I am using SQL*Plus. This is what I am to do: Using the BOOK_ORDER table, create a query using the correct function to return the order number, the date ordered, the date shipped, and a column representing the number of months between the two dates for all columns where a date shipped exists. Format the number returned from the function to display only two decimals, and give the column an alias of "Months Between".
NOTE: Be sure that all of the numbers in the fourth column are positive numbers
I've started it this way; however, I am a bit lost and confused in what I am doing.
SELECT BOOK_ORDER.ORDERID, BOOK_ORDER.ORDERDATE, BOOK_ORDER.SHIPDATE ||', ' ||
Can someone help?
The assignment clearly points to using the Oracle built-in function MONTHS_BETWEEN. It's in the documentation. Find out more.
select b.orderid
, b.orderdate
, b.shipdate
, round(months_between(b.orderdate, b.shipdate),2) as "months between"
from book_order b
where b.shipdate is not null
/
Please be sure to give SO credit when you hand in your homemwork.
Related
Im trying to make a small report for myself to see how my much time I get inputed in my system every day.
The goal is to have my SQL to sum up the name, Total time worked and Total NG product found for one specific day.
In this order:
1.) Sort out my data for a specific 'date'. I.E 2016-06-03
2.) Present a DISTINCT value for 'operators'
3.) SUM() all time registered at this 'date' and by this 'operator' under 'total_working_time_h'
4.) SUM() all no_of_defects registered at this 'date' and by this 'operator' under 'no_of_defects'
date, operator, total_working_time_h, no_of_defects
Currently I get the data I want by using the Query below. But now I need both the DISTINCT value of the operator and the SUM of the information. Can I use sub-queries for this or should it be done by a loop? Any other hints where I can learn more about how to solve this?
If i run the DISTINCT function I don't get the opportunity to sum my data the way I try.
SELECT date, operator, total_working_time_h, no_of_defects FROM {$table_work_hours} WHERE date = '2016-06-03' "
Without knowing the table structure or contents, the following query is only a good guess. The bits to notice and work with are sum() and GROUP BY. Actually syntax will vary a bit depending on what RDBMS you are using.
SELECT
date
,operator
,SUM(total_working_time_h) AS total_working_time_h
,SUM(no_of_defects) AS no_of_defects
FROM {$table_work_hours}
WHERE date = '2016-06-03'
GROUP BY
date
,operator
(Take out the WHERE clause or replace it with a range of dates to get results per operator per date.)
I'm not sure why you are trying to do DISTINCT. You want to know the data, no of hours, etc for a specific date.
do this....
Select Date, Operator, 'SumWorkHrs'=sum(total_working_time_h),
'SumDefects'=sum(no_ofDefects) from {$table_work_hours}
Where date='2016-06-03'
Try this:
SELECT SUM(total_working_time) as total_working_time,
SUM(no_of_defects) as no_of_defects ,
DISTINCT(operator) AS operator FROM {$table_work_hours} WHERE
date = '2016-06-03'
I have imported a price list from a csv to my SQL Server database. That has worked fine. But now some weird stuff. Table is named PRICE which includes a column (and some more) Endprice and a total of 761 rows. All datatypes are varchar(50).
SELECT MAX(Endprice)
FROM PRICE
When I want this simple SQL statement to show the highest price in the column, I get a wrong result. I don't know why.
I get 98,39 as a result, but that's definitively wrong, it must be 100,73.
Here you can see a part of the data:
And now the wrong MAX() result:
BUT when I'm using the MIN function I get the highest one!? The min is somewhere at ~50 (not shown in the screenshot part).
`
The resultset of SELECT Endprice FROM PRICE is correct. I am at my wit's end.
This is because your column is a varchar, so it is determining the min or max based on characters. The column should be a decimal or money type, so it sorts by the value of your number (instead of an alphabetic sort like you are getting now).
Alphabetic sort: 9 is more than 1, thus 98.39 is the max.
The reason is because price is a varchar().
Here are two solutions:
order by len(price), price
This works assuming that all the price values have the same structure.
Or:
order by cast(price as float)
If you could have non-numeric values (always a danger when storing numbers in the wrong data type):
order by (case when isnumeric(price) = 1 then cast(price as float) end)
Or better yet:
alter table alter column price money
Then you don't have to worry about having the wrong type for the column.
