unpivot row values into multiple columns - sql

Question

I have the following with the following structure:
http://sqlfiddle.com/#!6/0e72e/8
CREATE TABLE Prices
(
Day date,
ProductName nVARCHAR(10),
Location nVARCHAR(10),
RegPrice1 float,
SalePrice1 float,
SalePrice2 float
)
INSERT INTO Prices VALUES ('6/24/2014', 'xbox', 'NewYork',30,20,10)
INSERT INTO Prices VALUES ('6/24/2014', 'xbox', 'London', 100,80,60)
INSERT INTO Prices VALUES ('6/24/2014', 'xbox', 'Singapore', 70,50,30)
INSERT INTO Prices VALUES ('6/24/2014', 'watch1','NewYork', 500,400,300)
INSERT INTO Prices VALUES ('6/24/2014', 'watch1','London', 1000,800,600)
INSERT INTO Prices VALUES ('6/24/2014', 'watch1','Singapore', 999,888,777)
I want to unpivot this table so it looks like:
Day Pr_Name PriceType NewYork London Singapore
2014-06-24 xbox RegPrice1 30 100 70
2014-06-24 xbox SalePrice1 20 80 50
2014-06-24 xbox SalePrice2 10 60 30
2014-06-24 watch1 RegPrice1 500 1000 999
2014-06-24 watch1 SalePrice1 400 800 888
2014-06-24 watch1 SalePrice1 300 600 777
I was able to unpivot one layer to get the NewYork column but I haven't been able to get the London and Singapore columns in place. I have tinkered with the code below to add London and Singapore but have not been successful. Do I simply keep unpivoting?
select Day, ProductName, PriceType, NewYork
from (select * from Prices ) as t
Unpivot
(
NewYork for PriceType in (RegPrice1, SalePrice1, SalePrice2)
) As unpvt

Answer 1

we can use CROSS APPLY to unpivot the prices and then apply PIVOT
SELECT
*
FROM
( select Day, ProductName, Location, col, value
from Prices
cross apply
(
select 'RegPrice1' , Prices.RegPrice1 union all
select 'SalePrice1', Prices.SalePrice1 union all
select 'SalePrice2', Prices.SalePrice2
) c (col, value)
) PD
PIVOT
( max(value) for Location in ([NewYork],[London],[Singapore])
)pvt