I have a table with data like below :
ID SUMMARY_DATE KEYWORD_ID DATA
123 9/1/2014 5 98
I need to generate 18 more rows with the summary_date + 18 months, something like below :
ID SUMMARY_DATE KEYWORD_ID DATA
123 9/1/2014 5 98
123 10/1/2014 5 98
123 11/1/2014 5 98
123 12/1/2014 5 98
...
123 3/1/2016 5 98
I could do that using UNION but it will be so long. Is there any other ways to do it?
Thanks in advance.
Just generate a list of numbers and use add_months():
with n as (
select level as m
from dual
connect by level <= 18
)
select t.id, add_months(t.summary_date, n.m, keywork_id, data
from table t cross join
n;
Related
I have a list of codes by area and type. I need to get the unique codes for each type, which I can do with a simple SELECT query with a GROUP BY. I now need to know which area does not have one of the codes. So how do I run a query to group by unique values and tell me how records do not have one of the values?
ID Area Type Code
1 10 A 123
2 10 A 456
3 10 B 789
4 10 B 987
5 10 C 654
6 10 C 321
7 20 A 123
8 20 B 789
9 20 B 987
10 20 C 654
11 20 C 321
12 30 A 137
13 30 A 456
14 30 B 579
15 30 B 789
16 30 B 987
17 30 C 654
18 30 C 321
I can run this query to group them by type and get get the unique codes:
SELECT tblExample.Type, tblExample.Code
FROM tblExample
GROUP BY tblExample.Type, tblExample.Code
This gives me this:
Type Code
A 123
A 137
A 456
B 579
B 789
B 987
C 321
C 654
Now I need to know which areas do not have a given code. For example, Code 123 does not appear for Area 10 and code 137 does not appear for codes 10 and 20. How do I write a query to give me that areas are missing a code? The format of the output doesn't matter, I just need to get the results. I'm thinking the results could be in one column or spread out in multiple columns:
Type Code Missing Areas or Missing1 Missing2
A 123 30 30
A 137 10, 20 10 20
A 456 20 20
B 579 10, 20 10 20
B 789
B 987
C 321
C 654
You can get a list of the missing code/areas by first generating all combinations and then filtering out the ones that exist:
select t.type, c.code
from (select distinct type from tblExample) t cross join
(select distinct code from tblExample) c left join
tblExample e
on t.type = e.type and c.code = e.code
where e.type is null;
Consider the table Property.
KeyIdNum|Property|IdNum
1 12 1234
1 12 1234
1 44 1234
1 12 1234
1 56 1234
2 12 4567
3 12 6789
3 56 6789
3 12 6789
4 44 3434
5 12 4444
6 44 9999
6 44 9999
It contains property num associated with each id num.But it contains duplicates.
I applied distinct to avoid duplicates.
select distinct KeyIdNum,Property,IdNum from Property.
So i got the result as :
KeyIdNum |Property |IdNum
1 12 1234
1 44 1234
1 56 1234
2 12 4567
3 12 6789
3 56 6789
4 44 3434
5 12 4444
6 44 9999
But now I want to `select( after applying distinct) ,the KeyIdNum (or IdNum) which are coming more than one time in the distinct result set shown above.
Please help me on this.I am not able to find a way to get the count of a column in the distinct result set using a single query.
Below query will result of KeyidNum , its number of row count.
select KeyIdNum,count(KeyIdNum)
From (
select distinct KeyIdNum,Property,IdNum from Property )
group by KeyIdNum
select KeyIdNum,count(KeyIdNum) as count
From (
select distinct KeyIdNum,Property,IdNum from Table19 )A
group by KeyIdNum
output
KeyIdNum count
1 3
2 1
3 2
4 1
5 1
6 1
This answer uses t-sql:
SELECT x
FROM ( SELECT * ,
rn = rownumber() OVER ( PARTITION BY keyidnum, idnum
ORDER BY keyidnum, idnum )
FROM tblProperty
) x
WHERE rn > 1
I have a list of IDs, transactions, and the date of those transactions. I want to create a count of each transaction within each ID.
The starting table I have is looks something like this:
id trxn_dt trxn_amt
1 10/31/2014 58
1 11/9/2014 34
1 12/10/2014 12
2 7/8/2014 78
2 11/20/2014 99
3 1/5/2014 120
4 2/17/2014 588
4 2/18/2014 8
4 3/9/2014 65
4 4/25/2014 74
and I want the end result to look something like this:
id trxn_dt trxn_amt trxn_count
1 10/31/2014 58 1
1 11/9/2014 34 2
1 12/10/2014 12 3
2 7/8/2014 78 1
2 11/20/2014 99 2
3 1/5/2014 120 1
4 2/17/2014 588 1
4 2/18/2014 8 2
4 3/9/2014 65 3
4 4/25/2014 74 4
Count(distinct(id)) would only give me the overall number of distinct IDs and not a running total by each ID that restarts at each new ID.
