The goal of this select is to get the latest score for a system that is in status = 'FD'. I want to get the ID of the row (id), the system ID (sys_id), and the score (score).
The following SQL gives me the id of the system (sys_id) as well as the score (score), but I also would like to get the id column associated with this score and sys_id. Hopefully that makes sense.
select sys_id, score from example
where (sys_id, end_date) in
(
select sys_id, max (end_date)
from example
where status = 'FD'
group by sys_id
);
Here is a SQL Fiddle to give you an idea of what I am talking about http://www.sqlfiddle.com/#!4/169a2/3
Before you ask, yes the combination of sys_id and end_date would give me a unique row and I could find the id that way, but I would rather get the id in my select statement.
You can use a simple CTE to get the max date for each SYS_ID, and join that back to your table to get all the details for that particular record.
with CTE as (
select sys_id, max (end_date) as MaxDate
from example
where status = 'FD'
group by sys_id)
select
EXAMPLE.*
from
EXAMPLE
INNER JOIN CTE
ON EXAMPLE.SYS_ID = CTE.SYS_ID
and EXAMPLE.END_DATE = CTE.MaxDate
Check out the change to your SQL Fiddle
answer from comment. SUbquery a is from your statement...lazy programming on my part.
select a.*, e.score
from
(
select sys_id, max (end_date) as 'ed'
from example
where status = 'FD'
group by sys_id
)a
inner join example e on a.ed = e.end_date and a.sys_id = e.sys_ID
Works on the predicate that there is only one unqiue value for a given sys_id and end date. Multiple end dates will return multiple rows in a cross join format.
Related
I have a situation where I store in a table each member's availability.
It's a simple table with 4 column.
CREATE TABLE availablities (
availablity_id serial PRIMARY KEY,
member_id serial,
availablity_status_id serial,
start_date timestamp
);
Each member can have multiple records in the table and to get the current status
I get for each member the record that has the most recent start_date that is smaller then now().
I first tried with a naive Max() and Group by query
select
status_code, max(start_date) start_date,availablities.member_id
from
availablities
join
availablity_status on availablity_status.availablity_status_id = availablities.availablity_status_id
where
start_date <= now()
group by
status_code,availablities.member_id;
But this return multiple records per user as I get the most recent record by user and by status.
I finally came up with a query that gives me the expected result.
select status_code,start_date,a2.member_id from availablities a2
join availablity_status on availablity_status.availablity_status_id = a2.availablity_status_id
where a2.availablity_id in(
select
max(availablity_id)
from availablities a
where
a.member_id = a2.member_id and
start_date in(
select
max(start_date) start_date
from availablities
where
start_date <= now()
and a.member_id = availablities.member_id
)
);
But this query takes 60 times longer to execute and doesn't feel right.
I'm pretty sure there must be a better solution but I can't get my hands on it.
What is the correct way to get the expected result?
I've created a DB-fiddle to make it easier to see. Query 1 is incorrect and Query 2 is much slower when we have a couple more data.
https://www.db-fiddle.com/f/iWgvuj8kcms9F5CKuoKsny/2
It looks like you need to use a simple row_number window function here:
with a as (
select *, Row_Number() over(partition by member_id order by start_date desc, availablity_id desc) rn
from availablities
where start_date<now()
)
select s.status_code, a.start_date, a.member_id
from a join availablity_status s on s.availablity_status_id=a.availablity_status_id
where rn=1
Note your data is not selective enough, so for member_id 3, is it available or not? What is the most recent date when there are two identical dates?
I added a tie-breaker to also sort by availability_id to get your expected results
Actually it's availablity_id - you seem to have a common typo here!
See your updated Fiddle
I have a table where limits were sanctioned to the customer
I am trying to get the output as below picture i.e. total amount sanctioned till particular date
I am trying below code but this sums the total sanction amount
select gam.id, sum(SANCTION_AMOUNT) from gam
join (select ID,ACCOUNT_OPEN_DATE from gam where ACCOUNT_OPEN_DATE between'01-04-2019' and '30-04-2019' AND SCHEME_CODE IN ('SB','CCKLY')) ) action
on( gam.ACCOUNT_OPEN_DATE <=action.ACCOUNT_OPEN_DATE and gam.id=action.cust_id) group by gam.id;
In Oracle, this can be a way:
select id, sanction_amount, scheme_code, account_open_date,
sum(sanction_amount) over (partition BY ID order by account_open_date) as total_sanction_amount
from gam
order by account_open_date
Not sure your database is MySQL or Oracle, But this below script is workable in most of the database. Just adjust the table and column names accordingly.
You can check MySQL DEMO HERE
SELECT *,
(
SELECT SUM(sanction_Amount)
FROM Your_Table B
WHERE B.ID = A.ID
AND B.acc_open_date <= A.acc_open_date
) Total_sanction_Amount
FROM Your_Table A
Very simple basic SQL question here.
