I have a variable that I need to retain for the rest of the visit if it changes. I am not sure how to do that in SQL
What it looks like now:
ID DATE VISIT MARKER1
1 4-5-10 1 0
1 4-6-10 1 1
1 4-7-10 1 0
1 8-9-10 2 0
What I need to happen:
ID DATE VISIT MARKER1
1 4-5-10 1 0
1 4-6-10 1 1
1 4-7-10 1 1
1 8-9-10 2 0
I need the change to be carried through for the rest of the visit.
UPDATE t1
SET t1.Marker1=1
FROM TABLE t1
INNER JOIN(
SELECT MIN(DATE) [MinDate],Visit,ID FROM TABLE WHERE Marker1=1 GROUP BY ID,Visit
) minDate on minDate.ID=t1.ID
AND minDate.Visit=t1.Visit
AND t1.[DATE]>MinDate.MinDate
WHERE t1.Marker1=0
Related
For example there is some table with below data:
No Id Value
1 100 1
2 100 0
3 100 1
4 100 2
1 101 1
2 101 2
1 102 0
2 102 1
I have to write SQL query, which will return row count based on specific condition. If the value matches 0 then need to reset running counts and start from 1 and make previous row values as 0
So the result will be like:
No Id Value Running Count
1 100 1 0
2 100 0 0
3 100 1 1
4 100 1 2
1 101 1 1
2 101 2 2
1 102 1 0
2 102 0 0
Your sample dataset is quite limited so I'm not sure of all edge cases but see if the following works for you. If not it might help get you there.
This gets a running count using a window & case expression and uses lead to check the next value.
If the current value or next value is 0 the count is 0, otherwise it's the running count subtracting 1 if there is a 0 in the Id block indicating the count was reset.
select No, Id, Value,
case when value = 0 or nv = 0
then 0
else
rc - case when Min(value) over(partition by id) = 0 then 1 else 0 end
end Running_Count
from (
select *,
Sum(case when value = 0 then 0 else 1 end) over(partition by id order by no) rc,
Lead(Value) over(partition by Id order by No)nv
from t
)t;
I have data as below where for one customer ID there are several orders (KEY) which is the primary key. I have also have a activity flag as below (either 0 or 1).
CUST_ID KEY FLAG
1 1 1
1 2 1
1 3 1
1 4 0
1 5 0
1 6 1
1 7 1
1 8 0
1 9 0
Now I want to create ranks as below based on the FLAG. The idea is to give same Rank as preceding row if the FLAG is same as preceding row. The Rank increments if the current value is different from preceding value.
CUST_ID KEY FLAG RN
1 1 1 1
1 2 1 1
1 3 1 1
1 4 0 2
1 5 0 2
1 6 1 3
1 7 1 3
1 8 0 4
1 9 0 4
I'm new to SQL, so please let me know if I need to reframe my question.
Use LAG() window function to get each row's previous flag and then use SUM() window function to create the rankings:
SELECT CUST_ID, KEY, FLAG,
SUM(CASE WHEN FLAG <> prev_FLAG THEN 1 END) OVER (PARTITION BY CUST_ID ORDER BY KEY) RN
FROM (
SELECT *, LAG(FLAG, 1, FLAG - 1) OVER (PARTITION BY CUST_ID ORDER BY KEY) prev_FLAG
FROM tablename
) t;
See the demo.
The code could be simplified, depending on the specific database that you use.
I have a table with data as shown below (the table is built every day with current date, but I left off that field for ease of reading).
This table keeps track of people and the doors they enter on a daily basis.
Table entrance_t:
id entrance entered
------------------------
1 a 0
1 b 0
1 c 0
1 d 0
2 a 1
2 b 0
2 c 0
2 d 0
3 a 0
3 b 1
3 c 1
3 d 1
My goal is to report on people and count entrances not used(grouping on people), but ONLY if they entered(entered=1).
So using the above table, I would like the results of query to be...
id count
----------
2 3
3 1
(id=2 did not use 3 of the entrances and id=3 did not use 1)
I tried queries(some with inner joins on two instances of same table) and I can get the entrances not used, but it's always for everybody. Like this...
id count
----------
1 4
2 3
3 1
How do I not display results id=1 since they did not enter at all?
