Oracle Data Conversion: ORA-01722: invalid number - sql

Error while converting varchar2 column value to Number
i am unable to compare varchar2 value field with another value
like this '10:54' with '11.00', i have to compare minutes with minutes field.
How is it possible?
Query is:
select
adm_emp_num,adm_emp_nam,adm_ace_dte,asm_sft,asm_ed_tme,asm_st_tme,adm_ace_tme from Adm,asm
where adm_ace_dte =ass_sft_dte
and to_char(adm_ace_dte,'YYYYMM')=201409
--having min(to_char(adm_ace_tme,'HH24:MI')) < asm_st_tme
having min(to_char(adm_ace_tme,'HH24:MI')) < to_char(to_number(asm_st_tme,'99999
9.99'),'999999.99')
group by adm_emp_num,adm_emp_nam,adm_ace_dte,asm_sft,asm_ed_tme,asm_
st_tme,adm_ace_tme
order by 1,2
refer the table structures in the link:
https://stackoverflow.com/review/suggested-edits/5861972
Any help will be appreciated
Thanks

Use EXTRATC function to get minute part. Examples:
from TIMESTAMP type:
SELECT EXTRACT(MINUTE FROM SYSTIMESTAMP) FROM DUAL;
from DATE type:
SELECT EXTRACT(MINUTE FROM CAST(SYSDATE AS TIMESTAMP)) FROM DUAL;
from VARCHAR2 type (for example: 11:30):
SELECT EXTRACT(MINUTE FROM TO_TIMESTAMP('11:30', 'HH24:MI')) FROM DUAL;

You can do it like this:
select to_number(to_char(to_date('12:56', 'hh24:mi'), 'mi')) from dual;
i.e. first convert your string to a valid date, then extract the minute part (by specifying just 'mi' in the format), then casting that to a number.
You can then perform comparisons:
...where to_number(to_char(to_date('12:56', 'hh24:mi'), 'mi')) = ...
You could of course just parse out the substring, but you would then be vulnerable to invalid minutes, like 79.

You can substring your value and convert it to number, for example:
...
WHERE TO_NUMBER(SUBSTR('10:54',4,2)) >= TO_NUMBER(SUBSTR('11:00',4,2));
--for minutes
...
WHERE TO_NUMBER(SUBSTR('10:54',1,2)) >= TO_NUMBER(SUBSTR('11:00',1,2));
--for hours

Related

How to substract 2 varchar dates in oracle?

I have these varchar : 20211026231735.
So I would like a query to substract actual sysdate to that date and convert the substraction to DAY HOURS AND SECONDS.
select TO_CHAR(SYSDATE,'YYYYMMDDHH24MISS') - start_time from TABLEA where job_name='jOB_AA_BB';
I get 4220.
Any help please? Thanks
When you do datetime arithmetic with the DATE datatype, you get back a NUMBER of days. To get an INTERVAL you can subtract two TIMESTAMPs. You don't say what the data type is for start_time, but you might get away with this:
select localtimestamp - start_time
from tablea where job_name='jOB_AA_BB';
LOCALTIMESTAMP gives you a TIMESTAMP value in the current session time zone. There's also CURRENT_TIMESTAMP, which give you the same thing in a TIMESTAMP WITH TIME ZONE and SYSTIMESTAMP that gives you the database time in TIMESTAMP WITH TIME ZONE. You may need to convert your start_time to avoid time zone differences, if any.
You can us the function numtodsinterval to convert the results of date arithmetic to an interval. If necessary then use extract to pull out the needed components.
with tablea(job_name, start_time) as
(select 'jOB_AA_BB','20211026231735' from dual)
select numtodsinterval((SYSDATE - to_date( start_time,'yyyymmddhh24miss')),'hour') date_diff
from tablea where job_name='jOB_AA_BB' ;
with tablea(job_name, start_time) as
(select 'jOB_AA_BB','20211026231735' from dual)
select extract (hour from date_diff) || ':' || extract (minute from date_diff)
from (
select numtodsinterval((sysdate - to_date( start_time,'yyyymmddhh24miss')),'day') date_diff
from tablea where job_name='jOB_AA_BB'
);
NOTE: I am not sure how you got any result, other than an error, as your query winds up as a string - a string. You should not convert sysdate to a string but your string to a date (better yet store it as the proper data type - date).
You can convert the value to a date (rather than converting SYSDATE to a string) and then subtract and explicitly return the value as an INTERVAL DAY TO SECOND type:
SELECT (SYSDATE - TO_DATE('20211026231735', 'YYYYMMDDHH24MISS')) DAY TO SECOND
FROM DUAL;
Or, for your table:
SELECT (SYSDATE - TO_DATE(start_time,'YYYYMMDDHH24MISS')) DAY(5) TO SECOND
FROM TABLEA
WHERE job_name='jOB_AA_BB';
db<>fiddle here

