this is the first time I've tried including a row count within a select statement. I've tried the following but including COUNT(other row) is apparently not allowed in the way I'm trying to do it.
How can I include a row count from another table in a select statement, mainly consisting of objects from the first table?
-Thanks
...
SELECT
Reports.ReportID,
EmployeeADcontext,
ReportName,
CreatedDate,
COUNT(Expenses.ExpID) AS ExpCount,
ReportTotal,
Status
FROM
[dbo].[Reports]
INNER JOIN
[dbo].[Expenses]
ON
[dbo].[Expenses].ReportID = [dbo].[Reports].ReportID
WHERE EmployeeADcontext = #rptEmployeeADcontext
You are missing your GROUP BY. Whenever you aggregate (SUM, COUNT, MAX, etc..) you always need to include a GROUP BY statement that includes all visible fields except your aggregated fields. So your code should read:
SELECT
Reports.ReportID,
EmployeeADcontext,
ReportName,
CreatedDate,
COUNT(Expenses.ExpID) AS ExpCount,
ReportTotal,
Status
FROM
[dbo].[Reports]
INNER JOIN
[dbo].[Expenses]
ON
[dbo].[Expenses].ReportID = [dbo].[Reports].ReportID
WHERE EmployeeADcontext = #rptEmployeeADcontext
GROUP BY Reports.ReportID, EmployeeADcontext, ReportName, CreatedDate,
ReportTotal, Status
Here is some additional documentation on T-SQL GROUP BY.
You need a group by clause.
Add:
GROUP BY
Reports.ReportID,
EmployeeADcontext,
ReportName,
CreatedDate,
ReportTotal,
Status
You could use a sub-query to return the count. That way you don't need any joins. For example:
SELECT
r.ReportID,
r.EmployeeADcontext,
r.ReportName,
r.CreatedDate,
(select COUNT(e1.ExpID) FROM Expenses e1 where e1.ReportID = r.ReportId) AS ExpCount,
r.ReportTotal,
r.Status
FROM Reports r
WHERE r.EmployeeADcontext = #rptEmployeeADcontext
Related
I am trying to subquery and aggregate in SQL after doing an initial query with multiple joins. My ultimate goal is to get a count (or a sum) of specimens tested based on a grouping of multiple columns. This is slightly different from SQL Server query - Selecting COUNT(*) with DISTINCT and SQL Server: aggregate error on grouping.
The three tables that I use (PERSON, SPECIMEN, TEST), have 1-many relationships. So PERSON has many SPECIMENS and those SPECIMENS have many TESTS. I did three inner joins to combine these tables plus an additional table (ANALYSIS).
WITH TALLY as (
SELECT PERSON.NAME, PERSON.PHASE, TEST.DATE_STARTED, TEST.ANALYSIS, SPECIMEN.GROUP, TEST.STATUS,
ANALYSIS.ANALYSIS_TYPE, SPECIMEN.SPECIMEN_NUMBER
FROM DB.TEST
INNER JOIN
DB.SAMPLE ON
TEST.SPECIMEN_NUMBER = SPECIMEN.SPECIMEN_NUMBER
INNER JOIN
DB.PRODUCT ON
SPECIMEN.PERSON = PERSON.NAME
INNER JOIN
DB.ANALYSIS ON
TEST.ANALYSIS = ANALYSIS.NAME
WHERE PERSON.NAME = 'Joe'
AND TEST.DATE_STARTED >= '20-DEC-16' AND TEST.DATE_STARTED <='01-APR-18'
AND PERSON.PHASE = 'PHASE1'
ORDER BY TEST.DATE_STARTED)
SELECT COUNT(DISTINCT ANALYSIS) as SPECIMEN_COUNT, DATE_STARTED, ANALYSIS, STATUS, GROUP, ANALYSIS_TYPE
FROM TALLY
GROUP BY DATE_STARTED, ANALYSIS, STATUS, GROUP, ANALYSIS_TYPE
ORDER BY DATE_STARTED;
This gives me the repeated columns: first grouping repeated 4 times
What I am trying to see is: aggregated first grouping with total count
Any thoughts as to what is missing? SUM instead of COUNT or in addition to COUNT creates an error. Thanks in advance!
9/17/2020 Update: I have tried adding a subquery because I also need to use a new column of metadata (ANALYSIS_TYPE_ALIAS) which is created in the first query through a CASE STATEMENT(...). I have also tried using another subquery with inner join to count based on those conditions to a temp table, but still cannot seem to aggregate to flatten the table. Here is my current attempt:
WITH TALLY as (
SELECT PERSON.NAME, PERSON.PHASE, TEST.DATE_STARTED, TEST.ANALYSIS, SPECIMEN.GROUP, TEST.STATUS,
ANALYSIS.ANALYSIS_TYPE...
