Order By column 2, group by column 1 - sql

Question

Maybe is the title not clear enough, but didn't knew an better way to say it.
The thing is that I've got an table called Partij which has an idPartij and an Moederpartij. The column Moederpartij will point back to idPartij ( so we can create an Mother -> Child relation ).
This is the Query I have so far:
SELECT
P.idPartij,
P.Partijnaam,
P.Gewicht,
PER.Perceel,
P.Moederpartij
FROM Partij AS P
LEFT OUTER JOIN Perceel AS PER ON P.idPerceel = PER.idPerceel
WHERE P.Actief = 1
ORDER BY
P.Moederpartij ASC,
P.Partijnaam ASC
Which results in the following output:
360 | 34 Avarna 13-1V | | 0
280 | 36 Agata 13-1V | | 0
160 | 37 Excellency 13-1V | | 0
140 | 38 Erika 13-1V | | 0
300 | 39 Rosagold 13-1V | | 0
240 | 40 Fontane 13-2V | | 0
200 | 41 Fontane 13-1V | | 0
220 | 42 Fontane 13-3V | | 0
180 | 45 Spunta 13-3V | | 0
260 | 46 Arnova 13-1V | | 0
400 | 43 Spunta 13-2V | | 180
380 | 44 Spunta 13-1V | | 180
320 | 35 Altus 13-1V | | 260
340 | 47 Arizona 13-1V | | 260
But I'm trying to get the following output:
360 | 34 Avarna 13-1V | | 0
280 | 36 Agata 13-1V | | 0
160 | 37 Excellency 13-1V | | 0
140 | 38 Erika 13-1V | | 0
300 | 39 Rosagold 13-1V | | 0
240 | 40 Fontane 13-2V | | 0
200 | 41 Fontane 13-1V | | 0
220 | 42 Fontane 13-3V | | 0
180 | 45 Spunta 13-3V | | 0
400 | 43 Spunta 13-2V | | 180
380 | 44 Spunta 13-1V | | 180
260 | 46 Arnova 13-1V | | 0
320 | 35 Altus 13-1V | | 260
340 | 47 Arizona 13-1V | | 260
So that you first get the Mother (Moederpartij) And after that all the Childs, and so on...
Is this even possible in 1 single Query or should I loop in PHP through the records an get all the child for each record?
EDIT 1
The DB where this is running, is an MariaDB.

Answer 1

Try this one. I had added an column in the select query and sorted based on it. Since I don't have the MariaDB have not tested the query but I am sure it shld solve ur query.
SELECT
P.idPartij,
P.Partijnaam,
P.Gewicht,
PER.Perceel,
P.Moederpartij,
case when P.Moederpartij =0 then
Concat(P.idPartij ,"-", "0","-", P.idPartij )
else
Concat(P.Moederpartij ,"-", "9","-", P.idPartij )
end sorder
FROM Partij AS P
LEFT OUTER JOIN Perceel AS PER ON P.idPerceel = PER.idPerceel
WHERE P.Actief = 1
ORDER BY
sorder Asc

Answer 2

I am not sure if I understand your question, but is "Avarna 13-1V" for example the full party name, and the mother as you call it is "Avarna"?
I.e. you want all Spuntas, Fontanes etc. together but they also contain the 13-1V, 13-2V etc. and that's what throws it off?
You could order by just the first word first (locate the space separator & take the left of that), then by the mother party field. E.g. something like this:
ORDER BY LEFT(Partijnaam, LOCATE(' ',Partijnaam) - 1), Moederpartij
But if that is the case why not just separate the text name and the 13-v1 etc. into different columns?
(MySQL)