I am using PL/SQL v7.1
I am trying to find all address records where the country name has been entered in one of the address line fields, and also the country field.
The problem is that the country details have not been entered consistently eg.
addr4 addr5 country
---------- ---------- ---------------
JERSEY UK(JERSEY)
IRELAND REPUBLIC OFIRELAND
DOUGLAS ISLE OF MAN UK(ISLE OF MAN)
So, I need to find the records where ANY PART of the Country field is also found in either addr4 or addr5.
I started with this
SELECT *
FROM test_addresses
WHERE addr4||addr5 LIKE '%'||country||'%'
I know this doesn't work because it will, taking the 1st record as an example, check if 'UK(JERESEY)' is found in addr4||addr5 and ,so, no match will be found. But how do I make it check if 'JERSEY' is found in addr4||addr5
Try this way:
SELECT *
FROM test_addresses
WHERE (addr4 is not null and country like '%'||addr4||'%')
or (addr5 is not null and country like '%'||addr5||'%')
Sql Fiddle Demo
I don't know so much about plsql
but I think your query is backwards, try this.
SELECT *
FROM test_addresses
WHERE country LIKE '%'||addr4||'%'
or country LIKE '%'||addr5||'%'
Related
I was given a patient list with names and I am trying to match with a list already in our database and am having troubles given the format of the name field in the patient list. This list is taken from a web form so people can input names however they want so it does not match up well.
WEBFORM_NAME
PATIENT_NAME
JOHN SMITH
SMITH,JOHN L
SHANNON BROWN
BROWN,SHANNON MARIE
Is there a way to use a LIKE clause in an instance like this? All I really need is the LIKE clause to find the first name because I have joined on phone number and email address already. My issue is when households have the same phone number and email address (spouses for example) I just want to return the right person in the household.
Not sure if all you need is to get first name, here is the WIldCard expression to get first name
SELECT LEFT(WEBFORM_NAME,CHARINDEX(' ',WEBFORM_NAME)-1) AS FirstName1,
SUBSTRING(PATIENT_NAME,CHARINDEX(',',PATIENT_NAME)+1,(CHARINDEX(' ',PATIENT_NAME)-CHARINDEX(',',PATIENT_NAME))) AS FirstName2
FROM yourTable
The assumption here seems to be that the webform (where user would manually) type in the name would be of the format <First Name> [<optional middle Name(s)>] <Last Name>, where as the data stored in the table are of the form <Last Name>,<First Name> [<optional middle Name(s)>]. Its not an exact science, but since other criteria (like email, phone etc) have been matched best case
select *
from webform w, patient p
where
-- extract just the last name and match that
regexp_like(p.name,
'^' ||
regexp_extract(w.name,
'([^[:space:],][[:space:],])*([^[:space:],]+)', 1, 2))
and -- extract the first name and match it
regexp_like(p.name,
',[[:space:]]*' ||
regexp_extract(w.name, '(^[^[:space:],]+)'))
Since webform is free form user input, its hard to handle abbreviated middle name(s) and other variations so using the above will do first name and last name based matching which in addition to the matching you are already doing should help.
Looking into my notes for introduction to databases, I have stumbled upon a case that i do not understand (Between except and distinct).
It says so in my notes that:
The two queries below have the same results, but this will not be the case in general.
First query:
Select c.first_name,c.last_name,c.email
FROM customers as c
WHERE c.country = 'Japan'
EXCEPT
Select c.first_name,c.last_name,c.email
FROM customers as c
WHERE c.last_name LIKE 'D%';
Second query:
Select DISTINCT c.first_name,c.last_name,c.email
FROM customers as c
WHERE c.country = 'Japan' AND NOT (c.last_name LIKE 'D%');
Could anyone provide me some insights as to what are cases whereby the results would differ?
Number 1 selects first, last & email from customers who are from Japan and whose last names do not start with D.
Number 2 selects first, last & email, where no two records have all 3 fields the same, where the customers are from Singapore and their last names do not begin with D.
I suppose I can imagine a table where these would yield the same results, but I don't think it would ever appear except in very contrived circumstances.
Joe Smith jsmith#abc.com Japan
Joe Smith jsmith#abc.com Singapore
Would be one of them. Both queries would yield Joe Smith jsmith#abc.com. Another case would be if no-one was from either country or everyone's last name started with D, then they would both yield nothing.
None of this is tested, and the EXCEPT statement is something I've read about but never had occasion to use.
The first is looking at Japan, the second at Singapore, so I don't see why these would generally -- or specifically -- return the same data.
Even if the countries were the same you have another issue with NULL values. So, if your data looks like this:
first_name last_name email country
xxx NULL a Japan
Your first query would return the row. The second would not.
i've got a simple sql question:
I want to get all Customers(more precise: their name and their balance) working in a sector ending with E. I Want to order my results alphabetically by name. Therefore my query is:
SELECT Name,Balance FROM customer WHERE sector LIKE '%E' ORDER BY Name
, which is giving me false results.
I tested it by looking up which sectors exist:
SELECT Distinct(Sector) FROM Kunde
giving me:
Sector
----------
AUTOMOBILE
BUILDING
FURNITURE
HOUSEHOLD
MACHINERY
Now i tried using a query like
SELECT Distinct(Sector) FROM customer WHERE Sector LIKE '%E'
only giving me:
Sector
----------
AUTOMOBILE
It's probably me being stupid here, but why w'ont the last query give me AUTOMOBILE and FURNITURE? I don't see the problem. I'm using DB2 if thats important.
Thank you!
In case of trailing spaces, remove it :
SELECT Distinct(Sector)
FROM customer
WHERE RTRIM(Sector) LIKE '%E'
How would you list the people from a database that are not from 'London'?
Say the database is:
Cust_id address
1 33 avenue, Liverpool
2 21 street 12345, London
3 469 connection ave, Manchester
I'd like to list the customers that are NOT from London. Here's what I've tried:
select Cust_id from customers where address <> 'London';
Now when I do that, it lists all the customers, regardless of location.
Help would be greatly appericated.
Not ideal but might satisfy your requirements:
select Cust_id from customers
where address NOT LIKE '% London%';
[Note the added space: it assumes you will always precede the city name with a space. '%London%' would match words containing London]
(It might be better if you had a normalised address, i.e. broken into street address, town, city, etc.))
Try this:
select Cust_id from customers where address not like '%London%';
or this:
select Cust_id from customers where not address like '%London%';
Both of these are OK.
For more details on LIKE see e.g. here: SQL LIKE
I have a column called NAME, I have 2000 rows in that column that are filled with people's full names, e.g. ANN SMITH. How do I do a query that will list all the people whose first name is ANN? There are about 20 different names whose first name is ANN but the surname is different.
I tried
and (NAME = 'ANN')
but it returned zero results.
I have to enter the FULL name and (NAME = 'ANN SMITH') ANN SMITH to even get a result .
I just want to list all the people with there first name as ANN
Try in your where clause:
Where Name like 'ANN %'
Should work mate.
ANN% will find all results where ANN is first then anything after.
%ANN% will find the 3 letters ANN in any part of that rows field.
Hope it helps
Also usually Name is separated into First names and second name columns.
this will save Having to use wild cards in your SQL and provide A bit more normalized data.
SELECT NAME
FROM NAMES
WHERE NAME LIKE 'ANN %'
This should wildcard select anything that begins with 'ANN' followed by a space.