Conditional clause to DROP Table - sql

Question

I was trying to write a sql procedure to drop table who have a certain pattern in their names.
Something like the below code :
DECLARE #temp TABLE
(
ID bigint IDENTITY(1,1),
tabname sysname NOT NULL
)
INSERT INTO #temp
SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME LIKE '%:%'
DECLARE #ProcessedID bigint = 0
DECLARE #tablename sysname
SELECT #ProcessedID = ID, #tablename = tabname FROM #temp WHERE ID > #ProcessedID ORDER BY ID DESC
WHILE(#ProcessedID IS NOT NULL)
BEGIN
DROP TABLE dbo.[#tablename]
SELECT #ProcessedID = ID, #tablename = tabname FROM #temp WHERE ID > #ProcessedID ORDER BY ID DESC
END
But #tablename is not replaced with the right table name. Can any one point me in the right direction.

Answer 1

You need to do it dynamically when you want to use a variable name as an argument, so you need to wrap it in a string and execute that string and then do some small changes to the WHILE condition to fit.
I'd properly do something like this:
DECLARE #temp TABLE
(
ID bigint IDENTITY(1,1),
tabname sysname NOT NULL
):
INSERT INTO #temp
SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME LIKE '%:%';
DECLARE #tablename VARCHAR(255);
DECLARE #Count INT = ISNULL((SELECT COUNT(*) FROM #temp AS t), 0);
WHILE(#Count > 0)
BEGIN
SELECT #tablename = tabname FROM #temp AS t; --if the order of drop is not significant
EXEC('DROP TABLE dbo.[' + #tablename+ ']');
DELETE FROM #temp WHERE tabname = #tablename;
SET #Count = ISNULL((SELECT COUNT(*) FROM #temp AS t), 0);
END