I want to test some cases in my app with strings which have the same hash, and I can't find it =(
I've found two strings with the same MD5. here But their hash are different. And googling didn't help me =(
NSString(MD5) category
Little story about NSDictionary
- (void)applicationDidFinishLaunching:(NSNotification *)aNotification {
NSString *string1 = [self fileContentWithName:#"message1" encoding:NSUnicodeStringEncoding];
NSString *string2 = [self fileContentWithName:#"message2" encoding:NSUnicodeStringEncoding];
if (string1 != nil) {
if (string1.hash == string2.hash) {
NSLog(#"Hashes are the same");
} else {
if ([[string1 MD5Hash] isEqualToString:[string2 MD5Hash]]) {
NSLog(#"MD5 hases are equalfor:");
NSLog(#"lenght = %3ld - %#", string1.length, string1);
NSLog(#"lenght = %3ld - %#", string2.length, string2);
if ([string1 isEqualToString:string2]) {
NSLog(#"Strings are equal too");
} else {
NSLog(#"But strings are not equal");
}
}
}
}
}
#pragma mark -
- (NSString*)fileContentWithName:(NSString*)name encoding:(NSStringEncoding)enc
{
NSString *txtFilePath1 = [[NSBundle mainBundle] pathForResource:name ofType:#"bin"];
NSError *error = nil;
NSString *txtFileContents1 = [NSString stringWithContentsOfFile:txtFilePath1 encoding:enc error:&error];
return txtFileContents1;
}
I'm implementing an autocomplete in cocoa for an OSX application and thus far I've got it all pinned down. The one hangup is that the autocomplete is case-sensitive and that's not really what I want/need. Ideally the autocomplete will be case INSENSITIVE. Relevant code below:
#implementation autocompleteController
- (void)viewDidLoad {
[super viewDidLoad];
self.textField.delegate = self;
}
-(void)controlTextDidChange:(NSNotification *)obj{
NSTextView * fieldEditor = [[obj userInfo] objectForKey:#"NSFieldEditor"];
if (self.isAutocompleting == NO && !self.backspaceKey) {
self.isAutocompleting = YES;
self.lastEntry = [[[fieldEditor string] capitalizedString] copy];
[fieldEditor complete:nil];
self.isAutocompleting = NO;
}
if (self.backspaceKey) {
self.backspaceKey = NO;
}
}
-(NSArray *)control:(NSControl *)control textView:(NSTextView *)textView completions:(NSArray *)words forPartialWordRange:(NSRange)charRange indexOfSelectedItem:(NSInteger *)index{
NSMutableArray * suggestions = [NSMutableArray array];
NSArray * possibleStrings = #[#"TEST", #"ABC", #"abc", #"amauroy", #"AMA", #"amazing"];
if (!self.lastEntry || !possibleStrings) {
return nil;
}
for (NSString * string in possibleStrings) {
if ([string hasPrefix:self.lastEntry]) {
[suggestions addObject:string];
}
}
return suggestions;
}
-(BOOL)control:(NSControl *)control textView:(NSTextView *)textView doCommandBySelector:(SEL)commandSelector{
if (commandSelector == #selector(deleteBackward:)) {
self.backspaceKey = YES;
}
return NO;
}
#end
As Pro Blaster points out, the problem is with the following line:
if ([string hasPrefix:self.lastEntry]) {
Your autocompletion is case-sensitive because -hasPrefix: is case-sensitive. One approach is to convert everything to lower case (upper case would also work, of course). Another is to write a case-insensitive version of -hasPrefix: and add it to NSString using a category, like this:
#interface NSString (autocomplete)
- (BOOL)hasPrefixIgnoringCase:(NSString*)aString;
#end;
#implementation NSString (autocomplete)
- (BOOL)hasPrefixIgnoringCase:(NSString*)aString
{
NSRange *prefix = [self rangeOfString:aString options:NSCaseInsensitiveSearch];
return prefix.location == 0 && prefix.length == aString.length;
}
#end
Then use that method in your code:
if ([string hasPrefixIgnoringCase:self.lastEntry]) {
Note: The provided code is untested. The concept is sound, but you may find a syntax error or two.
I did this once.
