How to replace rows with duplicated values in Access? - sql

I have 2 tables and I'd like to substitute rows from Table1 where Customer value is duplicated (for example, B) with a row from Table2 with the same Customer.
Table 1:
Customer cod
A 2
B 1
B N/A
C 5
Table 2:
Customer cod
B 123
So the result should be:
Customer cod
A 2
B 123
C 5
The code could be something like:
INSERT INTO Table1
SELECT *
FROM Table2, Table1
WHERE Table1.Customer = Table2.Customer;

First insert wanted data from table2
INSERT INTO Table1
SELECT *
FROM Table2 t21
WHERE (SELECT count(*)
FROM Table1 t12
WHERE t12.Customer=t21.Customer) > 1;
Then remove duuplicates from table1 which are not matching cod from table 2
DELETE
FROM Table1 t11
WHERE ((SELECT count(*)
FROM Table1 t12
WHERE t11.Customer = t12.Customer)>1
AND NOT cod IN (SELECT cod
FROM Table2 t21
WHERE t11.Customer=t21.Customer))
OR t11.cod IS NULL;

Related

Delete Rows based on two columns

How can I delete rows based on just two column conditions.
Example
Table 1
id name phone
1 aa 123
1 aa 345
1 bb 123
2 aa 456
1 NULL 123
1 123
My Expected output
id name phone
1 bb 123
2 aa 456
My condition to delete: if id and name is same, delete the rows
If one of the value in a condition is null or blank it should also delete the row as given in the input.
Delete from table1 t where exists (
Select * from
(Select id, name from table1 group by id, name having count(*) > 1) t2 where t.id = t2.id and t.name = t2.name)
This should do what you want. You can do the select first for testing purposes, then remove the Select and uncomment out the delete.
-- This joins on the table the set of data that has more then 1 row with duplicate IDs, and names. Then you can delete from here.
--DELETE t1
SELECT *
FROM Table1 T1
INNER JOIN (
-- this gets all the records that have more then 1 ID and Name that are the same.
SELECT ID, name
FROM Table1
GROUP BY ID, name
HAVING COUNT(*) > 1
) ToDelete ON T1.ID = ToDelete.ID
AND T1.name = ToDelete.name
create table #tablea (
id int,
name varchar(3),
phone int
)
insert into #tablea (id, name, phone)
values
(1,'aa','123'),
(1,'aa','345'),
(1,'bb','123'),
(2,'aa','456')
select * from #tablea
delete a
from #tablea a
inner join (
select id, name
from #tablea
group by id, name
having COUNT(*) > 1
) b on a.id = b.id and a.name = b.name
select * from #tablea
drop table #tablea

multiple select in sql server

I want to search between 2 tables but that field i want to search is foreign key in other table
my tables are like this:
table 1
ID TitleSR
1 888
2 999
table 2
ID TitleSR
1 11
2 22
3 33
4 44
table contain value
ID value
11 italy
22 swiss
888 lilium
999 mount
33 england
I think I understand you. Try this one:
Select *
From table3 as VCT Inner Join
(Select * From table1
Union
Select * From table2) as FGT
On VCT.ID = FGT.TitleSR
Where value = 'italy';
You can use either of these methods:
Returns only t1 fields
SELECT * FROM Table1 t1
WHERE t1.ID in (SELECT ID FROM Table2);
Returns ALL fields
SELECT * FROM Table1 t1
JOIN Table2 t2 on t1.ID = t2.ID;
If your 'values' exist in a separate table (tblValues), you can use any of these:
Returns tblValues fields
SELECT * FROM tblValues tval
WHERE tval.ID in (SELECT TitleSR FROM Table1);
returns ALL fields
SELECT *
FROM (tblValues tval
JOIN Table1 t1 on tval.ID = t1.TitleSR)
JOIN Table2 on tval.ID = Table2.TitleSR;

