Fastest way to multiply X*X.transpose() in Eigen? - optimization

I want to multiple matrix with self transposed. The size of matrix about X[8, 100].
Now it looks " MatrixXf h = X*X.transpose()"
a) Is it possible to use faster multiplication using explicit facts:
Result matrix is symmetric
The X matrix use same data so, can use custom procedure for multiplication.
?
b)Also i can generate X matrix as transposed and use X.transpose()*X, whitch i should prefer for my dimensions ?
c) Any tips on faster multiplication of such matrixes.
Thanks.

(a) Your matrix is too small to take advantage of the symmetry of the result because if you do so, then you will loose vectorization. So there is not much you can do.
(b) The default column storage should be fine for that example.
(c) Make sure you compile with optimizations ON, that you enabled SSE2 (this is the default on 64 bits systems), the devel branch is at least twice as fast for such sizes, and you can get additional speedup by enabling AVX.

Related

Update submatrix in Tensorflow

Quite simply, what I want to do is the following
A = np.ones((3,3)) #arbitrary matrix
B = np.ones((2,2)) #arbitrary matrix
A[1:,1:] = A[1:,1:] + B
except in Tensorflow (where the matrices can be arbitrarily complicated tensor expressions). Neither A nor B is a Tensorflow Variable, but just a run-of-the-mill tensor.
What I have gathered so far: tensors are immutable, so I cannot assign to a submatrix. tf.scatter_nd is the current option for sub-assignment, but does not appear to support sub-matrices, only slices.
Methods that should work, but are perhaps not ideal:
I could pad B with zeros, but I'm sure this leads to instantiation of
an unnecessarily large B - can it be made sparse, maybe?
I could use the padding idea, but write it as a low-rank decomposition, e.g. in Numpy: A+U.dot(B).U.T where U is a stacked zero and identity matrix. I'm not sure this is actually advantageous.
I could split A into submatrices, and stack them back together. Might be the most efficient, but sounds like the code would be convoluted.
Ideally, I want to do this operation N times for progressively smaller matrices, resulting in one large final result, but this is tangential.
I'll use one of the hacks for now, but I'm hoping someone can tell me what the idiomatic version is!

Element-wise operations on arrays of different rank

How do I multiply two arrays of different rank, element-wise? For example, element-wise multiplying every row of a matrix with a vector.
real :: a(m,n), b(n)
My initial thought was to use spread(b,...), but it is my understanding that this tiles b in memory, which would make it undesirable for large arrays.
In MATLAB I would use bsxfun for this.
If the result of the expression is simply being assigned to another variable (versus being an intermediate in a more complicated expression or being used as an actual argument), then a loop (DO [CONCURRENT]) or FORALL assignment is likely to be best from the point of view of execution speed (though it will be processor dependent).

Optimize Blas-like operation - A`*B*A

Given two matrices, A and B, where B is symetric (and positive semi-definite), What is the best (fastest) way to calculate A`*B*A?
Currently, using BLAS, I first compute C=B*A using dsymm (introducing a temporary matrix C) and then A`*C using dgemm.
Is there a better (faster, no temporaries) way to do this using BLAS and mkl?
Thanks.
I'll offer somekind of answer: Compared to the general case A*B*C you know that the end result is symmetric matrix. After computing C=B*A with BLAS subroutine dsymm, you want to compute A'C, but you only need to compute the upper diagonal part of the matrix and the copy the strictly upper diagonal part to the lower diagonal part.
Unfortunately there doesn't seem to be a BLAS routine where you can claim beforehand that given two general matrices, the output matrix will be symmetric. I'm not sure if it would be beneficial to write you own function for this. This probably depends on the size of your matrices and the implementation.
EDIT:
This idea seems to be addressed recently here: A Matrix Multiplication Routine that Updates Only the Upper or Lower Triangular Part of the Result Matrix

Optimize MATLAB code (nested for loop to compute similarity matrix)