I have this table:
Row Id __________Hour__Minute__City_Search
1___1409346767__23____24_____Balears (Illes)
2___1409346767__23____13_____Albacete
3___1409345729__23____7______Balears (Illes)
4___1409345729__23____3______Balears (Illes)
5___1409345729__22____56_____Balears (Illes)
What I want to get is only one distinct row by ID and select the last City_Search made by the same Id.
So, in this case, the result would be:
Row Id __________Hour__Minute__City_Search
1___1409346767__23____24_____Balears (Illes)
3___1409345729__23____7______Balears (Illes)
What's the easier way to do it?
Obviously I don't want to delete any data just query it.
Thanks for your time.
SELECT Row,
Id,
Hour,
Minute,
City_Search
FROM Table T
JOIN
(
SELECT MIN(Row) AS Row,
ID
FROM Table
GROUP BY ID
) AS M
ON M.Row = T.Row
AND M.ID = T.ID
Can you change hour/minute to a timestamp?
What you want in this case is to first select what uniquely identifies your row:
Select id, max(time) from [table] group by id
Then use that query to add the data to it.
SELECT id,city search, time
FROM (SELECT id, max(time) as lasttime FROM [table] GROUP BY id) as Tkey
INNER JOIN [table] as tdata
ON tkey.id = tdata.id AND tkey.lasttime = tdata.time
That should do it.
two options to do it without join...
use Row_Number function to find the last one
Select * FROM
(Select *,
row_number() over(Partition BY ID Order BY Hour desc Minute Desc) as RNB
from table)
Where RNB=1
Manipulate the string and using simple Max function
Select ID,Right(MAX(Concat(Hour,Minute,RPAD(Searc,20,''))),20)
From Table
Group by ID
avoiding Joins is usually much faster...
Hope this helps
I am trying to write a script that will return the latest values for a unique documentid-physician-patient triplet. I need the script to act similar to a group by statement, except group by only works with one column at a time. I need to date and status information for only the most recent unique triplet. Please let me know what you will need to see from me to help. Here is the current, very bare, statement:
SELECT
TransmissionSend.CreateTimestamp,
TransmissionSendItem.Status,
TransmissionSendItem.PhysicianId,
TransmissionSendItem.DocumentIdDisplay,
Utility.SqlFunctions_NdnListToAccountList(TransmissionSendItem.NdocNum) AS AccountNum
FROM
Interface_SFAX.TransmissionSend,
Interface_SFAX.TransmissionSendItem
WHERE
TransmissionSend.ID = TransmissionSendItem.childsub --I don't know exactly what this does, I did not write this script. It must stay here though for the exact results.
ORDER BY TransmissionSend.CreateTimestamp DESC -- In the end, each latest result of the unique triplet will be ordered from most recent to oldest in return
My question is, again, how can I limit results to only the latest status for each physician id, document id, and account number combination?
First select the MAX(date) with the documentid GROUP BY documentid then select all data from the table by the first select result for example with an inner join.
SELECT table.additionalData, J.id, J.date
FROM table
INNER JOIN (SELECT id, MAX(date) AS date
FROM table GROUP BY id) AS J
ON J.id = table.id
AND J.date /* this is the max date */ = table.date
I have been trying to find some info on how to select a non-aggregate column that is not contained in the Group By statement in SQL, but nothing I've found so far seems to answer my question. I have a table with three columns that I want from it. One is a create date, one is a ID that groups the records by a particular Claim ID, and the final is the PK. I want to find the record that has the max creation date in each group of claim IDs. I am selecting the MAX(creation date), and Claim ID (cpe.fmgcms_cpeclaimid), and grouping by the Claim ID. But I need the PK from these records (cpe.fmgcms_claimid), and if I try to add it to my select clause, I get an error. And I can't add it to my group by clause because then it will throw off my intended grouping. Does anyone know any workarounds for this? Here is a sample of my code:
Select MAX(cpe.createdon) As MaxDate, cpe.fmgcms_cpeclaimid
from Filteredfmgcms_claimpaymentestimate cpe
where cpe.createdon < 'reportstartdate'
group by cpe.fmgcms_cpeclaimid
This is the result I'd like to get:
Select MAX(cpe.createdon) As MaxDate, cpe.fmgcms_cpeclaimid, cpe.fmgcms_claimid
from Filteredfmgcms_claimpaymentestimate cpe
where cpe.createdon < 'reportstartdate'
group by cpe.fmgcms_cpeclaimid
The columns in the result set of a select query with group by clause must be:
an expression used as one of the group by criteria , or ...
an aggregate function , or ...
