Date Diff- TSQL # months in each year between dates - sql

Problem: Time Span between two dates. I would like to know how many months are between each date. The trick is: the number of months in each year between the two dates.
For example:
Start date = 1/1/2014
End Date = 3/1/2016
The output:
Column 1: "2014" would have a value of 12
Column 2: "2015" would have a value of 12
Column 3: "2016" would have a value of 2
This would be for a list with many dates (with different years)
EDIT: You would indeed have to have 14 year columns for a date span between 2000-2014. However, it is unlikely that more than 5 columns would need to be added.
Current train of thought
declare #datediff as int
select
#datediff=(Datediff(MONTH,[begin date], [end date]))
from [DateRange]
select
case
when #datediff <= 12 then #datediff
when #datediff <= 24 then #datediff -12
when #datediff <= 36 then #datediff -24
when #datediff <= 48 then #datediff -36
else NULL
end
from [DateRange]
Any ideas on this one?
I am very new to SQL and was only able to get the total months between the two with the following code:
select
datediff(MONTH,[begin date], [end date])
from [tableofdates]

Use below Query, you need to use your table in place of mydates table in below example. I used for maximum 10 year difference (represented by columns Y1,Y2 ... Y10).
The outer Query group by is used transpose the data to match to your requirement where you wanted month difference in column...
Inner query Q3 will provide the same results in rows with no limit to date range (actually there is limit i.e 2048 years due to master table master..spt_values which I guess you will not reach).
select
Q3.begindt,
Q3.enddt,
Q3.Diff_in_Year,
sum(Case when Q3.Year_Counter = 0 Then datediff(mm,Q3.y_start,Q3.y_end)+1 else 0 end) Y1,
sum(Case when Q3.Year_Counter = 1 Then datediff(mm,Q3.y_start,Q3.y_end)+1 else 0 end) Y2,
sum(Case when Q3.Year_Counter = 2 Then datediff(mm,Q3.y_start,Q3.y_end)+1 else 0 end) Y3,
sum(Case when Q3.Year_Counter = 3 Then datediff(mm,Q3.y_start,Q3.y_end)+1 else 0 end) Y4,
sum(Case when Q3.Year_Counter = 4 Then datediff(mm,Q3.y_start,Q3.y_end)+1 else 0 end) Y5,
sum(Case when Q3.Year_Counter = 5 Then datediff(mm,Q3.y_start,Q3.y_end)+1 else 0 end) Y6,
sum(Case when Q3.Year_Counter = 6 Then datediff(mm,Q3.y_start,Q3.y_end)+1 else 0 end) Y7,
sum(Case when Q3.Year_Counter = 7 Then datediff(mm,Q3.y_start,Q3.y_end)+1 else 0 end) Y8,
sum(Case when Q3.Year_Counter = 8 Then datediff(mm,Q3.y_start,Q3.y_end)+1 else 0 end) Y9,
sum(Case when Q3.Year_Counter = 9 Then datediff(mm,Q3.y_start,Q3.y_end)+1 else 0 end) Y10
From
(select
Q1.begindt,
Q1.enddt,
Q1.years Diff_in_Year,
Q2.number as Year_Counter,
(Case when Q2.number = 0 then Q1.begindt else dateadd(yy, datediff(yy,0,dateadd(yy,q2.number,q1.begindt)),0)End) AS y_Start,
(case when ((Q1.years-1) = Q2.number) then Q1.enddt else DATEADD(yy, DATEDIFF(yy,0,dateadd(yy,q2.number+1,q1.begindt) + 1), -1) End) AS y_End,
Year(Q1.begindt)+Q2.number YearInYYYY
from
(select begindt,enddt,DATEDIFF(year,begindt,enddt)+1 as years from mydates) Q1
join master..spt_values Q2 on Q2.type = 'P' and Q2.number < Q1.years
) Q3
Group by Q3.begindt,Q3.enddt,q3.Diff_in_Year
Output of the Above Query
begindt enddt YDif Y1 Y2 Y3 Y4 Y5 Y6 Y7 Y8 Y9 Y10
2010-07-02 2014-02-06 5 6 12 12 12 2 0 0 0 0 0
2011-01-01 2014-12-31 4 12 12 12 12 0 0 0 0 0 0
2012-05-22 2017-12-16 6 8 12 12 12 12 12 0 0 0 0