Your problem is Endprice columns is varchar(50), therefore it is comparing strings not numbers, which means that a 9>1 no matter what cames next of the first digit. You have to convert it to a number before the max!
Also you really should consider in doing what #a_horse_with_no_name suggested change your column into a number like column type.
This is a example on how you solve your actual problem
select max(cast(endprice as money)) from sample
See it here: http://sqlfiddle.com/#!3/767f6/1
Note that I used . as a decimal separator it will depend on your database language setup.
I have this simple data base:
7/2/2013
7/13/2013
I write a simple SQL statement to select the greatest date from a list of date. I try to use the (max function) as follow:
select max([P_Date]) from [BalDB].[dbo].[tab_Product]
The result was incorrect; it gives me the smallest date not the greatest as follow:
7/2/2013
So please help me to know what is the problem in my SQL statement and how can I solve it
Problem: Get the greatest date from a list of date or compare it with local date and take the greater!!
The sql max function returns the largest value of the selected column, in your case since your data type is a nvarchar the largest value is what is alphabetically larger, which in this case is 7/2/2013 (since the "2" is greater then the "1" in "13").
What you need to do is basically what #David mentioned, either chance the data type of the column or if it isn't feasible then you can cast it in your query as a datetime
For example
select max(cast([P_Date] as datetime)) from [BalDB].[dbo].[tab_Product]
The max function is making this slower than it needs to be, try this.
select top 1 convert(datetime,P_Date) from [BalDB].[dbo].[tab_Product] order by convert(datetime,P_Date) desc
Now your dates should be date types, not varchars, but for the sake of querying your data as is, this will work.
I am trying to add months to an existing date in SQL. The new column displayed will have a followup column instead of a days column. Im getting an error in the select statement.can u help?
Create table auctions(
item varchar2(50),
datebought date,
datesold date,
days number
);
Insert into auctions values (‘Radio’,’12-MAY-2001’,’21-MAY-2001’,9);
Select item,datebought,datesold,ADD MONTHS(datesold,3)”followup” from auctions;
Your usage of the add_months() function is incorrect. It's not two words, it's just one (with an underscore)
add_months(datesold, 1)
note the underscore _ between ADD and MONTHS. It's function call not an operator.
Alternatively you could use:
datesold + INTERVAL '1' month
Although it's worth noting that the arithmetics with intervals is limited (if not broken) because it simply "increments" the month value of the date value. That can lead to invalid dates (e.g. from January to February). Although this is documented behaviour (see below links) I consider this a bug (the SQL standard requires those operations to "Arithmetic obey the natural rules associated with dates and times and yield valid datetime or interval results according to the Gregorian calendar")
See the manual for details:
http://docs.oracle.com/cd/E11882_01/server.112/e26088/functions011.htm#i76717
http://docs.oracle.com/cd/E11882_01/server.112/e26088/sql_elements001.htm#i48042
Another thing:
I am trying to add months to an existing date in SQL.
Then why are you using an INSERT statement? To change the data of existing rows you should use UPDATE. So it seems what you are really after is something like this:
update auctions
set datesold = add_months(datesold, 1)
where item = 'Radio';
Your SQL has typographical quotation marks, not standard ones. E.g. ’ is not the same as '. Instead of delimiting a string value, those quotes become part of the value, at least for the particular SQL I have here to test with.
If this doesn't fix your problem, try posting the error you're getting in your question. Magical debugging isn't possible.
This can be used to add months to a date in SQL:
select DATEADD(mm,1,getdate())
This might be a useful link.
I'm blacking out on my basic SQL and would appreciate a quick hand:
I have a SQLite table, with 2 columns: Datetime, and a string saying something like "call from 555-555-3344".
I need a simple query that will give me a count of all distinct phone numbers that called on a certain day.
If the field had contained just the number, I could have used Select Distinct on it. How do I do it if the value (phone number) is a substring in that field (though always the last 10 digits).
Assistance, as always, much appreciated.
Guy
You can use the following (I used 12 instead of 10 in order to include the separator -):
SELECT COUNT(DISTINCT SUBSTR(phone_nbr, -12))
FROM table
WHERE call_dt = :call_dt;