I have a table that has column with statuses. I need to write the query that returns records where some column value appears more than once?
Something like this:
select * from Table1
where COUNT(StatusID = 6) > 1
You can write your query like following:
SELECT *
FROM Table1
WHERE StatusID IN
(
SELECT StatusID
FROM (SELECT StatusID,Count(*) AS cnt FROM Table1 WHERE StatusID=6
GROUP BY StatusID
HAVING COUNT(*) > 1) AS tbl
)
Related
I have a table with data similar to below. I am trying to get a list of results that will display all rows where only one unique SourceID exists in status 10. If I were querying this table, I would expect ID's 3 and 4 to be returned.
Table Example
Select *
From table
Where Status = 10 and Source ID in
(
Select SourceID
From Table
Group by SourceID
Having Count(*) = 1
)
You can use NOT EXISTS :
SELECT t.*
FROM table t
WHERE NOT EXISTS (SELECT 1 FROM table t1 WHERE t1.SourceID = t.SourceID AND t1.Status <> t.Status);
Maybe that would work?
SELECT ID FROM Mytable
WHERE [Status] = 10
GROUP BY ID
HAVING COUNT(SourceID) = 1
First, find out all the unique SourceIDs
SELECT
SourceID
FROM
Data
GROUP BY
SourceID
HAVING
COUNT(SourceID) = 1
And then use this query as a sub query to get all the rows that has unique SourceID;
SELECT
*
FROM
Data
WHERE
SourceID IN (
SELECT
SourceID
FROM
Data
GROUP BY
SourceID
HAVING
COUNT(SourceID) = 1
)
Use a sub-query to check if t there is an exact count of 1 of those source id's
SELECT t.* FROM YourTable t WHERE t.status = 10
AND
(SELECT COUNT(0) x From YourTable t2
where t2.sourceid = t.sourceid) = 1
I have a table in sql like this:
id billpay
-------------------------
1024 0
1024 0
1024 1
1025 1
1025 1
I want to retrieve only those id having billpay 1
Please help me with this
Try this:
select distinct id from yourtable where billpay = 1
It should be like this:
SELECT id FROM tabel WHERE billpay = 1;
This will retrieve those ids in ascending order which have at least one record in the table with billpay = 1.
The DISTINCT keyword will ensure you don't receive back multiple records with the same id.
SELECT DISTINCT id
FROM [TableName]
WHERE billpay = 1
ORDER BY id ASC
If you want to exclude those ids which also have records with billpay = 0, then use this:
SELECT DISTINCT id
FROM [TableName]
WHERE billpay = 1
AND id NOT IN (SELECT id FROM [TableName] WHERE billpay = 0)
ORDER BY id ASC
Regards,
select ID
from MyData
Where billpay = 1
Group By ID
The group by will list unique IDs
select ID
from MyData A
Where not exists (select 'X' from MyData B where B.billpay <> 1 and B.ID = A.ID)
Group By ID
This will only list IDs where billpay is only 1
Try this:
SELECT id
FROM mytable
GROUP BY id
HAVING COUNT(CASE WHEN COALESCE(billpay, 0) <> 1 THEN 1 END) = 0
The above will select only those ids associated to billpay=1 and nothing but billpay=1.
SQL Fiddle Demo
The following query selects the ids from group of ids where the number of records with billpay = 1 is the same as the number of records in the group
select id
from bills
group by id
having sum(billpay) = count(id)
Use NOT EXISTS to find rows with no other than billplay 1, use DISTINCT to return only one of each id found.
select distinct id
from tablename t1
where not exists (select 1 from tablename t2
where t1.id = t2.id
and t2.billpay <> 1)
Try to use GROUP BY +MIN statement to exclude Id's with existing billpay=0
SELECT id
FROM yourtable
GROUP BY id
HAVING MIN(billpay)=1
SELECT AS, COUNT(*)
FROM Table1
HAVING COUNT(AS)>1
group BY AS;
This produces the result
AS COUNT
5 2
I then want to use the AS value in another query and only output the end result. Is this possible.i was thinking something like.