Related

Sum of particular column with month and year with fiscal year from custom date

I have following data in my table:
uniqueId d_date amount
1 2018-02-01 100.25
2 2019-03-01 456.5
3 2018-02-01 455
4 2019-05-01 200.48
5 2018-06-01 100
6 2019-07-01 200
7 2018-12-01 6950
8 2019-02-01 60
9 2020-01-20 100
Now when I enter start date = '2018-03-12' then my fiscal year must start with march 2018 to feb 2019 and so on.
If i enter start date = '2019-05-12' then my fiscal year must start with May 2019 to April 2020
I have tried below query but it is not working properly and also it calculate past year which is 2017 I do not want any data from past year from my entered custom date. So if entered start date = '2018-03-12' then is must start calculation for 2018 and above years only. No past year.
Declare #startdate as date
Declare #monthDate as int
Declare #ownmonth as int
set #startdate = '2018-03-12'
set #monthDate = month(#startdate)
set #ownmonth = 1
select
year(dateadd(month, -#monthDate, d_date)) year,
sum(case when month(d_date) = case when #monthDate+1 > 12 then #ownmonth else #monthDate+1 End then amount end) ,
sum(case when month(d_date) = case when #monthDate+2 > 12 then #ownmonth+1 else #monthDate+2 End then amount end) ,
sum(case when month(d_date) = case when #monthDate+3 > 12 then #ownmonth+2 else #monthDate+3 End then amount end) ,
sum(case when month(d_date) = case when #monthDate+4 > 12 then #ownmonth+3 else #monthDate+4 End then amount end) ,
sum(case when month(d_date) = case when #monthDate+5 > 12 then #ownmonth+4 else #monthDate+5 End then amount end) ,
sum(case when month(d_date) = case when #monthDate+6 > 12 then #ownmonth+5 else #monthDate+6 End then amount end) ,
sum(case when month(d_date) = case when #monthDate+7 > 12 then #ownmonth+6 else #monthDate+7 End then amount end) ,
sum(case when month(d_date) = case when #monthDate+8 > 12 then #ownmonth+7 else #monthDate+8 End then amount end) ,
sum(case when month(d_date) = case when #monthDate+9 > 12 then #ownmonth+8 else #monthDate+9 End then amount end) ,
sum(case when month(d_date) = case when #monthDate+10 > 12 then #ownmonth+9 else #monthDate+10 End then amount end) ,
sum(case when month(d_date) = case when #monthDate+11 > 12 then #ownmonth+10 else #monthDate+11 End then amount end) ,
sum(case when month(d_date) = case when #monthDate+12 > 12 then #ownmonth+11 else #monthDate+12 End then amount end) ,
sum(amount) total
from mytable
group by year(dateadd(month, -#monthDate, amount))
order by year
But above query does not show proper year & month wise data
Now I want output with fiscal year calculation:
Year Mar Apr May Jun July Aug Sept Oct Nov Dec Jan Feb Total
2018 - - - 100 - - - - - 6950 - 60 7110
2019 456.5 - 200.48 - 200 - - - - - 100 - 956.98
I can not use PIVOT as it is not supported in my compact SQL Server version.
How can I do this?
Your rule for a fiscal year is the year's March until the following year's February:
date | fiscal year
... | ...
2018-02-28 | 2017
2018-03-01 | 2018
... | 2018
2019-02-28 | 2018
2019-03-01 | 2019
... | ...
That means when we subtract two months from a date, we get a date the year of which is the fiscal year:
date | date - 2 months | fiscal year
... | ... | ...
2018-02-28 | 2017-12-28 | 2017
2018-03-01 | 2018-01-01 | 2018
... | ... | 2018
