Complex sql server query - sql

Question

I need some help with a SQL query I'm working on. Here is a simplified version of the data I'm working with. I have 3 tables:
Contacts:
- ContactID
- ContactName
Submissions:
- SubmissionID
- ContactID
- SubmissionTypeID
SubmissionTypes:
- SubmissionTypeID
- SubmissionType
I need to return all of the Contacts (joined to Submissions on ContactID) where there are SubmissionTypeIDs that match up with a list of SubmissionTypeIDs. The tricky part is that I only want results where a Contact has a Submission record with a SubmissionTypeID that matches each of the values in the list. So, for instance, if I had this data:
Contacts
----------------
1 | Jim Johnson
2 | Sally Anderson
SubmissionTypes
----------------------
1 | Contact Form
2 | Request Form
3 | Generic Form
Submissions
----------------------
1 | 1 | 1
2 | 1 | 2
3 | 2 | 1
If my SubmissionTypeID values are 1 and 2, I'd want to get the following results:
Jim Johnson | Contact Form
Jim Johnson | Request Form
I wouldn't want to see Sally Anderson because she doesn't have a record in Submissions for both values.
I'm guessing there are a few ways to do this. I'm excited to see your ideas.
Thank you!

Answer 1

Here's a convoluted way using double negation.
declare #list table (SubmissionTypeID int not null primary key);
insert into #list values (1), (2); -- values to search for.
with c as (
select
c.ContactID,
c.ContactName
from
Contacts c
where
not exists (
select
'x'
from
#list l
where
not exists (
select
'x'
from
Submissions s
where
s.ContactID = c.ContactID and
s.SubmissionTypeID = l.SubmissionTypeID
)
)
)
select
c.ContactName,
t.SubmissionType
from
c
inner join
Submissions s
on c.ContactId = s.ContactId
inner join
SubmissionTypes t
on s.SubmissionTypeID = t.SubmissionTypeID
inner join
#list l
on t.SubmissionTypeID = l.SubmissionTypeID;
Example SQLFiddle

Answer 2

One way is with INTERSECT:
select c.contactname, t.submissiontype
from contacts c
join submissions s
on c.contactid = s.contactid
join submissiontypes t
on s.submissiontypeid = t.submissiontypeid
join (select c.contactid
from contacts c
join submissions s
on c.contactid = s.contactid
where s.submissiontypeid = 1
intersect
select c.contactid
from contacts c
join submissions s
on c.contactid = s.contactid
where s.submissiontypeid = 2) v
on c.contactid = v.contactid
where s.submissiontypeid in (1, 2)
Fiddle: http://sqlfiddle.com/#!6/9ee4e/2/0
You can also COUNT where equal to 2 (you have 2 values you're checking for):
select c.contactname, t.submissiontype
from contacts c
join submissions s
on c.contactid = s.contactid
join submissiontypes t
on s.submissiontypeid = t.submissiontypeid
join (select c.contactid
from contacts c
join submissions s
on c.contactid = s.contactid
where s.submissiontypeid in (1, 2)
group by c.contactid
having count(distinct s.submissiontypeid) = 2) v
on c.contactid = v.contactid
where s.submissiontypeid in (1, 2)
Fiddle: http://sqlfiddle.com/#!6/9ee4e/1/0

Answer 3

Try this.. It works fine to me
DECLARE #list TABLE (SubmissionTypeID int not null primary key);
INSERT INTO #list VALUES(1); -- values to search for.
SELECT C.ContactName, ST.SubmissionTypeName
FROM
(
SELECT *, ROW_NUMBER() OVER(PARTITION BY S.ContactID ORDER BY S.ContactID) AS RCount
FROM
Submission S
WHERE EXISTS
(SELECT 1 FROM #list l WHERE l.SubmissionTypeID = S.SubmissionTypeID)) AS Result
INNER JOIN Submission S1 ON S1.ContactID = Result.ContactID
INNER JOIN Contacts C ON C.ContactID = Result.ContactID
INNER JOIN SubmissionTypes ST ON ST.SubmissionTypeID = S1.SubmissionTypeID
WHERE RCOunt = (SELECT COUNT(DISTINCT SubmissionTypeID) FROM #list)
AND EXISTS
(SELECT 1 FROM #list l WHERE l.SubmissionTypeID = ST.SubmissionTypeID)
;