SELECT *
FROM
TABLE 2
Where AS =(
SELECT AS, COUNT(*)
FROM Table1
HAVING COUNT(AS)>1
group BY AS;
);
This is called a subquery. To be safe, you would use in instead of = (and as is a bad name for a column, because it is a SQL key word):
SELECT *
FROM TABLE2
WHERE col IN (SELECT col
FROM Table1
GROUP BY col
HAVING COUNT(col) > 1
);
Your first query is also incorrect, because the having clause goes after the group by.
You could use a subquery with the in operator:
SELECT *
FROM table2
WHERE AS IN (SELECT AS
FROM table1
GROUP BY AS
HAVING COUNT(*) > 1)
I have a set of data as below
number quantity
1 4
2 6
3 7
4 9
2 1
1 2
5 4
I need to find the unique value in the column "number"
The output should look like this:
number quantity
3 7
4 9
5 4
Any help would be appreciated. I am using MS SQL
In the inner query get all the distinct numbers, then join with again with the main table to get your expected results.
select o.*
from mytable o , (select number
from mytable
group by number) dist
where o.number = dist.number
One way to go could be to have an aggregate query that counts the number of occurrences for each number use it in a subquery:
SELECT number, quantity
FROM my_table
WHERE number IN (SELECT number
FROM my_table
GROUP BY number
HAVING COUNT(*) = 1)
If your column name is my_column in table my_table, the query is:
SELECT my_column, COUNT(*) as count
FROM my_table
GROUP BY my_column
HAVING COUNT(*) > 1
This will return all records that have duplicate my_column content, as well as how many times this content occurs in the database.
you can use below code for desire output:
SELECT DISTINCT(my_column), COUNT(*) as count
FROM my_table
GROUP BY my_column
Try this :
SELECT *
FROM yourtable t1
WHERE (SELECT Count(*)
FROM yourtable t2
WHERE t1.number = t2.number) = 1
Query in where clause will return number of occurrences of each number and checking it with 1 will return only those rows will have only one occurrence in table.
You can probably use ROW_NUMBER() analytic function like
select * from
(
select number,
quantity,
ROW_NUMBER() OVER(PARTITION BY number ORDER BY number) AS rn
from table1
) tab where rn = 1;
Try this:
create table #TableName(number int, quantity int)
insert into #TableName values(1, 2)
insert into #TableName values(1, 4)
insert into #TableName values(2, 4)
SELECT number, quantity
FROM #TableName
WHERE number
IN(SELECT number
FROM #TableName
GROUP BY number
HAVING COUNT(NUMBER) = 1)
I have a sql statement that says
SELECT coalesce((Select sum(SomeNumber)
FROM Table
WHERE ID NOT IN (SELECT IDs...)), 0) MyFirstNumber,
coalesce((Select sum(SomeNumber2)
FROM Table
WHERE ID NOT IN (SELECT IDs...)), 0) MySecondNumber
How can I make the (SELECT IDs...) query statement be called only once, say before the statement above.
I think it would be something like
DECLARE #MyIDs
SET #MyIDs = SELECT IDs FROM TABLE WHERE ...
SELECT coalesce((Select sum(SomeNumber)
FROM Table
WHERE ID NOT IN (#MyIDs)), 0) MyFirstNumber,
coalesce((Select sum(SomeNumber2)
FROM Table
WHERE ID NOT IN (#MyIDs)), 0) MySecondNumber
how about joining with that subselect and fitering only where the join is false ( returns null)
SELECT sum(coalesce(SomeNumber,0)) MyFirstNumber
,sum(coalesce(SomeNumber2,0)) MySecondNumber
FROM Table
LEFT JOIN (SELECT IDs.. FROM Table ) AS Filter ON Table.ID = Filter.ID
WHERE Filter.ID IS NULL
Calculate the amount in one SELECT statement
SELECT COALESCE(SUM(SomeNumber), 0) AS MyFirstNumber,
COALESCE(SUM(SomeNumber2), 0) AS MySecondNumber
FROM Table
WHERE ID NOT IN (SELECT IDs FROM TABLE WHERE...)
If need different conditions you can use CASE expression within SUM() functions
SELECT COALESCE(SUM(SomeNumber), 0) AS MyFirstNumber,
COALESCE(SUM(SomeNumber2), 0) AS MySecondNumber,
COALESCE(SUM(CASE WHEN ... THEN SomeNumber3 END), 0) AS MyThirdNumber
FROM Table
WHERE ID NOT IN (SELECT IDs FROM TABLE WHERE...)