2019-02-28 | 2018-12-28 | 2018
2019-03-01 | 2019-01-01 | 2019
... | ... | ...
select
year(dateadd(month, -2, d_date)) as fiscal_year,
sum(case when month(d_date) = 3 then amount else 0 end) as mar,
sum(case when month(d_date) = 4 then amount else 0 end) as apr,
sum(case when month(d_date) = 5 then amount else 0 end) as may,
sum(case when month(d_date) = 6 then amount else 0 end) as jun,
sum(case when month(d_date) = 7 then amount else 0 end) as jul,
sum(case when month(d_date) = 8 then amount else 0 end) as aug,
sum(case when month(d_date) = 9 then amount else 0 end) as sep,
sum(case when month(d_date) = 10 then amount else 0 end) as oct,
sum(case when month(d_date) = 11 then amount else 0 end) as nov,
sum(case when month(d_date) = 12 then amount else 0 end) as dec,
sum(case when month(d_date) = 1 then amount else 0 end) as jan,
sum(case when month(d_date) = 2 then amount else 0 end) as feb,
sum(amount) as total
from mytable
group by year(dateadd(month, -2, d_date))
order by year(dateadd(month, -2, d_date));
If you want to limit this to the fiscal year a given date resides in, add:
where year(dateadd(month, -2, d_date)) = year(dateadd(month, -2, #given_date))
And well, if you want to limit this to the fiscal years beginning with that year, that would of course be:
where year(dateadd(month, -2, d_date)) >= year(dateadd(month, -2, #given_date))
UPDATE: You want a fiscal year to start with the first day of the month of a given date. I.e. If the given date is 1990-04-23, then a fiscal year starts with April. This changes above query only slightly, because rather than subtracting 2 months (for March), we must generalize this to subtracting one month less than the given month.
I am using a modulo operation when comparing months in order not to end up with months 13, 14, etc.
select
year(dateadd(month, - month(#startdate) + 1, d_date)) as fiscal_year,
sum(case when month(d_date) = (month(#startdate) + 0) % 12 then amount else 0 end) as first,
sum(case when month(d_date) = (month(#startdate) + 1) % 12 then amount else 0 end) as second,
sum(case when month(d_date) = (month(#startdate) + 2) % 12 then amount else 0 end) as third,
sum(case when month(d_date) = (month(#startdate) + 3) % 12 then amount else 0 end) as fourth,
sum(case when month(d_date) = (month(#startdate) + 4) % 12 then amount else 0 end) as fith,
sum(case when month(d_date) = (month(#startdate) + 5) % 12 then amount else 0 end) as sixth,
sum(case when month(d_date) = (month(#startdate) + 6) % 12 then amount else 0 end) as seventh,
sum(case when month(d_date) = (month(#startdate) + 7) % 12 then amount else 0 end) as eighth,
sum(case when month(d_date) = (month(#startdate) + 8) % 12 then amount else 0 end) as nineth,
sum(case when month(d_date) = (month(#startdate) + 9) % 12 then amount else 0 end) as tenth,
sum(case when month(d_date) = (month(#startdate) + 10) % 12 then amount else 0 end) as eleventh,
sum(case when month(d_date) = (month(#startdate) + 11) % 12 then amount else 0 end) as twelfth,
sum(amount) as total
from mytable
group by year(dateadd(month, - month(#startdate) + 1, d_date))
order by year(dateadd(month, - month(#startdate) + 1, d_date));
And again, if we want our results start from the fiscal year of the given date, we'd add:
where year(dateadd(month, - month(#startdate) + 1, d_date)) >= year(#startdate)