I am computing a similarity matrix based on Euclidean distance in MATLAB. My code is as follows:
for i=1:N % M,N is the size of the matrix x for whose elements I am computing similarity matrix
for j=1:N
D(i,j) = sqrt(sum(x(:,i)-x(:,j)).^2)); % D is the similarity matrix
end
end
Can any help with optimizing this = reducing the for loops as my matrix x is of dimension 256x30000.
Thanks a lot!
--Aditya
The function to do so in matlab is called pdist. Unfortunately it is painfully slow and doesnt take Matlabs vectorization abilities into account.
The following is code I wrote for a project. Let me know what kind of speed up you get.
Qx=repmat(dot(x,x,2),1,size(x,1));
D=sqrt(Qx+Qx'-2*x*x');
Note though that this will only work if your data points are in the rows and your dimensions the columns. So for example lets say I have 256 data points and 100000 dimensions then on my mac using x=rand(256,100000) and the above code produces a 256x256 matrix in about half a second.
There's probably a better way to do it, but the first thing I noticed was that you could cut the runtime in half by exploiting the symmetry D(i,j)==D(i,j)
You can also use the function norm(x(:,i)-x(:,j),2)
I think this is what you're looking for.
D=zeros(N);
jIndx=repmat(1:N,N,1);iIndx=jIndx'; %'# fix SO's syntax highlighting
D(:)=sqrt(sum((x(iIndx(:),:)-x(jIndx(:),:)).^2,2));
Here, I have assumed that the distance vector, x is initalized as an NxM array, where M is the number of dimensions of the system and N is the number of points. So if your ordering is different, you'll have to make changes accordingly.
To start with, you are computing twice as much as you need to here, because D will be symmetric. You don't need to calculate the (i,j) entry and the (j,i) entry separately. Change your inner loop to for j=1:i, and add in the body of that loop D(j,i)=D(i,j);
After that, there's really not much redundancy left in what that code does, so your only room left for improvement is to parallelize it: if you have the Parallel Computing Toolbox, convert your outer loop to a parfor and before you run it, say matlabpool(n), where n is the number of threads to use.

approximating log10[x^k0 + k1]

Greetings. I'm trying to approximate the function
Log10[x^k0 + k1], where .21 < k0 < 21, 0 < k1 < ~2000, and x is integer < 2^14.
k0 & k1 are constant. For practical purposes, you can assume k0 = 2.12, k1 = 2660. The desired accuracy is 5*10^-4 relative error.
This function is virtually identical to Log[x], except near 0, where it differs a lot.
I already have came up with a SIMD implementation that is ~1.15x faster than a simple lookup table, but would like to improve it if possible, which I think is very hard due to lack of efficient instructions.
My SIMD implementation uses 16bit fixed point arithmetic to evaluate a 3rd degree polynomial (I use least squares fit). The polynomial uses different coefficients for different input ranges. There are 8 ranges, and range i spans (64)2^i to (64)2^(i + 1).
The rational behind this is the derivatives of Log[x] drop rapidly with x, meaning a polynomial will fit it more accurately since polynomials are an exact fit for functions that have a derivative of 0 beyond a certain order.
SIMD table lookups are done very efficiently with a single _mm_shuffle_epi8(). I use SSE's float to int conversion to get the exponent and significand used for the fixed point approximation. I also software pipelined the loop to get ~1.25x speedup, so further code optimizations are probably unlikely.
What I'm asking is if there's a more efficient approximation at a higher level?
For example:
Can this function be decomposed into functions with a limited domain like
log2((2^x) * significand) = x + log2(significand)
hence eliminating the need to deal with different ranges (table lookups). The main problem I think is adding the k1 term kills all those nice log properties that we know and love, making it not possible. Or is it?
Iterative method? don't think so because the Newton method for log[x] is already a complicated expression
Exploiting locality of neighboring pixels? - if the range of the 8 inputs fall in the same approximation range, then I can look up a single coefficient, instead of looking up separate coefficients for each element. Thus, I can use this as a fast common case, and use a slower, general code path when it isn't. But for my data, the range needs to be ~2000 before this property hold 70% of the time, which doesn't seem to make this method competitive.
Please, give me some opinion, especially if you're an applied mathematician, even if you say it can't be done. Thanks.
You should be able to improve on least-squares fitting by using Chebyshev approximation. (The idea is, you're looking for the approximation whose worst-case deviation in a range is least; least-squares instead looks for the one whose summed squared difference is least.) I would guess this doesn't make a huge difference for your problem, but I'm not sure -- hopefully it could reduce the number of ranges you need to split into, somewhat.
If there's already a fast implementation of log(x), maybe compute P(x) * log(x) where P(x) is a polynomial chosen by Chebyshev approximation. (Instead of trying to do the whole function as a polynomial approx -- to need less range-reduction.)
I'm an amateur here -- just dipping my toe in as there aren't a lot of answers already.
One observation:
You can find an expression for how large x needs to be as a function of k0 and k1, such that the term x^k0 dominates k1 enough for the approximation:
x^k0 +k1 ~= x^k0, allowing you to approximately evaluate the function as
k0*Log(x).
This would take care of all x's above some value.
I recently read how the sRGB model compresses physical tri stimulus values into stored RGB values.
It basically is very similar to the function I try to approximate, except that it's defined piece wise:
k0 x, x < 0.0031308
k1 x^0.417 - k2 otherwise
I was told the constant addition in Log[x^k0 + k1] was to make the beginning of the function more linear. But that can easily be achieved with a piece wise approximation. That would make the approximation a lot more "uniform" - with only 2 approximation ranges. This should be cheaper to compute due to no longer needing to compute an approximation range index (integer log) and doing SIMD coefficient lookup.
For now, I conclude this will be the best approach, even though it doesn't approximate the function precisely. The hard part will be proposing this change and convincing people to use it.