FROM DB.TEST
INNER JOIN
DB.SAMPLE ON
TEST.SPECIMEN_NUMBER = SPECIMEN.SPECIMEN_NUMBER
INNER JOIN
DB.PRODUCT ON
SPECIMEN.PERSON = PERSON.NAME
INNER JOIN
DB.ANALYSIS ON
TEST.ANALYSIS = ANALYSIS.NAME
WHERE PERSON.NAME = 'Joe'
AND TEST.DATE_STARTED >= '20-DEC-16' AND TEST.DATE_STARTED <='01-APR-18'
AND PERSON.PHASE = 'PHASE1'
ORDER BY TEST.DATE_STARTED),
SUMMARY_COMBO AS (SELECT DISTINCT(CONCAT(CONCAT(CONCAT(CONCAT(ANALYSIS, DATE_STARTED),STATUS), GROUP), ANALYSIS_TYPE_ALIAS))AS UUID,
TALLY.NAME, TALLY.PHASE, TALLY.DATE_STARTED, TALLY.ANALYSIS, TALLY.GROUP, TALLY.STATUS, TALLY.ANALYSIS_TYPE_ALIAS
FROM TALLY)
SELECT SUMMARY_COMBO.NAME, SUMMARY_COMBO.PHASE, SUMMARY_COMBO.DATE_STARTED, SUMMARY_COMBO.ANALYSIS,SUMMARY_COMBO.GROUP, SUMMARY_COMBO.STATUS, SUMMARY_COMBO.ANALYSIS_TYPE_ALIAS,
COUNT(SUMMARY_COMBO.ANALYSIS) OVER (PARTITION BY SUMMARY_COMBO.UUID) AS SPECIMEN_COUNT
FROM SUMMARY_COMBO
ORDER BY SUMMARY_COMBO.DATE_STARTED;
This gave me the following table Shows aggregated counts, but doesn't aggregate based on unique UUID. Is there a way to take the sum of the count? I've tried to do this by storing count to a subquery and then referencing that count variable, but I am missing something in how to group the 8 columns of data that I want to show + the count of that combination of columns.
Thanks!
Just remove analysis from the group by clause, since that's the column whose distinct values you want to count. Otherwise, the query generates more groups than what you need (and the count of distinct analysis values in each group is always 1).
WITH TALLY as ( ...)
SELECT COUNT(DISTINCT ANALYSIS) as SPECIMEN_COUNT, DATE_STARTED, ANALYSIS, STATUS, GROUP, ANALYSIS_TYPE
FROM TALLY
GROUP BY DATE_STARTED, STATUS, GROUP, ANALYSIS_TYPE
ORDER BY DATE_STARTED;
I cannot solve a problem with my GROUP BY problem in my query containing CASE...WHEN
Could you help me please with that?
select ID,
CODE,
NOM AS TITLE,
level,
ID_PARENT,
CASE ID_PARENT
WHEN 1111 THEN 'MAIN'
ELSE
(
SUBSTR(
(
SELECT CODE FROM units o
INNER JOIN LIB_UNITS_MV oLab on oLab.ID = o.ID WHERE o.ID = units.ID_PARENT AND LNG_CD = 'ENG'
)
, 7)
)
END AS "PARENT_CODE"
from units
INNER JOIN LIB_UNITS_MV orgLab on orgLab.ID = units.ID
WHERE orgLab.LNG ='ENG'
start with units.id = 1111
connect by prior u.ID = u.ID_PARENT
GROUP BY ID, CODE, NOM, level, ID_PARENT
I obtain the error "not a GROUP BY expression" because I have the WHEN...CASE
Thank you in advance for your help
Regards
Becuase when you group by you need to group by sufficient number of columns, which you use in select statement, outside aggregating functions (min, max, sum etc). So in your case this means - you can either group by all columns used in your case statement, or group by the whole case statement (just copy it over to your group by), or any set of sub-combinations of the whole case, altogether covering it completely. However - since you are not using any aggregate functions I would just do distinct and drop group by altogether.
I got help with a function yesterday to correctly get the count of multiple items in a column based on multiple criteria/columns. However, if there is a way to get the DISTINCT count of all the entries in the table based on aggregated GROUP BY statement.
SELECT TIME = ap.day,
acms.tenantId,
acms.CallingService,
policyList = ltrim(sp.value),
policyInstanceList = ltrim(dp.value),
COUNT(*) AS DISTINCTCount
FROM dbo.acms_data acms
CROSS APPLY string_split(acms.policyList, ',') sp
CROSS APPLY string_split(acms.policyInstanceList, ',') dp
CROSS APPLY (select day = convert(date, acms.[Time])) ap
GROUP BY ap.day, acms.tenantId, sp.value, dp.value, acms.CallingService
I would just like to know if there would be a way to see if there is a workaround for using DISTINCT and Count(*) together and whether or not it would affect my results to make this algorithm potentially invulnerable to duplicate entries.