Group by datepart and find total count of individual values of each record

This is table structure;
ID Score Valid CreatedDate
1 A 1 2018-02-19 23:33:10.297
2 C 0 2018-02-19 23:32:40.700
3 B 1 2018-02-19 23:32:30.247
4 A 1 2018-02-19 23:31:37.153
5 B 0 2018-02-19 23:25:08.667
...
I need to find total number of each score and valid in each month
I mean final result should be like
Month A B C D E Valid(1) NotValid(0)
January 123 343 1021 98 12 1287 480
February 516 421 321 441 421 987 672
...
This is what I tried;
SELECT DATEPART(year, CreatedDate) as Ay,
(select count(*) from TableResults where Score='A') as 'A',
(select count(*) from TableResults where Score='B') as 'B',
...
FROM TableResults
group by DATEPART(MONTH, CreatedDate)
but couldn't figure how to calculate all occurrence of scores on each month.
Use conditional aggregation.
SELECT DATEPART(year, CreatedDate) as YR
, DATEPART(month, CreatedDate) MO
, sum(Case when score = 'A' then 1 else 0 end) as A
, sum(Case when score = 'B' then 1 else 0 end) as B
, sum(Case when score = 'C' then 1 else 0 end) as C
, sum(Case when score = 'D' then 1 else 0 end) as D
, sum(Case when score = 'E' then 1 else 0 end) as E
, sum(case when valid = 1 then 1 else 0 end) as Valid
, sum(case when valid = 0 then 1 else 0 end) as NotValid
FROM TableResults
GROUP BY DATEPART(MONTH, CreatedDate), DATEPART(year, CreatedDate)
I'm not a big fan of queries in the select; I find they tend to cause performance problems in the long run. Since we're aggregating here I just applied the conditional logic to all the columns.

Group by day from a certain hour of the day

SQLServer 2008r2. I have a table which is populated with a record at 10 mins past every hour of every day. Every hour the job is run it also enters 48 records which represent a forecast of what is likely to happen for the next 48 hours. Note - Just before it enters the 48 hour forecast it deletes the forecast which was entered last time. So although it enters a 48 hour forecast every hour there is only ever one forecast in the system. The relevant fields in the table look like this:
currentScore obsDate
9 2017-06-22 08:10:00
9 2017-06-22 07:10:00
9 2017-06-22 06:10:00
10 2017-06-22 05:10:00
... ...
How can I query this table and group by day from a certain time of day? I would like the day to start at 6am the day before and finish at 6am on the day. I only need five records from the table, the day, two before and two in the future. So if its Jun 20 I want June 18, 19, 20, 21 and 22. Here is the query which gets the correct results by calendar day.
SELECT cast(obsDate AS DATE) AS theDate
,sum(CASE
WHEN currentScore < 8
THEN 1
ELSE 0
END) AS currentscore_low
,sum(CASE
WHEN currentScore >= 8
AND currentScore < 17
THEN 1
ELSE 0
END) AS currentscore_medium
,sum(CASE
WHEN currentScore >= 17
THEN 1
ELSE 0
END) AS currentscore_high
FROM diseaseScores
WHERE siteID = 8315
AND obsDate >= cast(getdate() - 2 AS DATE)
GROUP BY cast(obsDate AS DATE)
ORDER BY cast(obsDate AS DATE);
which returns this result:
theDAte low med high
2017-06-18 23 0 0
2017-06-19 22 0 0
2017-06-20 5 19 0
2017-06-21 0 24 0
2017-06-22 0 9 0
There is a new requirement to get the same result but the group by and the subsequent counts need to be from 6am to 6am. e.g
the first rec should be from 2017-06-17 06:00am to 2017-06-18 06:00am
the second rec should be from 2017-06-18 06:00am to 2017-06-19 06:00am
....etc
How can I do this? Thanks in advance
UPDATE, I have done two things:
1..introduce Tims idea
2..I also add an extra field 'numOfScores' to show how many hours worth of data
each line represent
select
cast(dateadd(hour, -6, obsDate) as date) as theDate, count(currentScore) as numOfScores,
sum(case when currentScore < 8 then 1 else 0 end) as currentscore_low,
sum(case when currentScore >= 8 and currentScore < 17
then 1 else 0 end) as currentscore_medium,
sum(case when currentScore >= 17 then 1 else 0 end) as currentscore_high
from diseaseScores
where siteID = 8315 and
obsDate >= cast(getdate() - 2 as date)
group by cast(dateadd(hour, -6, obsDate) as date)
order by cast(dateadd(hour, -6, obsDate) as date);
I now get this result:
2017-06-18 5 5 0 0
2017-06-19 24 23 1 0
2017-06-20 24 1 23 0
2017-06-21 24 8 16 0
2017-06-22 24 1 23 0
2017-06-23 9 0 9 0
This tells me that that there is only 5 hours worth of scores on the 2017-06-18. I want this first line to be 24 hours worth. From 6am on the 17th until 6am on the 18th. This makes me think I am not getting the result I wish
The 23rd only having 9 hours is ok because this is the most recent forecast
UPDATED:
I dont think its easily done in one query (if even possible) so I will just use five queries and specifically state the dates&times to get my outcome. e.g here are the first two:
select
sum(case when currentScore < 9 then 1 else 0 end) as numOfLOWRecs,
sum(case when currentScore > 8 and currentScore < 17 then 1 else 0 end) as currentscore_medium,
sum(case when currentScore >= 17 then 1 else 0 end) as currentscore_high
from diseaseScores where siteID = 9999
and obsDate >= '2017-06-18 06:00' and obsDate < '2017-06-19 06:00'
select
sum(case when currentScore < 9 then 1 else 0 end) as numOfLOWRecs,
sum(case when currentScore > 8 and currentScore < 17 then 1 else 0 end) as currentscore_medium,
sum(case when currentScore >= 17 then 1 else 0 end) as currentscore_high
from diseaseScores where siteID = 9999
and obsDate >= '2017-06-19 06:00' and obsDate < '2017-06-20 06:00'
One trick which might work here would be to simply shift each observation backwards by 6 hours. This would shift 2017-06-17 06:00:00 to 2017-06-17 00:00:00, i.e. now 6am becomes the start of that actual day.
select
cast(dateadd(hour, -6, obsDate) as date) as theDate,
sum(case when currentScore < 8 then 1 else 0 end) as currentscore_low,
sum(case when currentScore >= 8 and currentScore < 17
then 1 else 0 end) as currentscore_medium,
sum(case when currentScore >= 17 then 1 else 0 end) as currentscore_high
from diseaseScores
where siteID = 8315 and
obsDate >= cast(getdate() - 2 as date)
group by cast(dateadd(hour, -6, obsDate) as date)
order by cast(dateadd(hour, -6, obsDate) as date);

