returning only the most recent record in dataset - sql

Question

I have a query returning data for several dates.
I want to return only record with the most recent date in the field SAPOD (the date is in fact CYYMMDD where C=0 before 2000 and 1 after 2000 and I can show this as YYYYMMDD using SAPOD=Case when LEFT(SAPOD,1)=1 then '20' else '19' end + SUBSTRING(cast(sapod as nvarchar(7)),2,7))
here is my query:
SELECT GFCUS, Ne.NEEAN, SCDLE, SAPOD, SATCD,CUS.GFCUN, BGCFN1,
BGCFN2, BGCFN3, SV.SVCSA, SV.SVNA1, SV.SVNA2, SV.SVNA3,
SV.SVNA4, SV.SVNA5, SV.SVPZIP, SV.NONUK
FROM SCPF ACC
INNER JOIN GFPF CUS ON GFCPNC = SCAN
LEFT OUTER JOIN SXPF SEQ ON SXCUS = GFCUS AND SXPRIM = ''
LEFT OUTER JOIN SVPFClean SV ON SVSEQ = SXSEQ
LEFT OUTER JOIN BGPF ON BGCUS = GFCUS AND BGCLC = GFCLC
LEFT OUTER JOIN NEPF NE ON SCAB=NE.NEAB and SCAN=ne.NEAN and SCAS=ne.NEAS
LEFT OUTER JOIN SAPF SA ON SCAB=SAAB and SCAN=SAAN and SCAS=SAAS
WHERE
(SATCD>500 and
scsac='IV' and
scbal = 0 and
scai30<>'Y' and
scai14<>'Y' and
not exists(select * from v5pf where v5and=scan and v5bal<>0))
GROUP BY GFCUS, Ne.NEEAN, SCDLE, SAPOD, SATCD,
CUS.GFCUN, BGCFN1, BGCFN2, BGCFN3, SV.SVCSA,
SV.SVNA1, SV.SVNA2, SV.SVNA3, SV.SVNA4, SV.SVNA5, SV.SVPZIP, SV.NONUK
ORDER BY MAX(SCAN) ASC, SAPOD DESC
I am getting results like the below where there are several transactions by a customer, and we only want to show the data of the most recent transaction:
So how can I show just the most recent transaction? Is this a case where I should use an OUTER APPLY or CROSS APPY?
EDIT:
Sorry I should clarify that I need the most recent date for each of the unique records in the field NEEAN which is the Account number

Answer 1

You can use ROW_NUMBER() as follows:
SELECT
ROW_NUMBER() OVER (PARTITION BY Ne.NEEAN ORDER BY SAPOD DESC) AS [Row],
GFCUS, Ne.NEEAN, SCDLE, SAPOD, SATCD,CUS.GFCUN, BGCFN1,
BGCFN2, BGCFN3, SV.SVCSA, SV.SVNA1, SV.SVNA2, SV.SVNA3,
SV.SVNA4, SV.SVNA5, SV.SVPZIP, SV.NONUK
FROM SCPF ACC
INNER JOIN GFPF CUS ON GFCPNC = SCAN
LEFT OUTER JOIN SXPF SEQ ON SXCUS = GFCUS AND SXPRIM = ''
LEFT OUTER JOIN SVPFClean SV ON SVSEQ = SXSEQ
LEFT OUTER JOIN BGPF ON BGCUS = GFCUS AND BGCLC = GFCLC
LEFT OUTER JOIN NEPF NE ON SCAB=NE.NEAB and SCAN=ne.NEAN and SCAS=ne.NEAS
LEFT OUTER JOIN SAPF SA ON SCAB=SAAB and SCAN=SAAN and SCAS=SAAS
WHERE
(SATCD>500 and
scsac='IV' and
scbal = 0 and
scai30<>'Y' and
scai14<>'Y' and
not exists(select * from v5pf where v5and=scan and v5bal<>0)) and
[Row] = 1
GROUP BY GFCUS, Ne.NEEAN, SCDLE, SAPOD, SATCD,
CUS.GFCUN, BGCFN1, BGCFN2, BGCFN3, SV.SVCSA,
SV.SVNA1, SV.SVNA2, SV.SVNA3, SV.SVNA4, SV.SVNA5, SV.SVPZIP, SV.NONUK
ORDER BY MAX(SCAN) ASC
You could encapsulate this within a subquery if you don't want to return the [Row] column.

Answer 2

you can user row_number to get top 1 row per customer
In the where clause need to return values with pos value as 1
sample query
row_number() over ( partition by GFCUS order by SAPOD desc) as pos