combing two rows of data in Sql - sql

Question

So my data looks like this:
+-----------+---------+-------------+-------+-------------+--+
| time | Outlets | Meal_Period | cover | day_of_week | |
+-----------+---------+-------------+-------+-------------+--+
| 10/1/2013 | 72 | 1 | 0 | Tuesday | |
| 10/1/2013 | 72 | 2 | 31 | Tuesday | |
| 10/1/2013 | 72 | 3 | 116 | Tuesday | |
| 10/1/2013 | 72 | 6 | 32 | Tuesday | |
| 10/1/2013 | 187 | 17 | 121 | Tuesday | |
| 10/1/2013 | 187 | 18 | 214 | Tuesday | |
| 10/1/2013 | 187 | 19 | 204 | Tuesday | |
| 10/1/2013 | 101 | 2 | 0 | Tuesday | |
| 10/1/2013 | 101 | 3 | 0 | Tuesday | |
| 10/1/2013 | 101 | 4 | 0 | Tuesday | |
| 10/1/2013 | 101 | 6 | 0 | Tuesday | |
| 10/1/2013 | 282 | 1 | 17 | Tuesday | |
| 10/1/2013 | 282 | 2 | 207 | Tuesday | |
| 10/1/2013 | 282 | 3 | 340 | Tuesday | |
| 10/1/2013 | 282 | 6 | 4 | Tuesday | |
| 10/1/2013 | 103 | 1 | 0 | Tuesday | |
+-----------+---------+-------------+-------+-------------+--+
The code is:
IF OBJECT_ID('tempdb.dbo.#time') IS NOT NULL
DROP TABLE #time
SELECT DATEADD(dd, 0, DATEDIFF(DD, 0, open_dttime)) AS 'time'
,profit_center_id AS 'Outlets'
,meal_period_id AS 'Meal_Period'
,sum(num_covers) AS 'Number_Covers'
INTO #time
FROM [STOF_Infogen].[dbo].[Order_Header]
WHERE CasinoID = 'csg'
AND profit_center_id IN (
'102'
,'100'
,'283'
,'101'
,'282'
,'187'
,'280'
,'103'
,'281'
,'72'
,'183'
)
AND (
open_dttime BETWEEN '2014-02-01 06:30'
AND '2014-03-01 06:30'
)
GROUP BY profit_center_id
,open_dttime
,meal_period_id
ORDER BY profit_center_id
,meal_period_id
IF OBJECT_ID('tempdb.dbo.#time2') IS NOT NULL
DROP TABLE #time2
SELECT [TIME]
,Outlets AS 'Outlets'
,meal_period AS 'Meal_Period'
,SUM(number_covers) AS 'cover'
,DATENAME(DW, [time]) AS 'day_of_week'
INTO #time2
FROM #time
GROUP BY [TIME]
,Outlets
,Meal_Period
ORDER BY [TIME] ASC
,Outlets
,Meal_Period
SELECT *
FROM #time2
I created temporary drop tables for my date but I'm having two issues;
I will like to group where the profit centres are 187 and 282 while still keeping the other rows.
for some reason I can't tweek the date stamp because it excludes the last day of the month.
As always any help is appreciated.

Answer 1

Making some test data:
DECLARE #MealInfo TABLE
(
MealTime DATETIME,
Outlets VARCHAR(10),
Meal_Period int,
Cover INT
)
INSERT INTO #MealInfo
VALUES
('10/1/2013', '72', 1, 0),
('10/1/2013', '72', 2, 31),
('10/1/2013', '72', 3, 116),
('10/1/2013', '72', 6, 32),
('10/1/2013', '187', 17, 121),
('10/1/2013', '187', 18, 214),
('10/1/2013', '187', 19, 204),
('10/1/2013', '101', 2, 0),
('10/1/2013', '101', 3, 0),
('10/1/2013', '101', 4, 0),
('10/1/2013', '101', 6, 0),
('10/1/2013', '282', 1, 17),
('10/1/2013', '282', 2, 207),
('10/1/2013', '282', 3, 340),
('10/1/2013', '282', 6, 4),
('10/1/2013', '103', 1, 0);
Because you want to group 187 and 282 together, I use a case statement to lump them into one outlet and then we can group on the outlets to break out the sums:
SELECT
m.MealTime,
m.Outlets,
m.Meal_Period,
SUM(m.Cover) AS Number_Covers
FROM
(
SELECT mi.MealTime,
(CASE WHEN mi.Outlets IN ('187', '282') THEN '187+282' ELSE mi.Outlets END) Outlets,
mi.Meal_Period,
mi.Cover
FROM #MealInfo mi
) m
GROUP BY m.MealTime, m.Outlets, m.Meal_Period
Here is the output:
MealTime Outlets Meal_Period Number_Covers
2013-10-01 00:00:00.000 101 2 0
2013-10-01 00:00:00.000 101 3 0
2013-10-01 00:00:00.000 101 4 0
2013-10-01 00:00:00.000 101 6 0
2013-10-01 00:00:00.000 103 1 0
2013-10-01 00:00:00.000 187+282 1 17
2013-10-01 00:00:00.000 187+282 2 207
2013-10-01 00:00:00.000 187+282 3 340
2013-10-01 00:00:00.000 187+282 6 4
2013-10-01 00:00:00.000 187+282 17 121
2013-10-01 00:00:00.000 187+282 18 214
2013-10-01 00:00:00.000 187+282 19 204
2013-10-01 00:00:00.000 72 1 0
2013-10-01 00:00:00.000 72 2 31
2013-10-01 00:00:00.000 72 3 116
2013-10-01 00:00:00.000 72 6 32
If your data had overlapping periods for 187 and 282, the sum total would contain both parts into 1 column.