SQL left join two tables independently - sql

If I have these tables:
Thing
id | name
---+---------
1 | thing 1
2 | thing 2
3 | thing 3
Photos
id | thing_id | src
---+----------+---------
1 | 1 | thing-i1.jpg
2 | 1 | thing-i2.jpg
3 | 2 | thing2.jpg
Ratings
id | thing_id | rating
---+----------+---------
1 | 1 | 6
2 | 2 | 3
3 | 2 | 4
How can I join them to produce
id | name | rating | photo
---+---------+--------+--------
1 | thing 1 | 6 | NULL
1 | thing 1 | NULL | thing-i1.jpg
1 | thing 1 | NULL | thing-i2.jpg
2 | thing 2 | 3 | NULL
2 | thing 2 | 4 | NULL
2 | thing 2 | NULL | thing2.jpg
3 | thing 3 | NULL | NULL
Ie, left join on each table simultaneously, rather than left joining on one than the next?
This is the closest I can get:
SELECT Thing.*, Rating.rating, Photo.src
From Thing
Left Join Photo on Thing.id = Photo.thing_id
Left Join Rating on Thing.id = Rating.thing_id

You can get the results you want with a union, which seems the most obvious, since you return a field from either ranking or photo.
Your additional case (have none of either), is solved by making the joins left join instead of inner joins. You will get a duplicate record with NULL, NULL in ranking, photo. You can filter this out by moving the lot to a subquery and do select distinct on the main query, but the more obvious solution is to replace union all by union, which also filters out duplicates. Easier and more readable.
select
t.id,
t.name,
r.rating,
null as photo
from
Thing t
left join Rating r on r.thing_id = t.id
union
select
t.id,
t.name,
null,
p.src
from
Thing t
left join Photo p on p.thing_id = t.id
order by
id,
photo,
rating

Here's what I came up with:
SELECT
Thing.*,
rp.src,
rp.rating
FROM
Thing
LEFT JOIN (
(
SELECT
Photo.src,
Photo.thing_id AS ptid,
Rating.rating,
Rating.thing_id AS rtid
FROM
Photo
LEFT JOIN Rating
ON 1 = 0
)
UNION
(
SELECT
Photo.src,
Photo.thing_id AS ptid,
Rating.rating,
Rating.thing_id AS rtid
FROM
Rating
LEFT JOIN Photo
ON 1 = 0
)
) AS rp
ON Thing.id IN (rp.rtid, rp.ptid)

MySQL has no support for full outer joins so you have to hack around it using a UNION:
Here's the fiddle: http://sqlfiddle.com/#!2/d3d2f/13
SELECT *
FROM (
SELECT Thing.*,
Rating.rating,
NULL AS photo
FROM Thing
LEFT JOIN Rating ON Thing.id = Rating.thing_id
UNION ALL
SELECT Thing.*,
NULL,
Photo.src
FROM Thing
LEFT JOIN Photo ON Thing.id = Photo.thing_id
) s
ORDER BY id, photo, rating

Related

How can I get join results as JSON in a PostgreSQL query?

I have the query below that almost works: It returns 3 rows one of which should have first_nation populated (other two should be NULL). But they all get the same data for first_nation. What I need is the person.id from the outer where to be a part of the WHERE in the inner query but I don't think that's doable. Any help would be appreciated.
Or another way, I'd like the results of the JOIN to be JSON rather than appearing as additional columns.
SELECT person.id,
(
SELECT row_to_json(x)
FROM (
SELECT ref_first_nations_gov.id
FROM ref_first_nations_gov JOIN person ON person.first_nation_id = ref_first_nations_gov.id
WHERE person.application_id = 1 AND person.archived = false
) x
) AS first_nation
FROM person
WHERE application_id = 1 AND archived = false;
EDIT: Sample Data
SELECT id, application_id, first_nation_id FROM person WHERE application_id = 1;
id | application_id | first_nation_id
----+----------------+-----------------
4 | 1 |
1 | 1 |
2 | 1 |
3 | 1 | 1
What the query above gives me:
id | first_nation
----+--------------
4 | {"id":1}
1 | {"id":1}
3 | {"id":1}
What I want
id | first_nation
----+--------------
4 |
1 |
3 | {"id":1}
Even though I don't have how to test this right now, I don't think you need a subquery.
Try something like this.
SELECT p.id, row_to_json(r.id) FROM person p
FULL OUTER JOIN ref_first_nations_gov r on r.id = p.first_nation_id
WHERE p.application_id = 1 AND p.archived = false;

