passing multiple varchar values to parameter in procedure [duplicate] - sql

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Passing an array of parameters to a stored procedure
(11 answers)
Closed 8 years ago.
sp_panelistid1 '585','201401','108972',''4','5''
alter procedure sp_panelistid1
(
#branch int,
#yearweak int,
#id int ,
#branchid varchar(10))
as
print #branchid
select f.lydelse as QuestionText, f.id as QuestionID, i.artal as Year, i.vecka as Week, i.id as Intervjuperson,
b.beskrivning as Branch, b.id as BranchID, v.beskrivning as Brand, v.id as BrandID, s.regperson as Buss, f.land as CountryID
, vi.NepaVikt as Weight , cp.CintPanelistId
from fraga f
inner join svar s on s.fraga = f.id
inner join bransch b on b.id = f.bransch
inner join varumarke v on v.id = s.varumarke
inner join intervjuperson i on i.id = s.intervjuperson
inner join vikt vi ON f.Bransch = vi.Bransch AND s.Intervjuperson = vi.Intervjuperson
inner join CintPanelistIntervjuperson cp on s.Intervjuperson=cp.Intervjuperson
where f.bransch = #branch
and (100*i.artal)+i.vecka > #yearweak
and f.land = 1 and f.id=#id
and v.beskrivning in (#branchid)
I need to pass multiple values in #branch id how do I pass parameters such that it works in 'IN condition ' like v.beskrivning in ('4','5','6','7 = Stämmer helt')

Answer 1

If you pass comma separated ids like this - '1, 2, 3' and if you want to use with "In" clause then you have to use Split() function. like this -
SELECT f.lydelse AS QuestionText
,f.id AS QuestionID
,i.artal AS Year
,i.vecka AS Week
,i.id AS Intervjuperson
,b.beskrivning AS Branch
,b.id AS BranchID
,v.beskrivning AS Brand
,v.id AS BrandID
,s.regperson AS Buss
,f.land AS CountryID
,vi.NepaVikt AS Weight
,cp.CintPanelistId
FROM fraga f
INNER JOIN svar s ON s.fraga = f.id
INNER JOIN bransch b ON b.id = f.bransch
INNER JOIN varumarke v ON v.id = s.varumarke
INNER JOIN intervjuperson i ON i.id = s.intervjuperson
INNER JOIN vikt vi ON f.Bransch = vi.Bransch
AND s.Intervjuperson = vi.Intervjuperson
INNER JOIN CintPanelistIntervjuperson cp ON s.Intervjuperson = cp.Intervjuperson
WHERE f.bransch = #branch
AND (100 * i.artal) + i.vecka > #yearweak
AND f.land = 1
AND f.id = #id
AND v.beskrivning IN (SELECT items FROM dbo.split(#branchid, ','))
Note: Split function is not in-built function. Its used defined table-valued function.
and here is the split function.
and here is the function.
CREATE FUNCTION [dbo].[Split] (
#String NVARCHAR(4000)
,#Delimiter CHAR(1)
)
RETURNS #Results TABLE (Items NVARCHAR(4000))
AS
BEGIN
DECLARE #INDEX INT
DECLARE #SLICE NVARCHAR(4000)
-- HAVE TO SET TO 1 SO IT DOESNT EQUAL Z
SELECT #INDEX = 1
IF #String IS NULL
RETURN
WHILE #INDEX != 0
BEGIN
-- GET THE INDEX OF THE FIRST OCCURENCE OF THE SPLIT CHARACTER
SELECT #INDEX = CHARINDEX(#Delimiter, #STRING)
-- NOW PUSH EVERYTHING TO THE LEFT OF IT INTO THE SLICE VARIABLE
IF #INDEX != 0
SELECT #SLICE = LEFT(#STRING, #INDEX - 1)
ELSE
SELECT #SLICE = #STRING
-- PUT THE ITEM INTO THE RESULTS SET
INSERT INTO #Results (Items)
VALUES (#SLICE)
-- CHOP THE ITEM REMOVED OFF THE MAIN STRING
SELECT #STRING = RIGHT(#STRING, LEN(#STRING) - #INDEX)
-- BREAK OUT IF WE ARE DONE
IF LEN(#STRING) = 0
BREAK
END
RETURN
END