Aggregate functions as column results from multiple tables

I have the following table structures:
Table1
--------------
Table1Id
Field1
Field2
Table2
------------
Table2Id
Table1Id
Field1
Field2
Table3
-----------
Table3Id
Table1Id
Field1
Field2
I need to be able to select all fields in Table1, count of records in Table2, and count of records in Table3 Where count of records in Table2 > count of records in Table3
Here is an example of expected output with the given data:
Table1 Data
-------------
1 Record1Field1 Record1Feild2
2 Record2Field1 Record2Feild2
3 Record3Field1 Record3Feild2
4 Record4Field1 Record4Feild2
Table2 Data
------------
1 1 Record1Field1 Record1Feild2
2 1 Record2Field1 Record2Feild2
3 2 Record3Field1 Record3Feild2
4 2 Record4Field1 Record4Feild2
5 2 Record5Field1 Record5Feild2
6 4 Record6Field1 Record6Feild2
7 4 Record6Field1 Record6Feild2
8 4 Record6Field1 Record6Feild2
Table3 Data
------------
1 2 Record1Field1 Record1Feild2
2 2 Record2Field1 Record2Feild2
3 3 Record3Field1 Record3Feild2
4 3 Record4Field1 Record4Feild2
5 3 Record5Field1 Record5Feild2
6 4 Record6Field1 Record6Feild2
Desired Results
Table1Id Field1 Field2 Table2Count Table3Count
1 Record1Field1 Record1Field2 2 0
2 Record2Field1 Recird2Field2 3 2
4 Record4Field1 Recird4Field2 3 1
Notice record 3 in Table 1 is not shown because the record count in Table2 is less than the record count in Table3. I was able to make this work using a very ugly query similar to the one below but feel there is a much better way to do this using joins.
SELECT
t1.Table1Id,
t1.Field1,
t1.Field2
(Select Count(Table2Id) From Table2 t2 Where t2.Table1Id = t1.Table1Id) as Table2Count,
(Select Count(Table3Id) From Table3 t3 Where t3.Table1Id = t1.Table1Id) as Table3Count,
From
Table1 t1
Where
(Select Count(Table2Id) From Table2 t2 Where t2.Table1Id = t1.Table1Id) > (Select Count(Table3Id) From Table3 t3 Where t3.Table1Id = t1.Table1Id)
Hard to test it without working examples but something along these lines should be a good starting point.
SELECT
t1.Table1Id,
t1.Field1,
t1.Field2,
COUNT(DISTINCT t2.Table2Id),
COUNT(DISTINCT t3.Table3Id)
From Table1 t1
LEFT OUTER JOIN Table2 t2 ON t1.Table1Id = t2.Table1Id
LEFT OUTER JOIN Table3 t3 ON t1.Table1Id = t3.Table1Id
GROUP BY t1.Table1Id
HAVING COUNT(DISTINCT t2.Table2Id) > COUNT(DISTINCT t3.Table3Id)
You could get all the value in t1 and the data form t2 e t3 for your comparision using a couple of join on grouped values
SELECT
t1.Table1Id
,t1.Field1
,t1.Field2
, tt2.count_t2
, tt3.count_t3
from table1 t1
join (
select Table1Id, count(*) count_t2
From Table2
group by Table1Id
) tt2 on tt2.Table1Id = t1.Table1Id
join (
select Table1Id, count(*) count_t3
From Table3
group by Table1Id
) tt3 on tt3.Table1Id = t1.Table1Id
where tt2.count_t2 < tt3.count_t3 <

Query to get oldest date into a column?

I have some tables that look like this:
Table1
Column1
A
B
C
Table2
column1 Id1 Id2
A 2 100
A 3 101
B 2 100
B 3 101
C 2 100
Table3
Id2 Date Item Status
100 10/20/17 A1 A
101 10/21/17 A1 A
100 11/22/17 A2 I
101 11/23/17 A2 A
My query looks like this:
Select
Date, *
FROM TABLE1 T1
LEFT JOIN Table2 T2 ON
T1.Column1 = T2.Column2
LEFT JOIN Table3 T3 ON
T2.Id2 = T3.Id2
I would like to return the oldest date on table 3 where the status is A into the date column in my query.
I was able to return the oldest date with this query but can't integrate this into my query with joins.
SELECT
MIN(DATE)
FROM Table3
WHERE Id2 IN (100,101)
AND STATUS = 'A'
group by Id2, ITEM
How can I get the oldest date into the query that uses the join clauses?
Couple of ways to approach what I believe that you're trying to do.
I'd say the easiest would be to simplify your search parameters with a subquery of Table 3.
select * from table2 t2
LEFT JOIN
(Select Id2, Item, max(Date)from Table 3
WHERE Status = 'A'
GROUP BY Id2, Item)a ON t2.Id2 = a.Id2;
The subquery does the filtering and then a quick join to table 2 would get all your data.

Return null for second duplicate row in JOIN in Access

I saw few posts for avoiding duplicates. But this is not about removing duplicates from the output. but keeping duplicates from one table but avoiding rows repeating from the joining table.
So I have 2 table Table1 and Table2 . Table1 has duplicate values for ID column. Table2 does not have duplicate values for ID column. I wish to join both tables. In the result I want all rows from Table1 including duplicates but i do not want Table2 to repeat rows for each duplicate row in Table1.
Table1
ID Column2
1 A
1 B
2 C
3 D
Table2
ID Column3
1 X
2 Y
My Query is
Select A.ID,A.Column2,B.ID,B.Column3 from Table1 A LEFT JOIN Table2 B on A.ID=B.ID
The result i get is
ID Column2 ID Column3
1 A 1 X
1 B 1 X
2 C 2 Y
3 D null null
The expected result is
ID Column2 ID Column3
1 A 1 X
1 B null null
2 C 2 Y
3 D null null
i could not see any possibilities in access database .
Please let me know if there is any possibility of getting this result
I can not check right now, but you will get the idea:
select t11.id, t11.col2, t2.id, t2.col3
from (table1 t11
left join (select id, min(col2) as col2 from table1 group by id) t12
on t11.id = t12.id and t11.col2 = t12.col2)
left join table2 t2 on t12.id = t2.id