I've created an iPhone app in objective-c with Xcode 5. It's a simple redirect to an app on AppStore via button (UIbutton and its IBAction). Can I open directly this app if it's already installed on iOS? Because in spite of this app is already available on iPhone it's carry on to open it via AppStore!
If it is your app, or you know it well and it has a custom url scheme, you may use Application::canOpenUrl: (link) to check for its existence and Application::openUrl: to launch the application.
This will not be possible for third party applications that do not have, or of which you don't know a custom url scheme.
you need to use URL schemes, a method for sending and receiving data between applications.
A physical device is required for testing this app.look at this example .sample example
try this example . if you face any issue let me know about that.
Yeah! Problem solved...I had to use only URL Scheme of the App I want to open, and insert inside openurl method, -> https://stackoverflow.com/a/24033837/3706995
Related
I need to open a third-party app from my react native mobile app. I understand that this is called universal linking on iOS and AppLink on Android.
I have done a lot of research for this, and I have been able to set up a link to the third party app on the app store. Now I just need to get my app to open up the app if the user has it installed. That requires the URI scheme of the other app, though.
My question is, how do I get the URI scheme to this third party app? Rather, how do I get the URI scheme of any app? I know the URI scheme of the twitter app is 'twitter://app', but the app I am trying to link to is way more niche than twitter or other popular apps, so there is no help for this sort of thing online.
Any tips?
Finding the URL scheme of an iOS app
Due to Apple's tendency for secrecy, it's not easy to find the URL scheme of an iOS app. But it can be done. Here's how I do it, using a Mac app called iMazing.
Launch iMazing, select a connected iOS device, click Apps:
In the footer of the window, click Manage Apps:
Select the app you're interested in , then select Export .IPA menu item. Note: You may need to download the app first.
The saved file will have the .ipa extension. Change the extension to .zip, and unzip the file. You now have a directory with the name matching the app's name.
Assuming "asana" is the app name, open the file "asana/Payload/asana.app/Info.plist" in a text editor, and search for a section that contains "CFBundleURLSchemes". Assuming the app contains CFBundleURLSchemes (they are optional), it should look something like this:
The URL scheme is in the <string>asana</string>, so the complete url scheme in this case is "asana://". Test that the URL launches the app by typing it into iOS Safari browser window. If it works, Safari should display an alert like this:
What About Apps Without CFBundleURLSchemes?
I haven't found a way to launch apps without CFBundleURLSchemes directly, but you can link to the app's page in the App Store, where the user can open the app with the Open button (or Get button if the app is not installed).
You will need to obtain the app page's URL from the App Store:
Open App Store, go to the app's page, click the share icon:
Click Copy Link:
The URL will look like this:
https://apps.apple.com/us/app/asana-organize-tasks-work/id489969512
Clicking on that link in Safari will bring up the app page in the App Store.
Maybe it is worth to start with some background:
There are various ways to deep link into an app, and it depends on the platform (iOS\Android\WindowsPhone...) and its version.
On iOS, up until version 9, the way to open an app was by using URI schemes, e.g. the one you added above: twitter://app. Each app declares the scheme that should be used. Therefore in order to deep link into the app you wish to open, you'll need to use the scheme that it declared. This is the same for Android until version 6.
Starting iOS9+, Apple introduced Universal Links as the method for deep linking. Here's some information: https://developer.apple.com/ios/universal-links/
In these versions, URI schemes won't longer work when using Safari browser (which is the iOS default browser) if the app is not installed. If the app is installed, however, URI schemes should allow opening the app, if everything is configured successfully. In Android there's a similar method called "AppLinks".
Having said this, the above information is for setting deep link for your app. I do not think that it is a common use case to open a third party app from your app - deep links are configured and used by the app owner (e.g. for publishing his\her app to engage users).
Using onesignal, When one sets the push notification value "url" for a notificaiton to open in an app, aka universal linking, by default the app is opened and a webview screen emerges (not on android, only iOS - at least in React Native).