The reason why I have to use COUNT(*) is because I am aggregating based on every column in the table not just a specific column or multiple.
We can use DISTINCT with COUNT together like this example.
USE AdventureWorks2012
GO
-- This query shows 290 JobTitle
SELECT COUNT(JobTitle) Total_JobTitle
FROM [HumanResources].[Employee]
GO
-- This query shows only 67 JobTitle
SELECT COUNT( DISTINCT JobTitle) Total_Distinct_JobTitle
FROM [HumanResources].[Employee]
GO
select COUNT(analysed) from Results where analysed="True"
I want to display count of rows in which analysed value is true.
However, my query gives the error: "The multi-part identifier "Results.runId" could not be bound.".
This is the actual query:
select ((SELECT COUNT(*) AS 'Count'
FROM Results
WHERE Analysed = 'True')/failCount) as PercentAnalysed
from Runs
where Runs.runId=Analysed.runId
My table schema is:
The value I want for a particular runId is: (the number of entries where analysed=true)/failCount
EDIT : How to merge these two queries?
i) select runId,Runs.prodId,prodDate,prodName,buildNumber,totalCount as TotalTestCases,(passCount*100)/(passCount+failCount) as PassPercent,
passCount,failCount,runOwner from Runs,Product where Runs.prodId=Product.prodId
ii) select (cast(counts.Count as decimal(10,4)) / cast(failCount as decimal(10,4))) as PercentAnalysed
from Runs
inner join
(
SELECT COUNT(*) AS 'Count', runId
FROM Results
WHERE Analysed = 'True'
GROUP BY runId
) counts
on counts.runId = Runs.runId
I tried this :
select runId,Runs.prodId,prodDate,prodName,buildNumber,totalCount as TotalTestCases,(passCount*100)/(passCount+failCount) as PassPercent,
passCount,failCount,runOwner,counts.runId,(cast(counts.Count as decimal(10,4)) / cast(failCount as decimal(10,4))) as PercentAnalysed
from Runs,Product
inner join
(
SELECT COUNT(*) AS 'Count', runId
FROM Results
WHERE Analysed = 'True'
GROUP BY runId
) counts
on counts.runId = Runs.runId
where Runs.prodId=Product.prodId
but it gives error.
Your problems are arising from improper joining of tables. You need information from both Runs and Results, but they aren't combined properly in your query. You have the right idea with a nested subquery, but it's in the wrong spot. You're also referencing the Analysed table in the outer where clause, but it hasn't been included in the from clause.
Try this instead:
select (cast(counts.Count as decimal(10,4)) / cast(failCount as decimal(10,4))) as PercentAnalysed
from Runs
inner join
(
SELECT COUNT(*) AS 'Count', runId
FROM Results
WHERE Analysed = 'True'
GROUP BY runId
) counts
on counts.runId = Runs.runId
I've set this up as an inner join to eliminate any runs which don't have analysed results; you can change it to a left join if you want those rows, but will need to add code to handle the null case. I've also added casts to the two numbers, because otherwise the query will perform integer division and truncate any fractional amounts.
I'd try the following query:
SELECT COUNT(*) AS 'Count'
FROM Results
WHERE Analysed = 'True'
This will count all of your rows where Analysed is 'True'. This should work if the datatype of your Analysed column is either BIT (Boolean) or STRING(VARCHAR, NVARCHAR).
Use CASE in Count
SELECT COUNT(CASE WHEN analysed='True' THEN analysed END) [COUNT]
FROM Results
Click here to view result
select COUNT(*) from Results where analysed="True"
I have 2 tables, Student and Supervisor:
STUDENT(supervisorid(pk),name,email....)
SUPERVISOR(supervisorid(pk),name,email....)
Now I need to print supervisor name, email and the # of students under the supervisor (they will have same supervisor id). Something like:
select supervisorname,
supervisoremail,
tot_stud as (select count(*)
Phd_Student s
where s.supervisor_id = r.supervisor_id)
from Phd_Supervisor r
Can you please tell me the SQL query for this.
You will want to use the group by clause for this query. You can specify all of the fields that you want to display, as well as the count(*), join the tables, relate the tables , and then put in your group by clause, listing all of the display fields,(without the count(*)), as those are the fields you are grouping the students by to get their count.
select supervisorname,
supervisoremail,
(select count(*)
from Phd_Student s
where s.supervisor_id = r.supervisor_id) as tot_stud
from Phd_Supervisor r