You would do so by replacing :
for (NSString * string in possibleStrings) {
if ([string hasPrefix:self.lastEntry]) {
[suggestions addObject:string];
}
}
return suggestions
with:
for (NSString * string in possibleStrings) {
if ([[string lowercaseString] hasPrefix:[self.lastEntry lowercaseString]]) {
[suggestions addObject:string];
}
}
return suggestions;
This question already has answers here:
Restrict NSTextField to only allow numbers
(10 answers)
Closed 8 years ago.
In textfield I want to restrict numbers like (1234567890) and special characters but I want to allow alphanumeric characters. How I am suppose to do this?
Use the UITextField delegate method
textField:shouldChangeCharactersInRange:replacementString:
To check the string that is about to be replaced, if you allow it then return yes if not then return no.
Here is some more information.
Apple UITextField Delegate
try following code
+ (BOOL)isNumber:(NSString *)value {
if ( (value == nil) || ([#"" isEqualToString:value]) ) {
return NO;
}
int l = [value length];
BOOL b = NO;
for (int i = 0; i < l; i++) {
NSString *str =
[[value substringFromIndex:i]
substringToIndex:1];
const char *c =
[str cStringUsingEncoding:
NSASCIIStringEncoding];
if ( c == NULL ) {
b = NO;
break;
}
if ((c[0] >= 0x30) && (c[0] <= 0x39)) {
b = YES;
} else {
b = NO;
break;
}
}
if (b) {
return YES;
} else {
return NO;
}
}
-(BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {
if ( (string != nil) && (string != #"") ) {
if (![self isNumber:string]) {
return NO;
}
}
return YES;
}
You need to write a NSFormatter and assign it to your text field. Here an example implementation of a such NSFormatter which uses a NSRegularExpression to validate the NSTextField contents.
#interface XXNameElementFormatter : NSFormatter
#end
#implementation HcNameElementFormatter {
NSRegularExpression *_re;
}
- (id)init {
self = [super init];
if (self) {
[self initRegularExpression];
}
return self;
}
- (void)awakeFromNib
{
[self initRegularExpression];
}
- (void)initRegularExpression
{
NSError *reError;
_re = [NSRegularExpression regularExpressionWithPattern:#"^[a-z]*$" options:NSRegularExpressionCaseInsensitive error:&reError];
NSAssert(_re != nil, #"Error in regular expression, error: %#", reError);
}
- (NSString *)stringForObjectValue:(id)obj
{
return obj;
}
- (BOOL)getObjectValue:(out __autoreleasing id *)obj forString:(NSString *)string errorDescription:(out NSString *__autoreleasing *)error
{
*obj = string;
return YES;
}
- (BOOL)isPartialStringValid:(NSString *__autoreleasing *)partialStringPtr proposedSelectedRange:(NSRangePointer)proposedSelRangePtr originalString:(NSString *)origString originalSelectedRange:(NSRange)origSelRange errorDescription:(NSString *__autoreleasing *)error
{
NSParameterAssert(partialStringPtr != nil);
NSString *partialString = *partialStringPtr;
NSRange firstMatch = [_re rangeOfFirstMatchInString:*partialStringPtr options:0 range:NSMakeRange(0, partialString.length)];
return firstMatch.location != NSNotFound;
}
#end
I have a NSString like this:
456673\tSomething
But I would like to extract Something only.... ...
All the data must be in this format ....
xxxx\tyyyy
How can I split it bases on \t? thank you.
You may be looking for this instance method:
- (NSArray *)componentsSeparatedByString:(NSString *)separator
If that fails your needs and you want something more powerful, I can personally recommend RegexKitLite. RegexKitLite adds the power of regular expressions to NSString in the form of a category.
I've added a category to NSString for convenience (class: NSString+Utility):
- (NSString *)substringFromFirstOccurenceOfString:(NSString *)string {
NSRange range = [self rangeOfString:string];
if (range.location != NSIntegerMax) {
int index = range.location + range.length;
return [self substringFromIndex:index];
} else {
return self;
}
}
- (NSString *)substringFromLastOccurenceOfString:(NSString *)string {
NSRange range = [self rangeOfString:string options:NSBackwardsSearch];
if (range.location != NSIntegerMax) {
int index = range.location + range.length;
return [self substringFromIndex:index];
} else {
return self;
}
}
- (NSString *)substringToFirstOccurenceOfString:(NSString *)string {
NSRange range = [self rangeOfString:string];
if (range.location != NSIntegerMax) {
int index = range.location + range.length;
return [self substringToIndex:index];
} else {
return self;
}
}
- (NSString *)substringToLastOccurenceOfString:(NSString *)string {
NSRange range = [self rangeOfString:string options:NSBackwardsSearch];
if (range.location != NSIntegerMax) {
int index = range.location;
return [self substringToIndex:index];
} else {
return self;
}
}
How do I validate the string input to a UITextField? I want to check that the string is numeric, including decimal points.