Not a Valid Month - Working with Dates in Oracle

I am finding it strenuous to work with dates in my customized environment. I have a request to add a where clause which caters to specific dates but I just cannot get oracle to budge. Any ideas anyone please.
select created_date, cast(created_date as date) as created_date_cast
from mytable;
created_date created_date_cast
04-Mar-20 05.21.15.772000 AM 3/4/2020 5:21:15 AM
04-Mar-20 05.21.15.709000 AM 3/4/2020 5:21:15 AM
04-Mar-20 05.17.14.902000 AM 3/4/2020 5:14:14 AM
28-Feb-20 01.15.25.702700 AM 2/28/2020 1:15:25 AM
When I try to add a where clause the snippet blows up with the error:
select created_date, cast(created_date as date) as created_date_cast
from mytable
where cast(created_date as date) <= '02/28/2020';
ORA-01843: not a valid month
I have also tried to_date(created_date, 'MM/DD/YYYY') in the from but proves to be erroneous with:
ORA-01858: a non-numeric character was found where a numeric was expected
Firstly cast as date which converts a timestamp value to a date value, and then don't forget to add trunc() function in order to include the boundry value (date'2020-02-28' in this case) also as
where trunc(cast(created_date as date)) <= date'2020-02-28'
Demo
Don't use CAST and don't use TRUNC (as then Oracle will not be able to use an index on your column but would, instead, require a function-based index created on TRUNC(created_date)) just add a day and use a literal:
SELECT created_date
FROM mytable
WHERE created_date < DATE '2020-02-29';
or
SELECT created_date
FROM mytable
WHERE created_date < TIMESTAMP '2020-02-29 00:00:00';
or, if you want to specify the exact date then just add a day. E.g.:
SELECT created_date
FROM mytable
WHERE created_date < DATE '2020-02-28' + INTERVAL '1' DAY;
All of those options should be able to use an index on the created_date column.
I have also tried to_date(created_date, 'MM/DD/YYYY') in the from but proves to be erroneous with:
ORA-01858: a non-numeric character was found where a numeric was expected
TO_DATE( value_string, format_model ) takes strings as its arguments but CREATED_DATE is a TIMESTAMP data type and not a string so Oracle must make an implicit TIMESTAMP-to-string conversion and it does this using the NLS_TIMESTAMP_FORMAT session parameter; so your expression is effectively:
TO_DATE(
TO_CHAR(
created_date,
( SELECT value FROM NLS_SESSION_PARAMETERS WHERE parameter = 'NLS_TIMESTAMP_FORMAT' )
),
'MM/DD/YYYY'
)
And if your NLS_TIMESTAMP_FORMAT is not MM/DD/YYYY then its highly likely that an exception will be raised (i.e. like the ORA-01858 you had).
You should never rely on implicit string conversions as any user can change their own session parameters at any time and an implicit conversion that works for one user may not work for another just because they have different parameter values (even though the queries are identical).
Use a date literal:
cast(created_date as date) <= date '2020-02-28'
I would also recommend dispensing with the cast() -- assuming that created_date is correctly stored as a date or timestamp:
created_date < (date '2020-02-28' + interval '1' day)

