Remove grouped data set when total of count is zero with subquery - sql

Question

I'm generating a data set that looks like this
category user total
1 jonesa 0
2 jonesa 0
3 jonesa 0
1 smithb 0
2 smithb 0
3 smithb 5
1 brownc 2
2 brownc 3
3 brownc 4
Where a particular user has 0 records in all categories is it possible to remove their rows form the set? If a user has some activity like smithb does, I'd like to keep all of their records. Even the zeroes rows. Not sure how to go about that, I thought a CASE statement may be of some help but I'm not sure, this is pretty complicated for me. Here is my query
SELECT DISTINCT c.category,
u.user_name,
CASE WHEN (
SELECT COUNT(e.entry_id)
FROM category c1
INNER JOIN entry e1
ON c1.category_id = e1.category_id
WHERE c1.category_id = c.category_id
AND e.user_name = u.user_name
AND e1.entered_date >= TO_DATE ('20140625','YYYYMMDD')
AND e1.entered_date <= TO_DATE ('20140731', 'YYYYMMDD')) > 0 -- I know this won't work
THEN 'Yes'
ELSE NULL
END AS TOTAL
FROM user u
INNER JOIN role r
ON u.id = r.user_id
AND r.id IN (1,2),
category c
LEFT JOIN entry e
ON c.category_id = e.category_id
WHERE c.category_id NOT IN (19,20)
I realise the case statement won't work, but it was an attempt on how this might be possible. I'm really not sure if it's possible or the best direction. Appreciate any guidance.

Answer 1

Try this:
delete from t1
where user in (
select user
from t1
group by user
having count(distinct category) = sum(case when total=0 then 1 else 0 end) )
The sub query can get all the users fit your removal requirement.
count(distinct category) get how many category a user have.
sum(case when total=0 then 1 else 0 end) get how many rows with activities a user have.

Answer 2

There are a number of ways to do this, but the less verbose the SQL is, the harder it may be for you to follow along with the logic. For that reason, I think that using multiple Common Table Expressions will avoid the need to use redundant joins, while being the most readable.
-- assuming user_name and category_name are unique on [user] and [category] respectively.
WITH valid_categories (category_id, category_name) AS
(
-- get set of valid categories
SELECT c.category_id, c.category AS category_name
FROM category c
WHERE c.category_id NOT IN (19,20)
),
valid_users ([user_name]) AS
(
-- get set of users who belong to valid roles
SELECT u.[user_name]
FROM [user] u
WHERE EXISTS (
SELECT *
FROM [role] r
WHERE u.id = r.[user_id] AND r.id IN (1,2)
)
),
valid_entries (entry_id, [user_name], category_id, entry_count) AS
(
-- provides a flag of 1 for easier aggregation
SELECT e.[entry_id], e.[user_name], e.category_id, CAST( 1 AS INT) AS entry_count
FROM [entry] e
WHERE e.entered_date BETWEEN TO_DATE('20140625','YYYYMMDD') AND TO_DATE('20140731', 'YYYYMMDD')
-- determines if entry is within date range
),
user_categories ([user_name], category_id, category_name) AS
( SELECT u.[user_name], c.category_id, c.category_name
FROM valid_users u
-- get the cartesian product of users and categories
CROSS JOIN valid_categories c
-- get only users with a valid entry
WHERE EXISTS (
SELECT *
FROM valid_entries e
WHERE e.[user_name] = u.[user_name]
)
)
/*
You can use these for testing.
SELECT COUNT(*) AS valid_categories_count
FROM valid_categories
SELECT COUNT(*) AS valid_users_count
FROM valid_users
SELECT COUNT(*) AS valid_entries_count
FROM valid_entries
SELECT COUNT(*) AS users_with_entries_count
FROM valid_users u
WHERE EXISTS (
SELECT *
FROM user_categories uc
WHERE uc.user_name = u.user_name
)
SELECT COUNT(*) AS users_without_entries_count
FROM valid_users u
WHERE NOT EXISTS (
SELECT *
FROM user_categories uc
WHERE uc.user_name = u.user_name
)
SELECT uc.[user_name], uc.[category_name], e.[entry_count]
FROM user_categories uc
INNER JOIN valid_entries e ON (uc.[user_name] = e.[user_name] AND uc.[category_id] = e.[category_id])
*/
-- Finally, the results:
SELECT uc.[user_name], uc.[category_name], SUM(NVL(e.[entry_count],0)) AS [entry_count]
FROM user_categories uc
LEFT OUTER JOIN valid_entries e ON (uc.[user_name] = e.[user_name] AND uc.[category_id] = e.[category_id])

Answer 3

Here's another method:
WITH totals AS (
SELECT
c.category,
u.user_name,
COUNT(e.entry_id) AS total,
SUM(COUNT(e.entry_id)) OVER (PARTITION BY u.user_name) AS user_total
FROM
user u
INNER JOIN
role r ON u.id = r.user_id
CROSS JOIN
category c
LEFT JOIN
entry e ON c.category_id = e.category_id
AND u.user_name = e.user_name
AND e1.entered_date >= TO_DATE ('20140625', 'YYYYMMDD')
AND e1.entered_date <= TO_DATE ('20140731', 'YYYYMMDD')
WHERE
r.id IN (1, 2)
AND c.category_id IN (19, 20)
GROUP BY
c.category,
u.user_name
)
SELECT
category,
user_name,
total
FROM
totals
WHERE
user_total > 0
;
The totals derived table calculates the totals per user and category as well as totals across all categories per user (using SUM() OVER ...). The main query returns only rows where the user total is greater than zero.