a literal value
So, you can't do what you want to do in a single, simple query. The first thing to do is state your problem statement in a clear way, something like:
I want to find the individual claim row bearing the most recent
creation date within each group in my claims table
Given
create table dbo.some_claims_table
(
claim_id int not null ,
group_id int not null ,
date_created datetime not null ,
constraint some_table_PK primary key ( claim_id ) ,
constraint some_table_AK01 unique ( group_id , claim_id ) ,
constraint some_Table_AK02 unique ( group_id , date_created ) ,
)
The first thing to do is identify the most recent creation date for each group:
select group_id ,
date_created = max( date_created )
from dbo.claims_table
group by group_id
That gives you the selection criteria you need (1 row per group, with 2 columns: group_id and the highwater created date) to fullfill the 1st part of the requirement (selecting the individual row from each group. That needs to be a virtual table in your final select query:
select *
from dbo.claims_table t
join ( select group_id ,
date_created = max( date_created )
from dbo.claims_table
group by group_id
) x on x.group_id = t.group_id
and x.date_created = t.date_created
If the table is not unique by date_created within group_id (AK02), you you can get duplicate rows for a given group.
You can do this with PARTITION and RANK:
select * from
(
select MyPK, fmgcms_cpeclaimid, createdon,
Rank() over (Partition BY fmgcms_cpeclaimid order by createdon DESC) as Rank
from Filteredfmgcms_claimpaymentestimate
where createdon < 'reportstartdate'
) tmp
where Rank = 1
The direct answer is that you can't. You must select either an aggregate or something that you are grouping by.
So, you need an alternative approach.
1). Take you current query and join the base data back on it
SELECT
cpe.*
FROM
Filteredfmgcms_claimpaymentestimate cpe
INNER JOIN
(yourQuery) AS lookup
ON lookup.MaxData = cpe.createdOn
AND lookup.fmgcms_cpeclaimid = cpe.fmgcms_cpeclaimid
2). Use a CTE to do it all in one go...
WITH
sequenced_data AS
(
SELECT
*,
ROW_NUMBER() OVER (PARITION BY fmgcms_cpeclaimid ORDER BY CreatedOn DESC) AS sequence_id
FROM
Filteredfmgcms_claimpaymentestimate
WHERE
createdon < 'reportstartdate'
)
SELECT
*
FROM
sequenced_data
WHERE
sequence_id = 1
NOTE: Using ROW_NUMBER() will ensure just one record per fmgcms_cpeclaimid. Even if multiple records are tied with the exact same createdon value. If you can have ties, and want all records with the same createdon value, use RANK() instead.
You can join the table on itself to get the PK:
Select cpe1.PK, cpe2.MaxDate, cpe1.fmgcms_cpeclaimid
from Filteredfmgcms_claimpaymentestimate cpe1
INNER JOIN
(
select MAX(createdon) As MaxDate, fmgcms_cpeclaimid
from Filteredfmgcms_claimpaymentestimate
group by fmgcms_cpeclaimid
) cpe2
on cpe1.fmgcms_cpeclaimid = cpe2.fmgcms_cpeclaimid
and cpe1.createdon = cpe2.MaxDate
where cpe1.createdon < 'reportstartdate'
Thing I like to do is to wrap addition columns in aggregate function, like max().
It works very good when you don't expect duplicate values.
Select MAX(cpe.createdon) As MaxDate, cpe.fmgcms_cpeclaimid, MAX(cpe.fmgcms_claimid) As fmgcms_claimid
from Filteredfmgcms_claimpaymentestimate cpe
where cpe.createdon < 'reportstartdate'
group by cpe.fmgcms_cpeclaimid
What you are asking, Sir, is as the answer of RedFilter.
This answer as well helps in understanding why group by is somehow a simpler version or partition over:
SQL Server: Difference between PARTITION BY and GROUP BY
since it changes the way the returned value is calculated and therefore you could (somehow) return columns group by can not return.
You can use as below,
Select X.a, X.b, Y.c from (
Select X.a as a, sum (b) as sum_b from name_table X
group by X.a)X
left join from name_table Y on Y.a = X.a
Example;
CREATE TABLE #products (
product_name VARCHAR(MAX),
code varchar(3),
list_price [numeric](8, 2) NOT NULL
);
INSERT INTO #products VALUES ('paku', 'ACE', 2000)
INSERT INTO #products VALUES ('paku', 'ACE', 2000)
INSERT INTO #products VALUES ('Dinding', 'ADE', 2000)
INSERT INTO #products VALUES ('Kaca', 'AKB', 2000)
INSERT INTO #products VALUES ('paku', 'ACE', 2000)
--SELECT * FROM #products
SELECT distinct x.code, x.SUM_PRICE, product_name FROM (SELECT code, SUM(list_price) as SUM_PRICE From #products
group by code)x
left join #products y on y.code=x.code
DROP TABLE #products