Sorry for the cryptic title, but i didn't find a better question
I have a Table with lets say these Data:
Table Article
ID ArticleNumber Type
1 10 1
2 10 3
3 20 1
4 30 1
5 30 3
I'm looking for the 3. Row where no type 3 article exists but a type 1 article exists.
I think it have to be a very easy SQL query but i can't find a solution...
To get all ArticleNumbers for which exists a row with type = 1 but there is no row with type = 3, use this:
SELECT
*
FROM
Article a
WHERE
a.`Type` = 1
AND NOT EXISTS (
SELECT * FROM
Article a2
WHERE
a2.`Type` = 3
AND a2.ArticleNumber = a.ArticleNumber
)
You can select the first ID by aggregating the original data (see subquery), then you can filter those records where could be any anomalies.
If you want, you can change the aggregation to COUNT, then you can compare the count for each types.
SELECT
ArticleNumber
FROM (
-- Conditional aggregation to find the first ID for each type per ArticleNumber
SELECT
ArticleNumber
, MIN(CASE WHEN Type = 1 THEN ID ELSE NULL END) AS Type_1
, MIN(CASE WHEN Type = 3 THEN ID ELSE NULL END) AS Type_3
GROUP BY
ArticleNumber
) AS X
WHERE
Type_1 IS NULL
OR Type_2 IS NULL
Note You can change the above query to use the HAVING keyword instead of subquery if you want.
Another variant, using MINUS to remove the articles with Type 3:
select ID, ArticleNumber from Article where type = 1
MINUS
select ID, ArticleNumber from Article where type = 3
UPDATE
After re-reading your question, I guess you want to also have those with Type = 3, but where no row with Type = 1 exists. For this, you can use COUNT DISTINCT:
select * from (
select ID, ArticleNumber, count(distinct type) as type_cnt
from Article
group by ID, ArticleNumber
)
where type_cnt < 2
You mean you want all rows where type is not 3?
That would be this statement:
SELECT
*
FROM
`Article`
WHERE
`type` != 3;
After re-reading your question I understand your problem. I would go with Eriks solution.
Related
I have a table as follows
groupCode
ProductIdentifier
1
dental
1
membership
2
dental
2
vision
2
health
3
dental
3
vision
I need to find out if a specific groupCode have "dental", "vision" and "health" (all three simultaneously)
The expected result is code 2
What I need to identify is if groupCode 2 has the three products (or two, or whatever the user enters). This is part of a huge kitchen sink query I'm building.
I'm doing
SELECT groupCode
FROM dbo.table
WHERE (productIdentifier = N'dental')
AND (productIdentifier = N'vision')
AND (productIdentifier = N'health')
AND (groupCode = 2)
But clearly is wrong because it's not working.
I tried to do something like its described here but it didn't return a result for me:
Select rows with same id but different value in another column
Thanks.
If each of 'dental','vision' and 'health' occur only once per group identifier, you can group by group identifier and filter by the groups having count(*) = 3:
WITH
-- your input ..
indata(groupCode,ProductIdentifier) AS (
SELECT 1,'dental'
UNION ALL SELECT 1,'membership'
UNION ALL SELECT 2,'dental'
UNION ALL SELECT 2,'vision'
UNION ALL SELECT 2,'health'
UNION ALL SELECT 3,'dental'
UNION ALL SELECT 3,'vision'
)
-- real query starts here ...
SELECT
groupcode
FROM indata
WHERE productidentifier IN ('dental','vision','health')
GROUP BY
groupcode
HAVING COUNT(*) = 3;
-- out groupcode
-- out -----------
-- out 2
As per Marcothesane answer, if you know the groupCode (2) and the number of products (vision, dental and health), 3 in this case, and you need to confirm if that code has those three specific products, this will work for you:
SELECT COUNT(groupCode) AS totalRecords
FROM dbo.table
WHERE (groupCode = 2) AND (productIdentifier IN ('dental', 'vision', 'health'))
HAVING (COUNT(groupCode) = 3)
This will return 3 (number of records = number of products).
Its basically's Marcothesane answer in a way you can "copy/paste" to your code by just changing the table name. You should accept Marcothesane answer.
I have a table with following rows :
SectionId
SectionStatus
1
Assigned
1
Approved
2
Assigned
2
Assigned
3
Assigned
Now I want to fetch the SectionId where al SectionStatus belong to that SectionId are not Approved.
Result expected for above table : 1,2,3
Another Example :
SectionId
SectionStatus
1
Approved
1
Approved
2
Assigned
2
Assigned
3
Assigned
Result expected for above table : 2,3
This looks like aggregation with a conditional count in the HAVING clause.
SELECT t.SectionId
FROM yourtable t
GROUP BY t.SectionId
HAVING COUNT(CASE WHEN t.SectionStatus = 'Approved' THEN 1 END) = 0;
db<>fiddle
One way to get that is by cross-applying the record and check whether that is 'Approved' or not.
Try the following:
select distinct SectionId from yourtable tab
cross apply (select 'Approved' Stat)t
where t.Stat <> tab.SectionStatus
Please see the db<>fiddle here.
In the example table below, I'm trying to figure out a way to sum amount over marks in two situations: the first, when mark 'C' exists within a single id, and the second, when mark 'C' doesn't exist within an id (see id 1 or 2). In the first situation, I want to exclude the amount against mark 'A' within that id (see id 3 in the desired conversion table below). In the second situation, I want to perform no exclusion and take a simple sum of the amounts against the marks.