GROUP BY with SUM without removing empty (null) values

TABLES:
Players
player_no | transaction_id
----------------------------
1 | 11
2 | 22
3 | (null)
1 | 33
Transactions
id | value |
-----------------------
11 | 5
22 | 10
33 | 2
My goal is to fetch all data, maintaining all the players, even with null values in following query:
SELECT p.player_no, COUNT(p.player_no), SUM(t.value) FROM Players p
INNER JOIN Transactions t ON p.transaction_id = t.id
GROUP BY p.player_no
nevertheless results omit null value, example:
player_no | count | sum
------------------------
1 | 2 | 7
2 | 1 | 10
What I would like to have is mention about the empty value:
player_no | count | sum
------------------------
1 | 2 | 7
2 | 1 | 10
3 | 0 | 0
What do I miss here?
Actually I use QueryDSL for that, but translated example into pure SQL since it behaves in the same manner.
using LEFT JOIN and coalesce function
SELECT p.player_no, COUNT(p.player_no), coalesce(SUM(t.value),0)
FROM Players p
LEFT JOIN Transactions t ON p.transaction_id = t.id
GROUP BY p.player_no
Change your JOIN to a LEFT JOIN, then add IFNULL(value, 0) in your SUM()
left join keeps all the rows in the left table
SELECT p.player_no
, COUNT(*) as count
, SUM(isnull(t.value,0))
FROM Players p
LEFT JOIN Transactions t
ON p.transaction_id = t.id
GROUP BY p.player_no
You might be looking for count(t.value) rather than count(*)
I'm just offering this so you have a correct answer:
SELECT p.player_no, COUNT(t.id) as [count], COALESCE(SUM(t.value), 0) as [sum]
FROM Players p LEFT JOIN
Transactions t
ON p.transaction_id = t.id
GROUP BY p.player_no;
You need to pay attention to the aggregation functions as well as the JOIN.
Please Try This:
SELECT P.player_no,
COUNT(*) as count,
SUM(isnull(T.value,0))
FROM Players P
LEFT JOIN Transactions T
ON P.transaction_id = T.id
GROUP BY P.player_no
Hope this helps.