You can do it in a few lines like this:
BOOL valid;
NSCharacterSet *alphaNums = [NSCharacterSet decimalDigitCharacterSet];
NSCharacterSet *inStringSet = [NSCharacterSet characterSetWithCharactersInString:myInputField.text];
valid = [alphaNums isSupersetOfSet:inStringSet];
if (!valid) // Not numeric
-- this is for validating input is numeric chars only. Look at the documentation for NSCharacterSet for the other options. You can use characterSetWithCharactersInString to specify any set of valid input characters.
There are a few ways you could do this:
Use NSNumberFormatter's numberFromString: method. This will return an NSNumber if it can parse the string correctly, or nil if it cannot.
Use NSScanner
Strip any non-numeric character and see if the string still matches
Use a regular expression
IMO, using something like -[NSString doubleValue] wouldn't be the best option because both #"0.0" and #"abc" will have a doubleValue of 0. The *value methods all return 0 if they're not able to convert the string properly, so it would be difficult to distinguish between a legitimate string of #"0" and a non-valid string. Something like C's strtol function would have the same issue.
I think using NSNumberFormatter would be the best option, since it takes locale into account (ie, the number #"1,23" in Europe, versus #"1.23" in the USA).
I use this code in my Mac app, the same or similar should work with the iPhone. It's based on the RegexKitLite regular expressions and turns the text red when its invalid.
static bool TextIsValidValue( NSString* newText, double &value )
{
bool result = false;
if ( [newText isMatchedByRegex:#"^(?:|0|[1-9]\\d*)(?:\\.\\d*)?$"] ) {
result = true;
value = [newText doubleValue];
}
return result;
}
- (IBAction) doTextChanged:(id)sender;
{
double value;
if ( TextIsValidValue( [i_pause stringValue], value ) ) {
[i_pause setTextColor:[NSColor blackColor]];
// do something with the value
} else {
[i_pause setTextColor:[NSColor redColor]];
}
}
If you want a user to only be allowed to enter numerals, you can make your ViewController implement part of UITextFieldDelegate and define this method:
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {
NSString *resultingString = [textField.text stringByReplacingCharactersInRange: range withString: string];
// The user deleting all input is perfectly acceptable.
if ([resultingString length] == 0) {
return true;
}
NSInteger holder;
NSScanner *scan = [NSScanner scannerWithString: resultingString];
return [scan scanInteger: &holder] && [scan isAtEnd];
}
There are probably more efficient ways, but I find this a pretty convenient way. And the method should be readily adaptable to validating doubles or whatever: just use scanDouble: or similar.
#pragma mark - UItextfield Delegate
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {
if ([string isEqualToString:#"("]||[string isEqualToString:#")"]) {
return TRUE;
}
NSLog(#"Range ==%d ,%d",range.length,range.location);
//NSRange *CURRANGE = [NSString rangeOfString:string];
if (range.location == 0 && range.length == 0) {
if ([string isEqualToString:#"+"]) {
return TRUE;
}
}
return [self isNumeric:string];
}
-(BOOL)isNumeric:(NSString*)inputString{
BOOL isValid = NO;
NSCharacterSet *alphaNumbersSet = [NSCharacterSet decimalDigitCharacterSet];
NSCharacterSet *stringSet = [NSCharacterSet characterSetWithCharactersInString:inputString];
isValid = [alphaNumbersSet isSupersetOfSet:stringSet];
return isValid;
}
Here are a few one-liners which combine Peter Lewis' answer above (Check that a input to UITextField is numeric only) with NSPredicates
#define REGEX_FOR_NUMBERS #"^([+-]?)(?:|0|[1-9]\\d*)(?:\\.\\d*)?$"
#define REGEX_FOR_INTEGERS #"^([+-]?)(?:|0|[1-9]\\d*)?$"
#define IS_A_NUMBER(string) [[NSPredicate predicateWithFormat:#"SELF MATCHES %#", REGEX_FOR_NUMBERS] evaluateWithObject:string]
#define IS_AN_INTEGER(string) [[NSPredicate predicateWithFormat:#"SELF MATCHES %#", REGEX_FOR_INTEGERS] evaluateWithObject:string]
For integer test it'll be:
- (BOOL) isIntegerNumber: (NSString*)input
{
return [input integerValue] != 0 || [input isEqualToString:#"0"];
}
You can use the doubleValue of your string like
NSString *string=#"1.22";
double a=[string doubleValue];
i think this will return a as 0.0 if the string is invalid (it might throw an exception, in which case you can just catch it, the docs say 0.0 tho). more info here
Hi had the exact same problem and I don't see the answer I used posted, so here it is.
