How to get hours and minutes by subtracting two dates? - sql

Question

I want to get the hours and minutes between two dates. But it's not working and I getting this error
ORA-01843: not a valid month
01843. 00000 - "not a valid month"
Here's the script
select q.name as queue_name
,to_date(t.create_time, 'dd-mon-yyyy hh24:mi:ss')
,to_date(t.close_time, 'dd-mon-yyyy hh24:mi:ss')
,NUMTOYMINTERVAL(t.close_time - t.create_time, 'DAY')*24
,NUMTOYMINTERVAL(t.close_time - t.create_time, 'DAY')*24*60
from app_account.otrs_ticket t
left join app_account.otrs_user u
on t.create_user_id=u.id
left join app_account.otrs_queue q
on q.id=t.queue_id
group by to_date(t.create_time, 'dd-mon-yyyy hh24:mi:ss')
,to_date(t.close_time, 'dd-mon-yyyy hh24:mi:ss')
,NUMTOYMINTERVAL(t.close_time - t.create_time, 'DAY')*24
,NUMTOYMINTERVAL(t.close_time - t.create_time, 'DAY')*24*60
,q.name
order by to_date(t.create_time, 'dd-mon-yyyy hh24:mi:ss') desc;

Answer 1

Try this you will get atleast idea how to calculate time difference between two dates.
SELECT floor(((date1-date2)*24*60*60)/3600)
|| ' HOURS ' ||
floor((((date1-date2)*24*60*60) -
floor(((date1-date2)*24*60*60)/3600)*3600)/60)
|| ' MINUTES ' ||
round((((date1-date2)*24*60*60) -
floor(((date1-date2)*24*60*60)/3600)*3600 -
(floor((((date1-date2)*24*60*60) -
floor(((date1-date2)*24*60*60)/3600)*3600)/60)*60) ))
|| ' SECS ' time_difference
FROM dates;
TIME_DIFFERENCE
--------------------------------------------------------------------------------
24 HOURS 0 MINUTES 0 SECS
1 HOURS 0 MINUTES 0 SECS
0 HOURS 1 MINUTES 0 SECS
For Futher Reference Please Refer This Link :
Click Here

Answer 2

use NUMTODSINTERVAL(close_date - create_date, 'DAY') or NUMTOYMINTERVAL(close_date - create_date, 'DAY') for calculating the difference in days.
For hours multiply the value with 24 and for minutes with 24*60.
select q.name as queue_name
,to_date(t.create_time, 'dd-mon-yyyy hh24:mi:ss') as create_date
,to_date(t.close_time, 'dd-mon-yyyy hh24:mi:ss') as close_date
,NUMTODSINTERVAL(close_date - create_date, 'DAY') or NUMTOYMINTERVAL(close_date - create_date, 'DAY')*24
,NUMTODSINTERVAL(close_date - create_date, 'DAY') or NUMTOYMINTERVAL(close_date - create_date, 'DAY') *24*60
from app_account.otrs_ticket t
left join app_account.otrs_user u
on t.create_user_id=u.id
left join app_account.otrs_queue q
on q.id=t.queue_id
where q.name not like 'Facilities Management::%'
and q.name not like 'HR::%'
and q.name not like 'Raw%'
and q.name not like 'Procurement::%'
and q.name not like 'Facilities Management%'
and q.name not like 'Junk%'
and q.name not like 'Facility Request Test%'
and q.name not like 'Misc%'
and q.name not like 'POS::POS issue - need paper%'
group by to_date(t.create_time, 'dd-mon-yyyy hh24:mi:ss') as create_date
,to_date(t.close_time, 'dd-mon-yyyy hh24:mi:ss') as close_date
order by to_date(t.create_time, 'dd-mon-yyyy hh24:mi:ss') desc;

Answer 3

Another way would be to calculate the values directly without using any oracle function:
Here is an example:
WITH q AS
(SELECT TO_DATE(create_time, 'YYYY-MM-DD HH24:MI') AS d_start,
TO_DATE(close_time, 'YYYY-MM-DD HH24:MI') AS d_end
FROM app_account.otrs_ticket
)
SELECT FLOOR((d_end - d_start) * 24) AS hours,
FLOOR(((d_end - d_start) * 24 * 60) - (floor((d_end - d_start) * 24) * 60)) AS minutes
FROM q;
Hope it helps!

Answer 4

Cast your DATE (or whatever data type it is) to a TIMESTAMP. The difference gives you an INTERVAL value where you can extract all information. Should be like this:
EXTRACT(DAY FROM CAST(t.close_time AS TIMESTAMP) - CAST(t.create_time AS TIMESTAMP))*24*60
+ EXTRACT(HOUR FROM CAST(t.close_time AS TIMESTAMP) - CAST(t.create_time AS TIMESTAMP))*60
+ EXTRACT(MINUTE FROM CAST(t.close_time AS TIMESTAMP) - CAST(t.create_time AS TIMESTAMP)) AS MINUTES