POSTGRESQL: Error: date format not recognized

Have a table "user_order" with columns "user_id", "code" (character varying) and created_date_key (integer). I am trying to write a query which displays all records for code 26 and date greater that '12-5-2013 23:59:59'.
Select *
from user_order
where code like 26 ::text
and to_date(created_date_key ::text, 'YYYY-MM-DD') > to_date ('12-5-2013 23:59:59' ::text, 'YYYY-MM-DD')
ERROR: date format not recognized.
created_date_key should be timestamp and not integer.
select *
from user_order
where code like 26 ::text
and to_date(created_date_key ::text, 'YYYY-MM-DD') > '12-5-2013 23:59:59'
String values need to be included within single quotes. You do not need to specify text to convert the data type. to_timestamp function is used to convert the text data to timestamp value. The following query would select the required data:
Select *
from user_order
where code = '26'
and created_date_key > to_timestamp ('12-5-2013 23:59:59', 'MM-DD-YYYY HH24:MI:SS');
References:
SELECT on PostgreSQL Manual. There are a lot of examples on this page.
Data Type Formatting Functions on PostgreSQL Manual

Using "Interval" in Oracle where "Interval" is a value from a table

I need to generate a list of values in an Oracle DB with the following columns of data:
ITEM_TYPE VARCHAR2(20)
ITEM_LAST_UPDATED DATE
ITEM_UPDATE_TOLERANCE NUMBER(1)
The only data that should be send out to the console would be items that have the date in 'ITEM_LAST_UPDATED' less than the sysdate minus the integer value within 'ITEM_UPDATE_TOLERANCE'.
So, if I wanted to just show the ones that were one hour past due, I can do:
select ITEM_TYPE from MY_TABLE
where
to_char(ITEM_LAST_UPDATED, 'DD-MON-YYYY HH24:MI')
<=
to_char(sysdate - interval '1' hour, 'DD-MON-YYYY HH24:MI');
However, rather than using the '1' in the above statement, I need to replace it with the numeric value of ITEM_UPDATE_TOLERANCE.
I tried several different versions, but all error (such as):
select ITEM_TYPE from MY_TABLE
where
to_char(ITEM_LAST_UPDATED, 'DD-MON-YYYY HH24:MI')
<=
to_char(sysdate - interval to_number(ITEM_UPDATE_TOLERANCE) hour, 'DD-MON-YYYY HH24:MI');
Why are you converting a perfect DATE column to a character value just to compare it another DATE value converted to a character column.
Simply use:
ITEM_LAST_UPDATED <= sysdate - interval '1' hour
To achieve what you want, just multiply the value:
ITEM_LAST_UPDATED <= sysdate - (interval '1' hour) * ITEM_UPDATE_TOLERANCE
There is also absolutely no need to convert a number to a number using the to_number() function.
As an alternative to #a_horse_with_no_name's interval multiplication trick, or San's division method, you can also use the numtodsinterval() function:
ITEM_LAST_UPDATED <= sysdate - numtodsinterval(ITEM_UPDATE_TOLERANCE, 'HOUR')
As an example:
select sysdate, sysdate - numtodsinterval(3, 'HOUR') from dual;
SYSDATE SYSDATE-NUMTODSINTE
------------------- -------------------
2014-03-07 19:08:27 2014-03-07 16:08:27
Well you can try using simple calculation
select ITEM_TYPE from MY_TABLE
where
ITEM_LAST_UPDATED
<=
sysdate - (ITEM_UPDATE_TOLERANCE/24);
Calculation of ITEM_UPDATE_TOLERANCE/24 will convert hours into days and then can be subtracted from sysdate.

Get Exact timestamp value?

I am trying to subtract some days from 'current_timestamp' and converting that to timestamp using to_timestamp() function in Oracle. But I am always getting start of day time, that is 12 AM.
When I execute
select to_timestamp(current_timestamp - 3) from dual;
It will give me result like,
18-FEB-14 12.00.00.000000000 AM
But I need exact deduction of 3 days from current time.
Thanks!!!!
select current_timestamp - 3 ts from dual;
or
SELECT SYSTIMESTAMP - INTERVAL '3' DAY AS day FROM dual;
Will give you time as well:
select sysdate - 3 from dual;
Edit based on your comment:
select to_timestamp(to_char(sysdate-3,'DD-Mon-RR HH24:MI:SS'),'DD-Mon-RR HH24:MI:SS') from dual;
Or more simply:
select systimestamp - 3 from dual
An important difference is that SYSDATE gives you server time, and CURRENT_TIMESTAMP gives you session time.
Also, according to the documentation, TO_TIMESTAMP operates on CHAR, VARCHAR2, NCHAR, or NVARCHAR2 data types, not DATE. So I think you need to look elsewhere:
SELECT CAST (SYSDATE AS TIMESTAMP) from dual;