I created and connected my text field via IB. When I connected it to my code via Control+Drag, I chose Action, then selected the Editing Changed event. This triggers the method on each character entry. You can use a different event to suit.
Afterwards, I used this simple code to replace the text. Note that I created my own character set to include the decimal/period character and numbers. Basically separates the string on the invalid characters, then rejoins them with empty string.
- (IBAction)myTextFieldEditingChangedMethod:(UITextField *)sender {
NSCharacterSet *validCharacterSet = [NSCharacterSet characterSetWithCharactersInString:#".0123456789"];
NSCharacterSet *invalidCharacterSet = validCharacterSet.invertedSet;
sender.text = [[sender.text componentsSeparatedByCharactersInSet:invalidCharacterSet] componentsJoinedByString:#""];
}
Credits:
Remove all but numbers from NSString
Late to the game but here a handy little category I use that accounts for decimal places and the local symbol used for it. link to its gist here
#interface NSString (Extension)
- (BOOL) isAnEmail;
- (BOOL) isNumeric;
#end
#implementation NSString (Extension)
/**
* Determines if the current string is a valid email address.
*
* #return BOOL - True if the string is a valid email address.
*/
- (BOOL) isAnEmail
{
NSString *emailRegex = #"[A-Z0-9a-z._%+-]+#[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}";
NSPredicate *emailTest = [NSPredicate predicateWithFormat:#"SELF MATCHES %#", emailRegex];
return [emailTest evaluateWithObject:self];
}
/**
* Determines if the current NSString is numeric or not. It also accounts for the localised (Germany for example use "," instead of ".") decimal point and includes these as a valid number.
*
* #return BOOL - True if the string is numeric.
*/
- (BOOL) isNumeric
{
NSString *localDecimalSymbol = [[NSLocale currentLocale] objectForKey:NSLocaleDecimalSeparator];
NSMutableCharacterSet *decimalCharacterSet = [NSMutableCharacterSet characterSetWithCharactersInString:localDecimalSymbol];
[decimalCharacterSet formUnionWithCharacterSet:[NSCharacterSet alphanumericCharacterSet]];
NSCharacterSet* nonNumbers = [decimalCharacterSet invertedSet];
NSRange r = [self rangeOfCharacterFromSet: nonNumbers];
if (r.location == NSNotFound)
{
// check to see how many times the decimal symbol appears in the string. It should only appear once for the number to be numeric.
int numberOfOccurances = [[self componentsSeparatedByString:localDecimalSymbol] count]-1;
return (numberOfOccurances > 1) ? NO : YES;
}
else return NO;
}
#end
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
if(string.length > 0)
{
NSCharacterSet *numbersOnly = [NSCharacterSet characterSetWithCharactersInString:#"0123456789"];
NSCharacterSet *characterSetFromTextField = [NSCharacterSet characterSetWithCharactersInString:string];
BOOL stringIsValid = [numbersOnly isSupersetOfSet:characterSetFromTextField];
return stringIsValid;
}
return YES;
}
IMO the best way to accomplish your goal is to display a numeric keyboard rather than the normal keyboard. This restricts which keys are available to the user. This alleviates the need to do validation, and more importantly it prevents the user from making a mistake. The number pad is also much nicer for entering numbers because the keys are substantially larger.
In interface builder select the UITextField, go to the Attributes Inspector and change the "Keyboard Type" to "Decimal Pad".