How to convert Dynamic 7 day rows into columns with t-sql

Background Info
I have a large table 400M+ rows that changes daily (one days data drops out an a new days data drops in) The table is partitioned on a 'day' field so there are 31 paritions.
Each row in the table has data similar to this:
ID, Postcode, DeliveryPoint, Quantity, Day, Month
1 SN1 1BG A1 6 29 1
2 SN1 1BG A1 1 28 1
3 SN1 1BG A2 2 27 1
4 SN1 1BG A1 3 28 1
5 SN2 1AQ B1 1 29 12
6 SN1 1BG A1 2 26 12
I need to pull out 7 days of data in the format:
Postcode, Deliverypoint, 7dayAverage, Day1,day2,Day3,Day4,Day5,Day6,Day7
SN1 1BG A1 2 0 1 2 1 3 4 0
I can easily extract the data for the 7 day period but need to create a columnar version as shown above.
I have something like this:
select postcode,deliverypoint,
sum (case day when 23 then quantity else 0 end) as day1,
sum (case day when 24 then quantity else 0 end) as day2,
sum(case day when 25 then quantity else 0 end) as day3,
sum(case day when 26 then quantity else 0 end) as day4,
sum(case day when 27 then quantity else 0 end) as day5,
sum(case day when 28 then quantity else 0 end) as day6,
sum(case day when 29 then quantity else 0 end) as day7,
sum(quantity)*1.0/#daysinweek as wkavg
into #allweekdp
from maintable dp with (nolock)
where day in (select day from #days)
group by postcode,deliverypoint
where #days has the day numbers in the 7 day period.
But as you can see, I've hard-coded the day numbers into the query, I want to get them out of my temporary table #days but can't see a way of doing it (an array would be perfect here)
Or a I going about this in completely the wrong way ?
Kind Regards
Steve
If I understand correctly, what I would do is:
Convert the day and month columns into datetime values,
Get the first day of the week and day of the weekday (1-7) for each date, and
Pivot the data and group by the first day of the week
see here: sqlfiddle
As utexaspunk suggested, Pivot might be the way to go. I've never been comfortable with pivot and have preferred to pivot it manually so I control how everything looks, so I'm using a similar solution to how you did your script to solve the issue. No idea how the performance between my way and utexaspunk's will compare.
Declare #Min_Day Integer = Select MIN(day) as Min_Day From #days;
With Day_Coding_CTE as (
Select Distinct day
, day - #Min_Day + 1 as Day_Label
From #days
)
, Non_Columnar_CTE as (
Select dp.postcode
, dp.deliverypoint
, d.day
, c.Day_Label
, SUM(quantity) as Quantity
From maintable dp with (nolock)
Left Outer Join #days d
on dp.day = d.day --It also seems like you'll need more criteria here, but you'll have to figure out what those should be
Left Outer Join Day_Coding_CTE c
on d.day = c.day
)
Select postcode
, deliverypoint
, SUM(Case
When Day_Label = 1
Then Quantity
Else 0
End) as Day1
, SUM(Case
When Day_Label = 2
Then Quantity
Else 0
End) as Day2
, SUM(Case
When Day_Label = 3
Then Quantity
Else 0
End) as Day3
, SUM(Case
When Day_Label = 4
Then Quantity
Else 0
End) as Day4
, SUM(Case
When Day_Label = 5
Then Quantity
Else 0
End) as Day5
, SUM(Case
When Day_Label = 6
Then Quantity
Else 0
End) as Day6
, SUM(Case
When Day_Label = 7
Then Quantity
Else 0
End) as Day7
, SUM(Quantity)/#daysinweek as wkavg
From Non_Columnar_CTE
Group by postcode
deliverypoint