Count / sum values in subquery and order by it

I have tables like below:
user
id | status
1 | 0
gallery
id | status | create_by_user_id
1 | 0 | 1
2 | 0 | 1
3 | 0 | 1
media
id | status
1 | 0
2 | 0
3 | 0
gallery_media
fk gallery.id fk media.id
id | gallery_id | media_id | sequence
1 | 1 | 1 | 1
2 | 2 | 2 | 1
3 | 2 | 3 | 2
monitor_traffic
1:gallery 2:media
id | anonymous_id | user_id | endpoint_code | endpoint_id
1 | 1 | | 1 | 2 gallery.id 2
2 | 2 | | 1 | 2 gallery.id 2
3 | | 1 | 2 | 3 media.id 3 include in gallery.id 2
these means gallery.id 2 contain 3 rows
gallery_information
fk gallery.id
id | gallery_id
gallery includes media.
monitor_traffic.endpoint_code: 1 .. gallery; 2 .. media
If 1 then monitor_traffic.endpoint_id references gallery.id
monitor_traffic.user_id, monitor_traffic.anonymous_id integer or null
Objective
I want to output gallery rows sort by count each gallery rows in monitor_traffic, then count the gallery related media rows in monitor_traffic. Finally sum them.
The query I provide only counts media in monitor_traffic without summing them and also does not count gallery in monitor_traffic.
How to do this?
This is part of a function, input option then output build query, something like this. I hope to find a solution (maybe with a subquery) that does not require to change other parts of the query.
Query:
SELECT
g.*,
row_to_json(gi.*) as gallery_information
FROM gallery g
LEFT JOIN gallery_information gi ON gi.gallery_id = g.id
LEFT JOIN "user" u ON u.id = g.create_by_user_id
-- start
LEFT JOIN gallery_media gm ON gm.gallery_id = g.id
LEFT JOIN (
SELECT
endpoint_id,
COUNT(*) as mt_count
FROM monitor_traffic
WHERE endpoint_code = 2
GROUP BY endpoint_id
) mt ON mt.endpoint_id = m.id
-- end
ORDER BY mt.mt_count desc NULLS LAST;
sql fiddle
I suggest a CTE to count both types in one aggregation and join to it two times in the FROM clause:
WITH mt AS ( -- count once for both media and gallery
SELECT endpoint_code, endpoint_id, count(*) AS ct
FROM monitor_traffic
GROUP BY 1, 2
)
SELECT g.*, row_to_json(gi.*) AS gallery_information
FROM gallery g
LEFT JOIN mt ON mt.endpoint_id = g.id -- 1st join to mt
AND mt.endpoint_code = 1 -- gallery
LEFT JOIN (
SELECT gm.gallery_id, sum(ct) AS ct
FROM gallery_media gm
JOIN mt ON mt.endpoint_id = gm.media_id -- 2nd join to mt
AND mt.endpoint_code = 2 -- media
GROUP BY 1
) mmt ON mmt.gallery_id = g.id
LEFT JOIN gallery_information gi ON gi.gallery_id = g.id
ORDER BY mt.ct DESC NULLS LAST -- count of galleries
, mmt.ct DESC NULLS LAST; -- count of "gallery related media"
Or, to order by the sum of both counts:
...
ORDER BY COALESCE(mt.ct, 0) + COALESCE(mmt.ct, 0) DESC;
Aggregate first, then join. That prevents complications with "proxy-cross joins" that multiply rows:
Two SQL LEFT JOINS produce incorrect result
The LEFT JOIN to "user" seems to be dead freight. Remove it:
LEFT JOIN "user" u ON u.id = g.create_by_user_id
Don't use reserved words like "user" as identifier, even if that's allowed as long as you double-quote. Very error-prone.

Count how many times a value appears in tables SQL

Here's the situation:
So, in my database, a person is "responsible" for job X and "linked" to job Y. What I want is a query that returns: name of person, his ID and he number of jobs it's linked/responsible. So far I got this:
select id_job, count(id_job) number_jobs
from
(
select responsible.id
from responsible
union all
select linked.id
from linked
GROUP BY id
) id_job
GROUP BY id_job
And it returns a table with id in the first column and number of occurrences in the second. Now, what I can't do is associate the name of person to the table. When i put that in the "select" from beginning it gives me all the possible combinations... How can I solve this? Thanks in advance!
Example data and desirable output:
| Person |
id | name
1 | John
2 | Francis
3 | Chuck
4 | Anthony
| Responsible |
process_no | id
100 | 2
200 | 2
300 | 1
400 | 4
| Linked |
process_no | id
101 | 4
201 | 1
301 | 1
401 | 2
OUTPUT:
| OUTPUT |
id | name | number_jobs
1 | John | 3
2 | Francis | 3
3 | Chuck | 0
4 | Anthony | 2
Try this way
select prs.id, prs.name, count(*) from Person prs
join(select process_no, id
from Responsible res
Union all
select process_no, id
from Linked lin ) a on a.id=prs.id
group by prs.id, prs.name
I would recommend aggregating each of the tables by the person and then joining the results back to the person table:
select p.*, coalesce(r.cnt, 0) + coalesce(l.cnt, 0) as numjobs
from person p left join
(select id, count(*) as cnt
from responsible
group by id
) r
on r.id = p.id left join
(select id, count(*) as cnt
from linked
group by id
) l
on l.id = p.id;
select id, name, count(process_no) FROM (
select pr.id, pr.name, res.process_no from Person pr
LEFT JOIN Responsible res on pr.id = res.id
UNION
select pr.id, pr.name, lin.process_no from Person pr
LEFT JOIN Linked lin on pr.id = lin.id) src
group by id, name
order by id
Query ain't tested, give it a shot, but this is the way you want to go