Thank you!
In SQL-Server you can use ROW_NUMBER in following:
SELECT id,
trxn_dt,
trxn_amt,
ROW_NUMBER() OVER(PARTITION BY Id ORDER BY Id, trxn_dt) AS trxn_count
FROM StarningTable
In MySQL you can do in following:
SELECT
t.id,
t.trxn_dt,
t.trxn_amt,
#cur:= IF(id=#id, #cur+1, 1) AS RowNumber,
#id := id
FROM
StarningTable t
CROSS JOIN
(SELECT #id:=(SELECT MIN(id) FROM StarningTable t), #cur:=0) AS init
ORDER BY
t.id
using Row_number we can achieve this
Select *,
ROW_NUMBER()OVER(PARTITION BY id ORDER BY (SELECT NULL))trxn_count
from Transactions
I'm attempting to create group_ids based on a set of item_ids. The only indication that the item_ids are part of a single group is the fact that item_ids are sequential. For example, based on the first two columns below, the output I want is the third:
item item_id group_id
ABC 282 2
ABC 283 2
ABC 284 2
ABC 285 2
ABC 051 3
ABC 052 3
ABC 189 4
ABC 231 5
ABC 232 5
ABC 233 5
ABC 234 5
ABC 247 6
ABC 248 6
ABC 249 6
ABC 250 6
ABC 091 7
ABC 092 7
The group_id doesn't necessarily have to be sequential itself, it only has to be unique. I attempted this with the following code:
create sequence seq
start with 1
minvalue 1
increment by 1
cache 20;
select seq.nextval from dual; --to initialize the sequence
select
item,
item_id,
case when diff = 1 then seq.currval else seq.nextval end group_id
from
(
select
item,
item_id,
(id - lag(id, 1, 0) over (order by 1) diff
from
(
select
item,
item_id
from
table
)
);
But get the following output:
item item_id group_id
ABC 282 2
ABC 283 3
ABC 284 4
ABC 285 5
ABC 051 6
ABC 052 7
ABC 189 8
ABC 231 9
ABC 232 10
ABC 233 11
ABC 234 12
ABC 247 13
ABC 248 14
ABC 249 15
ABC 250 16
ABC 091 17
ABC 092 18
When looking for the cause of the problem, I found an excellent explanation by user ShannonSeverance that details why my solution won't work. However, it didn't provide any suggestions on how to move forward.
Does anyone have any ideas?
You have a problem, because SQL tables are inherently unordered. The following "should" logically work, although it won't in practice:
select ii.*, (item_id - rownum) as grp_id
from item_ids ii;
A sequence of item_ids in order minus the row number is constant. You can use that for a group, at least for a given item. To handle multiple items, concatenate the values together:
select ii.*, item||'-'||(item_id - rownum) as grp_id
from item_ids ii;
To really make this work, you need to add an order by -- this guarantees the ordering of the results from the select. This might work, assuming that there are "holes" between the groups:
select ii.*, item||'-'||(item_id - rownum) as grp_id
from item_ids ii
order by item, item_id;
Otherwise, you need some other column to determine the proper ordering for the items.
I have a table with an ID and multiple informative columns. Sometimes however, I can have multiple data for an ID, so I added a column called "Sequence". Here is a shortened example:
ID Sequence Name Tel Date Amount
124 1 Bob 873-4356 2001-02-03 10
124 2 Bob 873-4356 2002-03-12 7
124 3 Bob 873-4351 2006-07-08 24
125 1 John 983-4568 2007-02-01 3
125 2 John 983-4568 2008-02-08 13
126 1 Eric 345-9845 2010-01-01 18
So, I would like to obtain only these lines:
124 3 Bob 873-4351 2006-07-08 24
125 2 John 983-4568 2008-02-08 13
126 1 Eric 345-9845 2010-01-01 18
Anyone could give me a hand on how I could build a SQL query to do this ?
Thanks !
You can calculate the maximum sequence using group by. Then you can use join to get only the maximum in the original data.
Assuming your table is called t:
select t.*
from t join
(select id, MAX(sequence) as maxs
from t
group by id
) tmax
on t.id = tmax.id and
t.sequence = tmax.maxs