Thank you,
You could use conditional aggregation:
SELECT id, count(CASE WHEN entered = 0 THEN 1 END) AS cnt
FROM entrance_t
GROUP BY id
HAVING count(CASE WHEN entered = 1 THEN 1 END) > 0;
DBFiddle Demo
Have the following table tblTrans where
Trans_ID Trans Sequence Trans_PointsEarned Trans_PointsApplied
4452 1 1 1
4452 2 1 1
4452 3 0 1
4462 1 1 1
4462 2 1 1
4462 3 1 1
4462 4 1 1
4462 5 1 1
9101 1 0 1
9101 2 0 1
9101 3 0 1
9101 4 0 1
(useless table doesnt work)
I need to set the following on another field per every customer ID.
So Customer_OverallPoints
4452 = 2 (doesn't count 0's)
4462 = 4 (I want to cap the points to 4 based on the sequence and transID and customerID)
9101 = 0 (dont count 0's).
This needs to be applied to thousands of records based on customerID and TransID where Trans_Sequence is within the same Trans_ID and it only counts the first 4 rows that have the Trans_pointsEarned = 1.
I tried putting a psuedocode together but it just looked ridicilous and I can't even come up with the logic for this.
Thanks
Assuming that TransId is really the customer id, I think the basic logic is just an aggregation:
select t.TransId,
(case when sum(t.Trans_PointsEarned) > 4 then 4
else sum(t.Trans_PointsEarned)
end) as Customer_OverallPoints
from tblTrans t
group by t.TransId;
You can put this into an update statement as:
update customers c
set Customer_OverallPoints = (select (case when sum(t.Trans_PointsEarned) > 4 then 4
else sum(t.Trans_PointsEarned)
end)
from tblTrans t
where t.TransId = c.CustomerId
);
The simple question is how can you take a set of records with a PK and create exactly two records for each source with a slightly altered key for the duplicate? In other words, I take 4000 records and produce 8000 records where 4000 are identical and the other 4000 have a slightly altered key. I cannot do a union because this is essentially two selects (long story).
The rest gets complicated, but maybe necessary to provide examples.
This is my original set (it contains over 4000 records)
dateGroup areaGroup itemID editionID
1 1 1 1
1 1 1 2
1 2 1 1
1 2 2 1
2 1 1 1
2 1 1 2
2 2 1 1
2 2 1 2
For each record I need to create a duplicate record ganging the areaGroups together under '0', then create a comma separated list of original areaGroups as a separate field. (The "why" is some dumb programmer (me) made a mistake about 15 years ago.) I can renumber the editionIDs as necessary, but the original and duplicate record must have the same editionID (thus why a union wouldn't work). The PK remains the same as above (all fields)
dateGroup areaGroup itemID editionID aGroups
1 0 1 1 1
1 0 1 2 1
1 0 1 1 2 // Duplicate (EditionID)
1 0 2 1 2
2 0 1 1 1
2 0 1 2 1
2 0 1 1 2 // Duplicate (EditionID)
2 0 1 2 2
The end result would renumber the editionID as needed to make the record unique.
dateGroup areaGroup itemID editionID aGroups (EditionID is what is altered)
1 0 1 1 1
1 0 1 2 1
1 0 1 2 2 1 changed to 2 (one more than row 1)
1 0 2 1 2
2 0 1 1 1
2 0 1 2 1
2 0 1 2 2 1 changed to 2 (one more than row 1)
2 0 1 2 2
1 1 1 1
1 1 1 2
1 2 1 2 1 changed to 2 (editionID) to match
1 2 2 1
2 1 1 1
2 1 1 2
2 2 1 2 1 changed to 2 to match above
2 2 1 2
I know you could calculate the editionID like a row rank like so:
select row_number() over (
partition by dateGroup, itemID
order by dateGroup, itemID) as editionID
So all I need is to know how to duplicate the records from a single set
do a cross join on a derived table:
( select 1 as aGroups union all select 2 )
I'd create a temporary table with duplicates and their count.
Then I'd filter the original table to have only unique rows, and insert another row for each row in the temporary table, incrementing their editionID.
In MySQL, I'd use user #variables; not sure about MS SQL.
Did you try UNION ALL instead of just UNION
UDPATE perhaps I misunderstood the problem and I thought you were having a problem with the union loosing the duplicates.
If the problem is that you want to do a row_number over a union why don't you do somthing like
select row_number() over (
partition by dateGroup, itemID
order by dateGroup, itemID) as editionID
FROM
(
SELECT
dateGroup, itemID
FROM TableA
UNION ALL
SELECT
dateGroup, itemID
FROM TableB
) Data