mm = 5 then cnt else 0 end) as May
from (select vluk.pbrUserkey, month(vluk.EndDate) as mm, day(vluk.EndDate) as dd,
count(distinct vluk.idPackage) as cnt
from [license_usage] as vluk
where vluk.[EndDate] >= '2015-01-01' AND vluk.[EndDate] < '2016-01-01'
group by vluk.Userkey, month(vluk.EndDate), day(vluk.EndDate)
) umd
group by umd.Userkey;
If I understand correctly, you want the maximum by day usage per month for each user. The basic data you want is:
select UserKey, month(license_usage) as mm, day(license_usage) as dd,
count(distinct license) as cnt
from license_usage vlu
where vlu.EndDate] >= '2015-01-01' and vlu.EndDate < '2016-01-01'
group by UserKey, month(license_usage), day(license_usage);
Then you can pivot this in several ways, such as using conditional aggregation:
select UserKey,
max(case when mm = 1 then cnt else 0 end) as Jan,
. . .
from (select UserKey, month(license_usage) as mm, day(license_usage) as dd,
count(distinct license) as cnt
from license_usage vlu
where vlu.EndDate] >= '2015-01-01' AND vlu.EndDate < '2016-01-01'
group by UserKey, month(license_usage), day(license_usage)
) umd
group by UserKey;
CROSS APPLY is an interesting approach, but I can't think of a simpler way to get this information.
When running the following query I am trying to find a way to display the returned months by federal fiscal year instead of normal sequential value.
(ie I want to display months in the following order Oct, Nov, Dec, Jan, Feb, Mar, Apr, May Jun, Jul, Aug, Sept instead of Jan thru Dec.) Thanks
select wrkgrp,
sum (case when extract(month from reportdate) = 1 then 1 else 0 end) as January,
sum (case when extract(month from reportdate) = 2 then 1 else 0 end) as February,
sum (case when extract(month from reportdate) = 3 then 1 else 0 end) as March,
sum (case when extract(month from reportdate) = 4 then 1 else 0 end) as April,
sum (case when extract(month from reportdate) = 5 then 1 else 0 end) as May,
sum (case when extract(month from reportdate) = 6 then 1 else 0 end) as June,
sum (case when extract(month from reportdate) = 7 then 1 else 0 end) as July,
sum (case when extract(month from reportdate) = 8 then 1 else 0 end) as August,
sum (case when extract(month from reportdate) = 9 then 1 else 0 end) as September,
sum (case when extract(month from reportdate) = 10 then 1 else 0 end) as October,
sum (case when extract(month from reportdate) = 11 then 1 else 0 end) as November,
sum (case when extract(month from reportdate) = 12 then 1 else 0 end) as December,
from workorder
where reportdate between to_date ('2014-10-01 00:00:00', 'yyyy/mm/dd hh24:mi:ss')
and to_date ('2015-09-30 00:00:00', 'yyyy/mm/dd hh24:mi:ss')
and wrkgrp = 'PublicWorks'
group by 'wrkgrp;'
The fields will display in your results (horizontally) in the order you list them in your select statement. Structure your statement with Oct listed first like this:
select wrkgrp,
sum (case when extract(month from reportdate) = 10 then 1 else 0 end) as October,
sum (case when extract(month from reportdate) = 11 then 1 else 0 end) as November,
sum (case when extract(month from reportdate) = 12 then 1 else 0 end) as December,
sum (case when extract(month from reportdate) = 1 then 1 else 0 end) as January,
sum (case when extract(month from reportdate) = 2 then 1 else 0 end) as February,
sum (case when extract(month from reportdate) = 3 then 1 else 0 end) as March,
sum (case when extract(month from reportdate) = 4 then 1 else 0 end) as April,
sum (case when extract(month from reportdate) = 5 then 1 else 0 end) as May,
sum (case when extract(month from reportdate) = 6 then 1 else 0 end) as June,
sum (case when extract(month from reportdate) = 7 then 1 else 0 end) as July,
sum (case when extract(month from reportdate) = 8 then 1 else 0 end) as August,
sum (case when extract(month from reportdate) = 9 then 1 else 0 end) as September
from workorder
where reportdate between to_date ('2014-10-01 00:00:00', 'yyyy/mm/dd hh24:mi:ss') ad to_date ('2015-09-30 00:00:00', 'yyyy/mm/dd hh24:mi:ss') and
wrkgrp = 'PublicWorks'
group by 'wrkgrp;'
Add case statements in your order by clause to get the desired sort.
ORDER BY
CASE WHEN extract(month from reportdate) = 10 THEN 1
CASE WHEN extract(month from reportdate) = 11 THEN 2
ASC