Remove NULL values from multiple LEFT JOIN in sql server

I have the following tables
ITEM1
ID | NAME | GEARS | ITEM2_ID |
-------------------------------
1 | Test | 56 | 4 |
2 | Test2| 12 | 2 |
ITEM3
ID | NAME | DATA | ITEM2_ID |
-------------------------------
1 | Test | 1 | 1 |
2 | Test7| 22 | 3 |
ITEM2
ID | VALUE |
--------------------
1 | is simple |
2 | is hard |
3 | is different|
4 | is good |
5 | very good |
And my query
SELECT TOP(3) * FROM (
SELECT ID,
rankTable.RANK as RANK_,
TOTALROWS = COUNT(*) OVER()
FROM ITEM2
INNER JOIN
CONTAINSTABLE(ITEM2, [VALUE], 'ISABOUT("good")') as rankTable
ON ITEM2.ID = rankTable.[KEY]
) as ITEM2table
LEFT JOIN (
SELECT ID,
NAME,
GEARS,
ITEM2_ID
FROM ITEM1
) as ITEM1table
ON ITEM1table.ITEM2_ID = ITEM2table.ID
LEFT JOIN (
SELECT ID,
NAME,
DATA,
ITEM2_ID
FROM ITEM3
) as ITEM3table
ON ITEM3table.ITEM2_ID = ITEM2table.ID
and the results
How to remove (if is possible) the first row (ID = 5) using the above SQL query ? Also I want to show TOTALROWS = 1 because other row contains NULL's except first 3 columns.
Thank you.
If I understand correctly, you want to keep only the rows where either the first or the second (or both) outer join succeeds:
WHERE ITEM1table.ITEM2_ID IS NOT NULL
OR ITEM3table.ITEM2_ID IS NOT NULL
Some simplifications can be done on the query. No need for the nested subqueries:
SELECT TOP(3)
ITEM2table.ID,
rankTable.RANK as RANK_,
TOTALROWS = COUNT(*) OVER(),
ITEM1table.*,
ITEM3table.*
FROM
ITEM2
INNER JOIN
CONTAINSTABLE(ITEM2, [VALUE], 'ISABOUT("good")') as rankTable
ON ITEM2.ID = rankTable.[KEY]
LEFT JOIN
ITEM1 as ITEM1table
ON ITEM1table.ITEM2_ID = ITEM2.ID
LEFT JOIN
ITEM3 as ITEM3table
ON ITEM3table.ITEM2_ID = ITEM2.ID
WHERE ITEM1table.ITEM2_ID IS NOT NULL
OR ITEM3table.ITEM2_ID IS NOT NULL
ORDER BY something --- you need to order by something
--- if you use TOP. Unless you want
--- 3 (random) rows.
Maybe there's an obvious reason, but if you want to eliminate rows where the second table doesn't have a match, why are you using a left join? It seems like your first join should be an inner join and your second should be left - that would give you the results you want in this case.
You can either use INNER JOIN instead of LEFT JOIN, or put
WHERE ITEM1table.ID IS NOT NULL AND ITEM3table.ID IS NOT NULL
at the end of your query