SQL Server - Using Sum of Count

I am using SQL Server. The Formula I need to use is (Good-Bad)/Total_Responses. A Good is when the value is >=9 and a Bad is <=6.
The Data I have is:
DATE Q1 Q2
2012-03-04 9 9
2012-03-04 8 8
2012-03-04 7 9
2012-03-04 4 NA
2012-03-04 10 10
2012-03-04 8 3
2012-03-04 3 4
2012-03-04 2 6
2012-03-04 6 8
2012-03-04 NA 6
I know I am going to have to use a "CASE WHEN ISNUMERIC(Q1)=1" to make sure it does not use the NA values (They are stored as Nvarchar)
So the formula would end up being (5-8)/18=-0.16666
So overall I am trying to get the data to look like:
DATE Promotor_Score
2012-03-04 -0.16666
Thank You!
Does this do the trick?
SELECT Date,
CAST((SUM(CASE WHEN ISNUMERIC(Q1) != 1 THEN 0
WHEN CAST(Q1 AS int) >= 9 THEN 1
WHEN CAST(Q1 AS int) <= 6 THEN -1
ELSE 0 END)
+ SUM(CASE WHEN ISNUMERIC(Q2) != 1 THEN 0
WHEN CAST(Q2 AS int) >= 9 THEN 1
WHEN CAST(Q2 AS int) <= 6 THEN -1
ELSE 0 END)) AS float)
/ (SUM(CASE WHEN ISNUMERIC(Q1) != 1 THEN 0
ELSE 1 END)
+ SUM(CASE WHEN ISNUMERIC(Q2) != 1 THEN 0
ELSE 1 END))
FROM Questions
GROUP BY Date
Or if 'NA' is the only non-numeric value, test for it explicitly.
Buildin on #DavidM answer, I added float conversion and Q2 column awareness:
SELECT [date],
1e0 -- a float multiplier to avoid integer value
* SUM( 0
-- get the positive, negative or neutral from q1
+ CASE WHEN ISNUMERIC(q1) != 1 THEN 0
WHEN CAST(q1 AS int) >= 9 THEN 1
WHEN CAST(q1 AS int) <= 6 THEN -1
ELSE 0 END
-- get the positive, negative or neutral from q2
+ CASE WHEN ISNUMERIC(q2) != 1 THEN 0
WHEN CAST(q2 AS int) >= 9 THEN 1
WHEN CAST(q2 AS int) <= 6 THEN -1
ELSE 0 END
)
/ SUM( 0
-- get the number of valid questions from q1
+ CASE WHEN ISNUMERIC(q1) != 1 THEN 0 ELSE 1 END
-- get the number of valid questions from q2
+ CASE WHEN ISNUMERIC(q2) != 1 THEN 0 ELSE 1 END
)
FROM Questions
GROUP BY Date;