That'll make the keyboard look like this:
The only thing left to do is ensure the user doesn't enter in two decimal places. You can do this while they're editing. Add the following code to your view controller. This code removes a second decimal place as soon as it is entered. It appears to the user as if the 2nd decimal never appeared in the first place.
- (void)viewDidLoad
{
[super viewDidLoad];
[self.textField addTarget:self
action:#selector(textFieldDidChange:)
forControlEvents:UIControlEventEditingChanged];
}
- (void)textFieldDidChange:(UITextField *)textField
{
NSString *text = textField.text;
NSRange range = [text rangeOfString:#"."];
if (range.location != NSNotFound &&
[text hasSuffix:#"."] &&
range.location != (text.length - 1))
{
// There's more than one decimal
textField.text = [text substringToIndex:text.length - 1];
}
}
#property (strong) NSNumberFormatter *numberFormatter;
#property (strong) NSString *oldStringValue;
- (void)awakeFromNib
{
[super awakeFromNib];
self.numberFormatter = [[NSNumberFormatter alloc] init];
self.oldStringValue = self.stringValue;
[self setDelegate:self];
}
- (void)controlTextDidChange:(NSNotification *)obj
{
NSNumber *number = [self.numberFormatter numberFromString:self.stringValue];
if (number) {
self.oldStringValue = self.stringValue;
} else {
self.stringValue = self.oldStringValue;
}
}
Old thread, but it's worth mentioning that Apple introduced NSRegularExpression in iOS 4.0. (Taking the regular expression from Peter's response)
// Look for 0-n digits from start to finish
NSRegularExpression *noFunnyStuff = [NSRegularExpression regularExpressionWithPattern:#"^(?:|0|[1-9]\\d*)(?:\\.\\d*)?$" options:0 error:nil];
// There should be just one match
if ([noFunnyStuff numberOfMatchesInString:<#theString#> options:0 range:NSMakeRange(0, <#theString#>.length)] == 1)
{
// Yay, digits!
}
I suggest storing the NSRegularExpression instance somewhere.
I wanted a text field that only allowed integers. Here's what I ended up with (using info from here and elsewhere):
Create integer number formatter (in UIApplicationDelegate so it can be reused):
#property (nonatomic, retain) NSNumberFormatter *integerNumberFormatter;
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
// Create and configure an NSNumberFormatter for integers
integerNumberFormatter = [[NSNumberFormatter alloc] init];
[integerNumberFormatter setMaximumFractionDigits:0];
return YES;
}
Use filter in UITextFieldDelegate:
#interface MyTableViewController : UITableViewController <UITextFieldDelegate> {
ictAppDelegate *appDelegate;
}
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {
// Make sure the proposed string is a number
NSNumberFormatter *inf = [appDelegate integerNumberFormatter];
NSString* proposedString = [textField.text stringByReplacingCharactersInRange:range withString:string];
NSNumber *proposedNumber = [inf numberFromString:proposedString];
if (proposedNumber) {
// Make sure the proposed number is an integer
NSString *integerString = [inf stringFromNumber:proposedNumber];
if ([integerString isEqualToString:proposedString]) {
// proposed string is an integer
return YES;
}
}
// Warn the user we're rejecting the change
AudioServicesPlayAlertSound(kSystemSoundID_Vibrate);
return NO;
}
Not so elegant, but simple :)
- (BOOL) isNumber: (NSString*)input
{
return [input doubleValue] != 0 || [input isEqualToString:#"0"] || [input isEqualToString:#"0.0"];
}
Accept decimal values in text fields with single (.)dot working with iPad and iPhone in Swift 3
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
let inverseSet = NSCharacterSet(charactersIn:"0123456789").inverted
let components = string.components(separatedBy: inverseSet)
let filtered = components.joined(separator: "")
if filtered == string {
return true
} else {
if string == "." {
let countdots = textField.text!.components(separatedBy:".").count - 1
if countdots == 0 {
return true
}else{
if countdots > 0 && string == "." {
return false
} else {
return true
}
}
}else{
return false
}
}
}