I want to ignore this webview. I don't want to open it. The url is supposed to open the app to the corresponding universal link/deep link, not my domain on a web broswer. If I click on a similar link from a non-notificaiton source, it takes me to the screen, why does the push notification not do this?
How do I override this? I can't seem to figure it out. Do I have to manually implement this? Why does it open a webview by default and not the corresponding screen in the app instead?
It seems you have to manually route it if one were to go this route, unfortunately. From what I'm gathering bits here and there.
this is a bad choice to go with if you're using iOS:
https://www.myapp.com/p/fdsafa
this is better:
myapp://p/fdsafa
unfortunately onesignal has it setup in some weird way with the https://www.myapp.com that it makes it useless on iOS, unless your actual intention is to open an actual web url in a webview. Where as myapp:// is compatible with both platforms (just don't put a host on Android, leave the host out, just do the myapp as the schema). Works.
I have a requirement to open the native version of the hybrid app (.ipa/.apk/.appx) when the hybrid app is requested in a device browser.
I am able to detect the environment using WL.Client.getEnvironment(); method, if it is found to be Android/iPad, I want to launch the respective .apk/.ipa file in the device. Any help is appreciated.
Re-reading this question and the comments several times... I still do not understand the actual scenario... it'd be best to rephrase it.
Scenario: How to open an app from the web browser:
If you have added the following environments to your Worklight application:
Mobile Web
Android
iPhone
And when visiting the Mobile Web version of your app, you want to display a message like "For the full experience, open the full application by clicking here".
Then:
It is implied that the user already has the application installed.
If it is not installed, you need to take care of that somehow
The way to handle this scenario is to use URI schemas:
For Android: How to implement my very own URI scheme on Android
This means that after adding the custom URI schema to AndroidManifest.xml, you could then detect the device OS the Mobile Web app is currently running on and display a custom link: myapp://<the URI schema you've defined>. Tapping it will open the app installed on the device.
For iOS, in a similar fashion: https://coderwall.com/p/mtjaeq
Also see: http://wiki.akosma.com/IPhone_URL_Schemes
Alternate solution: If you are not sure if the app will be installed or not, then instead of using URI schemas you can always point to either Google Play or Apple App Store, to the app page; the user will then have either a "Open" or "Install" link.
Scenario: How to open an app from my own app
If you have a Worklight Hybrid application (Mobile Web is not a Hybrid application), and you want to open another application from within it, you can:
Use the same approach of URI schemas, or
Use Cordova plug-ins
I have created this Worklight 6.1.0 project to demonstrate:
Android - How to open, for example, the Android Settings app from your Worklight Hybrid app
iOS - How to check if Waze is installed and open it, and if it is not installed then to open Apple Maps instead.
See instructions.txt in the apps\test folder.
Are you asking that if the user via their device browser hits the webapp version of your app on the internet, the website will ask the user to fire up the native app on their device? kind of like what ebay does?
if that is what you want check out these pages
android:Launch custom android application from android browser
IOS:
iPhone - Open Application from Web Page
I want to place a button or a link in my app with which the user can start the app-store and buy my app if the app is in trial mode.
I can not find any relavant Information on this. How can I implement this?
MSDN documentation: Creating links with the Windows Store protocol. Alternatively, the URI for the app in the store can be accessed using the Windows.ApplicationModel.Store.CurrentApp.LinkUri property.
You can then open a link to your app in the store using Windows.System.Launcher.LaunchUriAsync.
Is it possible/allowed to run 2nd App from 1st App ? if yes, how ?
IOS platform. i want to find out is it possible to pass data to 2nd app and execute it?
You can register a custom URL scheme if you are the developer of both apps. Alternatively the 3rd party app might support it's own URL scheme, allowing you to launch and pass data.
There's a tutorial on how to implement custom URL schemes in an iOS app here: http://iosdevelopertips.com/cocoa/launching-your-own-application-via-a-custom-url-scheme.html
system(3), or fork(2) and exec(3).