In other words, for id's containing both mark 'A' and 'C', I want to make the amount against 'A' as zero. For id's that do not contain mark 'C' but contain mark 'A', keep the original amount against mark 'A'.
My desired output is at the bottom. I've considered trying to partition over id or use the EXISTS command, but I'm having trouble conceptualizing the solution. If any of you could take a look and point me in the right direction, it would be greatly appreciated :)
example table:
id mark amount
------------------
1 A 1
2 A 3
2 B 2
3 A 1
3 C 3
desired conversion:
id mark amount
------------------
1 A 1
2 A 3
2 B 2
3 A 0
3 C 3
desired output:
mark sum(amount)
--------------------
A 4
B 2
C 3
You could slightly modify my previous answer and end up with this:
SELECT
mark,
sum(amount) AS sum_amount
FROM atable t
WHERE mark <> 'A'
OR NOT EXISTS (
SELECT *
FROM atable
WHERE id = t.id
AND mark = 'C'
)
GROUP BY
mark
;
There's a live demo at SQL Fiddle.
Try:
select
mark,
sum(amount)
from ( select
id,
mark,
case
when (mark = 'A' and id in (select id from table where mark = 'C')) then 0
else amount
end as amount
from table ) t1
group by mark
What I am looking for is to group by and count the total of different data in the same table and have them show in two different columns. Like below.
Data in table A
Fields:
Name Type
Bob 1
John 2
Bob 1
Steve 1
John 1
Bob 2
Desired result from query:
Name Type 1 Type 2
Bob 2 1
John 1 1
Steve 1 0
This will do the trick in SQL Server:
SELECT
name,
SUM( CASE type WHEN 1 THEN 1 ELSE 0 END) AS type1,
SUM( CASE type WHEN 2 THEN 1 ELSE 0 END) AS type2
FROM
myTable
GROUP BY
name
No time to write the code, but the Case statement is what you want here. SImply havea value of 1 if it meets the case and zero if it deosn't. Then you can sum the columns.
Use two separate GROUP BY subqueries.
SELECT Name, a.Count1, b.Count2
from myTable
JOIN
(SELECT Name, SUM(Type) AS Count1 FROM myTable GROUP BY Name WHERE Type=1) AS a ON a.Name = myTable.Name
(SELECT Name, SUM(Type) FROM myTable GROUP BY Name WHERE Type=2) AS b ON b.Name = myTable.Name
You're looking for a CrossTab solution. The above solutions will work, but you'll come unstuck if you want a general solution and have N types.
A CrossTab solution will solve this for you. If this is for quickly crunching some numbers then dump your data into Excel and use the native Pivot Table feature.
If it's for a RDBMS in an app, then it depends upon the RDBMS. MS SQL 2005 and above has a crosstab syntax. See:
http://www.databasejournal.com/features/mssql/article.php/3521101/Cross-Tab-reports-in-SQL-Server-2005.htm
#Seb has a good solution, but it's server-dependent. Here's an alternate using subselects that should be portable:
select
name,
(select count(type) from myTable where type=1 and name=a.name) as type1,
(select count(type) from myTable where type=2 and name=a.name) as type2
from
myTable as a
group by
name
I have a table in my database:
Name | Element
1 2
1 3
4 2
4 3
4 5
I need to make a query that for a number of arguments will select the value of Name that has on the right side these and only these values.
E.g.:
arguments are 2 and 3, the query should return only 1 and not 4 (because 4 also has 5). For arguments 2,3,5 it should return 4.
My query looks like this:
SELECT name FROM aggregations WHERE (element=2 and name in (select name from aggregations where element=3))
What do i have to add to this query to make it not return 4?
A simple way to do it:
SELECT name
FROM aggregations
WHERE element IN (2,3)
GROUP BY name
HAVING COUNT(element) = 2
If you want to add more, you'll need to change both the IN (2,3) part and the HAVING part:
SELECT name
FROM aggregations
WHERE element IN (2,3,5)
GROUP BY name
HAVING COUNT(element) = 3
A more robust way would be to check for everything that isn't not in your set:
SELECT name
FROM aggregations
WHERE NOT EXISTS (
SELECT DISTINCT a.element
FROM aggregations a
WHERE a.element NOT IN (2,3,5)
AND a.name = aggregations.name
)
GROUP BY name
HAVING COUNT(element) = 3
It's not very efficient, though.
Create a temporary table, fill it with your values and query like this:
SELECT name
FROM (
SELECT DISTINCT name
FROM aggregations
) n
WHERE NOT EXISTS
(
SELECT 1
FROM (
SELECT element
FROM aggregations aii
WHERE aii.name = n.name
) ai
FULL OUTER JOIN
temptable tt
ON tt.element = ai.element
WHERE ai.element IS NULL OR tt.element IS NULL
)
This is more efficient than using COUNT(*), since it will stop checking a name as soon as it finds the first row that doesn't have a match (either in aggregations or in temptable)
This isn't tested, but usually I would do this with a query in my where clause for a small amount of data. Note that this is not efficient for large record counts.
SELECT ag1.Name FROM aggregations ag1
WHERE ag1.Element IN (2,3)
AND 0 = (select COUNT(ag2.Name)
FROM aggregatsions ag2
WHERE ag1.Name = ag2.Name
AND ag2.Element NOT IN (2,3)
)
GROUP BY ag1.name;
This says "Give me all of the names that have the elements I want, but have no records with elements I don't want"