To be more international (and not only US colored ;-) ) just replace in the code above by
-(NSNumber *) getNumber
{
NSString* localeIdentifier = [[NSLocale autoupdatingCurrentLocale] localeIdentifier];
NSLocale *l_en = [[NSLocale alloc] initWithLocaleIdentifier: localeIdentifier] ;
return [self getNumberWithLocale: [l_en autorelease] ];
}
This answer uses NSFormatter as said previously. Check it out:
#interface NSString (NSNumber)
- (BOOL) isNumberWithLocale:(NSLocale *) stringLocale;
- (BOOL) isNumber;
- (NSNumber *) getNumber;
- (NSNumber *) getNumberWithLocale:(NSLocale*) stringLocale;
#end
#implementation NSString (NSNumber)
- (BOOL) isNumberWithLocale:(NSLocale *) stringLocale
{
return [self getNumberWithLocale:stringLocale] != nil;
}
- (BOOL) isNumber
{
return [ self getNumber ] != nil;
}
- (NSNumber *) getNumber
{
NSLocale *l_en = [[NSLocale alloc] initWithLocaleIdentifier: #"en_US"] ;
return [self getNumberWithLocale: [l_en autorelease] ];
}
- (NSNumber *) getNumberWithLocale:(NSLocale*) stringLocale
{
NSNumberFormatter *formatter = [[ [ NSNumberFormatter alloc ] init ] autorelease];
[formatter setLocale: stringLocale ];
return [ formatter numberFromString:self ];
}
#end
I hope it helps someone. =)
#import "NSString+Extension.h"
//#interface NSString (Extension)
//
//- (BOOL) isAnEmail;
//- (BOOL) isNumeric;
//
//#end
#implementation NSString (Extension)
- (BOOL) isNumeric
{
NSString *emailRegex = #"[0-9]+";
NSPredicate *emailTest = [NSPredicate predicateWithFormat:#"SELF MATCHES %#", emailRegex];
return [emailTest evaluateWithObject:self];
// NSString *localDecimalSymbol = [[NSLocale currentLocale] objectForKey:NSLocaleDecimalSeparator];
// NSMutableCharacterSet *decimalCharacterSet = [NSMutableCharacterSet characterSetWithCharactersInString:localDecimalSymbol];
// [decimalCharacterSet formUnionWithCharacterSet:[NSCharacterSet alphanumericCharacterSet]];
//
// NSCharacterSet* nonNumbers = [decimalCharacterSet invertedSet];
// NSRange r = [self rangeOfCharacterFromSet: nonNumbers];
//
// if (r.location == NSNotFound)
// {
// // check to see how many times the decimal symbol appears in the string. It should only appear once for the number to be numeric.
// int numberOfOccurances = [[self componentsSeparatedByString:localDecimalSymbol] count]-1;
// return (numberOfOccurances > 1) ? NO : YES;
// }
// else return NO;
}
In Swift 4:
let formatString = "12345"
if let number = Decimal(string:formatString){
print("String contains only number")
}
else{
print("String doesn't contains only number")
}
This covers: Decimal part control (including number of decimals allowed), copy/paste control, international separators.
Steps:
Make sure your view controller inherits from UITextFieldDelegate
class MyViewController: UIViewController, UITextFieldDelegate {...
In viewDidLoad, set your control delegate to self:
override func viewDidLoad() {
super.viewDidLoad();
yourTextField.delegate = self
}
Implement the following method and update the "decsAllowed" constant with the desired amount of decimals or 0 if you want a natural number.
Swift 4
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
let decsAllowed: Int = 2
let candidateText = NSString(string: textField.text!).replacingCharacters(in: range, with: string)
let decSeparator: String = NumberFormatter().decimalSeparator!;
let splitted = candidateText.components(separatedBy: decSeparator)
let decSeparatorsFound = splitted.count - 1
let decimalPart = decSeparatorsFound > 0 ? splitted.last! : ""
let decimalPartCount = decimalPart.characters.count
let characterSet = NSMutableCharacterSet.decimalDigit()
if decsAllowed > 0 {characterSet.addCharacters(in: decSeparator)}
let valid = characterSet.isSuperset(of: CharacterSet(charactersIn: candidateText)) &&
decSeparatorsFound <= 1 &&
decsAllowed >= decimalPartCount
return valid
}
If afterwards you need to safely convert that string into a number, you can just use Double(yourstring) or Int(yourstring) type cast, or the more academic way:
let formatter = NumberFormatter()
let theNumber: NSNumber = formatter.number(from: yourTextField.text)!